Calculate duration between date ios in Years, months and date format - ios

Im new at swift programming and i havent been able successfully find code to find difference between two dates in terms of years , months and days.
I tried the following code but it didnt work
let form = NSDateComponentsFormatter()
form.maximumUnitCount = 2
form.unitsStyle = .Full
let s = form.stringFromTimeInterval( date2.timeIntervalSinceReferenceDate - date1.timeIntervalSinceReferenceDate)
Input
Date1 = "12/March/2015"
Date2 = "1/June/2015"
Output : x years y months z days
Please advice

We can use this function in Swift 2.0
func yearsBetweenDate(startDate: NSDate, endDate: NSDate) -> Int
{
let calendar = NSCalendar.currentCalendar()
let components = calendar.components([.Year], fromDate: startDate, toDate: endDate, options: [])
return components.year
}
You can return anything like I returned year in this function. This will return number of years between the two dates.
You can just write months,days etc in order to find the difference between the two dates in months and days respectively.
Edit
Swift 3.0 and Above
func yearsBetweenDate(startDate: Date, endDate: Date) -> Int {
let calendar = Calendar.current
let components = calendar.dateComponents([.year], from: startDate, to: endDate)
return components.year!
}

If you need the difference (in years, months, days) numerically then
compute NSDateComponents as in Swift days between two NSDates or Rajan's answer.
If you need the difference as a (localized) string to present it to the user,
then use NSDateComponentsFormatter like this
let form = NSDateComponentsFormatter()
form.maximumUnitCount = 2
form.unitsStyle = .Full
form.allowedUnits = [.Year, .Month, .Day]
let s = form.stringFromDate(date1, toDate: date2)
As already mentioned in the comments, computing the difference
from the pure time interval between the dates cannot give correct
results because most information about the dates is lost.
Update for Swift 3:
let form = DateComponentsFormatter()
form.maximumUnitCount = 2
form.unitsStyle = .full
form.allowedUnits = [.year, .month, .day]
let s = form.string(from: date1, to: date2)

With Swift 5 and iOS 12, you can use one of the 3 solutions below in order to calculate the difference (in years, months, days) between two dates.
#1. Using Calendar's dateComponents(_:from:to:) method
Calendar has a method called dateComponents(_:from:to:). dateComponents(_:from:to:) has the following declaration:
func dateComponents(_ components: Set<Calendar.Component>, from start: DateComponents, to end: DateComponents) -> DateComponents
Returns the difference between two dates specified as DateComponents.
The Playground example below show how to use dateComponents(_:from:to:) in order to compute the difference between two dates:
import Foundation
let calendar = Calendar.current
let startComponents = DateComponents(year: 2010, month: 11, day: 22)
let endComponents = DateComponents(year: 2015, month: 5, day: 1)
let dateComponents = calendar.dateComponents([.year, .month, .day], from: startComponents, to: endComponents)
print(dateComponents) // prints: year: 4 month: 5 day: 9 isLeapMonth: false
#2. Using Calendar's dateComponents(_:from:to:) method
Calendar has a method called dateComponents(_:from:to:). dateComponents(_:from:to:) has the following declaration:
func dateComponents(_ components: Set<Calendar.Component>, from start: Date, to end: Date) -> DateComponents
Returns the difference between two dates.
The Playground example below show how to use dateComponents(_:from:to:) in order to compute the difference between two dates:
import Foundation
let calendar = Calendar.current
let startDate = calendar.date(from: DateComponents(year: 2010, month: 11, day: 22))!
let endDate = calendar.date(from: DateComponents(year: 2015, month: 5, day: 1))!
let dateComponents = calendar.dateComponents([.year, .month, .day], from: startDate, to: endDate)
print(dateComponents) // prints: year: 4 month: 5 day: 9 isLeapMonth: false
#3. Using DateComponentsFormatter's string(from:to:) method
DateComponentsFormatter has a method called string(from:to:). string(from:to:) has the following declaration:
func string(from startDate: Date, to endDate: Date) -> String?
Returns a formatted string based on the time difference between two dates.
The Playground example below show how to use string(from:to:) in order to compute the difference between two dates:
import Foundation
let calendar = Calendar.current
let startDate = calendar.date(from: DateComponents(year: 2010, month: 11, day: 22))!
let endDate = calendar.date(from: DateComponents(year: 2015, month: 5, day: 1))!
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .full
formatter.allowedUnits = [.year, .month, .day]
let string = formatter.string(from: startDate, to: endDate)!
print(string) // prints: 4 years, 5 months, 9 days

