OR operator inside EVALUATE statement COBOL - cobol

I would like to know if i can use the OR operator in this way:
EVALUATE TRUE
WHEN (COD-USER NOT EQUAL TO 01) OR (COD-USER NOT EQUAL TO 02)
ADD 1 TO CTN-ERROR
WHEN
...
END-EVALUATE
I think that it will work using IF but i need to do it with this statement. I have tried to put the parentheses on different positions but it did not work.
I have also tried to use different sentences like the following one and i got an invalid expression error:
COD-USER NOT EQUAL TO 01 OR 02

The answer to your question...
I would like to know if i can use the OR operator in this way:
...is "yes." However...
Is this what you want?
[...]
05 WS-COD-USER PIC 99 VALUE ZEROES.
88 DONT-ADD-1-TO-CTN-ERROR VALUES 1, 2.
[...]
MOVE COD-USER TO WS-COD-USER
EVALUATE TRUE
WHEN DONT-ADD-1-TO-CTN-ERROR
CONTINUE
WHEN OTHER
ADD 1 TO CTN-ERROR
END-EVALUATE
This will not add 1 to CTN-ERROR if COD-USER is 1. This will not add 1 to CTN-ERROR if COD-USER is 2. If COD-USER is any other value 1 will be added to CTN-ERROR.
I'm presuming COD-USER is in an FD or copybook. Otherwise you could just add the 88-levels following it.

In your example, you will always ADD 1 TO CTN-ERROR
Not sure what you want your other WHEN's to be or what you want to happen when COD-USER is 01 and when COD-USER is 02, but if you are wanting your code to something only when COD-USER is 01 or 02 then you could try something like:
EVALUATE COD-USER
WHEN 01
DO-SOMETHING
WHEN 02
DO-SOMETHING-ELSE
WHEN OTHER
ADD 1 TO CTN-ERROR
END-EVALUATE
OR
EVALUATE TRUE
WHEN COD-USER = 01
DO-SOMETHING
WHEN COD-USER = 02
DO-SOMETHING-ELSE
WHEN OTHER
ADD 1 TO CTN-ERROR
END-EVALUATE
This will do whatever you need it to when you match on 01 or 02 and anything else adds 1 to your count.

Yes you can use OR but the way you have written code will always be true as someone already stated in above answer. When can be written twice also as shown below
EVALUATE TRUE
WHEN COD-USER = 01
WHEN COD-USER = 02
CONTINUE
WHEN OTHER
ADD 1 TO CTN-ERROR
END-EVALUATE
In the above example when COD-USER = 01 or when COD-USER = 02 it will continue and for all other condition it will add 1 to the CTN-ERROR

Related

What is an easy way to get the ASCII value of a character in Cobol

We have to find more than one way to get the ascii value of a character.
On top of that we also need to get the sum of all the characters's ascii values.
I currently have the below and works alright for the first section where you need individual values
.
I just need to know if there is an easier way or a function to do this in Cobol?
DATA DIVISION.
FILE SECTION.
WORKING-STORAGE SECTION.
01 WS-COUNTERS.
03 WS-COUNTER PIC 9(05).
03 WS-INPUT PIC X(01).
03 WS-DISPLAY PIC 9(03).
01 W1-ARRAY.
03 ALPHABETIC-CHARS OCCURS 26 TIMES PIC X.
01 W3-ARRAY.
03 NUMERIC-CHARS OCCURS 26 TIMES PIC X.
PROCEDURE DIVISION.
A000-MAIN SECTION.
BEGIN.
PERFORM B000-INITIALIZE.
PERFORM C000-PROCESS UNTIL WS-COUNTER > 26.
PERFORM D000-END.
A099-EXIT.
STOP RUN.
B000-INITIALIZE SECTION.
ACCEPT WS-INPUT.
MOVE "ABCDEFGHIJKLMNOPQRSTUVWXYZ" TO W1-ARRAY.
MOVE "01234567890000000000000000" TO W3-ARRAY.
MOVE 1 TO WS-COUNTER.
MOVE 0 TO WS-DISPLAY.
B099-EXIT.
EXIT.
C000-PROCESS SECTION.
C001-BEGIN.
IF WS-INPUT IS NUMERIC
IF NUMERIC-CHARS(WS-COUNTER) = WS-INPUT
COMPUTE WS-DISPLAY = WS-COUNTER + 48 - 1
END-IF
ELSE
IF ALPHABETIC-CHARS(WS-COUNTER) = WS-INPUT
COMPUTE WS-DISPLAY = WS-COUNTER + 65 - 1
END-IF
END-IF.
ADD 1 TO WS-COUNTER.
C099-EXIT.
EXIT.
Have a look at FUNCTION ORD and keep in mind that you will get the ordinal number in the program's collating sequence (which may be EBCDIC or not the full ASCII).
As this function was introduced in the COBOL85 standard it should be available in most compilers (your question misses the compiler/machine you use).

