How to get contact (firstname, lastname, contactid, number) - ios

Question

I have used AddessBook library (for ios8) to get all contact (firstname, lastname, contactId, all phone number). it worked perfect on simulitor.
my code:
private func getContacts()->[Person] {
var peapleOfContact: [Person] = []
if !self.determineStatus() {
return peapleOfContact
}
if let people = ABAddressBookCopyArrayOfAllPeople(self.adbk)?.takeRetainedValue() as? NSArray {
for person in people{
let contactID = ABRecordGetRecordID(person)
let firstName = ABRecordCopyValue(person, kABPersonFirstNameProperty).takeRetainedValue() as! String
let lastName = ABRecordCopyValue(person, kABPersonLastNameProperty).takeRetainedValue() as! String
let personOfContact = Person(id: String(contactID), firstName: firstName, lastName: lastName)
let numbers:ABMultiValue = ABRecordCopyValue(person, kABPersonPhoneProperty).takeRetainedValue()
for ix in 0 ..< ABMultiValueGetCount(numbers) {
let type = ABMultiValueCopyLabelAtIndex(numbers,ix).takeRetainedValue() as String
let number = ABMultiValueCopyValueAtIndex(numbers,ix).takeRetainedValue() as! String
let cleaned = self.removeSpecialCharsFromString(type)
let shortNumber = self.makeSpecialShortNumberFromString(number)
let phone = Number(number: number, short: shortNumber, type: cleaned)
personOfContact.addPhoneNumber(phone)
}
peapleOfContact.append(personOfContact)
}
}
return peapleOfContact
}
when xcode 7.1.1 is updated and used ios9, this library not work so used ContactUI Framework.
my code:
private func getContact(){
let keysToFetch = [CNContactFormatter.descriptorForRequiredKeysForStyle(.FullName),
CNContactImageDataKey,
CNContactPhoneNumbersKey]
let fetchRequest = CNContactFetchRequest(keysToFetch: keysToFetch)
do {
try store.enumerateContactsWithFetchRequest(fetchRequest, usingBlock: { (let contact, let stop) -> Void in
self.contacts.append(contact)
})
}
catch let error as NSError {
print(error.localizedDescription)
}
}
and used like this:
self.getContact()
for contact in self.contacts{
print("Full name: \(CNContactFormatter.stringFromContact(contact, style: .FullName))")
print("Give name: \(contact.givenName)")
print("fimily name: \(contact.familyName)")
print("Idnetifier name: \(contact.identifier)")
for phoneNo in contact.phoneNumbers {
if phoneNo.label == CNLabelPhoneNumberMobile {
let number = (phoneNo.value as! CNPhoneNumber).stringValue
print("Phone Number: \(number)")
}
}
}
but not found contactId. How to get contactId ? How to use ContactUI Framework ?
advise me. thanks

Answer 1

In iOS 9.*, there is a new framework called 'Contacts'
Usage:
import Contacts
var validContacts: [CNContact] = []
let contactStore = CNContactStore()
// Request for contact access
contactStore.requestAccessForEntityType(.Contacts) { (granted, e) -> Void in
if granted {
do {
// Specify the key fields that you want to be fetched.
// Note: if you didn't specify your specific field request. your app will crash
let fetchRequest = CNContactFetchRequest(keysToFetch: [CNContactGivenNameKey, CNContactMiddleNameKey, CNContactFamilyNameKey, CNContactEmailAddressesKey, CNContactPhoneNumbersKey, CNContactImageDataKey, CNContactThumbnailImageDataKey])
try contactStore.enumerateContactsWithFetchRequest(fetchRequest, usingBlock: { (contact, error) -> Void in
// Lets filter (optional)
if !contact.emailAddresses.isEmpty || !contact.phoneNumbers.isEmpty {
validContacts.append(contact)
}
})
print(validContacts)
}catch let e as NSError {
print(e)
}
}
}
Parsing:
// Loop through contatcs
for contact in validContacts {
var phoneNumbers: [String] = []
for phoneNumber in contact.phoneNumbers {
let value = phoneNumber.value as! CNPhoneNumber
phoneNumbers.append(value.stringValue)
}
var emailAddresses: [String] = []
for emailAddress in contact.emailAddresses {
let value = emailAddress.value as! String
emailAddresses.append(value)
}
if let imageData = contact.imageData {
let image = UIImage(data: imageData)
print("image: \(image)")
}
// Lets log
print("givenName: \(contact.givenName), middleName: \(contact.middleName), familyName: \(contact.familyName), phoneNumbers: \(phoneNumbers), emailAddresses: \(emailAddresses)\n")
}
I have a sample project which implement this.
GitHub

Answer 2

This code sample will help you :
public static func refreshContacts(){
let status = ABAddressBookGetAuthorizationStatus()
if status == .Denied || status == .Restricted {
// user previously denied, to tell them to fix that in settings
return
}
// open it
var error: Unmanaged<CFError>?
let addressBook: ABAddressBook? = ABAddressBookCreateWithOptions(nil, &error)?.takeRetainedValue()
if addressBook == nil {
println(error?.takeRetainedValue())
return
}
// request permission to use it
ABAddressBookRequestAccessWithCompletion(addressBook) {
granted, error in
if !granted {
// warn the user that because they just denied permission, this functionality won't work
// also let them know that they have to fix this in settings
return
}
if let people = ABAddressBookCopyArrayOfAllPeople(addressBook)?.takeRetainedValue() as? NSArray {
for person in people{
if let name = ABRecordCopyValue(person, kABPersonFirstNameProperty).takeRetainedValue() as? String {
println(name)//persons name
}
let numbers:ABMultiValue = ABRecordCopyValue(
person, kABPersonPhoneProperty).takeRetainedValue()
for ix in 0 ..< ABMultiValueGetCount(numbers) {
let label = ABMultiValueCopyLabelAtIndex(numbers,ix).takeRetainedValue() as String
let value = ABMultiValueCopyValueAtIndex(numbers,ix).takeRetainedValue() as! String
println("Phonenumber \(label) is \(value))
}
}
}
}
}

Answer 3

Please try this working for me. sort according to givenname(firstname). import Contacts first
let contactStore = CNContactStore()
var results: [CNContact] = []
do {
let request:CNContactFetchRequest
request = CNContactFetchRequest(keysToFetch: [CNContactGivenNameKey, CNContactFamilyNameKey, CNContactMiddleNameKey, CNContactEmailAddressesKey,CNContactPhoneNumbersKey])
request.sortOrder = CNContactSortOrder.GivenName
try contactStore.enumerateContactsWithFetchRequest(request) {
(contact, cursor) -> Void in
results.append(contact)
}
}
catch{
print("Handle the error please")
}
print(results)