iOS: Reorder NSString characters alphabetically [duplicate] - ios

I'm trying to re-arrange words into alphabetical order. For example, tomato would become amoott, or stack would become ackst.
I've found some methods to do this in C with char arrays, but I'm having issues getting that to work within the confines of the NSString object.
Is there an easier way to do it within the NSString object itself?

You could store each of the string's characters into an NSArray of NSNumber objects and then sort that. Seems a bit expensive, so I would perhaps just use qsort() instead.
Here it's provided as an Objective-C category (untested):
NSString+SortExtension.h:
#import <Foundation/Foundation.h>
#interface NSString (SortExtension)
- (NSString *)sorted;
#end
NSString+SortExtension.m:
#import "NSString+SortExtension.h"
#implementation NSString (SortExtension)
- (NSString *)sorted
{
// init
NSUInteger length = [self length];
unichar *chars = (unichar *)malloc(sizeof(unichar) * length);
// extract
[self getCharacters:chars range:NSMakeRange(0, length)];
// sort (for western alphabets only)
qsort_b(chars, length, sizeof(unichar), ^(const void *l, const void *r) {
unichar left = *(unichar *)l;
unichar right = *(unichar *)r;
return (int)(left - right);
});
// recreate
NSString *sorted = [NSString stringWithCharacters:chars length:length];
// clean-up
free(chars);
return sorted;
}
#end

I think separate the string to an array of string(each string in the array contains only one char from the original string). Then sort the array will be OK. This is not efficient but is enough when the string is not very long. I've tested the code.
NSString *str = #"stack";
NSMutableArray *charArray = [NSMutableArray arrayWithCapacity:str.length];
for (int i=0; i<str.length; ++i) {
NSString *charStr = [str substringWithRange:NSMakeRange(i, 1)];
[charArray addObject:charStr];
}
NSString *sortedStr = [[charArray sortedArrayUsingSelector:#selector(localizedCaseInsensitiveCompare:)] componentsJoinedByString:#""];

// --------- Function To Make an Array from String
NSArray *makeArrayFromString(NSString *my_string) {
NSMutableArray *array = [[NSMutableArray alloc] init];
for (int i = 0; i < my_string.length; i ++) {
[array addObject:[NSString stringWithFormat:#"%c", [my_string characterAtIndex:i]]];
}
return array;
}
// --------- Function To Sort Array
NSArray *sortArrayAlphabetically(NSArray *my_array) {
my_array= [my_array sortedArrayUsingSelector:#selector(localizedCaseInsensitiveCompare:)];
return my_array;
}
// --------- Function Combine Array To Single String
NSString *combineArrayIntoString(NSArray *my_array) {
NSString * combinedString = [[my_array valueForKey:#"description"] componentsJoinedByString:#""];
return combinedString;
}
// Now you can call the functions as in below where string_to_arrange is your string
NSArray *blowUpArray;
blowUpArray = makeArrayFromString(string_to_arrange);
blowUpArray = sortArrayAlphabetically(blowUpArray);
NSString *arrayToString= combineArrayIntoString(blowUpArray);
NSLog(#"arranged string = %#",arrayToString);

Just another example using NSMutableString and sortUsingComparator:
NSMutableString *mutableString = [[NSMutableString alloc] initWithString:#"tomat"];
[mutableString appendString:#"o"];
NSLog(#"Orignal string: %#", mutableString);
NSMutableArray *charArray = [NSMutableArray array];
for (int i = 0; i < mutableString.length; ++i) {
[charArray addObject:[NSNumber numberWithChar:[mutableString characterAtIndex:i]]];
}
[charArray sortUsingComparator:^NSComparisonResult(id _Nonnull obj1, id _Nonnull obj2) {
if ([obj1 charValue] < [obj2 charValue]) return NSOrderedAscending;
return NSOrderedDescending;
}];
[mutableString setString:#""];
for (int i = 0; i < charArray.count; ++i) {
[mutableString appendFormat:#"%c", [charArray[i] charValue]];
}
NSLog(#"Sorted string: %#", mutableString);
Output:
Orignal string: tomato
Sorted string: amoott