Trouble with ACCEPT "ESC-CODE FROM ESCAPE KEY"

With Microsoft COBOL Compiler version 2.2 and I have this code that completely worked fine.
IDENTIFICATION DIVISION.
PROGRAM-ID. COCENTRY.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT COC-FILE
ASSIGN TO DISK
ORGANIZATION IS INDEXED
ACCESS MODE IS RANDOM
RECORD KEY IS COCNO
FILE STATUS IS FILE-STATUS.
DATA DIVISION.
FILE SECTION.
FD COC-FILE LABEL RECORD IS STANDARD
VALUE OF FILE-ID IS "COC.DAT".
01 COC-RECORD.
03 COCNO PIC 9(5).
03 COCDESC PIC X(40).
WORKING-STORAGE SECTION.
01 FILE-STATUS PIC XX.
01 ESC-CODE PIC 99 VALUE 0.
88 ESC-KEY VALUE 1.
88 F2 VALUE 3.
88 F10 VALUE 11.
01 ERRMSG PIC X(70) VALUE SPACES.
01 ERR PIC 9 VALUE 0.
SCREEN SECTION.
01 FORM1.
03 BLANK SCREEN BACKGROUND-COLOR 1.
03 LINE 1 COLUMN 1 'COCNO'.
03 LINE 2 COLUMN 1 'COCDESC'.
03 LINE 24 COLUMN 1 "Esc=Exit F2=Save F10=Cancel".
03 LINE 25 COLUMN 1 PIC X(70) FROM ERRMSG HIGHLIGHT.
01 FORM2.
03 LINE 1 COLUMN 14 PIC 9(5)
USING COCNO REVERSE-VIDEO.
03 LINE 2 COLUMN 14 PIC X(40)
USING COCDESC REVERSE-VIDEO.
03 LINE 24 COLUMN 1 PIC 99
USING ESC-CODE.
PROCEDURE DIVISION.
MAIN.
OPEN I-O COC-FILE.
IF FILE-STATUS NOT = '00'
OPEN OUTPUT COC-FILE
CLOSE COC-FILE
OPEN I-O COC-FILE.
PERFORM ENTRY1 THRU ENTRYX UNTIL ESC-KEY.
CLOSE COC-FILE.
STOP RUN.
ENTRY1.
MOVE SPACES TO COC-RECORD.
MOVE ZEROES TO COCNO.
ENTRY2.
DISPLAY FORM1 FORM2.
ACCEPT FORM2.
ACCEPT ESC-CODE FROM ESCAPE KEY.
IF F10
MOVE 'Entries canceled...' TO ERRMSG
GO ENTRY1
ELSE IF F2
GO ENTRY3
ELSE IF ESC-KEY
GO ENTRYX
ELSE
GO ENTRY2.
ENTRY3.
MOVE 0 TO ERR.
WRITE COC-RECORD INVALID KEY MOVE 1 TO ERR.
IF ERR = 1
MOVE 'Duplicate key not allowed...' TO ERRMSG
GO ENTRY2
ELSE
MOVE 'Entries recorded...' TO ERRMSG
GO ENTRY1.
ENTRYX.
EXIT.
Now I am using OpenCobol IDE 4.3.0 having GNUCobol version 1.1.0 and I am being prompted with this lines of
syntax error, unexpected "Literal", expecting LEADING or TRAILING
03 LINE 1 COLUMN 1 'COCNO'.
03 LINE 2 COLUMN 1 'COCDESC'.
03 LINE 24 COLUMN 1 "Esc=Exit F2=Save F10=Cancel".
So I fix them by adding VALUE keyword:
03 LINE 1 COLUMN 1 VALUE 'COCNO'.
03 LINE 2 COLUMN 1 VALUE 'COCDESC'.
03 LINE 24 COLUMN 1 VALUE "Esc=Exit F2=Save F10=Cancel".
but as soon as I do this I get a another prompt of
'ACCEPT .. FROM ESCAPE KEY' not implemented
on this line
ACCEPT ESC-CODE FROM ESCAPE KEY.
What could be the possible cause of this? And what could be the fix for this?
Your actual answer is here, https://sourceforge.net/p/open-cobol/discussion/help/thread/26a01c5f/, on the GnuCOBOL part of SourceForge. With minor changes your code will "completely work" with the change you've already made to include the VALUE clause, and if you use release 2.0 or higher of the GnuCOBOL compiler.
Your code may "completely work" but it is spaghetti code.