Try this one
func calculateDiffInTwoDate (date1: NSDate, date2: NSDate) -> NSInteger {
//var userAge : NSInteger = 0
let calendar : NSCalendar = NSCalendar.currentCalendar()
let unitFlags : NSCalendarUnit = [ .Year , .Month, .Day]
let dateComponentNow : NSDateComponents = calendar.components(unitFlags, fromDate: date2)
let dateComponentBirth : NSDateComponents = calendar.components(unitFlags, fromDate: date1)
if ( (dateComponentNow.month < dateComponentBirth.month) ||
((dateComponentNow.month == dateComponentBirth.month) && (dateComponentNow.day < dateComponentBirth.day))
)
{
return dateComponentNow.year - dateComponentBirth.year - 1
}
else {
return dateComponentNow.year - dateComponentBirth.year
}
}
By This you can get diff between two dates in Years

Why don't you use the inbuild method to find the difference between 2 dates in seconds, and then write a method to convert seconds in terms of years, months and days.
let diff = date1.timeIntervalSinceDate(date2)

//Assigning Dates
let StartDate = datePicker.date
let currentDate = Date()
//Finding Difference of Dates
let components = Set<Calendar.Component>([.day, .month, .year])
let differenceOfDate = Calendar.current.dateComponents(components, from:
StartDate, to: currentDate)
Print(differenceOfDate)

