SP2-0310: unable to open file "dba_files_all.sql" - sqlplus

Please advise. This SQLPlus call:
SQL > #dba_files_all
...is not working.
SP2-0310: unable to open file "dba_files_all.sql"
How can I resolve the error?

You need to provide the path of the file as string.
Put the path in double quotes and it will work.
For example:
#"C:\Users\Arpan Saini\Zions R2\Reports Statements and Notices\Patch\08312017_Patch_16.2.3.17\DB Scripts\snsp.sql";

I encountered this error when attempting to execute a file in the same folder as the calling function. In my example, this process:
Was executed in SQL Developer;
Has been a long-standing part of my system (moving a setup file with some settings and variable names through various folders; those folder names include the feature IDs and a short description);
Has worked fine in the past;
Did not require any pathing in my case because the files were in the same folder;
Failed on the most recent attempt with the error above (SP2-0310).
The issue in my situation was that the folder name in which it failed included a character (#) that was valid for a Windows file name, but confusing to SQL Developer.

1.Use absolute path:
/u01/app/oaracle/test.sql
2.Check the path to see if script exists:
ls -l /u01/app/oaracle/test.sql

Note that
SQL> #some_file.sql
means that sql app you are using will look for that using "absolute path" so if you want to use "relative path" use following format [add ?]
SQL> #?some_file.sql
else, use "full path" with first command.

All the answers so far imply that absolute paths are required. That aren't. Relative paths in sql is pretty universal in sql tools. Sometimes, you have to configure a lost default configuration such as in the case of SQLDeveloper as explained in this answer:
https://stackoverflow.com/a/24003529/442968

I just run into same error when I was trying to unlock oe schema.
While reading the error, I realized that when I run the following line:
>SQL #?/demo/schema/order_entry/oe_main.sql
The error returned a completely different path
SP2-0310: unable to open file "C:/app/USER/product/18.0.0/dbhomeXE/demo/schema/order_entry/oe_main.sql"
Thus I copied my sql file to the path specified by the error and everything worked. I recommend that you do the same. Check the path in the error and adjust accordingly.

Use absolute path or run sqlplus command from a shell/dos that points to the path of the script. Also, to use a masterscript, refer to subscripts with ##.

verify that your file has an extension .sql not .sql.txt

Related

Where should the erlang_ls.config go

I want to use coc.nvim and elrang_ls in vim8.2. There are some problems. It report missing an erlang_ls.config when I open a erlang file. But i have erlang_ls.config in project root.
the result of CocCommand workspace.showOutput show it read config from unexpected place
Where is correct position for erlang_ls.config?
Sorry for my poor English. Thanks.
It is possible to customize the behaviour of the erlang_ls server via
a configuration file, named erlang_ls.config. The erlang_ls.config
file should be placed in the root directory of a given project to
store the configuration for that project.
According to the picture, the clue has already been given to you. In the els_config.erl file consult_config function, line 126. error type = 2.
I think the information is enough, you can find source code file and read it and find why?
It is need create erlang_ls.config in C:\Users\Administrator\AppData\Roaming\erlang_ls and erlang_ls.config erlang_ls.yaml in the project root path. But I don't know why.

Erlang : exception error: no match of right hand side value {error,enoent} while reading a text file

