Swift - Remove white spaces from string doesn't work - ios

Question

i'm trying to remove white spaces and some characters from a string, please check my code below
// giving phoneString = [phone]
var phoneString = ABMultiValueCopyValueAtIndex(phone, indexPhone).takeRetainedValue() as! String
// Remove spaces from string
phoneString = phoneString.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
// Remove +39 if exist
if phoneString.rangeOfString("+39") != nil{
phoneString = phoneString.stringByReplacingOccurrencesOfString("\0", withString: "+39", options: NSStringCompareOptions.LiteralSearch, range: nil)
}
print(phoneString) // output [phone]
it seems like all the changes has no effect over my string, why this happen?
EDIT #V S
EDIT 2:
I tried to convert my string in utf 8, check the result:
43 51 57 194 160 51 51 51 194 160 51 51 51 51 51 51 51
where:
43 = +
51 = 3
57 = 9
160 = space
194 = wtf?!? is this?

Answer 1

what do you try to do is
// your input string
let str = "[phone]"
let arr = str.characters.split(" ").map(String.init) // ["+39", "333", "3333333"]
// remove country code and reconstruct the rest as one string without whitespaces
let str2 = arr.dropFirst().joinWithSeparator("") // "3333333333"
to filter out country code, only if exists (as Eendje asks)
let str = "[phone]"
let arr = str.characters.split(" ").map(String.init)
let str3 = arr.filter { !$0.hasPrefix("+") }.joinWithSeparator("") // "123456789"
UPDATE, based on your update.
160 represents no-breakable space. just modify next line in my code
let arr = str.characters.split{" \u{00A0}".characters.contains($0)}.map(String.init)
there is " \u{00A0}".characters.contains($0) expression where you can extend the string to as much whitespace characters, as you need. 160 is \u{00A0} see details here.
Update for Swift 4
String.characters is deprecated. So the correct answer would now be
// your input string
let str = "[phone]"
let arr = str.components(separatedBy: .whitespaces) // ["+39", "333", "3333333"]
// remove country code and reconstruct the rest as one string without whitespaces
let str2 = arr.dropFirst().joined() // "3333333333"

Answer 2

Firstly, stringByTrimmingCharactersInSet only trims the string - i.e. removes leading & trailing spaces - you need to use stringByReplacingOccurrencesOfString replacing " " with "".
Secondly, your parameters on stringByReplacingOccurrencesOfString for the country code are the wrong way round.
Thirdly, "\0" is not what you want- that's ASCII null, not zero.

Answer 3

Swift 3 / Swift 4
let withoutSpaces = phoneNumber.replacingOccurrences(of: "\\s", with: "", options: .regularExpression)

Answer 4

Swift 5
//MARK:- 3 ways to resolve it
var tempphone = "0345 55500 93"
//MARK:- No 1
tempphone = tempphone.replacingOccurrences(of: " ", with: "")
//MARK:- No 2
tempphone = tempphone.replacingOccurrences(of: "\\s", with: "", options: .regularExpression)
//MARK:- No 3
tempphone = tempphone.trimmingCharacters(in: .whitespaces)

Answer 5

phoneString = phoneString.stringByReplacingOccurrencesOfString("+39", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil)
phoneString = phoneString.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())

Answer 6

Try this. This has worked for me:
if phoneString.rangeOfString("+39") != nil{
freshString = phoneString.stringByReplacingOccurrencesOfString("\0", withString: "+39", options: NSStringCompareOptions.LiteralSearch, range: nil)
}
var strings = freshString.componentsSeparatedByString(" ") as NSArray
var finalString = strings.componentsJoinedByString("")
//outputs [phone]

Answer 7

You can use this replace the whitespace
phoneNumber.replacingOccurrences(of: "\u{00A0}", with: "")

Answer 8

let trimmedPhoneString = String(phoneString).stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
To Remove +39 if exist, you can use stringByReplacingOccurrencesOfString instead

Answer 9

var phoneString = "[phone]"
phoneString = phoneString.stringByReplacingOccurrencesOfString(" ", withString:"")
if phoneString.rangeOfString("+39") != nil
{
phoneString = phoneString.stringByReplacingOccurrencesOfString("+39", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil)
}
print(phoneString) // output 3333333333