How to implemented nested list in XSLT? - xslt-2.0

Question

I wanted to add <p> tag for every <li> elements, but there is a special situation when it is a nested list. If there is descendant <ol> tag, this adding <p> must be closed before this <ol> tag. Although it is happened, I could not be able to remove the <s>test tag</s><br/>part repetition.
Please help!
Input:
<a>
<ol>
<li>
<s>test tag</s><br/>
<ol>
<li>list item1</li>
<li>list item2</li>
<li>list item3</li>
</ol>
</li>
</ol>
</a>
Expected output:
<a>
<ol>
<li>
<p><s>test tag</s><br/></p>
<ol>
<p><li>list item1</li></p>
<p><li>list item1</li></p>
<p><li>list item1</li></p>
</ol>
</li>
</ol>
</a>
XSLT code:
<xsl:template match="ol">
<ol>
<xsl:apply-templates/>
</ol>
</xsl:template>
<xsl:template match="li[not(descendant::ol)]">
<li>
<p>
<xsl:apply-templates/>
</p>
</li>
</xsl:template>
<xsl:template match="li[descendant::ol]">
<li>
<p>
<xsl:apply-templates select="node()[parent::li][following-sibling::ol]"/>
</p>
</li>
<xsl:apply-templates select=""/>
</xsl:template>
<xsl:template match="node()[parent::li][following-sibling::ol]"/>

Answer 1

In the case where there is no descendant ol, your desired output has a p element outside each li, whereas your stylesheet is putting a p inside each ol. I don't know which you actually want, but I assume you know how to fix it.
In the case where there is a descendant ol, you have only given one possible example of what you want, and one example does not constitute a specification. However, for that example, the following would work:
<xsl:template match="li[ol]">
<li>
<p>
<xsl:apply-templates select="node()[not(self::ol)]"/>
</p>
<xsl:apply-templates select="ol"/>
</li>
</xsl:template>
If this doesn't solve the problem in the general case, that's because you haven't said what's required in the general case.