Related

Count in multi-dimensional array

How would you count this array?
NSArray *sortThisArray = #[#{#"numbers":#[#"One",#"Two"]},
#{#"numbers":#[#"Two",#"One"]},
#{#"numbers":#[#"One",#"Two",#"Three"]},
#{#"numbers":#[#"One",#"Two",#"Three"]},
#{#"numbers":#[#"One",#"Two",#"Three",#"Four"]},
];
The desired result would then be:
NSArray *sortedArray = #[#{#"numbers":#[#"One",#"Two"],
#"occures":#(2)},
#{#"numbers":#[#"One",#"Two",#"Three"],
#"occures":#(2)},
#{#"numbers":#[#"One",#"Two",#"Three",#"Four"],
#"occures":#(1)},
];
I've tried using NSCountedSet and countForObject, but the results are inaccurate. It seems to only count the arrays that are exactly the same. In other words, the array with #[#"Two",#"One"] gets ignored because its not 100% equal to #[#"One",#"Two"], even though they have the same objects and same count.
This should work. You have to have a consistent way to compare your arrays (either sorting like in this example or by moving the NSArray to NSSet).
NSMutableDictionary<NSArray<NSString *> *, NSNumber *> *valueCount = [NSMutableDictionary dictionary];
for (NSDictionary<NSString *, NSArray<NSString *> *> *value in sortThisArray) {
NSArray<NSString *> *numberStrings = [value[#"numbers"] sortedArrayUsingSelector:#selector(compare:)];
valueCount[numberStrings] = #(valueCount[numberStrings].integerValue + 1);
}
NSMutableArray *sortedArray = [NSMutableArray arrayWithCapacity:valueCount.count];
for (NSArray<NSString *> *key in valueCount) {
[sortedArray addObject:#{#"numbers": key, #"occures": valueCount[key]}];
}
May be something like this:
NSMutableArray *mArray = [NSMutableArray arrayWithArray:sortThisArray];
NSMutableArray *result = [[NSMutableArray alloc] init];
while ([mArray count]) {
NSDictionary *obj = [mArray firstObject];
int count = 1;
for (int i=1; i<[mArray count]; i++) {
NSDictionary *sObj = [mArray objectAtIndex:i];
if ([[sObj objectForKey:#"numbers"] count] == [[obj objectForKey:#"numbers"] count]) {
BOOL increase = YES;
for (int j=0; j<[[obj objectForKey:#"numbers"] count]; j++) {
if (![[sObj objectForKey:#"numbers"] containsObject:[[obj objectForKey:#"numbers"] objectAtIndex:j]]) {
increase = NO;
}
}
if (increase) {
count++;
[mArray removeObjectAtIndex:i];
}
}
}
[mArray removeObjectAtIndex:0];
[result addObject:#{#"numbers":obj, #"occurrs":[NSNumber numberWithInteger:count]}];
}
*Code is not tested

Find the highest repeated character in string and the count of the repeated character

