I'm drawing a Circle using ol.interaction.Draw.
this.draw = new ol.interaction.Draw({
source: this.vectorSource,
type: 'Circle'
});
this.draw.on('drawend', function( evt ){
// evt.feature have no geometry !!!
}
But How can I get the Circle geometry or anything that tell me how to draw same circle again?
OL3.0 you can create/edit Features, but not Circles... http://openlayers.org/en/v3.0.0/examples/draw-and-modify-features.html
OL3.5 you can create circles, but you can't edit .... http://openlayers.org/en/v3.5.0/examples/draw-features.html
OL_Latest you can't edit circles too: http://openlayers.org/en/latest/examples/draw-and-modify-features.html
I would be happy if I could reproduce the same circle later.
To get the center and radius of the circle feature drawn use the below code
this.draw.on('drawend', function( evt ){
var geometry = evt.feature.getGeometry();
var radius = geometry.getRadius();
var center = geometry.getCenter();
// .... your code
});
Since a circle is drawn the Geometry type would be of type ol.geom.Circle.
Using this Geometry object you can get the radius and center using getRadius() and getCenter() method. For more information about ol.geom.Circle go through this link.
http://openlayers.org/en/latest/apidoc/ol.geom.Circle.html
Almost there!
I'm now able to reproduce the "circle" by adding a geometry function to the draw intaraction.
var geometryFunction = ol.interaction.Draw.createRegularPolygon(90);
this.draw = new ol.interaction.Draw({
source: this.vectorSource,
type: 'Circle',
geometryFunction: geometryFunction,
});
this will generate geometries to the feature so I can store it and load it again later, but it is not a real circle, it is just composed by a 90 points polygon. so I can't edit it as a circle.
Some idea to get the radius of this geometry?
{"type":"Feature","geometry":{"type":"Polygon","coordinates":[[[-4804935.286197088,-2605909.2147242804],[-4804836.58537814,-2605831.0293000625],[-4804743.578928918,-2605746.149310523],[-4804656.719967494,-2605654.988282439],[-4804576.431661996,-2605557.9903431754],[-4804503.105168979,-2605455.6280569425],[-4804437.097727745,-2605348.4001225093],[-4804378.730919913,-2605236.8289435934],[-4804328.289102704,-2605121.458083764],[-4804286.018023582,-2605002.849618253],[-4804252.123622994,-2604881.581395582],[-4804226.771031053,-2604758.244222341],[-4804210.083763039,-2604633.4389848416],[-4804202.143117644,-2604507.773721655],[-4804202.987780893,-2604381.8606613115],[-4804212.613637674,-2604256.3132395847],[-4804230.973791778,-2604131.7431108924],[-4804257.978794381,-2604008.757168381],[-4804293.497079825,-2603887.954587199],[-4804337.355606593,-2603769.923905379],[-4804389.340700352,-2603655.2401565393],[-4804449.199094949,-2603544.462068375],[-4804516.639166305,-2603438.1293405974],[-4804591.332353169,-2603336.7600155673],[-4804672.914757844,-2603240.8479544464],[-4804760.988919055,-2603150.860431155],[-4804855.125748342,-2603067.2358558625],[-4804954.866620535,-2602990.3816390927],[-4805059.72560813,-2602920.672206864],[-4805169.19184868,-2602858.4471765244],[-4805282.732033666,-2602804.009702166],[-4805399.793006718,-2602757.6249976917],[-4805519.804458544,-2602719.5190447196],[-4805642.1817054115,-2602689.8774916218],[-4805766.328537677,-2602668.8447490656],[-4805891.640124453,-2602656.5232864586],[-4806017.505960285,-2602652.973132728],[-4806143.312839472,-2602658.211583866],[-4806268.447843544,-2602672.213118665],[-4806392.301327342,-2602694.909523055],[-4806514.269889141,-2602726.1902224356],[-4806633.759310369,-2602765.902820383],[-4806750.187450577,-2602813.8538411125],[-4806862.987083566,-2602869.809672071],[-4806971.608660867,-2602933.4977020747],[-4807075.522989073,-2603004.607649443],[-4807174.22380802,-2603082.793073661],[-4807267.230257243,-2603167.6730632004],[-4807354.089218667,-2603258.834091285],[-4807434.3775241645,-2603355.8320305482],[-4807507.704017182,-2603458.194316781],[-4807573.711458416,-2603565.4222512143],[-4807632.078266247,-2603676.99343013],[-4807682.520083456,-2603792.3642899594],[-4807724.791162578,-2603910.972755471],[-4807758.685563167,-2604032.240978142],[-4807784.038155108,-2604155.5781513825],[-4807800.725423122,-2604280.383388882],[-4807808.666068517,-2604406.0486520687],[-4807807.821405267,-2604531.961712412],[-4807798.195548487,-2604657.509134139],[-4807779.8353943825,-2604782.0792628312],[-4807752.83039178,-2604905.0652053426],[-4807717.312106336,-2605025.867786525],[-4807673.453579567,-2605143.8984683445],[-4807621.468485809,-2605258.5822171844],[-4807561.610091211,-2605369.3603053484],[-4807494.