Create JSON format using NSString as a key and values - ios

Question

I have JSON format requirement something like this.
{
"first_name" : "XYZ",
"last_name" : "ABC"
}
I have values in NSString.
NSString strFName = #"XYZ";
NSString strLName = #"ABC";
NSString strKeyFN = #"first_name";
NSString strKeyLN = #"last_name";
And I use NSMutableDictionary
NSMutableDictionary* dict = [[NSMutableDictionary alloc]init];
[dict setObject:strFName forKey:strKeyFN];
[dict setObject:strLName forKey:strKeyLN];
then output is
{
first_name = XYZ,
last_name = ABC
}
So I don't want "=" separating key & values instead I want ":" to separate key and values
I have went most of the stack overflow questions but didn't help getting "=" only in output
So please any help ?

Answer 1

Here is your answer :
NSString *strFName = #"XYZ";
NSString *strLName = #"ABC";
NSInteger number = 15;
NSString *strKeyFN = #"first_name";
NSString *strKeyLN = #"last_name";
NSString *numValue = #"Number";
NSMutableDictionary *dic = [[NSMutableDictionary alloc]init];
[dic setObject:strFName forKey:strKeyFN];
[dic setObject:strLName forKey:strKeyLN];
[dic setObject:[NSNumber numberWithInt:number] forKey:numValue];
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:[NSArray arrayWithObject:dic] options:NSJSONWritingPrettyPrinted error:nil];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSLog(#"JSON %#",jsonString);

Answer 2

You write this code after your NSDictionary
NSData *data = [NSJSONSerialization dataWithJSONObject:dict options:NSJSONWritingPrettyPrinted error:&error];
NSString *jsonstr = [[NSString alloc]initWithData:data encoding:NSUTF8StringEncoding];

Answer 3

NSString *strFName = #"XYZ";
NSString *strLName = #"ABC";
NSString *strKeyFN = #"first_name";
NSString *strKeyLN = #"last_name";
NSDictionary *ictionary = [NSDictionary dictionaryWithObjectsAndKeys:
strKeyFN, strFName,strKeyLN, strLName,nil];
NSError *error;
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:dictionary options:NSJSONWritingPrettyPrinted error:&error];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSLog(#"dictionary as string:%#", jsonString);

Answer 4

NSString *strFName = #"ABC";
NSString *strLName = #"XYZ";
NSString *strKeyFN = #"last_name";
NSString *strKeyLN = #"first_name";
NSMutableDictionary *dict = [[NSMutableDictionary alloc]init];
[dict setObject:strFName forKey:strKeyFN];
[dict setObject:strLName forKey:strKeyLN];
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:[NSArray arrayWithObject:dict] options:NSJSONWritingPrettyPrinted error:nil];
NSString *jsonStrng = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSLog(#"Your required JSON is %#",jsonStrng);

Answer 5

try this:-
NSString *cleanedString1 =[strFName stringByReplacingOccurrencesOfString:#"/"" withString:#""];
NSString *cleanedString2 =[strLName stringByReplacingOccurrencesOfString:#"/"" withString:#""];
NSDictionary *Dict = [NSDictionary dictionaryWithObjectsAndKeys:
cleanedString1, strKeyFN,
cleanedString2, strKeyLN,nil];
NSData *jsonData2 = [NSJSONSerialization dataWithJSONObject:Dict options:NSJSONWritingPrettyPrinted error:&error];
NSString *jsonString = [[NSString alloc] initWithData:jsonData2 encoding:NSUTF8StringEncoding];
NSLog(#"jsonData as string:\n%#", jsonString);

Answer 6

this very robust code to achieve you goal
NSDictionary *userDic = #{strKeyFN:strFName,strKeyLN:strLName};

Answer 7

you have to convert NSMutableDictionary into NSData
then convert the NSData Into json string you want
NSString *strFName = #"XYZ";
NSString *strLName = #"ABC";
NSString *strKeyFN = #"first_name";
NSString *strKeyLN = #"last_name";
NSMutableDictionary* dict = [[NSMutableDictionary alloc]init];
[dict setObject:strFName forKey:strKeyFN];
[dict setObject:strLName forKey:strKeyLN];
NSData *data = [NSJSONSerialization dataWithJSONObject:dict options:NSJSONWritingPrettyPrinted error:nil];
NSString *jasonString= [[NSString alloc]initWithData:data encoding:NSUTF8StringEncoding];