Performing segue if condition is met - ios

Question

You can see from the photo the set up of my UI.
The objective is when the button is pressed if a number is greater than 9 the label on the first viewcontroller to change to "number is greater than 9" and if its smaller than 9 the segue should be triggered and the label on the secondView should change to "number is greater than 9..
This is what i have done so far, but when the segue is triggered the label on the secondView does not change..
class ViewController: UIViewController {
#IBOutlet weak var labelFirst: UILabel!
#IBOutlet weak var numberEntered: UITextField!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
override func shouldPerformSegueWithIdentifier(identifier: String!, sender: AnyObject!) -> Bool {
var number: Int? {
get{
return Int(numberEntered.text!)
}
}
if number>9 {
labelFirst.text="number is greater than 9"
return false}
else {
return true
func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!) {
if (segue.identifier=="segue"){
let destinationVC:secondView = segue.destinationViewController as! secondView
destinationVC.outputText="number is smaller than 9"
}
}
}
}
}
the segue is connected to the button and directs to the second view.
secondView:
import UIKit
class secondView: UIViewController {
#IBOutlet weak var label: UILabel!
var outputText=String()
override func viewDidLoad() {
label.text=outputText
}
}
ui

Answer 1

Your prepareForSegue method is in the wrong place , it should be outside the shouldPerfomSegue method and marked with override.

Answer 2

The reason it is not updating on the second screen is because you are doing it inside viewDidLoad. That only happens once. Move the code to viewWillAppear.
import UIKit
class secondView: UIViewController {
#IBOutlet weak var label: UILabel!
var outputText=String()
override func viewWillAppear() {
super.viewWillAppear()
label.text = outputText
}
}