how to align in printf function - alignment

Question

I want to make the printf function print from right to left because this program convert the value of number to binary and I want it to be printed in proper form for example if I convert 16 it is written like that 00001 but it must look like that 10000 so does anyone know how to do that thanks in advance
#include <stdio.h>
#include <stdlib.h>
int main()
{
int x,rem;
printf("please enter number: ");
scanf("%d",&x);
while (x !=0)
{
rem=x%2;
if (rem==0)
{
printf("0");
}
else
{
printf("1");
}
x = x/2;
rem = 0;
}
return 0;
}

Answer 1

Here it is:
void print_binary(int x)
{
int skip = 1;
unsigned int mask = 1 << 31;
while(mask > 0){
if(x & mask){
skip = 0;
printf("1");
}else{
if(!skip) printf("0");
}
mask >>= 1;
}
printf("\n");
}
This will print the binary number without trailing zeroes.
If you rather want the result to be stored in a string, you can use:
#include <string.h>
void int_to_binary(int x, char * buff) // buff size must be >= 32 !
{
buff[0] = '\0'; // ensure string ends with \0
unsigned int mask = 1 << 31;
for (; mask > 0; mask >>= 1)
{
strcat(buff, (x & mask) ? "1" : "0");
}
}
To check both codes, use:
int main(int argc, char* argv[])
{
int x;
printf("please enter number: ");
scanf("%d",&x);
char bin[32];
int_to_binary(x, bin);
printf("%s\n", bin);
print_binary(x);
}
What we do is using a mask, which in binary is one "1" beginning on the far left and moving one step right at each loop. The "&" is a bite-wise operator (I let you google it to know how it works). If you need more explanation, feel free to ask.

Answer 2

#include<stdio.h>
#include<stdlib.h>
int main()
{
int binary[20];
int q,i=0;
printf("Enter the decimal no\n");
scanf("%d",&q);
while(q > 0)
{
binary[i]=q%2;
i++;
q=q/2;
}
for(int j=i-1;j>=0;j--)
{
printf("%d",binary[j]);
}
return 0;
}