This question already has answers here:
Passing data between view controllers
(45 answers)
Closed 7 years ago.
How can I pass data between from tableView to another tableView? As this example.
You need to use prepareForSegue and over there you will have the opportunity to pass data to your destination view controller.
Basically you need to set a segue identifier at the connection you made for the second view controller at the storyboard and then you will override (at the first view controller) the method prepareForSegue.
This method will be called automatically by the framework when ever the user will tap the relevant button/cell.
This method initiate your second view controller before the user will see the actual second view controller. You will then have the opportunity to pass/set what ever data you want from the first to the second view controller.
// This will get called before the destination view controller appears
override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!) {
{
if (segue.identifier == "IdentifierNameYouSet") {
// Get destination view
if let destinationVc = segue.destinationViewController as? YourTableViewControllerName{
// Pass the information to your destination view
destinationVc.propertyArray = yourOriginateVcArray
}
}
}
Related
This question already has answers here:
Changing label text of second ViewController upon clicking button in first ViewController
(4 answers)
Closed 6 years ago.
When using the prepare (forSegue) method to pass data to the destination view controller of a segue, all members of the destination VC are nil. Thus, my program crashes when trying to access these members.
My code in the source view controller:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "Second2DetailEdit"{
var detailVC = segue.destination as! DrinkDetailViewController
detailVC.headerLabel.text = "Edit Drink"
}
//...
}
The VC itself is not nil. Only all members of the VC. Did I forget something?
This does only occur in my new Swift 3 project. Similar code in my Swift 2 projects have no problems.
Thanks in advance.
The destination view controller's view is not created yet and that's why all IBOutlets are nil. Try sending the information you need in normal properties like Strings and in ViewDidLoad of the destination, update your view.
The best way around this is to create a variable in your second view controller and set the text to that instead.
Then once the vc has initialized you can set the headerLabel.text to the new variable in viewDidLoad
I would suggest safely unwrapping your detailVC rather than force unwrapping...
if segue.identifier == "Second2DetailEdit" {
if let detailVC = segue.destination as? DrinkDetailViewController {
detailVC.headerLabel.text = "Edit Drink"
}
}
You'll have an easier time setting properties on the destinationVC and passing info to those rather than trying to do it through UILabels...
This question already has answers here:
Passing data between view controllers
(45 answers)
Closed 6 years ago.
I'm making a new application.
If I have a text field on one view controller and a label on another (both View Controllers in ViewController class), How can i type something in on the text field and then take me to the next ViewController and display the text?
In the source controller in prepare for segue you set a property on your destination controller:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if let detailViewController = segue.destination as? DetailViewController {
detailViewController.titleText = mylabel.text
}
}
In your destination controller's view did load you assign this property to your label field.
var titleText = ""
override func viewDidLoad() {
super.viewDidLoad()
label.text = titleText
}
Note you cannot assign directly to your label in prepareForSegue because the label is not guaranteed to have been initialized until ViewDidLoad has been called. Thats why the value goes into a property. Proper model view separation also dictates that one controller shouldn't be writing to another controller's view anyways.
I have a storyboard with two main view controllers (ViewController / SecondViewController) and a container with an embedSegue that displays the EmbeddedViewController view.
Desired Result
I would like to pass the 5 from ViewController to EmbeddedViewController using prepareForSegue (I don't see a need for delegation here, since the data is only going 1 way, and that's TO the EmbeddedViewController.) Once "Segue" button is pressed, the second view controller appears with the yellow VC embedded with 5 in it.
Note - SecondViewController has no user interaction in displaying EmbeddedViewController. It just shows up automatically.
Problem
I can't get a reference to EmbeddedViewController from the mainSegue prepareForSegue. Nor can I access any child View Controllers from SecondViewController. Thought I could access properties of EmbeddedViewController if I access the children VC's of SecondViewController. See code below.
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "mainSegue" {
let secondVCSegue = segue.destinationViewController as! SecondViewController
print("array -- \(secondVCSegue.childViewControllers)")
// Array prints nothing. Just a blank [] :(
}
}
Any tips are appreciated thanks.
Currently developing a small ios app in swift, I have populated a collection view cell with data from a .plist, each cell has a title and button, what i'm wanting is to segue to multiple view controllers in the storyboard depending on the segue identity once the button is pressed. For example if the segue has the id set as food, i want it to navigate to the view called food?
or if it is easier for the segue to pull the title from the cell then navigate to the view with the same title as the cell?
ill try and explain in code:
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?)
{
if segue.identifier == "food"
{
//then navigate to the view controller called food
}
else if segue.identifier == "drink"{
{
//navigate to the view called drink
}
}
If food, drink or any other items have their own unique view in storyboard this is achievable.
You can assign a string to each button in UICollectionView and check which item in the collection was tapped and do a performSegueWithIdentifier: with button string.
performSegueWithIdentifier("toComments", sender: self)
Then prepareForSegue: method to pass data. Do another if for drink.
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "toFood" {
let ExchangeViewData = segue.destinationViewController as! FoodViewController
ExchangeViewData.foodMenuToShow = foodMenuID //This can be anything that you get your food items.
}
}
You can't do what you are asking for. A segue identifier is what determines which view controller gets invoked by the segue. If you want to go to a different view controller, invoke a segue with a different identifier. By the time you get to prepareForSegue it's too late. The segue to a specific view controller is already in progress.
You should explain what it is you're trying to do and we can help you solve your problem rather than trying to fight the APIs and do something that's neither possible nor appropriate. (Your question is an example of an "XY problem".)
I have a registration view controller. In it I process the input provided by the user soon as he clicks on the register button. This button in the view is connected to an IBAction where I validate the input provided.
How is t possible to trigger the segue and pass the data within the IBAction (not override prepareforsegue) to the next view controller? If the validation fails it shouldn't attempt to execute segue but rather stay on same view to display validation errors.
Thanks for support. The question has been asked in different ways before surely but I wasn't able to find a good combine of segue in ibaction and passing data too.
You can create a segue from one view controller to another and can put a check in your button's IBAction, like this:
if (validationPasses)
{
self.performSegueWithIdentifier("segueIdentifier", sender: self)
}
And if you don't won't to override your prepareforsegue, you can pass the data using delegates.
However, by overriding prepareforsegue, you can pass data to your next view controller like this:
override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!) {
if (segue.identifier == "segueIdentifier") {
// pass data to next view controller
let vc : NextViewController = segue!.destinationViewController as NextViewController
vc.someVariable = someValue
}
}
Here NextViewController is your next viewcontroller, change its name to your next view controller and in this view controller define variable to whom you want to pass value, in this case it is someVariable