I need to get the highest repeated character in string and the count of the repeated character.
For that i stored the each character of the string in the array and using the for loops i got each character and the count. is there any other delegate methods to find it to reduce the code?
for example
NSRange theRange = {0, 1}; //{location, length}
NSMutableArray * array = [NSMutableArray array];
for ( NSInteger i = 0; i < [myFormattedString length]; i++) {
theRange.location = i;
[array addObject:[myFormattedString substringWithRange:theRange]];
}
int countForChar = 0;
for (int i=0; i<[array count]; i++) {
NSString *firstCharacter = [array objectAtIndex:i];
for (int j=1; j< [array count]; j++) {
if ([firstCharacter isEqualToString:[array objectAtIndex:j]]) {
countForChar = countForChar + 1;
}
}
NSLog(#"The Charcter is %# The count is %d", firstCharacter, countForChar);
countForChar = 0;
}
Thanks in advance...
Because the string may have more than a char have same most repeat count, so here is my solution:
- (NSArray *)mostCharInString:(NSString *)string count:(int *)count{
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
int len = string.length;
NSRange theRange = {0, 1};
for (NSInteger i = 0; i < len; i++) {
theRange.location = i;
NSString *charStr = [string substringWithRange:theRange];
int preCount = 0;
if ([dict objectForKey:charStr]) {
preCount = [[dict objectForKey:charStr] unsignedIntegerValue];
}
[dict setObject:#(preCount+1) forKey:charStr];
}
NSArray *sortValues = [[dict allValues] sortedArrayUsingSelector:#selector(compare:)];
*count = [[sortValues lastObject] unsignedIntegerValue];
return [dict allKeysForObject:#(*count)];
}
How to use and test:
int mostRepeatCount = 0;
NSArray *mostChars = nil;
mostChars = [self mostCharInString:#"aaabbbcccc" count:&mostRepeatCount];
NSLog(#"count:%d char:%#", mostRepeatCount, mostChars);
the result is:
count:4 char:(
c
)
try:
mostChars = [self mostCharInString:#"aaabbbccccdddd" count:&mostRepeatCount];
the result is:
count:4 char:(
d,
c
)
Hope to help you.
Here is my code might be not good enough but I think its the fastest
NSString *myFormattedString = #"oksdflajdsfd";
NSMutableDictionary *lettersCount = [[NSMutableDictionary alloc] init];
for (NSInteger i = 0; i < [myFormattedString length]; i++) {
unichar charAtIndex = [myFormattedString characterAtIndex:i];
NSNumber *countForThisChar = [lettersCount objectForKey:[NSString stringWithFormat:#"%c",charAtIndex]];
int count = 1;
if(countForThisChar) {
count = [countForThisChar integerValue] + 1;
[lettersCount setObject:#(count) forKey:[NSString stringWithFormat:#"%c",charAtIndex]];
} else {
// not added yet, add it with 1 count
[lettersCount setObject:#(count) forKey:[NSString stringWithFormat:#"%c",charAtIndex]];
}
}
// for now the work is O(n)
// ignoring the work of this cycle or consider it as O(1)
NSString *mostFrequentChar = nil;
NSInteger maxCount = 0;
for(NSString *oneChar in lettersCount.keyEnumerator) {
NSNumber *count = [lettersCount objectForKey:oneChar];
if([count integerValue] > maxCount) {
mostFrequentChar = oneChar;
maxCount = [count integerValue];
}
}
NSLog(#"the char %# met for %d times", mostFrequentChar, maxCount);
Remember the search for an object in NsDictionary is O(1) for the average case scenario.
Here is an example that would work correctly with any string and has linear time complexity. This uses the NSCountedSet which can be pretty useful.
NSString* string = #"This is a very wonderful string. Ølsen & ジェイソン";
NSCountedSet* characterCounts = [[NSCountedSet alloc] init];
// This ensures that we deal with all unicode code points correctly
[string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
[characterCounts addObject:substring];
}];
NSString* highestCountCharacterSequence = nil;
NSUInteger highestCharacterCount = 0;
for (NSString* characterSequence in characterCounts) {
NSUInteger currentCount = [characterCounts countForObject:characterSequence];
if (currentCount > highestCharacterCount) {
highestCountCharacterSequence = characterSequence;
highestCharacterCount = currentCount;
}
}
NSLog(#"Highest Character Count is %# with count of %lu", highestCountCharacterSequence, (unsigned long)highestCharacterCount);
Sadly, my silly example string ends up having space characters as the most repeated :)
Every character can be presented by its int value. Make an instance of NSArray with n size (n number of unique characters string can have). Loop through string and add +1 on (int)character index in array at every cycle. When you finish the character with greatest value in array is the highest repeated character.

Printing from NSMutableArray

So i want to print the users in an NSMutableArray. But the strings keep coming out as nil.
here is what i have:
int users = 0;
- (IBAction)addNewUser:(id)sender {
NSString *string;
string = userNameTextField.text;
[usernameArray insertObject:string atIndex:users];
users++;
[self showUsers];
}
-(void)showUsers{
for (int i = 0; i < users; i++){
NSString *s = textView.text;
NSString *add;
add = [NSString stringWithFormat:#"%# ",[usernameArray objectAtIndex:i]];
NSString *display = [NSString stringWithFormat:#"%# \n %#", s, add];
textView.text = display;
}
}
i have also tried
-(void)showUsers{
for (int i = 1; i < users; i++){
NSString *s = textView.text;
NSString *add;
add = [usernameArray objectAtIndex:i];
NSString *display = [NSString stringWithFormat:#"%# \n %#", s, add];
textView.text = display;
}
}
First of all try using more comprehensive names for the objects. I'm rewriting your code.
Common Causes for the problem : Array not initialized, you are starting your for cycle with int i equal to 1, so you are missing the object at index 0 at your mutable array. Try the following code.
#interface InterfaceName : InterfaceInherits <IfDelegate> {
int usersCount;
NSMutableArray * usernameArray;
}
#implementation InterfaceName
/*There's no more confident way to initialize a variable than in the init method of the class. */
-(id)init{
usersCount = 0;
//You have to be sure that your array is not nil
usernameArray = [NSMutableArray alloc]init]];
return self;
}
- (IBAction)addNewUser:(id)sender {
NSString *username = [usernameTextField text];
[usernameArray insertObject:username atIndex:usersCount];
usersCount++;
//I'll omit the display as I'm not sure what you were doing with it.
}
-(void)showUsers{
for (int i = 0; i < usersCount; i++){
NSString *retrievedUser = [usernameArray objectAtIndex:i];
NSString *display = [NSString stringWithFormat:#"User Retrieved : %#",retrievedUser];
textView.text = display;
}
}
#end