The term comes from the old days, and relates to the use of many branches in programs, a common practice at that time, but which made trying to follow the logic a process like trying to follow one strand of cooked spaghetti which is part of a pile of cooked spaghetti.
If you change this:
PERFORM ENTRY1 THRU ENTRYX UNTIL ESC-KEY.
To this:
PERFORM ENTRY1 THRU ENTRYX.
Your program will still work. Confused? Yes, because you have spaghetti. Your program flow will only ever get to ENTRYX once. The value when it arrives at ENTRYX is ESC-KEY, but that is superfluous, because it can only ever get there once, when it is ESC-KEY. Clear? No? Because you have spaghetti.
Here is your logic, re-written:
PROCEDURE DIVISION.
OPEN I-O COC-FILE
IF FILE-STATUS NOT = '00'
[the following code is a horror. Deal with this outside the
program. Crash for an unexpected FILE STATUS on OPEN]
OPEN OUTPUT COC-FILE
CLOSE COC-FILE
OPEN I-O COC-FILE
END-IF
PERFORM PROCESS-USER-INPUT
UNTIL ESC-KEY
CLOSE COC-FILE
IF FILE-STATUS NOT = '00'
[something bad has happened, so don't go quietly]
END-IF
GOBACK
.
PROCESS-USER-INPUT.
PERFORM BLANK-OUTPUT-RECORD
PERFORM PROCESS-COC
UNTIL ESC-KEY
.
PROCESS-COC.
DISPLAY FORM1 FORM2
ACCEPT FORM2
ACCEPT ESC-CODE FROM ESCAPE KEY
EVALUATE TRUE
WHEN F10
MOVE 'Entries canceled...' TO ERRMSG
WHEN F2
PERFORM CREATE-OUTPUT
END-EVALUATE
.
CREATE-OUTPUT.
WRITE COC-RECORD
IF ATTEMPT-TO-WRITE-DUPLICATE [22 on the FILE STATUS field]
MOVE 'Duplicate key not allowed...' TO ERRMSG
ELSE
MOVE 'Entries recorded...' TO ERRMSG
PERFORM BLANK-OUTPUT-RECORD
END-IF
.
BLANK-OUTPUT-RECORD.
MOVE SPACES TO COC-RECORD
MOVE ZEROES TO COCNO
.
Does that make your program look simpler? Easier to follow, change, understand what it does when someone else looks at it (or when you do in two weeks time)?
There are other things, like why set COC-RECORD to space, and then COCNO to zero? Move the spaces to COCDESC.
Make your data/procedure names good and descriptive. FILE STATUS having a good name (don't call it FILE-STATUS) and one per file when you have more than one file. Use full-stops/periods only where you have to, and use scope-delimiters for all conditional constructs that you use. Use FILE STATUS checking for all IO, and don't use the tortuous AT on IO.
If you look now the first code in your program is quite long, executes only once, and is (should be) irrelevant to the business function of your program. So stick all that in a paragraph, and PERFORM that. Same for the close. Then you can have as much code as you need when starting up and closing down, without making your program more difficult to follow.
The screen and keyboard I/O was a MicroSoft Cobol specific flavor. You will likely need to tweak that a bit to make it work with OpenCobol.
PROCEDURE DIVISION.
SET ENVIRONMENT 'COB_SCREEN_EXCEPTIONS' TO 'Y'.
SET ENVIRONMENT 'COB_SCREEN_ESC' TO 'Y'.
Escape: IF cob-crt-status = 2005......
Enter: IF cob-crt-status = 0........
F1: IF cob-crt-status = 1001......
F2: IF cob-crt-status = 1002......