Related

first and last day of the current month in swift

I'm trying to get the first and last day of the month in swift.
So far I have the following:
let dateFormatter = NSDateFormatter()
let date = NSDate()
dateFormatter.dateFormat = "yyyy-MM-dd"
let calendar = NSCalendar.currentCalendar()
let components = calendar.components([.Year, .Month, .Day, .Hour, .Minute, .Second], fromDate: date)
let month = components.month
let year = components.year
let startOfMonth = ("\(year)-\(month)-01")
But I'm not sure how to get the last date. Is there a built in method I'm missing? Obviously it has to take into account leap years etc.
Swift 3 and 4 drop-in extensions
This actually gets a lot easier with Swift 3+:
You can do it without guard (you could if you wanted to, but because DateComponents is a non-optional type now, it's no longer necessary).
Using iOS 8's startOfDayForDate (now startOfDay), you don't need to manually set the time to 12pm unless you're doing some really crazy calendar calculations across time zones.
It's worth mentioning that some of the other answers claim you can shortcut this by using Calendar.current.date(byAdding: .month, value: 0, to: Date())!, but where this fails, is that it doesn't actually zero out the day, or account for differences in timezones.
Here you go:
extension Date {
func startOfMonth() -> Date {
return Calendar.current.date(from: Calendar.current.dateComponents([.year, .month], from: Calendar.current.startOfDay(for: self)))!
}
func endOfMonth() -> Date {
return Calendar.current.date(byAdding: DateComponents(month: 1, day: -1), to: self.startOfMonth())!
}
}
print(Date().startOfMonth()) // "2018-02-01 08:00:00 +0000\n"
print(Date().endOfMonth()) // "2018-02-28 08:00:00 +0000\n"
You get the first day of the month simply with
let components = calendar.components([.Year, .Month], fromDate: date)
let startOfMonth = calendar.dateFromComponents(components)!
print(dateFormatter.stringFromDate(startOfMonth)) // 2015-11-01
To get the last day of the month, add one month and subtract one day:
let comps2 = NSDateComponents()
comps2.month = 1
comps2.day = -1
let endOfMonth = calendar.dateByAddingComponents(comps2, toDate: startOfMonth, options: [])!
print(dateFormatter.stringFromDate(endOfMonth)) // 2015-11-30
Alternatively, use the rangeOfUnit method which gives you
the start and the length of the month:
var startOfMonth : NSDate?
var lengthOfMonth : NSTimeInterval = 0
calendar.rangeOfUnit(.Month, startDate: &startOfMonth, interval: &lengthOfMonth, forDate: date)
For a date on the last day of month, add the length of the month minus one second:
let endOfMonth = startOfMonth!.dateByAddingTimeInterval(lengthOfMonth - 1)
Updated for Swift5:
extension Date {
var startOfDay: Date {
return Calendar.current.startOfDay(for: self)
}
var startOfMonth: Date {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month], from: self)
return calendar.date(from: components)!
}
var endOfDay: Date {
var components = DateComponents()
components.day = 1
components.second = -1
return Calendar.current.date(byAdding: components, to: startOfDay)!
}
var endOfMonth: Date {
var components = DateComponents()
components.month = 1
components.second = -1
return Calendar(identifier: .gregorian).date(byAdding: components, to: startOfMonth)!
}
func isMonday() -> Bool {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.weekday], from: self)
return components.weekday == 2
}
}
With Swift 3 & iOS 10 the easiest way I found to do this is Calendar's dateInterval(of:for:):
guard let interval = calendar.dateInterval(of: .month, for: Date()) else { return }
You can then use interval.start and interval.end to get the dates you need.
Swift 3
Many date example for :
Last 6 month,
last 3 month,
yesterday, last 7 day, last 30 day, previous month,
current month start & end, last month start & end date
let startDate = dateFormatter.string(from: Date().getThisMonthStart()!)
let endDate = dateFormatter.string(from: Date().getThisMonthEnd()!)
extension Date {
func getLast6Month() -> Date? {
return Calendar.current.date(byAdding: .month, value: -6, to: self)
}
func getLast3Month() -> Date? {
return Calendar.current.date(byAdding: .month, value: -3, to: self)
}
func getYesterday() -> Date? {
return Calendar.current.date(byAdding: .day, value: -1, to: self)
}
func getLast7Day() -> Date? {
return Calendar.current.date(byAdding: .day, value: -7, to: self)
}
func getLast30Day() -> Date? {
return Calendar.current.date(byAdding: .day, value: -30, to: self)
}
func getPreviousMonth() -> Date? {
return Calendar.current.date(byAdding: .month, value: -1, to: self)
}
// This Month Start
func getThisMonthStart() -> Date? {
let components = Calendar.current.dateComponents([.year, .month], from: self)
return Calendar.current.date(from: components)!
}
func getThisMonthEnd() -> Date? {
let components:NSDateComponents = Calendar.current.dateComponents([.year, .month], from: self) as NSDateComponents
components.month += 1
components.day = 1
components.day -= 1
return Calendar.current.date(from: components as DateComponents)!
}
//Last Month Start
func getLastMonthStart() -> Date? {
let components:NSDateComponents = Calendar.current.dateComponents([.year, .month], from: self) as NSDateComponents
components.month -= 1
return Calendar.current.date(from: components as DateComponents)!
}
//Last Month End
func getLastMonthEnd() -> Date? {
let components:NSDateComponents = Calendar.current.dateComponents([.year, .month], from: self) as NSDateComponents
components.day = 1
components.day -= 1
return Calendar.current.date(from: components as DateComponents)!
}
}
Swift 4
If you only need the ordinal day:
