If I have week 7 in 2017 what week date is the Monday in that week in Google Sheets?
=DATE(B9,1,1)-WEEKDAY(DATE(B9,1,1),3)+7*(WEEKDAY(DATE(B9,1,1),3)>3)+7*(A9-1)
is the least complicated formula I know which works for week numbers in Sweden (i.e. Monday first day of week, ISO rules for what is week 1).
Short answer (A1==Week, B1==Year):
=DATE(B1;1;1)+((A1-1)*7)-WEEKDAY(DATE(B1;1;1);3)
Long answer:
DATE(<year>;1;1) // days since 1970 until the frist day of the year
plus
((<week number>-1)*7) // how many days into the year is this week
minus
WEEKDAY(DATE(<year>;1;1);3) // how many extra days from previous year in first week
PS:
This assumes monday as the first day of week you have to change the arguments for WEEKDAY to change it to sunday
Because of this definition (https://en.wikipedia.org/wiki/Week) the 4th of January must be used instead the 1st. The 4th of January is the first day which is always in the week 1.
=DATE(B1;1;4)+((A1-1)*7)-WEEKDAY(DATE(B1;1;4);3)
If you are using ISO weeks, the accepted answer doesn't account for weeks overlapping on 2 technical years like 2020-w53, which is from 28 Dec 2020 until 3 Jan 2021.
Therefore I'm using this formula instead:
=DATE(K2,1,1)-WEEKDAY(DATE(K2,1,1),2)+7*(WEEKDAY(DATE(K2,1,1),2)>3)+7*(L2-1) +1
Where K is the Year, and L is the Week number (split in 2 columns from yyyy-ww)
to have it in an arrayformula:
=ArrayFormula(if(K2:K="",, DATE(K2:K,1,1)-WEEKDAY(DATE(K2:K,1,1),2)+7*(WEEKDAY(DATE(K2:K,1,1),2)>3)+7*(L2:L-1) +1 ))
You can use =ArrayFormula(if(E2:E="",,split(E2:E,"-"))) to split yyyy-ww in two columns.
NOTE: This formula would return the Monday (Which is the first day of the week in international standard, ISO)
Worked this up for 2023. It will work through end of 2024 too .. that said the AND logic is flawed .. feel free to suggest something to make this better
=IFS(
AND(ISOWEEKNUM(A8)=52,YEAR(A8)<>YEAR(A7)),
DATE(YEAR(A8-1),1,1)-WEEKDAY(DATE(YEAR(A8-1),1,1),3)+7*(WEEKDAY(DATE(YEAR(A8-1),1,1),3)>3)+7*(ISOWEEKNUM(A8)-1),
DATE(YEAR(A8),1,1)-WEEKDAY(DATE(YEAR(A8),1,1),3)+7*(WEEKDAY(DATE(YEAR(A8),1,1),3)>3)+7*(ISOWEEKNUM(A8)-1)
)
Related
I want to count say how many Mondays we have from 2022-02-01 - 2022-03-01. I found smth like this:
=SUMPRODUCT(WEEKDAY(B4:C4)=2) - B4 and C4 are the dates
But it returns 0. I assume it only checks if specific date is the specific day. Any ideas how I can do this but for a date range? So how count how many Mondays there are in February
I also found this
=NETWORKDAYS.INTL(B4;C4;"1000000")
but this returns 25
You can take advantage of the NETWORKDAYS.INTL function by using the string method to make all the days as weekend except for Monday.
The String method states:
weekends can be specified using seven 0’s and 1’s, where the first number in the set represents Monday and the last number is for Sunday. A zero means that the day is a work day, a 1 means that the day is a weekend. For example, “0000011” would mean Saturday and Sunday are weekends.
In this case since you only want to know the Mondays, the string would be "0111111" and the function would look like:
=NETWORKDAYS.INTL(StartDate,EndDate,"0111111")
I think this is right. It's counting inclusively so you would get five Mondays starting on Monday 7th Feb 2022 and ended on Monday 7th March 2022 for example.
=floor((B2-(A2+7-weekday(A2,12)))/7)+1
where A2 and B2 contain the start date end end date.