Issues with GO TO statement on execution past the first time

Having issues with using the GO-TO statement. This is suppose to run until the user types 'END'. If I type 'END' when I first open the program it will close out but if I type it after entering valid data for the first pass thru it just continues to bring back the user input data screen.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT USED-CAR-FILE-OUT
ASSIGN TO 'USED-CAR.RPT'
ORGANIZATION IS LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD USED-CAR-FILE-OUT.
01 USED-CAR-RECORD-OUT PIC X(80).
WORKING-STORAGE SECTION.
01 FIRST-RECORD PIC X(3) VALUE 'YES'.
01 ID-CODE PIC X(3).
01 TOTAL-CASH-PAYMENT PIC 9(5).
01 MONTHLY-PAYMENT PIC 9(4).
01 NUMBER-OF-MONTHS PIC 9(3).
01 TOTAL-BALANCE PIC S9(6)V99 VALUE ZEROS.
01 INTEREST-COLLECTED PIC 99V99 VALUE ZEROS.
01 MONTH-DIFF PIC 99 VALUE ZEROS.
01 MONTH-NUM PIC 99 VALUE ZEROS.
01 YEAR-NUM PIC 99 VALUE ZEROS.
01 ID-HOLD PIC X(3) VALUE SPACES.
01 PAYMENT-HOLD PIC X(3) VALUE SPACES.
01 DETAIL-LINE.
05 ID-CODE-DL PIC X(3).
05 PIC X(3) VALUE SPACES.
05 PIC X(4) VALUE 'Yr='.
05 YEAR-NUMBER-DL PIC Z9.
05 PIC X(4) VALUE SPACES.
05 PIC X(4) VALUE 'MO='.
05 MONTH-NUMBER-DL PIC Z9.
05 PIC X(4) VALUE SPACES.
05 PIC X(5) VALUE 'Pmt='.
05 PAYMENT-DL PIC $$$,$$$.
05 PIC X(4) VALUE SPACES.
05 PIC X(5) VALUE 'Int='.
05 INTEREST-EARNED-DL PIC $$$$.99.
05 PIC X(3) VALUE SPACES.
05 PIC X(5) VALUE 'Bal='.
05 BALANCE-DL PIC $$$,$$$.99.
PROCEDURE DIVISION.
100-MAIN.
OPEN OUTPUT USED-CAR-FILE-OUT
PERFORM 200-USER-INPUT THRU 299-EXIT
CLOSE USED-CAR-FILE-OUT
STOP RUN.
200-USER-INPUT.
DISPLAY 'Used Car Sales Report'
DISPLAY 'Enter the ID code (or END) - maxium three char.'
ACCEPT ID-CODE
IF ID-CODE = 'END'
GO TO 299-EXIT
END-IF
DISPLAY 'Enter the Total Cash Payment - maximum five digits'
ACCEPT TOTAL-CASH-PAYMENT
DISPLAY 'Enter the Monthly Payment - maximum four digits'
ACCEPT MONTHLY-PAYMENT
DISPLAY 'Enter the Number of Months - maximum three digits'
ACCEPT NUMBER-OF-MONTHS
PERFORM 300-RECORD-PROCESS.
299-EXIT.
EXIT.
300-RECORD-PROCESS.
IF TOTAL-CASH-PAYMENT > 0
IF FIRST-RECORD = 'YES'
MOVE ID-CODE TO ID-CODE-DL
MOVE 1 TO YEAR-NUMBER-DL
MOVE 1 TO YEAR-NUM
move 1 to MONTH-NUMBER-DL
MOVE TOTAL-CASH-PAYMENT TO PAYMENT-DL
MOVE PAYMENT-DL TO MONTHLY-PAYMENT
ADD MONTHLY-PAYMENT TO TOTAL-BALANCE
MOVE 'NO' TO FIRST-RECORD
END-IF
COMPUTE INTEREST-COLLECTED ROUNDED = TOTAL-BALANCE
* .0175 / 12
MOVE INTEREST-COLLECTED TO INTEREST-EARNED-DL
ADD INTEREST-COLLECTED TO TOTAL-BALANCE
MOVE TOTAL-BALANCE TO BALANCE-DL
ADD 1 TO MONTH-DIFF
MOVE MONTH-DIFF TO MONTH-NUMBER-DL
IF MONTH-NUMBER-DL > 13
ADD 1 TO MONTH-NUM
MOVE MONTH-NUM TO MONTH-NUMBER-DL
END-IF
IF MONTH-NUMBER-DL = 13
MOVE 1 TO MONTH-NUM
MOVE MONTH-NUM TO MONTH-NUMBER-DL
END-IF
IF MONTH-NUM = 1
ADD 1 TO YEAR-NUM
MOVE YEAR-NUM TO YEAR-NUMBER-DL
END-IF
MOVE DETAIL-LINE TO USED-CAR-RECORD-OUT
WRITE USED-CAR-RECORD-OUT
AFTER ADVANCING 1 LINE
MOVE ID-HOLD TO ID-CODE-DL
IF MONTH-DIFF < NUMBER-OF-MONTHS
PERFORM 300-RECORD-PROCESS
END-IF
PERORM 200-USER-INPUT
END-IF
IF MONTHLY-PAYMENT > 0
IF FIRST-RECORD = 'YES'
MOVE ID-CODE TO ID-CODE-DL
MOVE 1 TO YEAR-NUMBER-DL
MOVE 1 TO YEAR-NUM
move 1 to MONTH-NUMBER-DL
MOVE 'NO' TO FIRST-RECORD
END-IF
MOVE MONTHLY-PAYMENT TO PAYMENT-DL
MOVE PAYMENT-DL TO MONTHLY-PAYMENT
ADD MONTHLY-PAYMENT TO TOTAL-BALANCE
COMPUTE INTEREST-COLLECTED ROUNDED = TOTAL-BALANCE
* .0175 / 12
MOVE INTEREST-COLLECTED TO INTEREST-EARNED-DL
ADD INTEREST-COLLECTED TO TOTAL-BALANCE
MOVE TOTAL-BALANCE TO BALANCE-DL
ADD 1 TO MONTH-DIFF
MOVE MONTH-DIFF TO MONTH-NUMBER-DL
IF MONTH-NUMBER-DL > 13
ADD 1 TO MONTH-NUM
MOVE MONTH-NUM TO MONTH-NUMBER-DL
END-IF
IF MONTH-NUMBER-DL = 13
MOVE 1 TO MONTH-NUM
MOVE MONTH-NUM TO MONTH-NUMBER-DL
END-IF
IF MONTH-NUM = 1
ADD 1 TO YEAR-NUM
MOVE YEAR-NUM TO YEAR-NUMBER-DL
END-IF
MOVE DETAIL-LINE TO USED-CAR-RECORD-OUT
WRITE USED-CAR-RECORD-OUT
AFTER ADVANCING 1 LINE
MOVE ID-HOLD TO ID-CODE-DL
IF TOTAL-CASH-PAYMENT > 0
MOVE 0 TO TOTAL-CASH-PaYMENT
MOVE 0 TO PAYMENT-DL
END-IF
IF MONTH-DIFF < NUMBER-OF-MONTHS
PERFORM 300-RECORD-PROCESS
END-IF
PERFORM 200-USER-INPUT
END-IF.
EDIT solved the issue below
I also am having issues if months > 24. I step through the program and it shows my last detail line as the correct result but yet my output stops at 24 months. Thanks in advance.
AAAAAAAk!
PERFORM SEVERE-BEATING-ON-WHOEVER-MENTIONED-PERFORM-THROUGH
USING HEAVY-OBJECT
UNTIL PROMISE-EXTRACTED-TO-NEVER-DO-IT-AGAIN.
PERFORM THOUGH is EVIL. It causes layout-dependent code.
At the top control-level, use
PERFORM 200-USER-INPUT
UNTIL ID-CODE = 'END'.
(or possibly use 88 USER-INPUT-ENDED on ID-CODE - matter of style)
How you then determine whether to continue with input in 200-... is your choice, either
