Take Screenshot of UIImageView and UILabel then Share it - ios

Question

I think I'm near to solving the problem. I've a UItableView with a prototype cell which looks like this:
The gray-scale background image you see is coming from server and the text is the overlay text which is a UILabel on it and will change on every image which is also in the server. So it's like two layers which I'm trying to send. Third red button is the button of share and say I select share this image in email this function will be called:
-(UIImage *)makeImageofCell:(NSUInteger)sender
{
HomeCell *cellObj;
cellObj.tag = sender;
UIGraphicsBeginImageContext(cellObj.homeImg.frame.size );
[cellObj.homeImg.layer renderInContext:UIGraphicsGetCurrentContext()];
[cellObj.overlayText.layer renderInContext:UIGraphicsGetCurrentContext()];
UIImage *viewImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return viewImage;
}
In -(void)shareButtonClicked:(UIButton*)sender I've written the code of sharing. Now in this function I want to send that image. Here is what I'm doing: UIImage *imageToShare = [self makeImageofCell:sender.tag]; which is calling the makeImageofCell function and assigning it's value to a UIImage. So I'm writing this to share that URL.
NSString *imageToShare = [NSString stringWithFormat:#"Hey! Check out this Image %#",imageToShare];
But all I'm getting is Image is: (null). Any idea how this can be achieved?

Answer 1

Please following code for the screen shot of UIWindow You just replace with you custom view or cell.
- (UIImage*)takeScreenshot
{
// get the key-window references
UIWindow *keyWindow = [[UIApplication sharedApplication] keyWindow];
// manipulate boundries of key-window
CGRect rect = [keyWindow bounds];
// create context using size
UIGraphicsBeginImageContextWithOptions(rect.size,YES,0.0f);
// get the context reference
CGContextRef context = UIGraphicsGetCurrentContext();
// render in context
[keyWindow.layer renderInContext:context];
// get the rendered image
UIImage *capturedScreen = UIGraphicsGetImageFromCurrentImageContext();
// complete context
UIGraphicsEndImageContext();
// return image
return takeScreenshot;
}
Edited
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
UIButton *btnShareImage = (UIButton*)[cell1 viewWithTag:KTAGABSENTBUTTON];
[btnShareImage addTarget:self action:#selector(shareImageAction:) forControlEvents:UIControlEventTouchUpInside];
[btnShareImage setTitle:[NSString stringWithFormat:#"%li %li",(long)indexPath.section,(long)indexPath.row] forState:UIControlStateDisabled];
return cell;
}
-(void)shareImageAction:(UIButton*)sender{
NSString *str=[sender titleForState:UIControlStateDisabled];
NSArray *ar=[str componentsSeparatedByString:#" "];
NSIndexPath *indexPath=[NSIndexPath indexPathForRow:[[ar objectAtIndex:1] intValue] inSection:[[ar objectAtIndex:0] intValue]];
HomeCell *cellObj = (HomeCell*) [yourTableView cellForRowAtIndexPath:indexPath];
UIImage *imageToShare = [self makeImageofCell:cellObj];
}
-(UIImage *)makeImageofCell:(HomeCell*)cellObj
{
UIGraphicsBeginImageContext(cellObj.homeImg.frame.size );
[cellObj.homeImg.layer renderInContext:UIGraphicsGetCurrentContext()];
[cellObj.overlayText.layer renderInContext:UIGraphicsGetCurrentContext()];
UIImage *viewImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
return viewImage;
}
May this help to you.