identify many cell in uitable view - ios

Question

I want to identify many custom cell in table view "i build them in storyboard " but the are error ask from me to return value , i am trying to return nil and int value and cell but the error be same
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
if indexPath == 0 {
let cell = tableView.dequeueReusableCellWithIdentifier("CheefsCell", forIndexPath: indexPath) as UITableViewCell
cell.accessoryType = .DisclosureIndicator
return cell }
else if indexPath == 1 {
let cell = tableView.dequeueReusableCellWithIdentifier("BeautyCell", forIndexPath: indexPath) as UITableViewCell
cell.accessoryType = .DisclosureIndicator
return cell }
else if indexPath == 2 {
let cell = tableView.dequeueReusableCellWithIdentifier("StudentServicesCell", forIndexPath: indexPath) as UITableViewCell
cell.accessoryType = .DisclosureIndicator
return cell }
else if indexPath == 3 {
let cell = tableView.dequeueReusableCellWithIdentifier("ArtAndDesigneCell", forIndexPath: indexPath) as UITableViewCell
cell.accessoryType = .DisclosureIndicator
return cell }
else if indexPath == 4 {
let cell = tableView.dequeueReusableCellWithIdentifier("StoreCell", forIndexPath: indexPath) as UITableViewCell
cell.accessoryType = .DisclosureIndicator
return cell }
else if indexPath == 5 {
let cell = tableView.dequeueReusableCellWithIdentifier("OthersCell", forIndexPath: indexPath) as UITableViewCell
cell.accessoryType = .DisclosureIndicator
return cell }
return
}
update ::
git hub link /

Answer 1

The method cellForRowAtIndexPath requires to return a non-optional UITableViewCell, so you must ensure to return a cell in any case. A simple return or return nil is not allowed.
The code can be simplified, most of it is redundant. The only difference is the identifier.
A suitable solution is a switch statement on the row property of the indexpath.
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
var identifier : String
switch indexPath.row {
case 0: identifier = "CheefsCell"
case 1: identifier = "BeautyCell"
case 2: identifier = "StudentServicesCell"
case 3: identifier = "ArtAndDesigneCell"
case 4: identifier = "StoreCell"
default: identifier = "OthersCell"
}
let cell = tableView.dequeueReusableCellWithIdentifier(identifier, forIndexPath: indexPath)
cell.accessoryType = .DisclosureIndicator
return cell
}

Answer 2

You're getting an error cause you're not returning a cell from the method.
Change your code so it always returns a cell.
When checking indexPaths, use their row property - indexPath.row.
Consider replacing your if-else tree with switch.

Answer 3

Another example based on #vadian's answer:
static let identifiers = [ "CheefsCell", "BeautyCell", "StudentServicesCell", "ArtAndDesigneCell", "StoreCell" ]
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let identifier = (indexPath.row < count) ? identifiers[ indexPath.row ] : "OthersCell"
var cell = tableView.dequeueReusableCellWithIdentifier(identifier, forIndexPath: indexPath)
if cell == nil {
cell = UITableViewCell() // allocate a new cell here
}
cell.accessoryType = .DisclosureIndicator
// configure your cell here
return cell
}