My partial view which is loaded into a bootstrap partial on my Index page, should be posting type Announcement but is posting type AnnouncementViewModel of the Index page model to the Create controller.
The #modal-container is specified in my _Layout, which is working as expected.
Unsure about the controllers - they appear correct, the problem is stemming from my ajax post I believe but I don't know what's the issue. I get the error after POST, however the database does update with the model correctly, but afterwards I get the below error.
I have specified $('#create-container')/$('form') as the form in which to serialize and send back to the controller.
Why is it doing this?
Error:
The model item passed into the dictionary is of type 'AnnouncementsViewModel', but this dictionary requires a model item of type 'Announcement'.
Index:
#model AnnouncementsViewModel
<h2>Announcements</h2>
<div>
#Html.ActionLink("Create", "Create", "Announcements", null, new { #class = "modal-link btn btn-sm" })
<div class="announcementTable">
<div id="announcementList">
#{Html.RenderPartial("List", Model.AnnouncementList);}
</div>
</div>
</div>
Partial:
#model Announcement
#section Scripts {
<script type="text/javascript">
$(function () {
$('#btn-create').click(function () {
$.ajax({
url: '#Url.Action("Create","Announcements")',
type: 'POST',
contentType: 'application/json',
data: $('#create-container').serialize(),
success: function (data) {
if (data.success == true) {
$('#modal-container').modal('hide');
location.reload(false)
} else {
$('#modal-container').html(data);
}
}
})
});
$('#btn-close').click(function () {
$('#modal-container').modal('hide');
});
});
</script>
}
<div class="create-container">
#using (Html.BeginForm())
{
<div class="newAnnouncementTableRow1">
<div>#Html.LabelFor(m => m.Title)</div>
<div>#Html.EditorFor(m => m.Title)</div>
<div>#Html.LabelFor(m => m.Details)</div>
<div>#Html.EditorFor(m => m.Details)</div>
</div>
<div class="newAnnouncementTableRow2">
<div>#Html.LabelFor(m => m.StartDT)</div>
<div>#Html.EditorFor(m => m.StartDT)</div>
<div>#Html.LabelFor(m => m.ExpiryDT)</div>
<div>#Html.EditorFor(m => m.ExpiryDT)</div>
<div>#Html.LabelFor(m => m.Enabled)</div>
<div>
#Html.RadioButtonFor(m => m.Enabled, 1)Yes
#Html.RadioButtonFor(m => m.Enabled, 0, new { #checked = "checked" })No
</div>
</div>
<div>
<button type="submit" id="btn-create" class="btn btn-sm">Save</button>
<button type="button" class="btn btn-default modal-close-btn" data-dissmiss="modal">Cancel</button>
</div>
}
</div>
Controller:
[HttpGet]
public ActionResult Index()
{
var avm = new AnnouncementsViewModel
{
AnnouncementList = new List<Announcement>()
};
avm.AnnouncementList = GetAnnouncementList();
return View(avm);
}
[HttpGet]
public ActionResult Create()
{
return PartialView("Create");
}
[HttpPost]
public ActionResult Create(Announcement a)
{
db.DbAnnouncement.Add(a);
db.SaveChanges();
return Index();
}
You set contentType: 'application/json' it your .ajax() call but returning View from Controller. Either change contentType to html or change controller to return JsonResult and return Json("yourData");
I recommend you to change your ajax call:
$.ajax({
/* other data */
dataType : "html",
contentType: "application/json; charset=utf-8",
/* other data */
success: function (data) {
$('#modal-container').modal('hide');
location.reload(false)
},
error: function (jqXHR, textStatus, errorThrown )
{
$('#modal-container').html(data);
}
/* other data */
});
Thing is response from server in your case always success but it returns html rather than json so you just don't have data.success at all.
The other issue as mentioned in the comments was that the controller was redirecting to an action method that it could not.
Changing return Index(); to return RedirectToAction("Index", "Announcements"); solved the error and the redirecting to the Create partial page caused by using return View();.
Related
After much of struggle im posing this question. Im using a Kendo Upload on a page. Am able to post the selected files on the asyn mode with whe the page has Html.BeginForm. But I'm not able to send file details as HttpPostedFileBase when I use ajax request to send data to the controller.