IF NOT USER-INPUT-ENDED
DISPLAY 'Enter the Total Cash Payment - maximum five digits'
ACCEPT TOTAL-CASH-PAYMENT
...
ACCEPT NUMBER-OF-MONTHS
PERFORM 300-RECORD-PROCESS.
OR
IF NOT USER-INPUT-ENDED
PERFORM 210-ACCEPT-DETAILS.
210-ACCEPT-DETAILS.
DISPLAY 'Enter the Total Cash Payment - maximum five digits'.
ACCEPT TOTAL-CASH-PAYMENT.
...
ACCEPT NUMBER-OF-MONTHS.
PERFORM 300-RECORD-PROCESS.
Since you PERFORMED 200-... then only 200-... will be executed; 210-... is a new paragraph which can only be reached from 200-... IF END is not entered.
Next step is to slightly modify 300-...
Move the initialisation ( FIRST-RECORD = 'YES' code) before the PERFORM 300-... in 200-... and then modify the PERFORM 300-RECORD-PROCESS. to
PERFORM 300-RECORD-PROCESS
UNTIL TOTAL-BALANCE = 0.
(I'm assuming here that this is the report-terination condition; if it isn't, substitute your report-termination condition)
You can now restructure 300-... to calculate the interest payable, modify the year and month numbers and show the result. ALL of the PERFORMs in 300-... will disappear.
So, in essence you have
MAIN:perform user-input until end-detected.
user-input: get user data; perform calculations until balance is zero.
calculations: one month's calculations at a time.
This also has the advantage that if you choose, you could insert
IF MONTHLY-PAYMENT IS LESS THAN INTEREST-COLLECTED
MOVE 'ERR' TO ID-CODE.
And use 'ERR' in ID-CODE to produce an appropriate error-message in 300-... instead of the progressive report lines AND at the same time assign 0 to TOTAL-BALANCE which terminates the PERFORM 300-... UNTIL ....
Your use of GO TO and PERFORM THROUGH paragraph ranges has corrupted the procedure return mechanism that COBOL
uses to maintain proper program flow of control. In essence, you have a program that is invalid - it might compile
without error but is still an invalid program according to the rules of COBOL.
Here is an outline of what your program is doing from a flow of control perspective. The
mainline program is essentially:
100-MAIN.
PERFORM 200-USER-INPUT THRU 299-EXIT
This is asking COBOL to execute all the code found from the beginning of
200-USER-INPUT through to the end of 299-EXIT. The outline for these
procedures is:
200-USER-INPUT.
IF some condition GO TO 299-EXIT
...
PERFORM 300-RECORD-PROCESS
.
299-EXIT.
Notice that if some condition is true, program flow will skip past the end
of 200-USER-INPUT and jump into 299-EXIT. 299-EXIT does not do anything
very interesting, it is just an empty paragraph serving as the end of a
PERFORMed range of paragraphs.
In paragraph 300-RECORD-PROCESS you have a fair bit of code. The interesting
bit is:
300-RECORD-PROCESS.
...
PERFORM 200-USER-INPUT
Notice that PERFORM 200-USER-INPUT this is not a PERFORM THRU, as you had coded in 100-MAIN.
The problem is that when you get back into 200-USER-INPUT and some codition becomes
true (as it will when you enter 'EXIT'), the flow of control
jumps to 299-EXIT which is past the end of the paragraph
you are currently performing. From this point
forward the flow of control mechanism used by COBOL to manage return from PERFORM verbs has
been corrupted. There is no longer a normal flow of control mechanism to return back to where 200-USER-INPUT
was performed from in 300-RECORD-PROCESS.
What happens next is not what most programmers would expect. Most programmers seem to expect
that when the end of 299-EXIT is reached program flow should return to wherever the last PERFORM
was done. In this case, just after PERFORM 200-USER-INPUT. No, COBOL doesn't work that way, flow of control
will continue with the next executable statement following 299-EXIT. This gets you
right back to the first executable statement in 300-RECORD-PROCESS! And that is why you
are not getting expected behaviour from this program.
Logic flow in COBOL programs must ensure that the end of performed procedures are
always reached in the reverse order from which they were made. This corresponds to the call/return
stack semantics that
most programmers are familiar with.
My advice to you is to avoid the use of PERFORM THRU and GO TO. These are two of the biggest
evils left in the COBOL programming language today. These constructs are hang-overs from a
bygone era of programming and have no constructive benefit today.
Your problem is that you have created an infinite loop for yourself. You 200- paragraph PERFORMs the 300- paragraph, and your 300- paragraph PERFORMS your 200- paragraph.
You need to restructure your program.
A paragraph called 200-USER-INPUT should just concern itself with that.
repeat until end of input
get some input
if there is input to process
process the input
Yoiks! I just noticed you also PERFORM 300- from within 300-!