Obvs nul points for me again but for the record this could be generalised if you put the day number in C2 (e.g. 1 if you want to find Sundays, 2 for Mondays):
=floor((B2-(A2+7-weekday(A2,10+C2)))/7)+1
When I use the formula below the results of the EOMONTH function
returns the start of the next month for any month with 30 days instead of the last day of the specified month. The month and years are correct, so I'm pretty sure it's EOMONTH when used in another function.
For example,the results in B3 should be "11/31/1965" but it returns "12/1/1965".
=DATE(YEAR(B2),MONTH(B2)+6,DAY(TEXT(EOMONTH(MONTH(B2)+6,0))))
I have tried subtracting a day, but it returns the end-of-month -1 for months with 31 days (30). So I have the same problem in the other case.
I have also used IFS() to account for months with 30 days, and it miscalculates the date the same way.
=IFS( MONTH(B2)+6 = 4,DATE(YEAR(B2),MONTH(B2)+6,DAY(EOMONTH(MONTH(B2)+6,0))-2) ,
MONTH(B2)+6 =
6,DATE(YEAR(B2),MONTH(B2)+6,DAY(EOMONTH(MONTH(B2)+6,0))-2) ,
MONTH(B2)+6 =
9,DATE(YEAR(B2),MONTH(B2)+6,DAY(EOMONTH(MONTH(B2)+6,0))-2) ,
MONTH(B2)+6 =
11,DATE(YEAR(B2),MONTH(B2)+6,DAY(EOMONTH(MONTH(B2)+6,0))-2) ,
TRUE ,DATE(YEAR(B2),MONTH(B2)+6,DAY(EOMONTH(MONTH(B2)+6,0)) ) )
The EOMONTH function by itself where I just pass in the date as a string works correctly (column F).
Any Idea on what I'm doing wrong?
Thanks in advance.
Yes, as #player0 has explained, you can't just add something to a month and feed it into eomonth. Try putting
=eomonth(month(B2)+6,0)
into B3 (formatted as a date).
You get
1/31/1900
Why? month(b2)+6 gives 11 (which is just a number). Dates in google sheets are represented as days since 12/31/1899. So 11 formatted as a date gives 1/11/1900. Applying eomonth to that gives the last day of January 1900, which is the 31st. Feeding that into your formula would give 11/31/65, but that date doesn't exist, so you get 12/1/65.
If you want to go forward 6 months and then get the last day of the month, you need
=eomonth(date(year(B2),month(B2)+6,1),0)
You can also use the Edate function, which does not roll over into the first day of the next month:
=eomonth(edate(B2,6),0)
EOMONTH does not understand MONTH. instead, it converts it into date. to use EOMONTH you need to supply it with valid date
=EOMONTH(B2, 0)
I have the year a car was purchased in column A. For example, 2015. I'm trying to calculate the age of the vehicle comparing the year provided in column A to TODAY() in an arrayformula, like this...
={"Vehicle Age";arrayformula(if(A2:A="",,(datedif(A2:A,today(),"Y"))))}
For some reason, it gives me the number 115 as the result for every cell where a year has been specified. Any idea why? I can't seem to find an answer on this anywhere on the internets.
Thanks for your help!
You are mixing apples and oranges here, so to speak.
Internally, Google Sheets sees all full dates as a number of days from an origin point of December 31, 1899. As such, the year 2015 on its own, in a comparison with a full date will be seen as two-thousand-fifteen days since December 31, 1899 (or July 7, 1905 — which was 115 some-odd years ago, as would be the case with any relatively recent year, because they'll all be interpreted in their raw form by Sheets as a cluster of days from late June to early July of 1905).
Instead, you want to compare the years only, which will mean extracting the year from TODAY(), since A2:A are already year-only numbers:
={"Vehicle Age";arrayformula(if(A2:A="",,year(TODAY())-A2:A))}
However, since any year's car models are actually released the year before, you may want to add a year to your formula:
={"Vehicle Age";arrayformula(if(A2:A="",,year((TODAY())-A2:A)+1))}
Of course, you could also have turned your A2:A years into real dates (e.g., January 1 of each year listed) and then used datedif as well:
={"Vehicle Age";arrayformula(if(A2:A="",,datedif(DATE(A2:A,1,1),today(),"Y")))}
... or with that extra year added ...
