I am trying to trim a phone number and using the following code but it does not trim whitespace or the '-'. I need to erase all chars except those in the character set given
func trimmedNumber(s : String)->String
{
let characterSet = NSCharacterSet(charactersInString: "+*#0123456789")
let trimmedString = s.stringByTrimmingCharactersInSet(characterSet.invertedSet)
return trimmedString
}
Swift 3/4:
let set = CharacterSet(charactersIn: "+*#0123456789")
let stripped = s.components(separatedBy: set.inverted).joined()
func trimmedNumber(s : String) -> String {
let characterSet = Set("+*#0123456789".characters)
return String(s.characters.lazy.filter(characterSet.contains))
}
Or in Swift 1:
func trimmedNumber(s : String) -> String {
let characterSet = Set("+*#0123456789")
return String(lazy(s).filter { characterSet.contains($0) })
}
Add the method removingCharacters(in:) to Swift's String type. It returns a new string made by removing the characters in a given character set from the String.
For example:
let string = "+1-202-555-0141"
let set = CharacterSet(charactersIn: "+*#0123456789")
let sanitized = string.removingCharacters(in: set.inverted)
// sanitized is equal to "+12025550141"
Helpers.swift
extension String {
public func removingCharacters(in set: CharacterSet) -> String {
let filtered = unicodeScalars.filter { !set.contains($0) }
return String(String.UnicodeScalarView(filtered))
}
}
HelpersTests.swift
import XCTest
class HelpersTests: XCTestCase {
func testRemovingCharacters() {
let inputText1 = ""
let set1 = CharacterSet.decimalDigits.inverted
let sanitized1 = inputText1.removingCharacters(in: set1)
XCTAssertEqual("", sanitized1)
let inputText2 = " tab:\tspace: no-break_space: "
let set2 = CharacterSet.whitespaces
let sanitized2 = inputText2.removingCharacters(in: set2)
XCTAssertEqual("tab:space:no-break_space:", sanitized2)
let inputText3 = " aBc!##12 $%^&*()-_=+[{]}\\|;:'\"3,<.>/?`~ "
let set3 = CharacterSet.alphanumerics.inverted
let sanitized3 = inputText3.removingCharacters(in: set3)
XCTAssertEqual("aBc123", sanitized3)
}
}
See also: Convert Array of UnicodeScalar into String in Swift
works in swift 1&2
let s = "adasdad+3124124+r323*4asdasdbk*($&##"
let characterSet = NSCharacterSet(charactersInString: "+*#0123456789").invertedSet;
let elements = s.componentsSeparatedByCharactersInSet(characterSet)
let filtered = (elements as NSArray).componentsJoinedByString("")
print(filtered);
Related
I have React Native project. And I need in the native part of IOS to make string interpolation of formattedValue with a character, but I get the error "Type of expression is ambiguous without more context", and if I try the same code in the playground everything is working with out error. I'm not so experienced in SWIFT, can you tell me please why I get this error? And which the best way to make a string interpolation?
import Foundation
import SciChart.Protected.SCILabelProviderBase
class SCIAxisNumericLabelProvider: SCILabelProviderBase<ISCINumericAxis> {
var format: String?
var specialChar: String?
init(format: String?) {
let pattern = "[^0-9.]"
let regex = try! NSRegularExpression(pattern: pattern)
let formatValue = regex.stringByReplacingMatches(in: format ?? "", range: NSMakeRange(0, format?.count ?? 0), withTemplate: "")
self.format = formatValue
self.specialChar = format?.replacingOccurrences(of: "\(formatValue)", with: "")
super.init(axisType: ISCINumericAxis.self)
}
override func formatLabel(_ dataValue: ISCIComparable!) -> ISCIString! {
let dataValueToDouble = dataValue.toDouble()
let formattedValue = NSString(format: NSString(string: self.toFormat()), dataValueToDouble == -0 ? 0 : dataValueToDouble)
if let char = specialChar {
return "\(formattedValue) \(NSString(char))" // Here I get the error Type of expression is ambiguous without more context
}
return formattedValue
}
override func formatCursorLabel(_ dataValue: ISCIComparable!) -> ISCIString! {
return formatLabel(dataValue)
}
func toFormat() -> String {
if (self.format != nil) {
let a = self.format!.split(separator: ".")