func lastDay(ofMonth m: Int, year y: Int) -> Int {
let cal = Calendar.current
var comps = DateComponents(calendar: cal, year: y, month: m)
comps.setValue(m + 1, for: .month)
comps.setValue(0, for: .day)
let date = cal.date(from: comps)!
return cal.component(.day, from: date)
}
lastDay(ofMonth: 2, year: 2018) // 28
lastDay(ofMonth: 2, year: 2020) // 29
This is the simplest way that I found (Swift 5+):
extension Date {
func getStart(of component: Calendar.Component, calendar: Calendar = Calendar.current) -> Date? {
return calendar.dateInterval(of: component, for: self)?.start
}
func getEnd(of component: Calendar.Component, calendar: Calendar = Calendar.current) -> Date? {
return calendar.dateInterval(of: component, for: self)?.end
}
}
Here is easiest solution:
extension Date {
func startOfMonth() -> Date {
let interval = Calendar.current.dateInterval(of: .month, for: self)
return (interval?.start.toLocalTime())! // Without toLocalTime it give last months last date
}
func endOfMonth() -> Date {
let interval = Calendar.current.dateInterval(of: .month, for: self)
return interval!.end
}
// Convert UTC (or GMT) to local time
func toLocalTime() -> Date {
let timezone = TimeZone.current
let seconds = TimeInterval(timezone.secondsFromGMT(for: self))
return Date(timeInterval: seconds, since: self)
}}
and then call these with your date instance:
print(Date().startOfMonth())
print(Date().endOfMonth())
2017...
First, get the month you need:
let cal = Calendar.current
let d = Calendar.current.date(byAdding: .month, value: 0, to: Date())!
// for "last month" just use -1, for "next month" just use 1, etc
To get the day-of-the-week for the first day of the month:
let c = cal.dateComponents([.year, .month], from: d)
let FDOM = cal.date(from: c)!
let dowFDOM = cal.component(.weekday, from: FDOM)
print("the day-of-week on the 1st is ... \(dowFDOM)")
// so, that's 1=Sunday, 2=Monday, etc.
To get the number of days in the month:
let r = cal.range(of: .day, in: .month, for: d)!
let kDays = r.count
print("the number of days is ... \(kDays)")
With Swift 3, you can choose one of the two following patters in order to retrieve the first and last days of a month.
#1. Using Calendar dateComponents(_:from:), date(from:) and date(byAdding:to:wrappingComponents:) methods
With this pattern, you first get the date of the first day of a month then add a month and remove a day from it in order to get the date of the last day of the month. The Playground code below shows how to set it:
import Foundation
// Set calendar and date
let calendar = Calendar.current
let date = calendar.date(byAdding: DateComponents(day: -10), to: Date())!
// Get first day of month
let firstDayComponents = calendar.dateComponents([.year, .month], from: date)
let firstDay = calendar.date(from: firstDayComponents)!
// Get last day of month
let lastDayComponents = DateComponents(month: 1, day: -1)
let lastDay = calendar.date(byAdding: lastDayComponents, to: firstDay)!
// Set date formatter
let dateFormatter = DateFormatter()
dateFormatter.locale = Locale(identifier: "en_UK")
dateFormatter.dateStyle = .long
dateFormatter.timeStyle = .long
// Print results
print(dateFormatter.string(from: date)) // Prints: 22 March 2017 at 18:07:15 CET
print(dateFormatter.string(from: firstDay)) // Prints: 1 March 2017 at 00:00:00 CET
print(dateFormatter.string(from: lastDay)) // Prints: 31 March 2017 at 00:00:00 CEST
#2. Using Calendar range(of:in:for:), dateComponents(_:from:) and date(from:) and methods
With this pattern, you get a range of absolute day values in a month and then retrieve the dates of the first day and last day of the month from it. The Playground code below shows how to set it:
import Foundation
// Set calendar and date
let calendar = Calendar.current
let date = calendar.date(byAdding: DateComponents(day: -10), to: Date())!
// Get range of days in month
let range = calendar.range(of: .day, in: .month, for: date)! // Range(1..<32)
// Get first day of month
var firstDayComponents = calendar.dateComponents([.year, .month], from: date)
firstDayComponents.day = range.lowerBound
let firstDay = calendar.date(from: firstDayComponents)!
// Get last day of month
var lastDayComponents = calendar.dateComponents([.year, .month], from: date)
lastDayComponents.day = range.upperBound - 1
//lastDayComponents.day = range.count // also works
let lastDay = calendar.date(from: lastDayComponents)!
// Set date formatter
let dateFormatter = DateFormatter()
dateFormatter.locale = Locale(identifier: "en_UK")
dateFormatter.dateStyle = .long
dateFormatter.timeStyle = .long
// Print results
print(dateFormatter.string(from: date)) // prints: 22 March 2017 at 18:07:15 CET
print(dateFormatter.string(from: firstDay)) // prints: 1 March 2017 at 00:00:00 CET
print(dateFormatter.string(from: lastDay)) // prints: 31 March 2017 at 00:00:00 CEST
In swift 3, if you put 0 to day component you can get the last day of the month. There's an example code:
public func isMoreDays(date: Date, asc: Bool)->Bool{
//components
var dayComponents = self.getDateComponents(date: date)
//asc is true if ascendant or false if descendant
dayComponents.day = asc ? 0 : 1
//plus 1 to month 'cos if you set up day to 0 you are going to the previous month
dayComponents.month = asc ? dayComponents.month! + 1 : dayComponents.month
//instantiate calendar and get the date
let calendar : Calendar = NSCalendar.current
let day = calendar.date(from: dayComponents)
//date comparison
if(day?.compare(date) == .orderedSame){
return false
}
return true
}
You can use the following extensions here :
let today = Date()
let startOfMonth = today.beginning(of: .month)
let endOfMonth = today.end(of: .month)

