How to search particular contact from nsarray of nsarray - ios

Question

I have store the contact in alphabetical order so I have array of array for contact list which i have display on screen. Now i want to search the contact via name but predicate not work properly here. I have done below code.
filterArray.filterUsingPredicate(NSPredicate(format: "ANY SELF.name CONTAINS[cd] '\(tfSearchBar.text!)'", argumentArray: nil))
In filter array first i have all contact but when i search for "a" it gives all the section array which has "a" in the contact name. but here i have stuck. It is not necessary that the all contact of the section contain "a" in the contact name.
For example
(
A:(
{
name = "abc"
number = "123456"
}
{
name = "azx"
number = "123456"
}
)
)
For example for above example after search for "a". when i search for "ab" then same array return by predicate.Not only first object. Any way to find only first object with out nested predicate.

Answer 1

I'm not sure what you are trying to accomplish with the word "ANY" in your predicate but it seems redundant. This code works as you describe when put into a Playground:
import UIKit
#objc class DataElement : NSObject {
let name : String
let number : String
init(name : String, number : String) {
self.name = name
self.number = number
}
}
let dataArray : NSArray = [
DataElement(name: "abc", number: "123456"),
DataElement(name: "azx", number: "689101")
]
let searchTerm = "a"
let predicate = NSPredicate(format: "SELF.name CONTAINS[cd] '\(searchTerm)'", argumentArray: nil)
dataArray.filteredArrayUsingPredicate(predicate)