Roblox script running multiple times? - lua

Question

I need a bit of help. Basically I have this code:
local plyIsEntered = false
function onTouched(hit)
plyIsEntered = true
if not plyIsEntered then
end
if plyIsEntered then
local humanoid = hit.Parent:FindFirstChild("Humanoid")
local ply = humanoid.Parent
if humanoid ~= nil then
print("Hit")
local playerName = hit.Parent.Name
print(playerName)
local laserEmitter = game.Workspace["Enterance PC"]:FindFirstChild("laserEmitter")
local scanLaser = Instance.new("Part", game.Workspace)
scanLaser.Position = laserEmitter.Position
scanLaser.Name = "ScanLaser"
scanLaser.Size = Vector3.new(1,1,1)
local scanLaserMesh = Instance.new("SpecialMesh", game.Workspace.ScanLaser)
scanLaserMesh.Name = "Cone mesh"
scanLaserMesh.MeshType = ""
plyIsEntered = false
end
end
end
script.Parent.Touched:connect(onTouched)
Now I'm checking if the player touches a box, it has no collisions and is invisible; when they do I want to create a laser that will scan them and open a door. The problem I'm having is when I walk into the trigger box it creates 8 or 9 blocks. One of those blocks is the block I'm applying a mesh too.
What I need to do is make sure it's only running once and not creating more than 1 brick. Hopefully someone can help me!

Answer 1

I believe to fix this you'll need to add a debounce.
You see, the touched event of a Part actually fires many times, so your code will execute multiple times if it is inside of the event.
To fix this, we use a debounce, which means your code won't execute if your part is touched too much in the same time frame. Here is an example:
local debounce = false
part.Touched:connect(function()
if debounce == false then
debounce = true
--Your code goes here.
wait(1)--Wait one second until you'll be able to execute the code again.
debounce = false
end
end)
To read more on debounces: http://wiki.roblox.com/index.php?title=Debounce