NSString subsstring

I have a string like this
12,23,45,3,12,
What I want to do is get this each number and check with an array value. How I can get each value as a substring to check
Thanks
Break this string to array.
NSString *string = #"12,23,45,3,12,";
NSArray *array = [string componentsSeparatedByString:#","];
Then you can compare with the array.
EDIT :
As per your comment that you want to check all the string values to be present in main-other-array.
NSString *string = #"12,23,45,3,12";
NSArray *array = [string componentsSeparatedByString:#","];
//below is the main-other-array
NSArray *toCheckArray = #[#"124",#"23",#"45",#"3",#"12",#"1000"];
BOOL arrayIsContainedInToCheckArray = YES;
for (NSString *arrayObj in array) {
if (![toCheckArray containsObject:arrayObj]) {
arrayIsContainedInToCheckArray = NO;
}
}
NSLog(#"%#",arrayIsContainedInToCheckArray?#"All exist":#"All doesn't exist");
May be it helps you :
NSString *str = #"12,23,45,3,12";
NSArray *strArray = [str componentsSeparatedByString:#","];
NSArray * anotherArray = nil; // have some value
for (NSString * value in strArray)
{
int intVal = [value integerValue]; // here is your separate value
for (int i = 0; i < [anotherArray count]; i++) // You can check against another array
{
id anotherVal = [anotherArray objectAtIndex:i];
// Here you can check intVal and anotherVal from another array
}
}
Use this, It will help you..
NSArray *detailArray = [yourString componentsSeparatedByString:#","];

how to capture the first letter of each array entry

I have a sorted array of NSString values, I would like to know how to capture the first letter of each string only when the first letter is different and put it in a new NSArray.
For instance if I have an array that was like like
"a, aaa, aaaa, b, c, d, dd, ddd"
it would be like this in the new NSArray
"a, b, c, d"
Any help would be greatly appreciated.
Something like this:
- (NSArray *)indexLettersForStrings:(NSArray *)strings {
NSMutableArray *letters = [NSMutableArray array];
NSString *currentLetter = nil;
for (NSString *string in strings) {
if (string.length > 0) {
NSString *letter = [string substringToIndex:1];
if (![letter isEqualToString:currentLetter]) {
[letters addObject:letter];
currentLetter = letter;
}
}
}
return [NSArray arrayWithArray:letters];
}
NSString+LetterIndex.h
#interface NSString (LetterIndex)
#property (nonatomic, readonly) NSString * firstLetter;
#end
NSString+LetterIndex.m
#implementation NSString (LetterIndex)
- (NSString *)firstLetter
{
return self.length ? [self substringToIndex:1] : #"";
}
your method:
- (NSArray *)indexLettersForStrings:(NSArray *)strings {
NSSet * distinctValues = [NSSet setWithArray:[strings valueForKey:#"firstLetter"]];
return [[distinctValues allObjects] sortedArrayUsingSelector:#selector(compare:)]
}
also if you have some objects of custom class and want to group them by first letters of some string parameter, you can use this:
NSSet * distinctValues = [NSSet setWithArray:[objects valueForKeyPath:#"myStringParam.firstLetter"]];
NSArray *array = [NSArray arrayWithObjects:#"a", #"aaa", #"aaaa",#"b", #"c", #"d", #"dd", #"ddd", nil];
BOOL control = YES;
NSMutableArray *array2 = [NSMutableArray array];
for (int i = 0; i<array.count; i++) {
for (int j = 0; j<array2.count;j++){
if ([[array2 objectAtIndex:j]isEqualToString:[[array objectAtIndex:i]substringToIndex:1]]){
control = NO;
}
else
control = YES;
}
if (control)
[array2 addObject:[[array objectAtIndex:i]substringToIndex:1]];
}
Try this:
NSArray *arr = #[#"a", #"aaa", #"aaaa", #"b", #"c", #"d", #"dd", #"ddd"];
NSMutableArray *newArr = [NSMutableArray array];
NSMutableSet *set = [NSMutableSet set];
for (NSString *str in arr)
{
if (![set containsObject:[str substringToIndex:1]])
[newArr addObject:[str substringToIndex:1]];
[set addObject:[str substringToIndex:1]];
}
NSLog(#"%#", newArr);
This uses a Set to keep track of occurrences that already past threw. When it doesnt exist it places them into a new array.

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