I am using ASP.NET MVC 5 and I have many classes with decimal fields.
I know that I can use:
[DisplayFormat(DataFormatString = "{0:n2}", ApplyFormatInEditMode = true)]
public decimal MyDecimal { get; set; }
in order to format the display of the number, but this means entering the attribute for every field.
I need a method to format these numbers globally.
In my ViewModel, I have the following System.ComponentModel.DataAnnotations on a property that contains USD currency:
[DisplayFormat(DataFormatString = "{0:C2}")]
[Range(0.01, 100000, ErrorMessage = "Payment amount is required between .01 and $100,000.")]
[DataType(DataType.Currency)]
[DisplayName("Payment Amount")]
public Double PrinAmount { get; set; } = 0.00;
When I enter a value of $10.005, I get the following validation model error from the ModelState.IsValid check:
The value '$10.005' is not valid for Payment Amount.
When I enter a value 10.005, the ModelState.IsValid is equal to true.
What do I need to do to modified the validation to capture both formats as invalid?
You can use Regular Expression;
[RegularExpression(#"^\d+\.\d{0,2}$")]
the DataAnnotations above ensures 2 digits.
I have the following razor code that I want to have mm/dd/yyyy date format:
Audit Date: #Html.DisplayFor(Model => Model.AuditDate)
I have tried number of different approaches but none of that approaches works in my situation
my AuditDate is a DateTime? type
I have tried something like this and got this error:
#Html.DisplayFor(Model => Model.AuditDate.Value.ToShortDateString())
Additional information: Templates can be used only with field access, property access, single-dimension array index, or single-parameter custom indexer expressions.
Tried this:
#Html.DisplayFor(Model => Model.AuditDate.ToString("mm/dd/yyyy"))
No overload for method 'ToString' takes 1 arguments
If you use DisplayFor, then you have to either define the format via the DisplayFormat attribute or use a custom display template. (A full list of preset DisplayFormatString's can be found here.)
[DisplayFormat(DataFormatString = "{0:d}")]
public DateTime? AuditDate { get; set; }
Or create the view Views\Shared\DisplayTemplates\DateTime.cshtml:
#model DateTime?
#if (Model.HasValue)
{
#Model.Value.ToString("MM/dd/yyyy")
}
That will apply to all DateTimes, though, even ones where you're encoding the time as well. If you want it to apply only to date-only properties, then use Views\Shared\DisplayTemplates\Date.cshtml and the DataType attribute on your property:
[DataType(DataType.Date)]
public DateTime? AuditDate { get; set; }
The final option is to not use DisplayFor and instead render the property directly:
#if (Model.AuditDate.HasValue)
{
#Model.AuditDate.Value.ToString("MM/dd/yyyy")
}
I have been using this change in my code :
old code :
<td>
#Html.DisplayFor(modelItem => item.dataakt)
</td>
new :
<td>
#Convert.ToDateTime(item.dataakt).ToString("dd/MM/yyyy")
</td>
If you are simply outputting the value of that model property, you don't need the DisplayFor html helper, just call it directly with the proper string formatting.
Audit Date: #Model.AuditDate.Value.ToString("d")
Should output
Audit Date: 1/21/2015
Lastly, your audit date could be null, so you should do the conditional check before you attempt to format a nullable value.
#if (item.AuditDate!= null) { #Model.AuditDate.Value.ToString("d")}
Googling the error that you are getting provides this answer, which shows that the error is from using the word Model in your Html helpers. For instance, using #Html.DisplayFor(Model=>Model.someProperty). Change these to use something else other than Model, for instance: #Html.DisplayFor(x=>x.someProperty) or change the capital M to a lowercase m in these helpers.
You can use the [DisplayFormat] attribute on your view model as you want to apply this format for the whole project.
[DisplayFormat(ApplyFormatInEditMode = true, DataFormatString = "{0:dd/MM/yyyy}")]
public Nullable<System.DateTime> Date { get; set; }
#ChrisPratt's answer about the use of Display Template is wrong. The correct code to make it work is:
#model DateTime?