COBOL issue - issue from a beginner , please guide

I want to acheive the below
a string of pic X(5) contains A1992 and is incremented to A9999 , after it reaches A9999 , the A should be replaced by B and the other characters should be reinitialized to 0000 ie B0000 , this should happen until Z9999 , is it possible somehow ?
or if you could show me how to increment A till Z that would be suffice
You will need to do some manual character manipulation on this one. There are several parts, first, you need to handle the simple addition of the numeric portion, then you need to handle the rollover of that to increment the alpha portion.
Data structures similar to this might be helpful:
01 Some-Work-Area.
02 Odometer-Char-Vals pic x(27) value 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'.
02 Odometer-Char occurs 27 pic x.
02 Odo-Char-Ndx pic s9(8) binary.
01 My-Odometer.
88 End-Odometer-Value value 'Z9999'.
02 My-Odometer-X pic X.
02 My-Odometer-9 pic 9999.
88 Carry-Is-True value 9999.
This would be used with a simple perform loop like so:
Move 0 to My-Odometer-9
Move 1 to Odo-Char-Ndx
Move Odometer-Char-Vals (Odo-Char-Ndx) to My-Odometer-X
Perform until End-Odometer-Value
Add 1 to My-Odometer-9
Display My-Odometer
If Carry-Is-True
Move 0 to My-Odometer-9
Add 1 to Odo-Char-Ndx
Move Odometer-Char-Vals (Odo-Char-Ndx) to My-Odometer-X
End-If
End-Perform
That is one way you could do it.
Please note, the code above took some shortcuts (aka skanky hacks) -- like putting a pad cell in the Odometer-Char array so I don't have to range check it. You wouldn't want to use this for anything but examples and ideas.
I'd probably do this with a nested perform loop.
Storage:
01 ws-counter-def
03 ws-counter-def-alpha-list pic x(27) value 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'.
03 ws-counter-def-num pic 9(4) comp-3.
01 ws-counter redefines ws-counter-def
03 ws-counter-alpha occurs 27 times indexed by counter-idx pic x.
03 ws-counter-num pic 9(4) comp-3.
01 ws-variable
03 ws-variable-alpha pic X
03 ws-variable-num pic X(4).
Procedure:
Initialize counter-idx.
Move 1992 to ws-counter-num.
Perform varying counter-idx from 1 by 1 until counter-idx > 26
move ws-counter-alpha(counter-idx) to ws-variable-alpha
perform until ws-counter-num = 9999
add 1 to ws-counter-
move ws-counter-num to ws-variable-num.
*do whatever it is you need to do to the pic X(5) value in ws-variable*
end-perform
move zeros to ws-counter-num
end-perform.
Just can't help myself... How about this...
IDENTIFICATION DIVISION.
PROGRAM-ID. EXAMPLE.
DATA DIVISION.
WORKING-STORAGE SECTION.
01.
02 ALL-LETTERS PIC X(26) VALUE 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'.
02 LETTERS REDEFINES ALL-LETTERS.
03 LETTER PIC X OCCURS 26 INDEXED BY I.
01 START-NUMBER PIC 9(4).
01 COUNTER.
02 COUNTER-LETTER PIC X.
02 COUNTER-NUMBER PIC 9(4).
PROCEDURE DIVISION.
MOVE 1992 TO START-NUMBER
PERFORM VARYING I FROM 1 BY 1 UNTIL I > LENGTH OF ALL-LETTERS
MOVE LETTER (I) TO COUNTER-LETTER
PERFORM TEST AFTER VARYING COUNTER-NUMBER FROM START-NUMBER BY 1
UNTIL COUNTER-NUMBER = 9999
DISPLAY COUNTER - or whatever else you need to do with the counter...
END-PERFORM
MOVE ZERO TO START-NUMBER
END-PERFORM
GOBACK
.
This will print all the "numbers" beginning with A1992 through to Z9999.
Basically stole Marcus_33's code and twiked it a tiny bit more. If you feel so inclined please upvote his answer, not mine
For lovers of obfuscated COBOL, here's the shortest (portable) version I can think of (assuming a compiler with Intrinsic Functions):
IDENTIFICATION DIVISION.
PROGRAM-ID. so.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 ws-counter value "A00".
03 ws-alpha pic x.
03 ws-number pic 99.
PROCEDURE DIVISION.
1.
Perform with test after until ws-counter > "Z99"
Display ws-counter, " " with no advancing
Add 1 To ws-number
On size error
Move zero to ws-number
perform with test after until ws-alpha is alphabetic-upper or > "Z"
Move Function Char (Function Ord( ws-alpha ) + 1) to ws-alpha
end-perform
End-add
End-perform.
END PROGRAM so.
Tested on OpenVMS/COBOL. I shorten the value to X(3) since it's boring to watch run. A non-portable version (if you are aware of the Endianness of your platform) is to redefined the prefix as a S9(4) COMP and increment the low-order bits directly. But that solution wouldn't be any shorter...

