Duplicate cells being exported as one cell - xslt-2.0

Question

I'm trying to export a simple spreadsheet where some of the cells are empty and some are full.
Every time this XSL exporter reads a cell which is the same as the cell before it doesn't write it. If there are cells with identical values next to each other they are missed out.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:office="urn:oasis:names:tc:opendocument:xmlns:office:1.0"
xmlns:table="urn:oasis:names:tc:opendocument:xmlns:table:1.0"
xmlns:text="urn:oasis:names:tc:opendocument:xmlns:text:1.0"
exclude-result-prefixes="office table text">
<xsl:output method = "xml" indent = "yes" encoding = "UTF-8" omit-xml-declaration = "yes"/>
<xsl:param name="targetURL"/>
<!-- Process the document model -->
<xsl:template match="/">
<data name="SiteData"><xsl:apply-templates select="//table:table"/></data>
</xsl:template>
<xsl:template match="table:table">
<!-- Process all table-rows after the column labels in table-row 1 -->
<xsl:for-each select="table:table-row">
<!-- Process the columns -->
<xsl:for-each select="table:table-cell">
<xsl:value-of select="."/>:</xsl:for-each>
<xsl:value-of select="text:p"/> ;</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I've tried every possible solution but I just can't work this out. Does anybody have an idea how to write ':' for every cell regardless of if it is empty or duplicated