Swift - how to run multiply timers? - ios

Question

In my app I have a view, and I want this view to be dismissed everytime it is shown after 8 seconds. In order to do that I created a timer inside view creation function that hides view after firing. It works. But in some cases I want to present two copies of the view I want both be dismissed after time it was created +8 seconds. Issue is that timer works only once - it hides one copy of view, and second remains on screen
My code is
func presentShowStatusShort(text text:String) {
pointsShort = NSBundle.mainBundle().loadNibNamed("helperShowStatusShort", owner: self, options: nil).first! as! helperShowStatusShort
pointsShort?.frame.size.width = self.view.bounds.width
if pointsShortOnScreen {
pointsShort!.frame.origin.y = pointsShort!.frame.origin.y + 39
}
pointsShort?.text.text = "\(text.uppercaseString)"
pointsShort!.dismissButton.addTarget(self, action: "dismissShowStatusShort", forControlEvents: UIControlEvents.TouchUpInside)
var timer = NSTimer.scheduledTimerWithTimeInterval(8, target: self, selector: "dismissShowStatusShort", userInfo: nil, repeats: false)
pointsShortOnScreen = true
view.addSubview(pointsShort!)
}
func dismissShowStatusShort() {
pointsShortOnScreen = false
UIView.animateWithDuration(0.5, animations: {
self.pointsShort?.frame.origin.y = (self.pointsShort?.frame.origin.y)! - 64
}, completion: {
finished in
self.pointsShort?.removeFromSuperview()
})
}

Answer 1

From an OOP point of view you should create a class to help you with this. The class would own the timer and maintain a reference to the view. When the timer expires it calls a callback, passing itself as the parameter, so the controller can get the associated view and dismiss it.
All of the instances of this class would be stored in an array instance variable on the controller so you can add multiple and remove each one once it expires.