Is there an option in neo4j to write a select query with where clause, that ignores non-latin characters ?
MATCH (places:Place)
WHERE (places.name =~ '.*(?ui)Fabergé.*')
RETURN places
I have place with Fabergé name in graph and i want to find it when user type Fabergé or Faberge without this special character.
I'm not aware of an easy way to do this directly with a regex match in Cypher.
One possible workaround is to store the string in question in a normalized form in a second property e.g. place.name_normalized and then compare it with the normalized search string. Of course normalization needs to be done on client side, see another SO question on how to achive this: Remove diacritical marks (ń ǹ ň ñ ṅ ņ ṇ ṋ ṉ ̈ ɲ ƞ ᶇ ɳ ȵ) from Unicode chars
Related
I have a field in the database which contains strings that look like: 58XBF2022L1001390 I need to be able to query results which match the last letter(in this case 'L'), and match or resemble the last four digits.
The regular expression I've been using to find records which match the structure is: \d{2}[A-Z]{3}\d{4}[A-Z]\d{7}, So far I've tried using a scope to refine the results, but I'm not getting any results. Here's my scope
def self.filter_by_shortcode(input)
q = input
starting = q.slice!(0)
ending = q
where("field ~* ?", "\d{2}[A-Z]{3}\d{4}/[#{starting}]/\d{3}[#{ending}]\g")
end
Here are some more example strings, and the substring that we would be looking for. Not every string stored in this database field matches this format, so we would need to be able to first match the string using the regex provided, then search by substring.
36GOD8837G6154231
G4231
13WLF8997V2119371
V9371
78FCY5027V4561374
V1374
06RNW7194P2075353
P5353
57RQN0368Y9090704
Y0704
edit: added some more examples as well as substrings that we would need to search by.
I do not know Rails, but the SQL for what you want is relative simple. Since your string if fixed format, once that format is validated, simple concatenation of sub-strings gives your desired result.
with base(target, goal) as
( values ('36GOD8837G6154231', 'G4231')
, ('13WLF8997V2119371', 'V9371')
, ('78FCY5027V4561374', 'V1374')
, ('06RNW7194P2075353', 'P5353')
, ('57RQN0368Y9090704', 'Y0704')
)
select substr(target,10,1) || substr(target,14,4) target, goal
from base
where target ~ '^\d{2}[A-Z]{3}\d{4}[A-Z]\d{7}$';
I am using:
c.customerName =~ '(?i).*$q.*'
in order to find insensitive case any kind of customername and this is working absolutely fine for all standard character. In German unfortunately there are special chars e.g. like Ä,Ö,Ü. In this cases the cypher statement is case sensitive, e.g. if we have two customer names like Ötest and ötest it will find only one of them depending if you type a lower or an upper Ö.
Anyone has a hint what I can do to expand the insensitive case search also on such special chars?
EDIT: The problem exists also when you have a name including e.g. a '&' - you'll find e.g. the company D&A Construction when you type 'D&' - the moment you add a thrid character 'D&A' the search fails and no result is shown. Any idea?
You need to add a 'u' in your regex to transform it in a case-insensitive unicode regex. Like this:
c.customerName =~ '(?ui).*$q.*'
Works here:
From this StackOverflow question.
I don't know the name for this kind of search, but I see that it's getting pretty common.
Let's say I have records with the following file names:
'order_spec.rb', 'order.sass', 'orders_controller_spec.rb'
If I search with the following string 'oc' I would like the result to return 'orders_controller_spec.rb' due to match the o in orders and the c in controller.
If the string is 'os' then I'd like all 3 to match, 'order_spec.rb', 'order.sass', 'orders_controller_spec.rb'.
If the string is 'oco' then I'd like 'orders_controller_spec.rb'
What is the name for this kind of search and how would I go about getting this done in Postgresql?
This is a called a subsequence search. One simple way to do it in Postgres is to use the LIKE operator (or several of the other options in those docs) and fill the spaces between your letters with a wildcard, which for LIKE is %. To match anything with an o followed by an s in the words column, that would look like this:
SELECT * FROM table WHERE words LIKE '%o%s%';
This is a relatively expensive search, but you can improve performance with a varchar_pattern_ops or text_pattern_ops index to support faster pattern matching.
CREATE INDEX pattern_index ON table (words varchar_pattern_ops);
I have a Rails app with a table: "clients". the clients table has a field: phone. phone data type is string. I'm using postgresql. I would like to write a query which selects all clients which have a phone value containing more than 10 digits. phone does not have a specific format:
+1 781-658-2687
+1 (207) 846-3332
2067891111
(345)222-777
123.234.3443
etc.
I've been trying variations of the following:
Client.where("LENGTH(REGEXP_REPLACE(phone,'[^\d]', '')) > 10")
Any help would be great.
You almost have it but you're missing the 'g' option to regexp_replace, from the fine manual:
The regexp_replace function provides substitution of new text for substrings that match POSIX regular expression patterns. [...] The flags parameter is an optional text string containing zero or more single-letter flags that change the function's behavior. Flag i specifies case-insensitive matching, while flag g specifies replacement of each matching substring rather than only the first one.
So regexp_replace(string, pattern, replacement) behaves like Ruby's String#sub whereas regexp_replace(string, pattern, replacement, 'g') behaves like Ruby's String#gsub.
You'll also need to get a \d through your double-quoted Ruby string all the way down to PostgreSQL so you'll need to say \\d in your Ruby. Things tend to get messy when everyone wants to use the same escape character.
This should do what you want:
Client.where("LENGTH(REGEXP_REPLACE(phone, '[^\\d]', '', 'g')) > 10")
# --------------------------------------------^^---------^^^
Try this:
phone_number.gsub(/[^\d]/, '').length
I am creating search query for filter my data it not filter as per my expectation
my query string is :Reinvestment Act of 2009 - RD&D
its not return me any result
after replace string : Reinvestment Act of 2009 / RD&D
its working fine.
is there any limitation at solr search if yes then which special char are not allowed.
what alternative to search using special character using solr
Solr query parsers treat certain characters specially. For example, - means exclude the next term in the Solr Query Parser syntax. You can escape these special characters with a backslash, or enclose them in quotes.
You can find more information in the Solr query documentation.