if (a.count > 1) {
return "%0." + String(a[1].count) + "f"
}
}
return "%0.f"
}
func extractSpecialChar(value: String) {
}
}
In the end of the day I decided this error, I separated string interpolation and converting:
override func formatLabel(_ dataValue: ISCIComparable!) -> ISCIString! {
let formatterValue = self.toFormat();
let valueDouble = dataValue.toDouble()
let valueDoubleExcludedNegZero = valueDouble == -0 ? 0 : valueDouble
let precisionString = String(format: formatterValue, valueDoubleExcludedNegZero)
if let char = specialChar {
let resultString = precisionString + " " + char
return NSString(string: resultString)
}
return NSString(string: precisionString)
}
I am getting data from Json and displaying it in table view how to check whether the number is float or double or integer in swift 3 if it is float how to get the no.of digits after decimal can anyone help me how to implement this in swift 3 ?
if specialLoop.attributeCode == "special_price" {
let attributeString: NSMutableAttributedString = NSMutableAttributedString(string: "$ \((arr.price))")
attributeString.addAttribute(NSStrikethroughStyleAttributeName, value: 1, range: NSMakeRange(0, attributeString.length))
let specialPrice = specialLoop.value.replacingOccurrences(of: ".0000", with: "0")
print(specialPrice)
cell.productPrice.text = "$ \(specialPrice)"
cell.specialPriceLabel.isHidden = false
cell.specialPriceLabel.attributedText = attributeString
break
}
else {
cell.specialPriceLabel.isHidden = true
let price = arr.price
print(price)
cell.productPrice.text = "$ \( (price))0"
}
You can use (if let)
let data = [String: Any]()
if let value = data["key"] as? Int {
} else if let value = data["key"] as? Float {
} else if let value = data["key"] as? Double {
}
as describe below, you can find a type of any object (whether custom class or built-in class like - String, Int, etc.).
class demo {
let a: String = ""
}
let demoObj = demo()
print(type(of: demoObj))
--> Output: "demo.Type"
My code snippet is:
unwanted = " £€₹jetztabfromnow"
let favouritesPriceLabel = priceDropsCollectionView.cells.element(boundBy: UInt(index)).staticTexts[IPCUIAHighlightsPriceDropsCollectionViewCellPriceLabel].label
let favouritesPriceLabelTrimmed = favouritesPriceLabel.components(separatedBy: "jetzt").flatMap { String($0.trimmingCharacters(in: .whitespaces)) }.last
favouritesHighlightsDictionary[favouritesTitleLabel] = favouritesPriceLabelTrimmed
My problem is, this didn't work:
let favouritesPriceLabelTrimmed = favouritesPriceLabel.components(separatedBy: unwanted).flatMap { String($0.trimmingCharacters(in: .whitespaces)) }.last
I have a price like "from 3,95 €" - I want to cut all currencies "£€₹" and words like "from" or "ab"
Do you have a solution for me, what I can use here?
Rather than mess around with trying to replace or remove the right characters or using regular expressions, I'd go with Foundation's built-in linguistic tagging support. It will do a lexical analysis of the string and return tokens of various types. Use it on this kind of string and it should reliably find any numbers in the string.
Something like:
var str = "from 3,95 €"
let range = Range(uncheckedBounds: (lower: str.startIndex, upper: str.endIndex))
var tokenRanges = [Range<String.Index>]()
let scheme = NSLinguisticTagSchemeLexicalClass
let option = NSLinguisticTagger.Options()
let tags = str.linguisticTags(in: range, scheme: scheme, options: option, orthography: nil, tokenRanges: &tokenRanges)
let tokens = tokenRanges.map { str.substring(with:$0) }
if let numberTagIndex = tags.index(where: { $0 == "Number" }) {
let number = tokens[numberTagIndex]
print("Found number: \(number)")
}
In this example the code prints "3,95". If you change str to "from £28.50", it prints "28.50".
