I am new to Lua, and would like to understand the following syntax:
init_state_global = some_integer
rnn_state = {[0] = init_state_global}
My Pythonic interpretation would be that the first element has index 0 and that the value of the element is equal to the variable init_state_global.
However, when I do
print(rnn_state[0])
I get
>> nil
Can someone can help me interpret this:
rnn_state = {[0] = init_state_global}
In Lua, you do it before the expression set(=) and after the array name. Also, Lua uses 1-based index
init_state_global = some_integer
rnn_state = {}
rnn_state[1] = init_state_global;
Perhaps you forgot to declare a variable:
init_state_global = 5
rnn_state = {[0] = init_state_global}
print(rnn_state[0])
it turns out it is easier than I thought.
Even though lua starts indexing at 1, you can set an index ad hoc to zero.
So
rnn_state = {[0] = init_state_global}
means just that,
rnn_state[0] = init_state_global
However, I stated above that
print(rnn_state[0]) was equal to
>> nil
that is because I forgot to declare the variable (in my code, not in the initial thread)
init_state_global = some_integer
:(
So if you declare the variable correctly, the following statement
print(rnn_state[0])
will return
>> some_integer
if you previously declared
init_state_global = some_integer
Another thing (may not be obvious to those of us used to python lists) is that
rnn_state = {}
rnn_state[0] = 4
is the same as
rnn_state = {[0] = 4}
Related
I'm working on a game where a bunch of characters will be generated on the fly, based on some constraints defined either in the project or externally via mod files. I am using MoonSharp Lua (5.2) interpreter for interfacing with my C# code, and Lua tables to store the constraint presets. As an example:
require "Defaults"
AgePresets = {}
-- Single value
AgePresets.Newborn = 0
-- Simple ranges
AgePresets.Default = defaultAgeRange --referring to the Defaults require
AgePresets.Child = {1, 12}
AgePresets.Teenager = {13, 19}
AgePresets.YoungAdult = {20, 29}
AgePresets.Adult = {30, 40}
AgePresets.MiddleAge = {40, 60}
AgePresets.Senior = {61, 80}
AgePresets.Elder = {81, 99}
AgePresets.Methuselah = {100, 150}
AgePresets.Methuselah2 = {150, 200}
-- Weighted ranges // again referring to previously defined elements to keep things concise
AgePresets.Tween = {
{weight = 1, minmax = AgePresets.Teenager },
{weight = 1, minmax = AgePresets.YoungAdult }
}
This works fine, but from an end-user point of view, there's a lot of unnecessary typing involved. We are clearly working on AgePresets here but it is still mentioned as a prefix before every member name.
I could of course define AgePresets as an array, like AgePresets = { Child = {}, Teenager = {} } but the problem with that is then I cannot refer to previously defined elements in the array.
This doesn't work:
AgePresets = {
Child = {1,12},
RefToChild = Child, //attempt to index a nil value exception
Teen = {13,19}
}
What I ideally want to achieve is a clean, concise way for users to enter this data in, like in the first example but without having to put AgePresets. prefix before everything. How do I go about declaring a scope in a file such that all succeeding members defined in the file will be within that scope, while maintaining the ability to refer to other members defined previously in the scope?
AgePresets = setmetatable({}, {__index = _G})
do
local _ENV = AgePresets
Newborn = 0
Child = {1,12}
RefToChild = Child -- this ref is Ok
Teen = {13,19}
YoungAdult = {20,29}
Tween = {
{weight = 1, minmax = Teen },
{weight = 1, minmax = YoungAdult }
}
rnd = math.random(10) -- global functions are available here
end
setmetatable(AgePresets, nil)
You can mix the two styles: table constructor for fields that don't need to reference variables that aren't in scope yet, followed by assignment statements for the rest.
I would do that unless the order of the fields in the code significantly enhanced comprehension.
I have a string which consists of numbers:
str = "1234567892"
And I want to iterate individual characters in it and get indices of specific numbers (for example, "2"). As I've learned, I can use gmatch and create a special iterator to store the indices (because, as I know, I just can't get indices with gmatch):
local indices = {}
local counter = 0
for c in str:gmatch"." do
counter = counter + 1
if c == "2" then
table.insert(indices, counter)
end
end
But, I guess, this is not the most efficient decision. I also can convert string to table and iterate table, but it seems to be even more inefficient. So what is the best way to solve the task?