Following is my html
<form class="form-horizontal" role="form">
<div class="form-group">
#Html.Label("Complaint Name", new { #class = "col-sm-3 control-label" })
<div class="col-sm-4">
#Html.TextBoxFor(
m => m.ComplaintName,
new
{
#TabIndex = "1",
#class = "form-control input-sm",
disabled = true
})
</div>
</div>
<div class="form-group">
#Html.Label("Complaint Details", new { #class = "col-sm-3 control-label" })
<div class="col-sm-4">
#Html.TextBoxFor(
m => m.ComplaintDetails,
new
{
#TabIndex = "2",
#class = "form-control input-sm",
disabled = true
})
</div>
</div>
<div class="form-group">
#Html.Label("Choose files to upload", new { #class = "col-sm-3 control-label" })
<div class="col-sm-9 nopaddingforTextArea">
<input name="files" id="files" type="file" />
</div>
</div>
<div class="form-group">
<div>
<input id="btnSubmit" class="btn btn-primary pull-right" type="button" />
</div>
</div>
</form>
Following is my action
public ActionResult SaveComplaintDetails(string complaintName, string complaintDetails, IEnumerable<HttpPostedFileBase> files)
{
}
Following is my js
$("#files").kendoUpload({
async: {
saveUrl: '#Url.Action("EsuperfundCommentsBind", ClientInboxConstants.NewQuery)',
autoUpload: false
},
multiple: true
});
$("#btnSubmit").click(function () {
//Ajax call from the server side
$.ajax({
//The Url action is for the Method FilterTable and the Controller PensionApplicationList
url: '#Url.Action("SaveComplaintDetails", "Complaints")',
//The text from the drop down and the corresponding flag are passed.
//Flag represents the Index of the value in the dropdown
data: {
complaintName: document.getElementById("ComplaintName").value,
complaintDetails: document.getElementById("ComplaintDetails").value,
files: //What to pass here??
},
contentType: "application/json; charset=utf-8",
//Json data
datatype: 'json',
//Specify if the method is GET or POST
type: 'GET',
//Error function gets called if there is an error in the ajax request
error: function () {
},
//Gets called on success of the Ajax Call
success: function (data) {
}
});
});
My question is how to pass the selected files in Kendo Upload in ajax as a parameter?
Any help in this aspect would be really appreciated.
If your view is based on a model and you have generated the controls inside <form> tags, then you can serialize the model to FormData using:
<script>
var formdata = new FormData($('form').get(0));
</script>
This will also include any files generated with: <input type="file" name="myImage" .../> and post it back using:
<script>
$.ajax({
url: '#Url.Action("YourActionName", "YourControllerName")',
type: 'POST',
data: formdata,
processData: false,
contentType: false,
});
</script>
and in your controller:
[HttpPost]
public ActionResult YourActionName(YourModelType model)
{
}
or (if your model does not include a property for HttpPostedFileBase)
[HttpPost]
public ActionResult YourActionName(YourModelType model,
HttpPostedFileBase myImage)
{
}
If you want to add additional information that is not in the form, then you can append it using
<script>
formdata.append('someProperty', 'SomeValue');
</script>
**Example Usage :**
View :
#using (Html.BeginForm("Create", "Issue", FormMethod.Post,
new { id = "frmCreate", enctype = "multipart/form-data" }))
{
#Html.LabelFor(m => m.FileAttachments, new { #class = "editor-label" })
#(Html.Kendo().Upload()
.HtmlAttributes(new { #class = "editor-field" })
.Name("files")
)
}
<script>
$(function () {
$('form').submit(function (event) {
event.preventDefault();
var formdata = new FormData($('#frmCreate').get(0));
$.ajax({
type: "POST",
url: '#Url.Action("Create", "Issue")',
data: formdata,
dataType: "json",
processData: false,
contentType: false,
success: function (response) {
//code omitted for brevity
}
});
});
});
</script>
*Controller :*
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create([Bind(Exclude = null)] Model viewModel, IEnumerable<HttpPostedFileBase> files)
{
//code omitted for brevity
return Json(new { success = false, message = "Max. file size 10MB" }, JsonRequestBehavior.AllowGet);
}
<script>
$(function () {
$('form').submit(function (event) {
event.preventDefault();
var formdata = new FormData($('#createDetail').get(0));
$.ajax(
{
type: 'POST',
url: '#Url.Action("Detail_Create", "Product")',
data: formdata,
processData: false,
success: function (result) {
if (result.success == false) {