#if (Model.HasValue)
{
#Convert.ToDateTime(Model).ToString("MM/dd/yyyy")
}
That's because .ToString() for Nullable<DateTime> doesn't accept Format parameter.
For me it was enough to use
[DataType(DataType.Date)]
[DisplayFormat(DataFormatString = "{0:dd/MM/yyyy}")]
public DateTime StartDate { set; get; }
I implemented the similar thing this way:
Use TextBoxFor to display date in required format and make the field readonly.
#Html.TextBoxFor(Model => Model.AuditDate, "{0:dd-MMM-yyyy}", new{#class="my-style", #readonly=true})
2. Give zero outline and zero border to TextBox in css.
.my-style {
outline: none;
border: none;
}
And......Its done :)
You could use Convert
<td>#Convert.ToString(string.Format("{0:dd/MM/yyyy}", o.frm_dt))</td>
In View Replace this:
#Html.DisplayFor(Model => Model.AuditDate.Value.ToShortDateString())
With:
#if(#Model.AuditDate.Value != null){#Model.AuditDate.Value.ToString("dd/MM/yyyy")}
else {#Html.DisplayFor(Model => Model.AuditDate)}
Explanation: If the AuditDate value is not null then it will format the date to dd/MM/yyyy, otherwise leave it as it is because it has no value.
After some digging and I ended up setting Thread's CurrentCulture value to have CultureInfo("en-US") in the controller’s action method:
Thread.CurrentThread.CurrentCulture = new System.Globalization.CultureInfo("en-US");
Here are some other options if you want have this setting on every view.
About CurrentCulture property value:
The CultureInfo object that is returned by this property, together
with its associated objects, determine the default format for dates,
times, numbers, currency values, the sorting order of text, casing
conventions, and string comparisons.
Source: MSDN CurrentCulture
Note: The previous CurrentCulture property setting is probably optional if the controller is already running with CultureInfo("en-US") or similar where the date format is "MM/dd/yyyy".
After setting the CurrentCulture property, add code block to convert the date to "M/d/yyyy" format in the view:
#{ //code block
var shortDateLocalFormat = "";
if (Model.AuditDate.HasValue) {
shortDateLocalFormat = ((DateTime)Model.AuditDate).ToString("M/d/yyyy");
//alternative way below
//shortDateLocalFormat = ((DateTime)Model.AuditDate).ToString("d");
}
}
#shortDateLocalFormat
Above the #shortDateLocalFormat variable is formatted with ToString("M/d/yyyy") works. If ToString("MM/dd/yyyy") is used, like I did first then you end up having leading zero issue. Also like recommended by Tommy ToString("d") works as well. Actually "d" stands for “Short date pattern” and can be used with different culture/language formats too.
I guess the code block from above can also be substituted with some cool helper method or similar.
For example
#helper DateFormatter(object date)
{
var shortDateLocalFormat = "";
if (date != null) {
shortDateLocalFormat = ((DateTime)date).ToString("M/d/yyyy");
}
#shortDateLocalFormat
}
can be used with this helper call
#DateFormatter(Model.AuditDate)
Update, I found out that there’s alternative way of doing the same thing when DateTime.ToString(String, IFormatProvider) method is used. When this method is used then there’s no need to use Thread’s CurrentCulture property. The CultureInfo("en-US") is passed as second argument --> IFormatProvider to DateTime.ToString(String, IFormatProvider) method.
Modified helper method:
#helper DateFormatter(object date)
{
var shortDateLocalFormat = "";
if (date != null) {
shortDateLocalFormat = ((DateTime)date).ToString("d", new System.Globalization.CultureInfo("en-US"));
}
#shortDateLocalFormat
}
.NET Fiddle
Maybe try simply
#(Model.AuditDate.HasValue ? Model.AuditDate.ToString("mm/dd/yyyy") : String.Empty)
also you can use many type of string format like
.ToString("dd MMM, yyyy")
.ToString("d") etc
This is the best way to get a simple date string :
#DateTime.Parse(Html.DisplayFor(Model => Model.AuditDate).ToString()).ToShortDateString()
Instead of
#Html.DisplayFor(Model => Model.AuditDate)
Use
#Model.AuditDate.ToString("MM/dd/yyyy")
This style renders the date as: 06/02/2022.