={"Vehicle Age";arrayformula(if(A2:A="",,datedif(DATE(A2:A,1,1),today(),"Y")+1))}
={"Vehicle Age";arrayformula(if(A2:A="",,datedif(DATE(A2:A,1,1),today(),"Y")))}
Not working
Looking for a formula (for google spreadsheets) that shows either the days past in the current month if we're not past the last day of the current month, or the total days in that month if that month is behind us.
So, if today's March 25th, the formula would output 25 ... if today's April 1st, though, the formula would output 31.
Based on your sample, this should work (assuming the date is in A1):
=if(day(A1)=1,A1-date(year(A1),month(A1)-1,1),A1-date(year(A1),month(A1),1)+1)
Delphi Xe, Win 7, System TimeZone UTC+4:0, The first day of week in system - Monday, Time is synchronised with time.windows.com
In a palette of standard components Delphi Win32 there is component MonthCalendar, at it property WeekNubers=true (display of numbers of weeks), date=now, the first day - Monday.
Shows on 19 number (today) - number of week 43.
I request number through dateutils.WeekOfTheYear(now) = returns 42.
Source (0.5 Mb) http://www.sendspace.com/file/yuz6ko
Judging by an initial code of component MonthCalendar - there like all it is true (even if not to expose the first day of week, it takes value from system parametres).
And in inquiry WeekOfTheYear it is told, that all is considered also standard ISO applied, but numbers do not coincide :(
In any way I will not understand, where one week disappears - if to look on a calendar, should be 43 and if to consider, that weeks 53 and the first concerns last year...
By the way WeekOfTheYear on 01.01.2011 too returns 52 though like should return 1...
Why distinctions and where it is correct?
Both results are correct, the difference is because the DateUtils.WeekOfTheYear function uses the ISO 8601 standard definition of a week. That is, a week is considered to start on a Monday and end on a Sunday.
Check this explanation about the Weeks Numbers in the ISO 8601 format.
If 1 January is on a Monday, Tuesday, Wednesday or Thursday, it is in
week 01. If 1 January is on a Friday, Saturday or Sunday, it is in
week 52 or 53 of the previous year (there is no week 00). 28 December
is always in the last week of its year.
Also the Embarcadero online help for the DateUtils.WeekOfTheYear function says
....if the first calendar day of the year is a Friday, Saturday, or
Sunday, then for the first three, two, or one days of the calendar
year, WeekOfTheYear returns the last week of the previous year.
Similarly, if the last calendar day of the year is a Monday, Tuesday,
or Wednesday, then for the last one, two, or three days of the
calendar year, WeekOfTheYear returns 1 (the first week of the next
calendar year).
So due which the 01-01-2011 was Saturday this week is considered the week number 52 of the previous year.
And that also explains why the week number returned for today (19-10-2011) is 42 instead of 43.
First of all, I could see no difference between the week numbers in the TMonthCalendar component and those returned by DateUtils.WeekOfTheYear(). (Monday is the first day of week on my system.) Both show 42 for the current week and 52 (not 53) for the week of 2011-01-01. (It's 53 for 2010-01-01, so maybe you just mixed that up.)
Now, as to why it's 52 or 53, but not 1, well, it's according to the definition of the first week by ISO:
First week is the week with the year's first Thursday in it.
So week number 1 in 2011 starts on 2011-01-03, and the previous one belongs to the previous ISO year.
The TMonthCalendar can treat the last week of the year as the first week of the next year, WeekOfTheYear function does not do it, hence the difference.
For example according to TMonthCalendar, 1 Jan 2012 belongs to both last week of 2011 and first week of 2012; 2 Jan 2012 is the first day of the second week of 2012.
According WeekOfTheYear function, 1 Jan 2012 belongs to the last week of 2011 only; 2 Jan 2012 is the first day of the first week of 2012.
Monday is the first day of the week for me.