Swift Datepicker with minimum date

Goord Morning all together,
i have an app with ios 8 and swift.
in there is a UIViewcontroller within a UIDatepicker
I set a minimum date. for example the date of today: 2 | May | 2015
with this solution it should not be possible to set a date which is in the past
but if would like to set this date 15 | January | 2016
i set at first the day to 15
than the month to january but then the UIDatepicker goes back to the minimum date 2 May 2015
is it be possible, that wenn change the day to 15 and the month to january, that the year changes automaticly to 2016?
Let your minimumDate unset and try to configure it by code...
Try this:
#IBAction func changeValue(sender: UIDatePicker)
{
//Get time Now, and convert to a NSCalendar
//Specify the minimun date if you want.
let now = NSDate()
let nowCalendar = NSCalendar.currentCalendar()
let nowComponents = nowCalendar.components([.Day, .Month, .Year], fromDate: now)
//Compare if date is lesser than now and then create a new date
if nowCalendar.compareDate(sender.date, toDate: now, toUnitGranularity: [.Day, .Month, .Year]) == NSComparisonResult.OrderedAscending
{
let dateCalendar = NSCalendar.currentCalendar()
let dateComponents = dateCalendar.components([.Day, .Month, .Year], fromDate: sender.date)
dateComponents.year = nowComponents.year + 1
let newDate = dateCalendar.dateFromComponents(dateComponents)
sender.date = newDate!
}
}
///Swift4 Version - I think it may works with 3 too.
#IBAction func changeValue(sender: UIDatePicker)
{
//Get time Now, and convert to a NSCalendar
//Specify the minimun date if you want.
let now = Date()
let nowCalendar = Calendar.current
let nowComponents = nowCalendar.dateComponents([.day, .month, .year], from: now)
//Compare if date is lesser than now and then create a new date
if nowCalendar.compare(sender.date, to: now, toGranularity: Calendar.Component.day) == ComparisonResult.orderedAscending
{
var dateCalendar = Calendar.current
var dateComponents = dateCalendar.dateComponents([.day, .month, .year], from: sender.date)
guard let year = nowComponents.year else { return }
dateComponents.year = year + 1
let newDate = dateCalendar.date(from:dateComponents)
sender.date = newDate!
}
}
I published a complete example working in playground if you wish to play a little.
https://gist.github.com/dedeexe/4878f78d7e1d5fe8b372ef84de629b59
For swift 4:
I have like this.
1. My function:
func AddDaysToToday(days: Int) -> Date? {
var dateComponents = DateComponents()
dateComponents.day = days
return Func.GetCalendar(tz: .utc).date(byAdding: dateComponents, to: Date()) //you can return your own Date here.
}
In my VC:
let today = DateFunc.AddDaysToToday(days: 0)
datePicker.minimumDate = today