One way is to place the unwanted strings into an array, and use String's replacingOccurrences(of:with:) method.
let stringToScan = "£28.50"
let toBeRemoved = ["£", "€", "₹", "ab", "from"]
var result = stringToScan
toBeRemoved.forEach { result = result.replacingOccurrences(of: $0, with: "") }
print(result)
...yields "28.50".
If you just want to extract the numeric value use regular expression, it considers comma or dot decimal separators.
let string = "from 3,95 €"
let pattern = "\\d+[.,]\\d+"
do {
let regex = try NSRegularExpression(pattern: pattern, options: [])
if let match = regex.firstMatch(in: string, range: NSRange(location: 0, length: string.utf16.count)) {
let range = match.range
let start = string.index(string.startIndex, offsetBy: range.location)
let end = string.index(start, offsetBy: range.length)
print(string.substring(with: start..<end)) // 3,95
} else {
print("Not found")
}
} catch {
print("Regex Error:", error)
}
I asked if you had a fixed locale for this string, because then you can use the locale to determine what the decimal separator is: For example, try this in a storyboard.
let string = "some initial text 3,95 €" // define the string to scan
// Add a convenience extension to Scanner so you don't have to deal with pointers directly.
extension Scanner {
func scanDouble() -> Double? {
var value = Double(0)
guard scanDouble(&value) else { return nil }
return value
}
// Convenience method to advance the location of the scanner up to the first digit. Returning the scanner itself or nil, which allows for optional chaining
func scanUpToNumber() -> Scanner? {
var value: NSString?
guard scanUpToCharacters(from: CharacterSet.decimalDigits, into: &value) else { return nil }
return self
}
}
let scanner = Scanner(string: string)
scanner.locale = Locale(identifier: "fr_FR")
let double = scanner.scanUpToNumber()?.scanDouble() // -> double = 3.95 (note the type is Double?)
Scanners are a lot easier to use than NSRegularExpressions in these cases.
You can filter by special character by removing alphanumerics.
extension String {
func removeCharacters(from forbiddenChars: CharacterSet) -> String {
let passed = self.unicodeScalars.filter { !forbiddenChars.contains($0) }
return String(String.UnicodeScalarView(passed))
}
}
let str = "£€₹jetztabfromnow12"
let t1 = str.removeCharacters(from: CharacterSet.alphanumerics)
print(t1) // will print: £€₹
let t2 = str.removeCharacters(from: CharacterSet.decimalDigits.inverted)
print(t2) // will print: 12
Updated 1:
var str = "£3,95SS"
str = str.replacingOccurrences(of: ",", with: "")
let digit = str.removeCharacters(from: CharacterSet.decimalDigits.inverted)
print(digit) // will print: 395
let currency = str.removeCharacters(from: CharacterSet.alphanumerics)
print(currency) // will print: £
let amount = currency + digit
print(amount) // will print: £3,95
Update 2:
let string = "£3,95SS"
let pattern = "-?\\d+(,\\d+)*?\\.?\\d+?"
do {
let regex = try NSRegularExpression(pattern: pattern, options: [])
if let match = regex.firstMatch(in: string, range: NSRange(location: 0, length: string.utf16.count)) {
let range = match.range
let start = string.index(string.startIndex, offsetBy: range.location)
let end = string.index(start, offsetBy: range.length)
let digit = string.substring(with: start..<end)
print(digit) //3,95
let symbol = string.removeCharacters(from: CharacterSet.symbols.inverted)
print(symbol) // £
print(symbol + digit) //£3,95
} else {
print("Not found")
}
} catch {
print("Regex Error:", error)
}
I have the following string I would like to edit:
var someString = "I wan't this text {something I don't want}"
I would like to remove all the text contained in the two braces, no matter how long that text is. I have been using the follow code to remove a section of a String when I know the range:
extension String {
mutating func deleteCharactersInRange(range: NSRange) {
let mutableSelf = NSMutableString(string: self)
mutableSelf.deleteCharactersInRange(range)
self = mutableSelf
}
}
However, I do not know the range in my problem. Any ideas?
Working with strings and ranges can be quite challenging when mixing NSString and NSRange with Swift's String and Range.