Do periods count as numerics (COBOL)

I am working on a bit of code at home and that is suppose to find and identify errors is a input file. I got it just about right, but two little errors are hitting me. The major problem though is this. I have to make a code that identifies "3077.B22" as an error because the first 5 columns are suppose to be numeric, but my current code is letting it pass. It hits every thing else though so I have to believe that it is seeing the period as a decimal point. Here is what I got that concerns to this part.
01 PART-NUMBER-CHECK.
05 P-N-NUM-1 PIC X(5).
05 P-N-LETTER PIC X.
05 P-N-NUM-2 PIC XX.
300-VALIDATE-PART-NUMBER.
MOVE 'NO' TO FIELD-ERROR-SWITCH
MOVE PART-NUMBER TO PART-NUMBER-CHECK
EVALUATE P-N-NUM-1
WHEN 00001 THRU 99999 CONTINUE
WHEN OTHER MOVE 'YES' TO FIELD-ERROR-SWITCH
END-EVALUATE
IF P-N-LETTER IS NUMERIC
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
IF P-N-LETTER IS ALPHABETIC-LOWER
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
IF P-N-NUM-2 IS ALPHABETIC
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
IF (P-N-NUM-2 > 00 AND < 69)
OR (P-N-NUM-2 >77 AND < 100)
CONTINUE
ELSE
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
IF FIELD-ERROR-SWITCH = 'YES'
MOVE 'YES' TO RECORD-ERROR-SWITCH
MOVE 'Part Number' TO FIELD-NAME
MOVE PART-NUMBER TO FIELD-VALUE
PERFORM 400-WRITE-DETAIL-LINE
END-IF.
My second problem is similar cause it is seeing an * in another field as a alphabetic.
Here is the paragraph to that:
340-VALIDATE-INITIAL.
MOVE 'NO' TO FIELD-ERROR-SWITCH
INSPECT INITIALS
TALLYING I-CHECK FOR ALL SPACES
IF I-CHECK > 0
MOVE 'YES' TO FIELD-ERROR-SWITCH
MOVE 0 TO I-CHECK
END-IF
IF INITIALS IS NUMERIC
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
IF FIELD-ERROR-SWITCH = 'YES'
MOVE 'YES' TO RECORD-ERROR-SWITCH
MOVE 'Initials' TO FIELD-NAME
MOVE INITIALS TO FIELD-VALUE
PERFORM 400-WRITE-DETAIL-LINE
END-IF.
Please help, I am done as soon as I get over this little bump in the road.
Given the following declaration:
01 PART-NUMBER-CHECK.
05 P-N-NUM-1 PIC X(5).
05 P-N-LETTER PIC X.
05 P-N-NUM-2 PIC XX.
and something like:
MOVE 'NO' TO FIELD-ERROR-SWITCH
MOVE '3077.B22' TO PART-NUMBER-CHECK
EVALUATE P-N-NUM-1
WHEN 00001 THRU 99999 CONTINUE
WHEN OTHER MOVE 'YES' TO FIELD-ERROR-SWITCH
END-EVALUATE
Why isn't the FIELD-ERROR-SWITCH set to 'YES'? COBOL casts
00001 and 99999 into their PIC X equivalents before applying
the range tests (casting rules here are rather complicated so I'm not going to
get into it). The actual test COBOL performs here
is roughly equivalent to the following:
IF '00001' <= '3077.' AND '99999' >= '3077.'
Given that these are string tests the condition is
true, meaning that you bypass setting the FIELD-ERROR-SWITCH. Using
a THRU range test in COBOL is very useful but requires a bit of caution. Only use
THRU when you know you have valid data to begin with or are doing single character
comparisons. For example
05 TEST-CHAR PIC X.
88 IS-DIGIT VALUE '0' THRU '9'.
88 IS-LOWER-LETTER VALUE 'a' THRU 'i',
'j' THRU 'r',
's' THRU 'z'.
88 IS-UPPER-LETTER VALUE 'A' THRU 'I',
'J' THRU 'R',
'S' THRU 'Z'.
88 IS-SPACE VALUE SPACE.
Then code like:
MOVE SOME-CHAR TO TEST-CHAR
EVALUATE TRUE