$("#divErr").html(result.responseText);
} else {
parent.$('#CreateWindowDetail').data('kendoWindow').close();
}
},
error: function (xhr, ajaxOptions, thrownError) {
$("#divErr").html(xhr.responseText);
}
});
});
});
#using (Html.BeginForm("Detail_Create", "Product", FormMethod.Post, new { id = "createDetail", enctype="multipart/form-data"}))
{
<div id="divErr" class="validation-summary-errors"></div>
<fieldset>
<ol>
<li>
#Html.LabelFor(m => m.Price)
#(Html.Kendo().NumericTextBoxFor(m => m.Price).Name("Price").Format("{0:0}")
.HtmlAttributes(new { style = "width:100%" })
)
</li>
<li>
#Html.LabelFor(m => m.Description)
#Html.TextBoxFor(model => model.Description, new { #class = "k-textbox", id = "Description", style = "width:100%;" })
</li>
<li>
#Html.LabelFor(m => m.Group)
#(Html.Kendo().ComboBox()
.Name("Group")
.Placeholder("Введите группу детали")
.DataTextField("Name")
.DataValueField("Id")
.HtmlAttributes(new { style = "width:100%;" })
.Filter("contains")
.MinLength(1)
.DataSource(source =>
{
source.Read(read =>
{
read.Action("Group_Read_ComboBox", "Product");
})
.ServerFiltering(true);
})
)
</li>
<li>
#Html.LabelFor(m => m.Image)
#(Html.Kendo().Upload()
.Name("files")
)
</li>
</ol>
</fieldset>
<button type="submit" id="get" class="k-button">Добавить</button>
}
[HttpPost]
public ActionResult Detail_Create(DetailModel model, IEnumerable<HttpPostedFileBase> files)
{
string error = string.Empty;
if (ModelState.IsValid)
{
.....
}
IEnumerable<System.Web.Mvc.ModelError> modelerrors = ModelState.SelectMany(r => r.Value.Errors);
foreach (var modelerror in modelerrors)
{
error += "• " + modelerror.ErrorMessage + "<br>";
}
return Json(new { success = false, responseText = error }, JsonRequestBehavior.AllowGet);
}
after pressing the button, the controller null comes to how to fix. 2 days already sitting, and the time comes to an end
I have a very simple view and can't figure out why my textbox value is not passing to my controller. Will the actionlink work for providing the controller the parameter?
#{
ViewBag.Title = "Home Page";
}
#using (Html.BeginForm("LookupEmployee", "Home")) {
<div class="jumbotron">
<h2>Personnel System</h2><br />
<p>ID: <input type="text" id=employeeID name="employeeID" /></p>
#Html.ActionLink("Your Leave Balance", "LeaveBalance", "Home", null, new { #class = "btn btn-primary btn-large" })
</div>
}
<div class="row">
</div>
My HomeController takes the parameter and fills the dataset. I have hard coded a value and verified that this code works:
public class HomeController : Controller
{
public ActionResult Index()
{
return View();
}
public ActionResult LeaveBalance(string employeeID)
{
//ViewBag.Message = "Your application description page.";
if (!String.IsNullOrEmpty(employeeID))
{
DataSet gotData;
LeaveRequestWCF myDataModel = new LeaveRequestWCF();
gotData = myDataModel.GetTheData(Convert.ToInt32(employeeID));
myDataModel.theModelSet = gotData;
return View(myDataModel);
}
return View();
}
}
Any advice? As you can tell, I'm new with MVC and trying to drift away from web forms.
OPTION 1:
You are using Html.ActionLink to post a form, which cannot be done because Html.ActionLinks are rendered as Anchor tags. Anchor tags make GET Requests unless we explicitly handle their JQuery click event. Use a Submit button to post a form for an appropriate controller action. So instead of -
#Html.ActionLink("Your Leave Balance", "LeaveBalance", "Home", null,
new { #class = "btn btn-primary btn-large" })
go for -
<input type="submit" class="SomeClass" value="Submit" />
OPTION 2:
You can also use AJAX POST using JQuery click event for anchor tag to post the form and once you get the result, you can make a client side redirection.
<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script>
$(document).ready(function() {
$("#solTitle a").click(function() {
var data = {
"Id": $("#TextId").val()
};
$.ajax({
type: "POST",
url: "http://localhost:23133/api/values",
data: JSON.stringify(data),
contentType: "application/json; charset=utf-8",
dataType: "json",
processData: true,
success: function (data, status, jqXHR) {
console.log(data);
console.log(status);
console.log(jqXHR);
alert("success..." + data);
// handle redirection here
},
error: function (xhr) {
alert(xhr.responseText);
}
});
});
});
</script>
ActionLink creates a simple <a href /> on the page, that will send a get request to the server.