Here is a pure Swift solution.
var someString = "I wan't this text {something I don't want}"
let rangeOpenCurl = someString.rangeOfString("{")
let rangeCloseCurl = someString.rangeOfString("}")
if let startLocation = rangeOpenCurl?.startIndex,
let endLocation = rangeCloseCurl?.endIndex {
someString.replaceRange(startLocation ..< endLocation, with: "")
}
With a RegEx pattern to match anything enclosed with curly brackets:
var sourceString: String = "I wan\'t this text {something I don't want}"
let destinationString = sourceString.stringByReplacingOccurrencesOfString("\\{(.*?)\\}", withString: "", options: .RegularExpressionSearch)
print(destinationString)
This will print "I wan't this text " without the double quotes.
extension String {
func getCurlyBraceRanges() -> [NSRange] {
var results = [NSRange]()
var leftCurlyBrace = -1
for index in 0..<self.characters.count {
let char = self[self.startIndex.advancedBy(index)]
if char == Character("{") {
leftCurlyBrace = index
} else if char == Character("}") {
if leftCurlyBrace != -1 {
results.append(NSRange(location: leftCurlyBrace, length: index - leftCurlyBrace + 1))
leftCurlyBrace = -1
}
}
}
return results
}
mutating func deleteCharactersInRange(range: NSRange) {
let mutableSelf = NSMutableString(string: self)
mutableSelf.deleteCharactersInRange(range)
self = String(mutableSelf)
}
mutating func deleteCharactersInRanges(ranges: [NSRange]) {
var tmpString = self
for i in (0..<ranges.count).reverse() {
tmpString.deleteCharactersInRange(ranges[i])
print(tmpString)
}
self = tmpString
}
}
var testString = "I wan't this text {something I don't want}"
testString.deleteCharactersInRanges(testString.getCurlyBraceRanges())
Output: "I wan't this text "
Here's what I am trying to do :
let courseName = "Bachelor of Tourism Administration(B.T.A)".condensedWhitespace
let upperCaseCourseName = courseName.uppercaseString
let extrctCourseName = upperCaseCourseName.componentsSeparatedByString(" ").reduce("") { $0.0 + String($0.1.characters.first!) }
let upperCasecourseFirstCharcters = extrctCourseName
print(upperCasecourseFirstCharcters) // output : "BOTA" but i want "BTA"
as you see that my outPut of "Bachelor of Tourism Administration(B.T.A)" is BOTA but the desired output is BTA because word of is starting from a lowerCase and i want to ignore that word in my this method , how am gonna do that any idea ?
let courseName = "Bachelor of Tourism Administration(B.T.A)" //.condensedWhitespace
var newString = ""
let array : NSArray = courseName.componentsSeparatedByString(" ")
for chr in array {
let str = chr as! NSString
if str.lowercaseString != str{
if newString.characters.count > 0{
newString = newString.stringByAppendingString(" "+(str as String))
continue
}
newString = newString.stringByAppendingString((str as String))
}
}
let upperCaseCourseName = newString.uppercaseString
let extrctCourseName = upperCaseCourseName.componentsSeparatedByString(" ").reduce("") { $0.0 + String($0.1.characters.first!) }
let upperCasecourseFirstCharcters = extrctCourseName
print(upperCasecourseFirstCharcters)
//This will defiantly meet to your problem/. Let me know if it works for u or not
You can paste this into a playground:
extension String {
func array() -> [String] {
return self.componentsSeparatedByString(" ")
}
func abbreviate() -> String {
var output = ""
let array = self.array()
for word in array {
let index = word.startIndex.advancedBy(0)
let str = String(word[index])
if str.lowercaseString != str {
output += str
}
}
return output
}
}
let courseName = "Bachelor of Tourism Administration(B.T.A)".abbreviate()
print(courseName) // prints BTA
A clean approach would be:
extension Character
{
public func isUpper() -> Bool
{
let characterString = String(self)
return (characterString == characterString.uppercaseString) && (characterString != characterString.lowercaseString)
}
}
let courseName = "Bachelor of Tourism Administration(B.T.A)"
let upperCaseCourseName = courseName
let extrctCourseName = upperCaseCourseName.componentsSeparatedByString(" ").reduce("") {
if($0.1.characters.first!.isUpper()) {
return $0.0 + String($0.1.characters.first!)
}else {
return $0.0
}
}