How to read a whole column in Powershell - powershell-2.0

Question

I'm trying to write a powershell script that will output the contents of a column inside a spreadsheet to a txt file. I don't know powershell but I found and figured out how to get a cell, now I need the whole column. The spreadsheet in question has 8K+ rows. Here is what I have so far:
$SMTPApprovedXLS = "c:\temp\SMTP\SMTPAPPLIST.XLS"
$SheetName = "Active"
$objExcel = New-Object -ComObject Excel.Application
$objExcel.Visible = $False
$Workbook = $objExcel.Workbooks.open($SMTPApprovedXLS)
$Worksheet = $Workbook.sheets.item($SheetName)
$startRow = 4
[pscustomobject][ordered]#{
ApprovedIPs = $Worksheet.Cells.Item(4,$startRow).Value()
}
The column is "D" and should start at row 4.
Thanks in advance.

Answer 1

All you have to do is use a loop to run through all the entries and capture the data. Try this:
$SMTPApprovedXLS = "c:\temp\SMTP\SMTPAPPLIST.XLS"
$SheetName = "Active"
$objExcel = New-Object -ComObject Excel.Application
$objExcel.Visible = $False
$Workbook = $objExcel.Workbooks.open($SMTPApprovedXLS)
$Worksheet = $Workbook.sheets.item($SheetName)
$startRow = 4
$ApprovedIPs = #()
$count = $Worksheet.Cells.Item(65536,4).End(-4162)
for($startRow=4; $startRow -le $count.row; $startRow++)
{
$ApprovedIPs += $Worksheet.Cells.Item($startRow, 4).Value()
}
$ApprovedIPs | Out-File C:\ApprovedIPs.txt
Note that the last line is what creates the txt file with the desired data, where C:\ is the directory and ApprovedIPs is the file name. You can just substitute them for your desired location and name of the file.