How to integrate Skype in my iPhone application - ios

Question

I am new to iOS. I want to integrate Skype in my iPhone application,for this I have searched lot but I have not found a solution for this
How can I get Skype SDK for integration. How can I integrate Skype API in my application. Is there any other way to make developer Skype account
If your people having any sample code please post that.Please help me. Many Thanks.
I have tried some code please see that below but using that code my simulator it's showing alert like below image
my code:-
- (IBAction)skypeMe:(id)sender {
BOOL installed = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:#"skype:"]];
if(installed)
{
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"skype:echo123?call"]];
}
else
{
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"http://itunes.com/apps/skype/skype"]];
}
}

Answer 1

For Swift 3.0 It opens itunes url if it is not installed, otherwise it will open skype.
#IBAction func btnSkypeLinkPressed(_ sender : UIButton) {
let installed = UIApplication.shared.canOpenURL(NSURL(string: "skype:")! as URL)
if installed {
UIApplication.shared.openURL(NSURL(string: "skype:skypeID")! as URL)
} else {
UIApplication.shared.openURL(NSURL(string: "https://itunes.apple.com/in/app/skype/id304878510?mt=8")! as URL)
}
}
and in plist add:
<key>LSApplicationQueriesSchemes</key>
<array>
<string>skype</string>
</array>
Hope it will work for swift users Thanks.

Answer 2

Here is your swift code:
Swift
#IBAction func skypeMe(sender: AnyObject) {
let installed = UIApplication.sharedApplication().canOpenURL(NSURL(string: "skype:")!)
if installed {
UIApplication.sharedApplication().openURL(NSURL(string: "skype:echo123?call")!)
} else {
UIApplication.sharedApplication().openURL(NSURL(string: "https://itunes.apple.com/in/app/skype/id304878510?mt=8")!)
}
}
Objective-C
- (IBAction)skypeMe:(id)sender {
BOOL installed = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:#"skype:"]];
if(installed){
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"skype:echo123?call"]];
} else {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"https://itunes.apple.com/in/app/skype/id304878510?mt=8"]];
}
}
I have changed skype URL for iTunes in this code and tested it with device and both URL is working fine.

Answer 3

in addition to #Dharmesh's answer, in iOS9 you must add the application you want to query for 'canOpenUrl' to you plist, under LSApplicationQueriesSchemes key
see this answer: https://stackoverflow.com/a/30988328/1787109

Answer 4

Using Swift 5 you can integrate "one to one" call and also one to many call in skype
#IBAction func btnStartSkypeCall(_ sender: UIButton) {
var installed: Bool? = nil
if let url = URL(string: "skype:") {
installed = UIApplication.shared.canOpenURL(url)
}
if installed ?? false {
if self.mainModelView.eventList!.students?.count ?? 0 <= 1{
if let url = URL(string: "skype:SkypeID?call&video=true") {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
}
}else if self.mainModelView.eventList!.students?.count ?? 0 > 1{
if let url = URL(string: "skype:test_skype;test2_skype;test3_skype?call&video=true") {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
}
}else{
print("Student list is empty")
}
} else {
if let url = URL(string: "https://itunes.apple.com/in/app/skype/id304878510?mt=8") {
UIApplication.shared.open(URL(string:"\(url)")!)
}
}
}
To start a chat use the schema
skype:user?chat
To start a video call use
skype:user?call&video=true
You must be add in plist file
<key>LSApplicationQueriesSchemes</key>
<array>
<string>skype</string>
</array>