WHEN IS-DIGIT
DISPLAY 'IS A DIGIT'
WHEN IS-LOWER-LETTER OR IS-UPPER-LETTER
DISPLAY 'IS ALPHA'
WHEN IS-SPACE
DISPLAY 'IS A SPACE'
WHEN OTHER
DISPLAY 'IS A SOMETHING ELSE'
END-EVALUATE
is pretty much bullet proof.
Why did I break the alphabet range up into distinct groups? Check out the EBCDIC
collating sequence and you will find that some non alphabet characters sneak
in between 'i' and 'j' then again between 'r' and 's'! Oh, how I love EBCDIC!
How to solve your problem? Something as simple as:
IF P-N-NUM-1 IS NUMERIC
IF P-N-NUM-1 = ZERO
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
ELSE
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
would do the trick. The NUMERIC test ensures that P-N-NUM-1 is composed
of only digits. The ZERO test ensures that it is not zero. In this case negative numbers
are excluded on the NUMERIC test. Period/plus/minus are not NUMERIC when the
item being tested is declared as PIC X or PIC 9. Had the elementary item been declared as PIC S9(5) PACKED-DECIMAL, then a leading sign would be pass the NUMERIC test. The COBOL NUMERIC class test takes a bit of study to fully understand.
Big hint: Ensure that things that are supposed to be numeric are stored
in elementary items that are declared as numeric. I would try declaring P-N-NUM-1 and
P-N-NUM-2 using PIC 9. Move un-validated data into PART-NUMBER-CHECK which by default
is PIC X so no errors occur, then validate elementary numeric data items using
IF NUMERIC tests. Once you know you have numeric data then your range tests (e.g. 00001 THRU 99999,
greater/less than) will not lead you astray - as happened here.
Why is an '*' sneaking through your second bit of code? You never set an error on non-alpha characters,
only on numerics. Why not try flipping your NUMERIC test into a NOT ALPHABETIC test?
See if that helps!
You are on the right track, but does your compiler support the NumVal function? You could do this:
01 Part-Num 9(5).9(2).
Compute Part-Num = Function NumVal( Part-Num-Input )
on exception
Set Part-Num-Not-Valid to true
End-Compute
A long time since I wrote my last COBOL, and I don't have a compiler at hand, so expect some sintax checks in the code, but you'll get the idea ...
01 PART-NUMBER-CHECK.
05 P-N-NUM-1 .
07 p-x-occ occurs 5 pic X.
05 P-N-NUM-1-N redefines P-N-NUM-1. .
07 p-n-occ occurs 5 pic 9.
05 P-N-LETTER PIC X.
05 P-N-NUM-2 PIC XX.
01 FIELD-ERROR-SWITCH pic x(3).
88 no-error value 'NO'.
300-VALIDATE-PART-NUMBER.
MOVE 'NO' TO FIELD-ERROR-SWITCH
MOVE PART-NUMBER TO PART-NUMBER-CHECK.
perform validate-p-n-occurs varying I from 1 to 5.
if no-error
IF ( P-N-LETTER IS NUMERIC or P-N-LETTER IS ALPHABETIC-LOWER or
P-N-NUM-2 IS ALPHABETIC)
MOVE 'YES' TO FIELD-ERROR-SWITCH
ELSE
IF (P-N-NUM-2 < 0) OR (P-N-NUM-20 > 68 AND < 79) OR (P-N-NUM-2 >99)
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF
END-IF
END-IF
IF FIELD-ERROR-SWITCH = 'YES'
MOVE 'YES' TO RECORD-ERROR-SWITCH
MOVE 'Part Number' TO FIELD-NAME
MOVE PART-NUMBER TO FIELD-VALUE
PERFORM 400-WRITE-DETAIL-LINE
END-IF.
validate-p-n-occurs.
IF p-x-occ(I) is not NUMERIC or (p-n-occ(I) < 0 or > 10)
MOVE 'YES' TO FIELD-ERROR-SWITCH
END-IF.

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