170019856,-2605475.693033126],[-4807419.4768329915,-2605577.0623581563],[-4807337.8944283165,-2605672.974419277],[-4807249.8202671055,-2605762.9619425684],[-4807155.683437819,-2605846.586517861],[-4807055.9425656255,-2605923.440734631],[-4806951.083578031,-2605993.1501668594],[-4806841.61733748,-2606055.375197199],[-4806728.077152494,-2606109.8126715575],[-4806611.016179442,-2606156.197376032],[-4806491.004727617,-2606194.303329004],[-4806368.627480749,-2606223.944882102],[-4806244.480648483,-2606244.977624658],[-4806119.169061707,-2606257.299087265],[-4805993.303225876,-2606260.8492409955],[-4805867.496346689,-2606255.610789858],[-4805742.361342616,-2606241.6092550587],[-4805618.507858818,-2606218.9128506687],[-4805496.539297019,-2606187.632151288],[-4805377.049875791,-2606147.9195533404],[-4805260.621735584,-2606099.968532611],[-4805147.822102594,-2606044.0127016525],[-4805039.200525293,-2605980.324671649],[-4804935.286197088,-2605909.2147242804]]]},"properties": null}
The Polygon's centroid can be the circle center I think.... the distance of this centroid to any point in the border can be the radius.... I don't know how to get this using JS.
To take the center:
this.draw.on('drawend', function( evt ){
var aa = evt.feature.getGeometry().getExtent();
var oo = ol.extent.getCenter(aa);
console.log( oo );
});
Now I must find a way to take the radius.
I am using getLength to retrieve the linestring length.
For the same segment:
1- when using google map measure tool, I get 228m
2- when using IGN geoportail measure tool, I get 228m
3- when I use e.feature.getGeometry().getLength() I get 330m
Here are the flat coordinates:
e.feature.getGeometry().getFlatCoordinates() :
[571382.4214041593, 5723486.068714521, 571593.8175605105, 5723741.65502785]
in 4326:
[5.132815622245775, 45.644023326845485, 5.134714626228319, 45.64562844964627]
When I check the coordinates position on either ol3 or google map, I get the same points. The difference must come from the calcul...
Did I miss something and I should not use the getLength method? Please give me some direction if you think this is not an issue.
geometry.getLength() returns the length in the map view projection, which is usually spherical mercator. Spherical mercator distances are stretched at a rate of 1/cos(latitude); in your example: 228/330 ~ cos(45.64).
To get the real spherical distance:
var geometry = feature.getGeometry();
alert (geometry.getLength());
// get points of geometry (for simplicity assume 2 points)
var coordinates = geometry.getCoordinates();
// transform points from map projection (usually spherical mercator) to WGS84
var mapProjection = map.getView().getProjection();
var t1 = ol.proj.transform(coordinates[0], mapProjection, 'EPSG:4326');
var t2 = ol.proj.transform(coordinates[1], mapProjection, 'EPSG:4326');
// create sphere to measure on
var wgs84sphere = new ol.Sphere(6378137); // one of WGS84 earth radius'
// get distance on sphere
var dist = wgs84sphere.haversineDistance(t1, t2);
alert (dist);
For even higher accuracy you have to measure on the WGS84 ellipsoid instead of the sphere.
The above answer is correct, allthough if you are trying to get the length of a LinePoint with several positions it will only calculate between the first ones.
Here is a small addition on working with LinePoints with several positions:
var geometry = feature.getGeometry();
// get points of geometry (for simplicity assume 2 points)
var coordinates = geometry.getCoordinates();
// transform points from map projection (usually spherical mercator) to WGS84
var mapProjection = map.getView().getProjection();
// create sphere to measure on
var wgs84sphere = new ol.Sphere(6378137); // one of WGS84 earth radius'
var dist = 0;
//loop through all coordinates
for(var i = 0; i < coordinates.length -1; i++) {
var t1 = ol.proj.transform(coordinates[i], mapProjection, 'EPSG:4326');
var t2 = ol.proj.transform(coordinates[i+1], mapProjection, 'EPSG:4326');
// get distance on sphere
dist += wgs84sphere.haversineDistance(t1, t2);
}
alert(dist);
I am currently working on a openlayers 3 project and for better visulaizing i need to show both. The Polygon shape(attribute based color) which works great and an icon on the polygon position. I know that the polygon contains multiple coordinates and so its not so easy to define a position for the icon. Now i have some kind of workaround that creates an seperate overlay with the interior Points of the polygon to mark the position of the icons. To make the project more simple i want to combine these two styling. Does anyone know if its possible?
