Is it possible to do a string manipulation of data in a Google Sheet query?
I want to do something like the following:
=QUERY(someRange!A:Z, SELECT A, SUBSTITUTE(B, "OCH", ""))
The idea being that all rows' column B is 'OCHXXXXXXX' where X is a digit. I would like to get rid of the chars.
On a side note... Is this possible in MySQL? How?
This formula might work for you:
=QUERY({Sheet1!A:A,ARRAYFORMULA(SUBSTITUTE(Sheet1!B:B,"OCH","")),Sheet1!C:Z})
I would suggest:
=arrayformula(REGEXREPLACE(somerange!B:B, "OCH", ""))
Related
I tried different approaches to accomplish what I am looking for and it might not be possible with how I have formated my data but I will try to explain it to see if there is a way.
My origin of data looks like the following:
Case
HELP
100
HELP-01
HELP-02
101
HELP-01
102
103
HELP-03
What I want is to be able to extract the HELP-* into another column without duplicate values and one after another. The result I am looking for is from the above table been able to have this:
HELP
HELP-01
HELP-02
HELP-03
Is there a way to do this in Google Sheets?
Thank you,
Alternatively you can use:
=UNIQUE(QUERY(FLATTEN(B2:C),"where Col1 like 'HELP-%'"))
The QUERY() will now only return those values that start with 'HELP-' in the case you might have other string-values.
A littel more specific even, could be to use:
=UNIQUE(QUERY(FLATTEN(B2:C),"where Col1 matches 'HELP-\d+'"))
Where 'matches' will now use the regular expression to only return values that start with 'HELP-' but end with any 1+ digits.
Try this in Google Sheets
=sort(array_constrain(unique(flatten(B2:C)),counta(B2:C),1))
I am trying to use substitute function inside a query function but not able to find the correct syntax to do that. My use case is as follows.
I have two columns Name and Salary. Values in these columns have comas ',' in them. I want to import these two columns to a new spreadsheet but replace comas in "Salary" column with empty string and retain comas in "Name" column. I also want to apply value function to "Salary" column after removing comas to do number formatting.
I tried with the following code but it is replacing comas in both the columns. I want a code which can apply the substitute function only to a subset of columns.
Code:
=arrayformula(SUBSTITUTE(QUERY(IMPORTRANGE(Address,"Sheet1!A2:B5"),"Select *"),",",""))
Result:
Converted v/s Expected Result
Note :
I have almost 10 columns to import and comas should be removed from 3 of them.
Based on your suggestions, I was able to achieve the objective by treating columns separately. Below is the code.
=QUERY({IMPORTRANGE(Address,"Sheet1!A3:A5"),arrayformula(VALUE(SUBSTITUTE(IMPORTRANGE(Address,"Sheet1!B3:B5"),",","")))},"Select * where Col2 is not null")
Basically, two IMPORTRANGE functions side by side for each column.
The same query on the actual data with 10 columns will look like this.
=QUERY({IMPORTRANGE(Address,"Sheet1!A3:C"),arrayformula(VALUE(SUBSTITUTE(IMPORTRANGE(Address,"Sheet1!D3:H"),",",""))),IMPORTRANGE(Address,"Sheet1!I3:J")},"Select * where Col2 is not null")
I used 3 IMPORTRANGE functions so that I can format the columns D to H by removing comas and changing them to number.
My suggestion is to use 2 formulas and more space in your sheets.
Formula #1: get the data and replace commas:
=arrayformula(SUBSTITUTE(IMPORTRANGE(Address,"Sheet1!A2:B5"),",",""))
Formula #2: to convert text into numbers:
=arrayformula (range_of_text_to_convert * 1)
Notes:
using 2 formulas will need extra space, but will speed up formulas (importrange is slow)
the second formula uses math operation (*1) which is the same as value formula.
Try this. I treats the columns separately.
=arrayformula(QUERY({Sheet1!A2:A5,SUBSTITUTE(Sheet1!B2:B5,",","")},"Select *"))
Thanks to Ed Nelson, I was able to figure out this:
=arrayformula(QUERY({'Accepted Connections'!A:R,SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE('Accepted Connections'!A:R,"AIF®",""),"APA",""),"APMA®",""),"ASA",""),"C(k)P®",""),"C(k)PS",""),"CAIA",""),"CBA",""),"CBI",""),"CCIM",""),"","")},"Select *"))
That removed all the text I didn't need in specific columns.
I have a google sheet with a column (A) of urls.
Xttps://tXco/008wnbebbw
Xttps://tXco/00lR1FNKBo
Xttps://tXco/00lR1Fw9cO
Xttps://tXco/00UwZwgh2h
Xttps://tXco/00UwZwxSqR
Xttps://tXco/00UwZwxSqR
Xttps://tXco/044TcIFl72
In column B I need to find all unique urls up to the 18th character. For instance column B should show:
Xttps://tXco/008wnbebbw
Xttps://tXco/00lR1FNKBo
Xttps://tXco/00UwZwgh2h
Xttps://tXco/044TcIFl72
I have this formula which I was trying to adapt for it (not sure if it helps at all). I was trying to adapt this to use with =UNIQUE( ?
