iOS: ActionSheetStringPicker successAction: wrong selection - ios

Question

I am using the ActionSheetStringPicker from the ActionSheetPickers3.0 (since I no longer can use the old picker views because of iOS 8). This is how I am calling the method:
ActionSheetStringPicker *genderPicker = [[ActionSheetStringPicker alloc]
initWithTitle:#"Gender" rows:categoryTypes initialSelection:nil target:self
successAction:#selector(selectedGender:) cancelAction:#selector(cancelledGender)
origin:gender];
[genderPicker showActionSheetPicker];
My success action code is this:
-(void) selectedGender:(NSNumber *)genderSelected {
NSLog(#"selected gender: %#",genderSelected);
if (genderSelected == 0) {
NSLog(#"male");
gender.text = #"Male";
} else {
NSLog(#"female");
gender.text = #"Female";
}
}
I am getting either a 1 or 0 value from the selected gender (male/female) when I NSLog the genderSelected value. My problem is that in my if-statement it always says I picked female. I'm getting the correct value that I select from the picker, but can't seem to figure out what the problem is. Does anyone know how I can get my if-statement working? Thanks!

Answer 1

In your success callback method the parameter you are getting is of type NSNumber. You cannot directly compare the object of type NSNumber with int value 0. Therefore use the following :
if (genderSelected.intValue == 0) {
NSLog(#"male");
gender.text = #"Male";
} else {
NSLog(#"female");
gender.text = #"Female";
}

Answer 2

Well this isn't exactly what I was looking for, but it worked. I set the NSNumber that I was getting as an NSString then compared to a "0" and "1" string. Here is my solution:
-(void) selectedGender:(NSNumber *)genderSelected {
NSString *string = [NSString stringWithFormat:#"%#",genderSelected];
if ([string isEqualToString:#"0"]) {
NSLog(#"male");
} else if ([string isEqualToString:#"1"]) {
NSLog(#"female");
}
}