Kind Regards
I presumes that you use a ol.source.serversource for your data.
The trick is to test all your features for being a polygon. If it is, you create a point feature you add to your source.
First create the source and the layer:
var avlVectorSource = new ol.source.ServerVector({
format: new ol.format.GeoJSON(),
loader: function(extent, resolution, projection) {
myLoader(resolution);
}
});
var myLayer = new ol.layer.Vector({
source: myVectorSource,
style: myStyleFunction
});
The layer has a style function to set the right icon.
The main thing is the loader:
var myLoader = function(resolution){
$.ajax({
url: "http://myJsonSource.com",
timeout: 1000,
success: function(response) {
var layerJSONString = $.parseJSON(response);
var newFeatures = [];
j= 0;
var size=layerJSONString.features.length;
for (i = 0; i < size; i++){
var feat = layerJSONString.features[i];
var geom = feat.geometry;
var type = geom.type;
if(type == "Polygon")
{
var poly = new ol.geom.Polygon(geom.coordinates);
var extent = poly.getExtent();
var coord = [];
coord[0] = (extent[2]-extent[0])/2 + extent[0];
coord[1] = (extent[3]-extent[1])/2 + extent[1];
var point = new ol.geom.Point(coord);
newFeatures[j++] = new ol.Feature({
geometry : point,
StyleName : feat.properties.StyleName
});
}
}
avlVectorSource.addFeatures(myVectorSource.readFeatures(response));
avlVectorSource.addFeatures(newFeatures);
},
error: myLoadError
});
}
};
The documentation says that ol.geom.Polygon has a method called getInteriorPoint(). It has but I can get it to work. So I calculate the center point of the extent of the polygon.
I use "StyleName" to set the right icon in my style function.
How can I center a map between two points? Sort of like when the native map application generates directions between location A and location B. I'm got a start coordinate and an end coordinate and I'll like to show two pins. I can place the pins in place, but I'm not sure how to set the center of the map.
Do I need to find the math to work out the exact distance from the points and set the map to that location? Is there a built in function for this?
this.currentMapView.SetCenterCoordinate (annotation.Coordinate, true);
Calculating the midpoint between two coordinates needs a simple formula. For example, let's say you have two coordinates: (x1,y1) and (x2,y2).
Their midpoint coordinate is: ( (x1+x2)/2, (y1+y2)/2 ).
So for example, in map coordinates, let's say you have the following start/end points:
a. long: 40, lat: 39
b. long: 41, lat: 38
Their midpoint coordinate is: ( (40+41)/2, (39+38)/2 ) = (40.5, 38.5)
So you set the map view's center coordinate to the outcome of this formula.
I am not aware of a built-in function for calculating this.
Taken from: http://codisllc.com/blog/zoom-mkmapview-to-fit-annotations/
BasicMapAnnotation is inherit class from MKAnnotation
private void GetRegion(MKMapView mapView)
{
var userWasVisible = mapView.ShowsUserLocation;
mapView.ShowsUserLocation = false; // ignoring the blue blip
// start with the widest possible viewport
var tl = new CLLocationCoordinate2D(-90, 180); // top left
var br = new CLLocationCoordinate2D(90, -180); // bottom right
foreach (var an in mapView.Annotations)
{
// narrow the viewport bit-by-bit
CLLocationCoordinate2D coordinate = ((BasicMapAnnotation) an).Coordinate;
tl.Longitude = Math.Min(tl.Longitude, coordinate.Longitude);
tl.Latitude = Math.Max(tl.Latitude, coordinate.Latitude);
br.Longitude = Math.Max(br.Longitude, coordinate.Longitude);
br.Latitude = Math.Min(br.Latitude, coordinate.Latitude);
}
var center = new CLLocationCoordinate2D
{
// divide the range by two to get the center
Latitude = tl.Latitude - (tl.Latitude - br.Latitude)*0.5
,
Longitude = tl.Longitude + (br.Longitude - tl.Longitude)*0.5
};
var span = new MKCoordinateSpan
{
// calculate the span, with 20% margin so pins aren’t on the edge
LatitudeDelta = Math.Abs(tl.Latitude - br.Latitude)*1.2
,
LongitudeDelta = Math.Abs(br.Longitude - tl.Longitude)*1.2
};
var region = new MKCoordinateRegion {Center = center, Span = span};
region = mapView.RegionThatFits(region); // adjusts zoom level too
mapView.SetRegion(region, true); // animated transition
mapView.ShowsUserLocation =
userWasVisible;
}
} ``