Simply loop over the string! You're overcomplicating it :)
local indices = {[0]={},{},{},{},{},{},{},{},{},{}} --Remove [0] = {}, if there's no chance of a 0 appearing in your string :)
local str = "26842170434179427"
local container
for i = 1,#str do
container = indices[str:sub(i, i)]
container[#container+1] = i
end
container = nil
To find all indices and also do not use regexp but just plain text search
local i = 0
while true do
i = string.find(str, '2', i+1, true)
if not i then break end
indices[#indices + 1] = i
end
Why isn't this working? I'm trying to put all my object tables in a single table and use a forloop to iterate through each of them and draw. It shows an error message saying: "}" expected near "=" at line 5
function love.load()
solidstatic = {
ground = {x = 0,y = 160,width = 1000,height = 1000},
box = {x = 80,y = 100,width = 15,height = 15}
}
end
function love.draw()
for i,obj in ipairs(solidstatic) do
love.graphics.rectangle("fill",obj[x],obj[y],obj[width],obj[height])
end
end
(edit) solved the error problem, I was running the wrong .lua file. But still, it doesn't draw anything on the screen
Two things.
Firstly, you must use pairs instead of ipairs to list keys that are not numbers.
for i, v in pairs(table) do
...
end
You must also index the variables as a string.
t = {
x = 1
}
t['x'] = 1
-- or
t.x = 1
This is because doing it without quotes would be indexing with the global variable x, which doesn't exist.
You need to use pairs instead of ipairs to iterate over elements in solidstatic as there are no array keys in that table.
How can I get variables that not declared yet?
Here are simple example:
a = b
b = 123
What I want from these 2 lines is a << 123. But obv it doesn't work.
I know the easy way to get the answer a = 123 is cut 1st line and paste it to lower than 2nd line.
But I'm in some problem. I need some function like 'WillDeclaredVar()' that I can use in like this:
a = WillDeclaredVar(b)
sheepCount = 123
b = sheepCount
print(a)
so I can get the answer '123'.
Or there are any built-in functions that will allows me to do similar thing?
===
I think the link given by timrau is not telling my case. the key point is how to get Variables 'that not declared yet'.
===
Adding actual Code:
triggerCount = 0 -- Counting number of 'Trigger' function
local Trigger = function (t)
triggerCount = triggerCount + 1
return Trigger (t)
end
-- following Triggers are same as while statement.
-- following Triggers doing: Add 1 MarineCount until get 64000 MarineCount
Trigger { -- Here the Trigger function. Now triggerCount = 1.
players = {P1}
actions = {
SetDeaths(P1, Add, 1, "Terran Marine")
},
flag = {preserved},
}
Portal(LoopStart);
-- function Portal(VariableName) returns VariableName = triggerCount. So LoopStart = 1.
Trigger { -- Now triggerCount = 2.
players = {P1}
actions = {
LinkList(LoopEnd, LoopStart);
-- function LinkList(From, To) changes 'From' Trigger's next pointer to the 'To' Trigger.
-- But now the problem happens. Because 'LoopEnd' is not declared yet.
},
flag = {preserved},
}
Trigger { -- Now triggerCount = 3.
players = {P1}
conditions = {
Deaths(P1, Exactly, 64000, "Terran Marine");
}
actions = {
_LinkList(LoopEnd);
-- Reset LoopEnd's next pointer(= LoopEscape) if MarineCount hits 64000
},
flag = {preserved},
}
Portal(LoopEnd); -- LoopEnd = 3.
Changing Order of Triggers will break the Trigger logic(while statement).
All i want is get easy to coding. To put in bluntly, I don't need to solve this problem(get undeclared var). I can imagine a few ways to avoid it. But if i using these ways then the coding work will be very complicated and the difficulty of coding will increases greatly. The difficulty made me stop coding in recent months.
How can I get variables that not declared yet?
Short of time travel, you can't.
Your example code doesn't explain the motivation for the question, because this:
a = WillDeclaredVar(b)
sheepCount = 123
b = sheepCount
print(a)
Can trivially be rearranged into this:
sheepCount = 123
b = sheepCount
a = WillDeclaredVar(b)
print(a)
It would be easier to answer your question if you showed the actual problem you're trying to solve (to avoid an XY problem).
However, as stated there are few things we can note.
First, you need to distinguish between declaring a variable and giving it a value. In Lua you can say:
local b
To declare b as a local variable, which presumably will make a slot for it in the stack frame and let you bind closures to it, before you give it a value. However, the line:
a = WillDeclaredVar(b)
Will pass WillDeclaredVar the value that b currently has, and there's no way for a to change retroactively as a result of b being assigned a new value. That's simply not going to happen, ever. Neither a nor WillDeclaredVar are even aware that b exists, they are receive the value it contains at the point of call.
You could however bind the variable b to a closure which will fetch b's current value when needed.