Days between 2 NSDates in a calendar year swift

I'm building a birthday reminder app. I want the user to be able to see how many days it is until somebody's next birthday.
Let's say I have an NSDate() = 2015-06-30 07:21:47 +0000
And the NSDate for the birthday = 1985-08-29 12:00:00 +0000
How would I get the number of days until the next birthday? I've used something like this which gives a negative number of days since the date's actual beginning (which are in the thousands with birthdates). Then with that I would add 365 to the numerical difference until it was positive but it still returns a wonky number. I'm assuming due to leap years or something.
Is there a method to this I can implement? Somehow equalize the year components so that it's always comparing from the next birthday and not the original birthdate?
Edit:
Here is the function I am using:
func daysBetween(date1: NSDate, date2: NSDate) -> Int {
var calendar: NSCalendar = NSCalendar.currentCalendar()
let date1 = calendar.startOfDayForDate(date1)
let date2 = calendar.startOfDayForDate(date2)
let flags = NSCalendarUnit.CalendarUnitDay
let components = calendar.components(flags, fromDate: date1, toDate: date2, options: nil)
return components.day
}
With the example dates I posted I would use it like this:
// sampleDate = 1985-08-29 12:00:00 +0000
daysBetween(sampleDate, date2: NSDate())
// --> 10897
Whether positive or negative, the number is in the thousands. I'm looking to equalize that into number of days to the next calendar birthday.
What you need is to compute the next occurrence of the (day and month
component of the) birthday after today:
let cal = NSCalendar.currentCalendar()
let today = cal.startOfDayForDate(NSDate())
let dayAndMonth = cal.components(.CalendarUnitDay | .CalendarUnitMonth,
fromDate: birthday)
let nextBirthDay = cal.nextDateAfterDate(today,
matchingComponents: dayAndMonth,
options: .MatchNextTimePreservingSmallerUnits)!
Remarks:
The purpose of the MatchNextTimePreservingSmallerUnits option is
that if the birthday is on February 29 (in the Gregorian calendar), its next occurrence will be
computed as March 1 if the year is not a leap year.
You might need to check first if the birthday is today, as it seems
that nextDateAfterDate() would return the next birthday in that case.
Then you can compute the difference in days as usual:
let diff = cal.components(.CalendarUnitDay,
fromDate: today,
toDate: nextBirthDay,
options: nil)
println(diff.day)
Update for Swift 2.2 (Xcode 7.3):
let cal = NSCalendar.currentCalendar()
let today = cal.startOfDayForDate(NSDate())
let dayAndMonth = cal.components([.Day, .Month],
fromDate: birthday)
let nextBirthDay = cal.nextDateAfterDate(today,
matchingComponents: dayAndMonth,
options: .MatchNextTimePreservingSmallerUnits)!
let diff = cal.components(.Day,
fromDate: today,
toDate: nextBirthDay,
options: [])
print(diff.day)
Update for Swift 3 (Xcode 8 GM):
let cal = Calendar.current
let today = cal.startOfDay(for: Date())
let dayAndMonth = cal.dateComponents([.day, .month], from: birthday)
let nextBirthDay = cal.nextDate(after: today, matching: dayAndMonth,
matchingPolicy: .nextTimePreservingSmallerComponents)!
let diff = cal.dateComponents([.day], from: today, to: nextBirthDay)
print(diff.day!)
Btw, in case anyone needs here is the #Aaron function in Swift 3:
func daysBetween(date1: Date, date2: Date) -> Int {
let calendar = Calendar.current
let date1 = calendar.startOfDay(for: date1)
let date2 = calendar.startOfDay(for: date2)
let components = calendar.dateComponents([Calendar.Component.day], from: date1, to: date2)
return components.day ?? 0
}

NSDate day of the year (swift)

How might the day number of the year be found with swift? Is there a simple way that I'm not seeing, or do I have to find the number of seconds from Jan 1 to the current date and divide by the number of seconds in a day?
This is a translation of the answer to How do you calculate the day of the year for a specific date in Objective-C? to Swift.
Swift 2:
let date = NSDate() // now
let cal = NSCalendar.currentCalendar()
let day = cal.ordinalityOfUnit(.Day, inUnit: .Year, forDate: date)
print(day)
Swift 3:
let date = Date() // now
let cal = Calendar.current
let day = cal.ordinality(of: .day, in: .year, for: date)
print(day)
This gives 1 for the first day in the year, and 56 = 31 + 25 for today (Feb 25).
... or do I have to find the number of seconds from Jan 1 to the current date
and divide by the number of seconds in a day
This would be a wrong approach, because a day does not have a fixed
number of seconds (transition from or to Daylight Saving Time).
Swift 3
extension Date {
var dayOfYear: Int {
return Calendar.current.ordinality(of: .day, in: .year, for: self)!
}
}
use like
Date().dayOfYear
Not at all !!! All you have to do is to use NSCalendar to help you do your calendar calculations as follow:
let firstDayOfTheYear = NSCalendar.currentCalendar().dateWithEra(1, year: NSCalendar.currentCalendar().component(.CalendarUnitYear, fromDate: NSDate()), month: 1, day: 1, hour: 0, minute: 0, second: 0, nanosecond: 0)! // "Jan 1, 2015, 12:00 AM"
let daysFromJanFirst = NSCalendar.currentCalendar().components(.CalendarUnitDay, fromDate: firstDayOfTheYear, toDate: NSDate(), options: nil).day // 55
let secondsFromJanFirst = NSCalendar.currentCalendar().components(.CalendarUnitSecond, fromDate: firstDayOfTheYear, toDate: NSDate(), options: nil).second // 4,770,357
You can find the number of days since your date like this:
let date = NSDate() // your date
let days = cal.ordinalityOfUnit(.CalendarUnitDay, inUnit: .CalendarUnitYear, forDate: date)
println(days)