You need a submit button instead, so your form gets posted with its form inputs. Use:
<button type="submit">Your Leave Balance</button>
I have a view within a MS MVC [razor] project where I want to submit view data back to a controller via a JSON post operation. I have looked around and I cannot find how to retrieve and package the view data for submission back to the controller. I was under the assumption that the JSON serialize operation would package the data when called but this does not seem to be happening. For example:
MVC View ------------------------------
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
#Html.ValidationSummary(true)
<center>
<fieldset id="UserCreateFieldset">
<div class="editor-label">
#Html.LabelFor(model => model.FirstName)
</div>
<div class="editor-field">
#Html.EditorFor(model => model.FirstName)
#Html.ValidationMessageFor(model => model.FirstName)
</div>
<p>
<input type="button" name="CreateButton" value="Create" onclick="CreateUser()" />
</p>
</fieldset>
</center>
}
<script>
function CreateUser()
{
var infoForm = $("#UserCreateFieldset");
var entries = infoForm.serializer.Serialize(Model);
$.ajax(
{
url: '#Url.Action("CreateUser", "User")',
data: entries,
type: "POST",
dataType: "json",
success: function (data)
{
$.event.trigger({
type: "CreateUserCompleted",
NewUserID: 1,
});
}
});
}
</script>
Just to note; when the controller is called via the post it receives back the model -- but it contains the original values used to load the view.
Peter
Use the .serialize() method from jquery:
function CreateUser()
{
var data = $('form').serialize();
$.ajax({
url: '#Url.Action("CreateUser", "User")',
data: data,
type: "POST",
dataType: "json",
success: function (data)
{
$.event.trigger({
type: "CreateUserCompleted",
NewUserID: 1,
});
}
});
}
You can instead of using Html.BeginForm use Ajax.BeginForm to not mess with the internals if you are doing the same thing as a the Html.BeginForm without anything special. you could change your code to:
#using(Ajax.BeginForm("MyAction", "MyController",
new AjaxOptions
{
HttpMethod = "POST"
}))
{
// Same form
}
It even has OnSuccess method which can be used in the AjaxOptions declaration:
#using(Ajax.BeginForm("MyAction", "MyController",
new AjaxOptions
{
HttpMethod = "POST",
OnSuccess = "TriggerEvent"
}))
{
// Same form
}
And you set a function in the javascript to be called on success:
function TriggerEvent() {
$.event.trigger({
type: "CreateUserCompleted",
NewUserID: 1,
});
}
I am trying to get the model data from a strongly typed view to a controller.
Using the submit button is ok, I can get the data. Now I want to achieve the same with html.actionlink.
This is what I have:
View:
#model WordAutomation.Models.Document
#{
ViewBag.Title = "Document";
}
<script type="text/javascript">
$(function () {
$("#dialog").dialog();
});
</script>
<h2>Document</h2>
#using (Html.BeginForm()) {
#Html.ValidationSummary(true)
<fieldset>
<legend>Document</legend>
<div class="editor-label">
#Html.LabelFor(model => model.ClientTitle)
</div>
<div class="editor-field">
#Html.EditorFor(model => model.ClientTitle)
#Html.ValidationMessageFor(model => model.ClientTitle)
</div>
<div class="editor-label">
#Html.LabelFor(model => model.ClientFullName)
</div>
<div class="editor-field">
#Html.EditorFor(model => model.ClientFullName)
#Html.ValidationMessageFor(model => model.ClientFullName)
</div>
<div class="editor-label">
#Html.LabelFor(model => model.ClientCustomSSN)
</div>
<div class="editor-field">
#Html.EditorFor(model => model.ClientCustomSSN)
#Html.ValidationMessageFor(model => model.ClientCustomSSN)
</div>
<p>
<input type="submit" value="Create" />
</p>
</fieldset>
}
<div>
#Html.ActionLink("Preview", "PreviewWordDocument", "Home", null, new { id = "previewLink" })
</div>
<div id="dialogcontainer">
<div id="dialogcontent"><input type="submit" value="Create" /> </div>
</div>
#section Scripts {
<script type="text/javascript">
$(document).ready(function() {
$("#dialogcontainer").dialog({
width: 400,
autoOpen:false,
resizable: false,
title: 'Test dialog',
open: function (event, ui) {
$("#dialogcontent").load("#Url.Action("PreviewWordDocument", "Home")");
},
buttons: {
"Close": function () {
$(this).dialog("close");
}
}
});
$("#previewLink").click(function(e) {
e.preventDefault();
$("#dialogcontainer").dialog('open');
});
});
</script>
}
Controller:
public ActionResult Document()
{
return View();
}
[HttpPost]
public ActionResult Document(WordAutomation.Models.Document model)
{
Models.Utility.EditWord word = new Models.Utility.EditWord();
word.EditWordDoc(model);
return View("Display", model);
}
public ActionResult PreviewWordDocument()
{
var image = Url.Content("~/Content/preview.jpeg");
return PartialView((object)image);
}
The document actionresult can get the model, but I want to know how can I get the values from the actionlink which will trigger the PreviewWordDocument action.