-- declare b before giving it a value, aka "forward reference"
local b
a = function() return b end
sheepCount = 123
b = sheepCount
print(a()) -- call a to get b's current value
Another way to do that would be to make b a global variable, which is really just a key into your environment table, so you could say:
a = WillDeclaredVar('b')
And have a be some object that can fetch the current value of __ENV['b'] when required.
However, neither of these will support this syntax:
print(a)
a needs to be a function, something that looks up the value of b when needed rather than simply holding a previously computed value. You could do it in this particular instance (i.e. a needs to be convertable to a string), by creating a proxy object that implements __tostring.
function WillDeclaredVar(variableName)
local proxy = { environment = _ENV or _G, variableName = variableName }
return setmetatable(proxy, {
__tostring = function(proxy)
return proxy.environment[proxy.variableName]
end
})
end
-- a will compute a value based on the current value of b when needed
a = WillDeclaredVar('b')
sheepCount = 123
b = sheepCount
print(a)
Output:
123
To make var1 be a reference for var2 write var1 = ReferenceF or var2 (please note a space inside "ReferenceFor"!)
do
local values, references, reference_flag = {}, {}
setmetatable(_G, {
__index = function (_, name)
if name == 'ReferenceF' then
reference_flag = true
elseif reference_flag then
reference_flag = false
return {[references] = name}
elseif references[name] then
return _G[references[name]]
else
return values[name]
end
end,
__newindex = function (_, name, val)
if type(val) == 'table' and val[references] then
references[name] = val[references]
else
values[name] = val
end
end
})
end
a = ReferenceF or b -- a is Reference For b
b = ReferenceF or c -- b is Reference For c
sheepCount = 123
c = sheepCount
print(a, b, c) --> 123 123 123
I am starting to learn Lua from Programming in Lua (2nd edition)
I didn't understand the following in the book. Its very vaguely explained.
a.) w={x=0,y=0,label="console"}
b.) x={math.sin(0),math.sin(1),math.sin(2)}
c.) w[1]="another field"
d.) x.f=w
e.) print (w["x"])
f.) print (w[1])
g.) print x.f[1]
When I do print(w[1]) after a.), why doesn't it print x=0
What does c.) do?
What is the difference between e.) and print (w.x)?
What is the role of b.) and g.)?
You have to realize that this:
t = {3, 4, "eggplant"}
is the same as this:
t = {}
t[1] = 3
t[2] = 4
t[3] = "eggplant"
And that this:
t = {x = 0, y = 2}
is the same as this:
t = {}
t["x"] = 0
t["y"] = 2
Or this:
t = {}
t.x = 0
t.y = 2
In Lua, tables are not just lists, they are associative arrays.
When you print w[1], then what really matters is line c.) In fact, w[1] is not defined at all until line c.).
There is no difference between e.) and print (w.x).
b.) creates a new table named x which is separate from w.
d.) places a reference to w inside of x. (NOTE: It does not actually make a copy of w, just a reference. If you've ever worked with pointers, it's similar.)
g.) Can be broken up in two parts. First we get x.f which is just another way to refer to w because of line d.). Then we look up the first element of that table, which is "another field" because of line c.)
There's another way of creating keys in in-line table declarations.
x = {["1st key has spaces!"] = 1}
The advantage here is that you can have keys with spaces and any extended ASCII character.
In fact, a key can be literally anything, even an instanced object.
function Example()
--example function
end
x = {[Example] = "A function."}
Any variable or value or data can go into the square brackets to work as a key. The same goes with the value.
Practically, this can replace features like the in keyword in python, as you can index the table by values to check if they are there.
Getting a value at an undefined part of the table will not cause an error. It will just give you nil. The same goes for using undefined variables.
local w = {
--[1] = "another field"; -- will be set this value
--["1"] = nil; -- not save to this place, different with some other language
x = 0;
y = 0;
label = "console";
}
local x = {
math.sin(0);
math.sin(1);
math.sin(2);
}
w[1] = "another field" --
x.f = w
print (w["x"])
-- because x.f = w
-- x.f and w point one talbe address
-- so value of (x.f)[1] and w[1] and x.f[1] is equal
print (w[1])
print ((x.f)[1])
print (x.f[1])
-- print (x.f)[1] this not follows lua syntax
-- only a function's has one param and type of is a string
-- you can use print "xxxx"
-- so you print x.f[1] will occuur error
-- in table you can use any lua internal type 's value to be a key
-- just like
local t_key = {v=123}
local f_key = function () print("f123") end
local t = {}
t[t_key] = 1
t[f_key] = 2
-- then t' key actualy like use t_key/f_key 's handle
-- when you user t[{}] = 123,
-- value 123 related to this no name table {} 's handle