How to get the hour of the day with Swift?

How would I get the hour of the day in Swift.
I have tried NSCalendar and NSDateComponents, but I'm afraid I'm just starting with Swift.
Swift 5.0 / 4.0 / 3.0
let hour = Calendar.current.component(.hour, from: Date())
Or, if you're interested in 12 hour AM/PM date format, then use NSDateFormatter
let formatter = DateFormatter()
formatter.dateFormat = "hh a" // "a" prints "pm" or "am"
let hourString = formatter.string(from: Date()) // "12 AM"
If you want minutes, seconds and others, do as following
let date = Date() // save date, so all components use the same date
let calendar = Calendar.current // or e.g. Calendar(identifier: .persian)
let hour = calendar.component(.hour, from: date)
let minute = calendar.component(.minute, from: date)
let second = calendar.component(.second, from: date)
Check out available components on Apple docs:
.era, .year, .month, .day, .hour, .minute, .second,
.weekday, .weekdayOrdinal, .quarter, weekOfMonth, .weekOfYear,
.yearForWeekOfYear, .nanosecond, .calendar, .timezone
Swift 2.0
let hour = NSCalendar.currentCalendar().component(.Hour, fromDate: NSDate())
Swift 1.0
let hour = NSCalendar.currentCalendar().component(.CalendarUnitHour, fromDate: NSDate())
Swift 3:
let date = Date()// Aug 25, 2017, 11:55 AM
let calendar = Calendar.current
let hour = calendar.component(.hour, from: date) //11
let minute = calendar.component(.minute, from: date) //55
let sec = calendar.component(.second, from: date) //33
let weekDay = calendar.component(.weekday, from: date) //6 (Friday)
Get any of component available from the API below
public enum Component {
case era
case year
case month
case day
case hour
case minute
case second
case weekday
case weekdayOrdinal
case quarter
case weekOfMonth
case weekOfYear
case yearForWeekOfYear
case nanosecond
case calendar
case timeZone
}
Swift 2:
let currentHour = NSCalendar.currentCalendar().component(.Hour, fromDate: NSDate())
This could be enough :
let currentDate = NSDate() // You can input the custom as well
let calendar = NSCalendar.currentCalendar()
let components = calendar.components(.CalendarUnitHour | .CalendarUnitMinute, fromDate: currentDate)
let currentHour = components.hour // You can play around with the ""components""
If you want the current hour in a String, this is as short and readable I could think of.
let formatter = NSDateFormatter()
formatter.dateFormat = "HH"
let timeString = formatter.stringFromDate(NSDate())
Finally I was able to find the easiest solution after struggling for a time
let dateComponents = NSCalendar.currentCalendar().components(NSCalendarUnit.HourCalendarUnit, fromDate: NSDate())
let nHourOfDay = dateComponents.hour
For Swift 2.0:
let hour = NSCalendar.currentCalendar().component(NSCalendarUnit.Hour, fromDate: NSDate())
Here is a reference example for how I do it (DateUtils.swift) -
Example Use:
let today = DateUtils.getToday();
let hr = DateUtils.getHours(today);
let min = DateUtils.getMinutes(today);
... (etc.) ...
DateUtils.swift:
//Field wrapper routines
class func getToday() -> Date { return Date(); }
class func getHours(_ date : Date) -> Int { return Calendar.current.component(.hour, from: date); }
class func getMinutes(_ date : Date) -> Int { return Calendar.current.component(.minute, from: date); }
... (continued for all fields, see file) ...
You can get the integer value of the current hour in one step like this:
let currentHour = NSCalendar.currentCalendar().components(.Hour, fromDate: NSDate()).hour

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