Thanks in advance, Laziale
The form can only be posted using the submit button to the URL given by its action attribute.
You can however send the form data to a different URL using the jQuery post method, manually validating the form before it is sent.
That way you can send the form data to the PreviewWordDocument controller method and handle the response in order to show the preview in the desired div.
(It will be helpful if you give an id to the form, so you can easily find it using jQuery)
So your click event handler for the preview link will look like this:
$("#previewLink").click(function(e) {
e.preventDefault();
if($("#YourFormId").valid()){
$("#dialogcontainer").dialog('open');
}
});
In the open function of the dialog you will post the form (which was already validated) to the preview controller method, using the jQuery ajax function. The response will be loaded into the dialogContent div:
$.ajax({
type: "POST",
url: $("#previewLink").attr("href"), //the preview controller method
data: $("#YourFormId").serialize(),
success: function (data) {
//load ajax response into the dialogContent div
$("#dialogcontent").html(data);
},
error: function(xhr, error) {
$("#YourFormId").prepend('<div id="ajaxErrors"></div>')
.html(xhr.responseText);
}
});
Now you will now be able to receive the whole document in the PreviewWordDocument action:
public ActionResult PreviewWordDocument(WordAutomation.Models.Document model)
{
var image = Url.Content("~/Content/preview.jpeg");
return PartialView((object)image);
}
in a HTML page when you click on a submit button all the input elements inside the form which the submit button resides in will posted to server, but when you click on a anchor (<a> tag ). you only send a request with a Get method and without posting any value.but if you want to send particular value to the server with this approach you can do it by query string.you have used following to make a request :
#Html.ActionLink("Preview", "PreviewWordDocument", "Home", null,
new { id = "previewLink" })
this will produce :
<a id="previewLink" href="/Home/PreviewWordDocument"> Preview </a>
which is incorrect.to pass any value to the server with ActionLink use 4th parameter like this :
#Html.ActionLink("Preview", "PreviewWordDocument", "Home",
new { id = "previewLink" }, null)
the result from this code would be :
Preview
cheers!
I have some ajax forms in my page and I need to get the form Id or some element inside the form when the OnSuccess function is called, example:
<li>
#using (Ajax.BeginForm(new AjaxOptions
{
OnSuccess = "form.onSuccess"
}))
{
#Html.TextBoxFor(m => m.TaskId)
<button type="submit">Save</button>
}
</li>
how can I get?
Option 1:
#using (Ajax.BeginForm(new AjaxOptions{OnComplete = "DefaultEditOnComplete(xhr, status, 'Person')"}))
{
//Person data and submit button
}
function DefaultEditOnComplete(xhr, status, entityName) {
//xhr - the ajax response
//status - the response text, ex. "success"
//entityName - your custom argument, in this example 'Person'
alert('DefaultEditOnComplete fired for ' + entityName);
}
Option 2:
$('form').submit(function () {
$(this).addClass('activeForm');
});
#using (Ajax.BeginForm(new AjaxOptions{OnSuccess= "JaxSuccess(xhr, status)"}))
{
....
}
function JaxSuccess(xhr, status) {
var active = $(".activeForm");
//Do some stuff here
.....
//When Done, remove the activeForm class, making everything clean
$(".activeForm").removeClass('activeForm');
}
Option 3:
Abandon Ajax.BeginForm, and substitute for regular form and jquery pairing:
#using (Html.BeginForm("SomethingNice", "Home", FormMethod.Post, new { #id = "CoolForm", #class = "ajaxForm" }))
{
#Html.LabelFor(m => m.Rating)
#Html.TextBoxFor(m => m.Rating)
#Html.LabelFor(m => m.Comment)
#Html.TextBoxFor(m => m.Comment)
<input type="submit" value="Submit"/>
}
<script type="text/javascript">
$(function() {
$(".ajaxForm").submit(function(e) {
e.preventDefault();
var form = $(this);
var jaxUrl = form.attr('action');
var dat = form.serialize();
alert(form.attr('id'));
$.ajax({
url: jaxUrl,
data: dat,
success: function(data) {
form.parent().append(data);
},
error: function(xhr, status) {
}
});
});
});
</script>