I am currenly working on an erlang project and stuck in reading the file. I want to read a text file which is in the /src folder where all the erlang and a text file are in the same structure. Then too, I am not being able to read the file despite of specifying file paths. Any help would be appreciated.
start() ->
{ok,DataList} = file:consult("Calls.txt"),
io:format("** Calls to be made **"),
io:fwrite("~w~n",[DataList]).
The data file stores contents like : {john, [jill,joe,bob]}.
Try add folder name to the path or try set full patch to the file:
1> {ok,DataList} = file:consult("src/Calls.txt").
Notes: the error {error,enoent} mean that the file does not exist or you don't have a rights to read/write current file, for this case need set 777 rights or similar.
If you need to use src/call.txt, then this simply means that your IDE (or you) has created a src folder in which the calls.txt file has been placed. At the same time, the IDE is using a path that only includes the top level folder (i.e., the root folder for the IDE project). So src/call.txt must be used in that case. This isn’t a problem with Erlang, or even the IDE. It’s just the way your project is set up.
You can do either of two things. Move the calls.txt file up one level in the IDE file manager, so that it can be referenced as calls.txt, not src/call.txt. You can also just change the path to “calls.txt” before you run it from the command line.
enoent means "Error: No Entry/Entity". It means the file couldn't be found. When I try your code, it works correctly and outputs
[{john,[jill,joe,bob]}]

'C:\Program' is not recognized error

I set ANT_HOME=C:\Program Files\ant-1.8.0
then try to build local host by Weblogic. But, it gives me the following error:
C:\Program' is not recognized as an internal or external command.
I already tried putting quotes when defining the variable: "ANT_HOME=C:\Program Files\ant-1.8.0". but it is not working either, it shows the following error message:
Files\ant-1.8.0""=="" was unexpected at this time.
I have been stuck here for the past few weeks. Iv'e googled it many times but I still cant resolve the problem.
Edited:
dir c:\pro /x
didn't show the Progra~1 and Progra~2
set "var=content" is a good practice to avoid having unintended trailing spaces, but your error occures when using the value. There you need qoutes (that are not part of your variable content with the above syntax):
set "folder=c:\program Files"
dir %folder%
dir "%folder%"
the first dir will give you "file not found", because it tries to show you the contents of c:\program (which doesn't exist) plus the contents of files (which also doesn't exist). The second dir will show you successfully the contents of "c:\program files"
Even current versions of Windows automatically create a second file name which adheres to the old 8.3 naming scheme which has been there since DOS was invented. This name does not contain a space character which makes it a good candidate to be used in scenarios like that described by you.
Unless this has been explicitly disabled you can show the alternative filenames.
Open a dosbox and enter dir C:\pro* /x. The result will be similar to this:
I ran this on a German Windows 10 Pro but the output will be identical on other versions of Windows.
You can see that for C:\Program Files Windows created an alternative name C:\Progra~1.

Process Task - Unzipping files is failing

I am using sql 2012 SSIS process task to unzip my files but I am getting the following error
[Execute Process Task] Error:
In Executing "C:\Windows\System32\compact.exe" "x F:\Imports\RenLearn\'Roseville City School District'.zip -oF:\Imports\RenLearn\Roseville City School District" at "",
The process exit code was "1" while the expected was "0".
The two paths above are created as variables along with the path to . Any suggestions and thanks ahead of time.
I had the exact same problem and I realised that I had copied the .exe file in the same folder as the .zip files because this resolved my problem in BIDS, but in Data Tools it seems like necessary to do that.. sounds little weird, but it worked for me so perhaps it will for you as well. :-)
If you have set the "Working directory" property, you need to remove it to make the task work.
Remove the space in zip file name as the Execute process fails if the file contains special characters. Instead of spaces, use "_" and try it. Even the same issue I got later was sorted out by this approach.

directory path question

What is the difference between:
include("./somepath/class.php");
and
include("somepath/class.php");
There shouldn't be any difference, directory wise, since the former assumes relative directory structure. The only potential pitfall could be if "somepath" were actually a command to be run - some users expect to type a command for a local script file and assume it should run, when you actually have to run "./somepath" to invoke it. This, of course, only pertains to commands not on your $PATH.
I don't see any difference. "." means current directory.
. refers to the current working directory.
Sometimes you want to specify explicitly that what you want is in the current working directory, and that it is not from something in your path variable for example.
For example in PHP "somepath/somefile" is appended after paths specified in include_dir (for example: /home/var/; /home/bin/ ....) directive.
The second variant is more specific it says: search in current directory!

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