How do I get my TableView selection to open my modal view? - ios

Question

I created a TableView with a TableViewCell in it.
I would like my cells in my TableView to open up in a separate ViewController.
My storyboard looks like this:
My TableViewController has this:
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "ShowVerse" {
let pageDetailViewController = segue.destinationViewController as! PageViewController
// Get the cell that generated this segue.
if let selectedPageCell = sender as? PageTableViewCell {
let indexPath = tableView.indexPathForCell(selectedPageCell)!
let selectedPage = pages[indexPath.row]
pageDetailViewController.page = selectedPage
}
}
}
And in my PageViewController.swift I have this :
var page: Page?
override func viewDidLoad() {
super.viewDidLoad()
if let page = page {
chapter.text = String(page.chapter)
verse.text = String(page.verse)
}
}
I do not get any errors. But tapping the cells does not nothing. What might I be missing?

Answer 1

Try this:
func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
performSegueWithIdentifier("ShowVerse", sender: self)
}

Answer 2

Swift
code in didSelectRowAtIndexPath
self.performSegueWithIdentifier("homeSegue", sender: self)
Before switching to next view controller, if you wants to pass value to next view controller
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if (segue.identifier == "homeSegue")
{
var homeController = segue.destinationViewController as? ViewController
homeController.name = "valeu"
}
}
Objective-C
code in didSelectRowAtIndexPath
[self performSegueWithIdentifier:#"ShowVerse" sender:self];
Before switching to next view controller, if you wants to pass value to next view controller
-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
if ([segue.identifier isEqualToString:#"ShowVerse"]) {
HomeViewController *controller = segue.destinationViewController;
controller.propertyName = #"value";
}
}