You can style your string accordingly to how you need it.
I had a similar issue on my controller and here is what worked for me:
model.DateSigned.HasValue ? model.DateSigned.Value.ToString("MM/dd/yyyy") : ""
"DateSigned" is the value from my model
The line reads, if the model value has a value then format the value, otherwise show nothing.
Hope that helps
You can use this instead of using #html.DisplayFor().
#Convert.ToString(string.Format("{0:dd/MM/yyyy}", Model.AuditDate))
You just need To set Data Annotation in your Model.
[DisplayFormat(ApplyFormatInEditMode = true,DataFormatString = "{0:MM/dd/yyyy}")]
public DateTime AuditDate {get; set;}
On view(cshtml page)
#Html.DisplayFor(model => model.AuditDate)
Nothing else you need to do.
Hope its useful.
See this answer about the No overload for method 'ToString' takes 1 arguments error.
You cannot format a nullable DateTime - you have to use the DateTime.Value property.
#Model.AuditDate.HasValue ? Model.AuditDate.Value.ToString("mm/dd/yyyy") : string.Empty
Tip: It is always helpful to work this stuff out in a standard class with intellisense before putting it into a view. In this case, you would get a compile error which would be easy to spot in a class.
I need to control a field with a min length if someone enters a value but if they don't enter anything in, I don't want the form to tell them there is a min value.
This is what I have:
[Required]
[StringLength(15, ErrorMessage = "Please supply at least {2} characters.", MinimumLength = 3)]
[Display(Name = "Last name on account or first part of the company's name")]
public string LastName { get; set; }
I just need for it to allow blanks also or if data is entered, require it to be a min of 3 characters..
Any suggestions?
The problem is with the validation logic of the StringLength attribute, that returns true also for the string with null value, here the implementation:
public override bool IsValid(object value)
{
this.EnsureLegalLengths();
int num = value == null ? 0 : ((string) value).Length;
if (value == null)
return true;
if (num >= this.MinimumLength)
return num <= this.MaximumLength;
else
return false;
}
Also the Required attribute that you used is not helping :-).
Anyway the only thing you can do for your scenario is to create a custom attribute to validate LastName with the logic that you need, here a link to an MVC3 example, or you can try googling, there is a lot of examples and is not hard to implement.
Is it possible to both validate, that the provided data is in the form of a phone number AND trim it down to just the numbers in the validator?
Input: (902) 837-2832
Output: VALID: YES, 9028372832
Or do I have to convert the input to the number-only format after the fact?
Add a property to your model with only a getter that returns the stripped down version of the property that is bound to the input. Put your validation attribute on that property.
public string PhoneNumber {get;set;}
[Required(ErrorMessage="Phone number is required.")]
[RegularExpression(#"\d{10}", ErrorMessage="Phone number is invalid.")]
public string PhoneNumberValue
{
get
{
var temp = PhoneNumber
temp = Regex.Replace(temp, #"[^0-9]", "");
temp = temp.Length == 11 && temp.StartsWith("1")
? temp.Substring(1) : temp;
}
set
{
// I can't remember off the top of my head if MVC model
// binding requires a setter or not. If so, just leave this
// empty. Otherwise you can remove it entirely.
}
}
Then, in your view, just render the alternate validation message.
#Html.LabelFor(x=>x.PhoneNumber)
#Html.TextBoxFor(x=>x.PhoneNumber)
#Html.ValidationMessageFor(x=>x.PhoneNumberValue)
Here is an example how to validate with Regular expression:
[Required(ErrorMessage="Phone Number is required")]
[RegularExpression("^(?([0-9]{3}))?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage="Not a valid number")]
public string PhoneNumber { get; set; }
We may use Trim method of string to clean the phone number and get only digits.
char[] charsToTrim = { '(', ' ', ')', '-'};
string phoneNumber = "(123)-345-6789";
string result = banner.Trim(charsToTrim);
Finally here is a post that explains Enabling Validation using DataAnnotations in more detail