how to get nsDictionary element by using for-in - ios

Question

NSDictionary *myDict = #{#"one":#"1",#"two":#"2"};
for (NSDictionary* tmp in myDict) {
NSLog(#"%#",tmp);
}
resut:
my tmpis NSString
I want to get a dictionary with key= one , value = 1

Answer 1

for in for NSDictionary will iterate the keys.
for (NSString * key in myDict) {
NSLog(#"%#",key);
NSString * value = [myDict objectForKey:key];
}
If you want to get a dictionary. You have to create a dictionary from these values
for (NSString * key in myDict) {
NSLog(#"%#",key);
NSString * value = [myDict objectForKey:key];
NSDictionary * dict = #{key:value};
}
Or you should init like this:
NSArray *arrDict = #[{#{"one":#"1"},#{#"two":#"2"}];
for (NSDictionary* tmp in arrDict) {
NSLog(#"%#",tmp);
}

Answer 2

You can get all keys from your dic then add the key and value to your new dic like this:
NSDictionary *myDict = #{#"one":#"1",#"two":#"2"};
NSArray *keys = [myDict allKeys];
for (NSString *key in keys) {
NSDictionary *yourDic = #{key: [myDict valueForKey:key]};
NSLog(#"%#", yourDic);
}

Answer 3

You didn't create it that way. If you wanted to have a NSDictionary inside another NSDictionary you should write something like this :
NSDictionary *myDict = #{
#"firstDict" : #{
#"one":#"1"
},
#"secondDict": #{
#"two":#"2"
}
};
Above code will create a NSDictionary with two dictionaries at keys #firstDict and #secondDict.
Also, bear in mind, that because dictionaries are key-value pairs, using a for-in loop, actually loops through the keys in that dictionary. So your code is equivalent to:
for(NSString *key in dict.allKeys) { ... }

Answer 4

I got the solution
NSDictionary *myDict = #{#"one":#"1",#"two":#"2"};
NSMutableArray *arrayObject = [[NSMutableArray alloc]init];
NSMutableArray *arrayKey = [[NSMutableArray alloc]init];
NSMutableArray *arrayObjectKey = [[NSMutableArray alloc]init];
NSMutableDictionary *dict = [[NSMutableDictionary alloc]init];
for (NSString *stringValue in myDict.allValues)
{
[arrayObject addObject:stringValue];
}
for (NSString *stringKey in myDict.allKeys)
{
[arrayKey addObject:stringKey];
}
for(int i = 0;i<[arrayKey count];i++)
{
dict = [[NSMutableDictionary alloc]initWithObjectsAndKeys:[NSString stringWithFormat:#"%#",[arrayKey objectAtIndex:i]],#"key",nil];
[dict setObject:[NSString stringWithFormat:#"%#",[arrayObject objectAtIndex:i]] forKey:#"value"];
[arrayObjectKey addObject:dict];
}
NSLog(#"The arrayObjectKey is - %#",arrayObjectKey);
The Output is
The arrayObjectKey is -
(
{
key = one;
value = 1;
},
{
key = two;
value = 2;
}
)

Answer 5

Create the dictionary:
NSDictionary *myDict = [NSDictionary dictionaryWithObjectsAndKeys:#"1",#"One",#"2","Two",nil];
Get a value out using:(this example tmp will be 1)
NSString *tmp = [myDict objectForKey:#"One"];
Display the output in console:
NSLog(#"%#",tmp);
To display the whole NSDictionary
NSLog (#"contents of myDict: %#",myDict);

Answer 6

What you are doing is creating a dictionary with key-value pairs. I think what you want to do is have an array with dictionaries.
NSArray *myArray = #[#{#"one":#"1"}, #{#"two":#"2"}];
for (NSDictionary* tmp in myArray) {
NSLog(#"%#",tmp);
}
However I don't see a point in doing this. What you could do is:
NSDictionary *myDict = #{#"one":#"1",#"two":#"2"};
for (NSString* key in [myDict allKeys]) {
NSLog(#"%# = %#", key, myDict[key]);
}