I am trying to retrieve the paths from Airport(A1) to Airport(A3) based on their relationships, when the arrival-time is less than departure-time.
here is my console link http://console.neo4j.org/r/7cw8h0
You had it almost right (you also misspelt your property value for Airport A1)
MATCH path =((A1:AIRPORT)-[Connections:Connect*]->(A3:AIRPORT))
WHERE A1.name='Airport A1' AND A3.name='Airport A3'
AND ALL (i IN Range(0, length(Connections)-2)
WHERE ((Connections[i]).arrvTime <(Connections[i+1]).dptrTime))
RETURN extract(Connect IN Connections | Connect.flightcode)
Your console was also not shared correctly, here is a correct version:
http://console.neo4j.org/r/jfxnsj
This might also be interesting for you:
http://maxdemarzi.com/?s=flights
http://gist.neo4j.org/?6619085
Related
Here is my simplified graph schema,
package:
property:
- name: str (indexed)
- version: str (indexed)
I want to query the version using multiple set of property criteria within single query. I can use within for a list of single property, but how to do it for multiple properties?
Consider I have 10 package nodes, (p1,v1, p2,v2, p3,v3,.. p10,v10)
I want to select only nodes which has (p1 with v1, p8 with v8, p10 with v10)
Is there a way to do with single gremlin query?
Something equivalent to SELECT * from package WHERE (name, version) in ((p1,v1),(p8,v8),(p10,v10)).
It's always best to provide some sample data when asking questions about Gremlin. I assume that this is an approximation of what your model is:
g.addV('package').property('name','gremlin').property('version', '1.0').
addV('package').property('name','gremlin').property('version', '2.0').
addV('package').property('name','gremlin').property('version', '3.0').
addV('package').property('name','blueprints').property('version', '1.0').
addV('package').property('name','blueprints').property('version', '2.0').
addV('package').property('name','rexster').property('version', '1.0').
addV('package').property('name','rexster').property('version', '2.0').iterate()
I don't think that there is a way that you can compare pairs of inputs and expect an index hit. You therefore have to do what you normally do in graphs and choose the index to best narrow your results before you filter in memory. I would assume that in your case this would be the "name" property, therefore grab those first then filter the pairs:
gremlin> g.V().has('package','name', within('gremlin','blueprints')).
......1> elementMap().
......2> where(select('name','version').is(within([name:'gremlin',version:'2.0'], [name:'blueprints',version:'2.0'])))
==>[id:3,label:package,name:gremlin,version:2.0]
==>[id:12,label:package,name:blueprints,version:2.0]
this might not be the most "creative" way of doing that,
but I think that the easiest way would be to use or:
g.V().or(
hasLabel('v1').has('prop', 'p1'),
hasLabel('v8').has('prop', 'p8'),
hasLabel('v10').has('prop', 'p10')
)
example: https://gremlify.com/6s
I am new to Neo4j and I have a relatively complex (but small) database which I have simplified to the following:
The first door has no key, all other doors have keys, the window doesn't require a key. The idea is that if a person has key:'A', I want to see all possible paths they could take.
Here is the code to generate the db
CREATE (r1:room {name:'room1'})-[:DOOR]->(r2:room {name:'room2'})-[:DOOR {key:'A'}]->(r3:room {name:'room3'})
CREATE (r2)-[:DOOR {key:'B'}]->(r4:room {name:'room4'})-[:DOOR {key:'A'}]->(r5:room {name:'room5'})
CREATE (r4)-[:DOOR {key:'C'}]->(r6:room {name:'room6'})
CREATE (r2)-[:WINDOW]->(r4)
Here is the query I have tried, expecting it to return everything except for room6, instead I have an error which means I really don't know how to construct the query.
with {key:'A'} as params
match (n:room {name:'room1'})-[r:DOOR*:WINDOW*]->(m)
where r.key=params.key or not exists(r.key)
return n,m
To be clear, I don't need my query debugged so much as help understanding how to write it correctly.
Thanks!
This should work for you:
WITH {key:'A'} AS params
MATCH p=(n:room {name:'room1'})-[:DOOR|WINDOW*]->(m)
WHERE ALL(r IN RELATIONSHIPS(p) WHERE NOT EXISTS(r.key) OR r.key=params.key)
RETURN n, m
With your sample data, the result is:
╒════════════════╤════════════════╕
│"n" │"m" │
╞════════════════╪════════════════╡
│{"name":"room1"}│{"name":"room2"}│
├────────────────┼────────────────┤
│{"name":"room1"}│{"name":"room3"}│
├────────────────┼────────────────┤
│{"name":"room1"}│{"name":"room4"}│
├────────────────┼────────────────┤
│{"name":"room1"}│{"name":"room5"}│
└────────────────┴────────────────┘
I want to visualise data from Neo4j with the frontend-library D3.js in an Rails application, using Neo4jrb. For example I could use the following query to get my graph data.
query = "MATCH path = (a)-[b]->(c) RETURN path"
result = Neo4j::Session.current.query(query)
But this query is not giving me the exact data I want.