=SUMPRODUCT(--(LEFT($A$1:$A$15,18)=LEFT(A1,18)))>1
If it helps to take a look at the sheet, here it is: https://docs.google.com/spreadsheets/d/1tG7TpHNvNY86PRiePsKyKfxnuEZah6T7ZDL7dXOIcEA/edit?usp=sharing
Thanks in advance!
You may try this formula:
=ArrayFormula(vlookup(
UNIQUE(FILTER(LEFT(A2:A,17),A2:A<>"")),
FILTER({LEFT(A2:A,17),A2:A},A2:A<>""),
2,0))
How it works
it will first find unique left N chars:
UNIQUE(FILTER(LEFT(A2:A,17),A2:A<>"")
then get left N chars and original strings:
FILTER({LEFT(A2:A,17),A2:A},A2:A<>"")
and then use vlookup to get top first entry for uniques.
Try this instead without the extra column. Put it in B1:
=unique(arrayformula(if(left(A1:A,18)=left(A1:A,18),A1:A,"")))
Try this: =unique(arrayformula(left(A1:A,18)))
In my Google spreadsheet, i'm using the query function to get data from one sheet onto another. The query looks something like this:
=QUERY('mySheet'!$A$1:100,"select F where "&C$3&"='myValue'")
This works fine until cell C3 has value "BY" (because the word "by" has significance in the query language). I've tried using single quotes, but then the query uses header "BY" instead of column BY and it returns an empty result.
Any ideas on how to work around this?
Put it in backticks.
=sum(QUERY(select `BY` where `BY` is not null limit 7))
This will sum the first 7 values in column BY.
(This was fun to debug. The formula worked in every other column...)
"BY" is a special word. It is present in clause group by
You may use this:
=QUERY({'mySheet'!$A$1:100},"select Col5 where Col"&C$3&"='myValue'", 0)
and paste the column number into C$3
see more info here
BTW you may use function column() to know BY is column 77 or find the right number by header name: =match("column name", 'mySheet'!1:1, 0)
I have a data set that looks like this: starting on A1 with "1"
1 a
2 b
3 c
4 d
Column A is an arrayformula =arrayformula(row(b1:b))
Column B is manual input
i want to query the database and finding the row of the item by match column B so i have code as such
=query("A1:B","select A where B like '%c%')
this should give me "3"
My question:
is there a way to pull the 1-4 numbers into the query line? with something like array formula row(b1:b). I don't want to waste an extra column on column A
so basically I want just the manual input and when i query it gives me the row number.
No script code please.
I've tried a few things and it didn't work.
Looking for a solutions that starts with
=query()
You can also use a formula to pull in more than one row in the dataset which matches the condition, if this is important to you:
=arrayformula(filter(row(B:B); B:B="c"))
And you can have wildcard type operators, under certain circumstances (you are going to match text or items that can look like text (so numbers can be treated as text - but boolean will need more steps); that the dataset is not huge), using regular expressions. e.g.
=arrayformula(filter(row(B:B); regexmatch(B:B, "(c|d)")))
You could also use standard spreadsheet wildcard operators, e.g.
=arrayformula(filter(row(B:B); countif(B:B, "*c*")))
Explanation: In this case, the filter will be true when countif is greater than zero, i.e. when it sees something with a letter c in it, since spreadsheets see a value greater than zero as a boolean true and so, for that row where there is a countif match, there will be a a filter match, and so it will display that row (indeed, it is a similar situation with the regexmatch creating a true when there is a match of either c or d, in the case above).
Personally, I wanted to learn regex a bit, so I would go towards the regexmatch option. But that is your choice.
You can also, of course, create the match outside of the cell. This makes it easy to create a list of matches that you want to satisfy elsewhere on the sheet. So you could have a column of words or parts of words, from Z2 downwards, and then join them together in cell Z1 for example like this
="("&join("|",filter(Z2:Z50,len(Z2:Z50)))&")"
Then your filter function would look like this:
=arrayformula(filter(row(B:B), regexmatch(B:B, Z1)))
If you want to use like operator in the query function, you can try something like this:
=arrayformula(query(if({1,0}, B:B,row(B:B)),"select Col2 where Col1 like '%c%' "))
You can also use the regular expressions in the query function, for example:
=arrayformula(query(if({1,0}, B:B,row(B:B)),"select Col2 where Col1 matches '(.*c.*|.*d.*)' "))
I'm not entirely clear on the question, but as I understand it, you want to be able to enter a formula, and have it return the row number of the matched item in a range? I'm not sure where array formulas come in.
If I've understood your question correctly, this should do the trick:
=MATCH("C",B1:B,0)
In your example, this returns 3.
Please forgive me if I've misunderstood your question.
Note: If there are multiple matches, this will return the row number for the first instance of your search.
=QUERY({A1:A,ARRAYFORMULA(ROW(A1:A))},"SELECT Col2 WHERE Col1 LIKE '%c%'")