According to the Neo4j data visualisation guide there is a possibility to set the parameter resultDataContents to "graph". (
Neo4j documentation for "resultDataContents")
This is exactly what I need for my application. Is there any possibility to set this parameter in Neo4jrb, or another idea how to achieve such a result?
Unfortunately not currently. The neo4j-core gem (which the neo4j gem uses) was build to abstract away the REST format. The "graph" format returns data in a different way.
You have a couple of options. You could make the JSON queries yourself or you could retrieve the nodes and relationships from the queries that you perform and then build your own nodes/relationships structure which is returned. This might be more future-proof anyway if you ever want to switch to Bolt.
A way that you might do this in your case:
query = "MATCH path = (a)-[b]->(c) RETURN nodes(path) AS nodes, rels(path) AS rels"
result = Neo4j::Session.current.query(query)
response = {nodes: [], rels: []}
result.each do |row|
response[:nodes].concat(row.nodes)
response[:rels].concat(row.rels)
end
response[:nodes].uniq!
response[:rels].uniq!
This is my first attempt at Neo4j, please excuse me if I am missing something very trivial.
Here is my problem:
Consider the graph as created in the following Neo4j console example:
http://console.neo4j.org/?id=y13kbv
We have following nodes in this example:
(Person {memberId, memberName, membershipDate})
(Email {value, badFlag})
(AccountNumber {value, badFlag})
We could potentially have more nodes capturing features related to a Person like creditCard, billAddress, shipAddress, etc.
All of these nodes will be the same as Email and AccountNumber nodes:
(creditCard {value, badFlag}), (billAddress {value, badFlag}),etc.
With the graph populated as seen in the Neo4j console example, assume that we add one more Person to the graph as follows:
(p7:Person {memberId:'18' , memberName:'John', membershipDate:'12/2/2015'}),
(email6:Email {value: 'john#gmail.com', badFlag:'false'}),
(a2)-[b13:BELONGS_TO]->(p7),
(email6)-[b14:BELONGS_TO]->(p7)
When we add this new person to the system, the use case is that we have to check if there exists a path from features of the new Person ("email6" and "a2" nodes) to any other node in the system where the "badFlag=true", in this case node (a1 {value:1234, badFlag:true}).
Here, the resultant path would be (email6)-[BELONGS_TO]->(p7)<-[BELONGS_TO]-(a2)-[BELONGS_TO]->(p6)<-[BELONGS_TO]-(email5)-[BELONGS_TO]->(p5)<-[BELONGS_TO]-(a1:{badFlag:true})
I tried something like this:
MATCH (newEmail:Email{value:'john#gmail.com'})-[:BELONGS_TO]->(p7)-[*]-(badPerson)<-[:BELONGS_TO]-(badFeature{badFlag:'true'}) RETURN badPerson, badFeature;
which seems to work when there is only one level of chaining, but it doesn't work when the path could be longer like in the case of Neo4j console example.
I need help with the Cypher query that will help me solve this problem.
I will eventually be doing this operation using Neo4j's Java API using my application. What could be the right way to go about doing this using Java API?
You had a typo in you query. PART_OF should be BELONGS_TO. This should work for you:
MATCH (newEmail:Email {value:'john#gmail.com'})-[:BELONGS_TO]->(p7)-[*]-(badPerson)<-[:BELONGS_TO]-(badFeature {badFlag:'true'})
RETURN badPerson, badFeature;
Aside: You seem to use string values for all properties. I'd replace the string values 'true' and 'false' with the boolean values true and false. Likewise, values that are always numeric should just use integer or float values.
How it's possible to run a collection of query like this (came from a spreadsheet copy) directly in one cypher query? one by one it's ok, but need 100 copy/paste
*******************************
MATCH (c:`alpha`)
where c.name = "a-01"
SET c.CP_PRI=1, c.TO_PRI=1, c.TA_PRI=2
return c ;
MATCH (c:`beta`)
where c.name = "a-02"
SET c.CP_PRI=1, c.TO_PRI=1, c.TA_PRI=0
return c ;
and 100 other lines ...
*********************************
you may try the 'union' clause, which joins the results of queries into one big-honkin result set:
http://docs.neo4j.org/chunked/milestone/query-union.html
That said - the root behavior of what you are trying to do could use some details - maybe there's a better way to write the query - you could use Excel to 'build' the unified query via calculations / macros, you could possibly write a unified query that combines the rules you are trying to follow, there's a lot of options, but it's hard to know a starting direction w/o context....
Talking about the REST API you can use the transactional endpoint in Neo4J 2.0, or the batch endpoint in Neo4J 1.x.
If you want to use the shell, have a look to the import page, in particular the neo4j-shell-tools where they're importing massive quantity of data batching multiple queries.