How to compare two strings ignoring case in Swift language? - ios

Question

How can we compare two strings in swift ignoring case ?
for eg :
var a = "Cash"
var b = "cash"
Is there any method that will return true if we compare var a & var b

Answer 1

Try this :
For older swift:
var a : String = "Cash"
var b : String = "cash"
if(a.caseInsensitiveCompare(b) == NSComparisonResult.OrderedSame){
println("Et voila")
}
Swift 3+
var a : String = "Cash"
var b : String = "cash"
if(a.caseInsensitiveCompare(b) == .orderedSame){
print("Et voila")
}

Answer 2

Use caseInsensitiveCompare method:
let a = "Cash"
let b = "cash"
let c = a.caseInsensitiveCompare(b) == .orderedSame
print(c) // "true"
ComparisonResult tells you which word comes earlier than the other in lexicographic order (i.e. which one comes closer to the front of a dictionary). .orderedSame means the strings would end up in the same spot in the dictionary

Answer 3

if a.lowercaseString == b.lowercaseString {
//Strings match
}

Answer 4

Try this:
var a = "Cash"
var b = "cash"
let result: NSComparisonResult = a.compare(b, options: NSStringCompareOptions.CaseInsensitiveSearch, range: nil, locale: nil)
// You can also ignore last two parameters(thanks 0x7fffffff)
//let result: NSComparisonResult = a.compare(b, options: NSStringCompareOptions.CaseInsensitiveSearch)
result is type of NSComparisonResult enum:
enum NSComparisonResult : Int {
case OrderedAscending
case OrderedSame
case OrderedDescending
}
So you can use if statement:
if result == .OrderedSame {
println("equal")
} else {
println("not equal")
}

Answer 5

localizedCaseInsensitiveContains : Returns whether the receiver contains a given string by performing a case-insensitive, locale-aware search
if a.localizedCaseInsensitiveContains(b) {
//returns true if a contains b (case insensitive)
}
Edited:
caseInsensitiveCompare : Returns the result of invoking compare(_:options:) with NSCaseInsensitiveSearch as the only option.
if a.caseInsensitiveCompare(b) == .orderedSame {
//returns true if a equals b (case insensitive)
}

Answer 6

CORRECT WAY:
let a: String = "Cash"
let b: String = "cash"
if a.caseInsensitiveCompare(b) == .orderedSame {
//Strings match
}
Please note: ComparisonResult.orderedSame can also be written as .orderedSame in shorthand.
OTHER WAYS:
a.
if a.lowercased() == b.lowercased() {
//Strings match
}
b.
if a.uppercased() == b.uppercased() {
//Strings match
}
c.
if a.capitalized() == b.capitalized() {
//Strings match
}

Answer 7

Could just roll your own:
func equalIgnoringCase(a:String, b:String) -> Bool {
return a.lowercaseString == b.lowercaseString
}

Answer 8

For Swift 5
Ignoring the case and compare two string
var a = "cash"
var b = "Cash"
if(a.caseInsensitiveCompare(b) == .orderedSame){
print("Ok")
}

Answer 9

Phone numbers comparison example; using swift 4.2
var selectPhone = [String]()
if selectPhone.index(where: {$0.caseInsensitiveCompare(contactsList[indexPath.row].phone!) == .orderedSame}) != nil {
print("Same value")
} else {
print("Not the same")
}

Answer 10

You can just write your String Extension for comparison in just a few line of code
extension String {
func compare(_ with : String)->Bool{
return self.caseInsensitiveCompare(with) == .orderedSame
}
}

Answer 11

Swift 4, I went the String extension route using caseInsensitiveCompare() as a template (but allowing the operand to be an optional). Here's the playground I used to put it together (new to Swift so feedback more than welcome).
import UIKit
extension String {
func caseInsensitiveEquals<T>(_ otherString: T?) -> Bool where T : StringProtocol {
guard let otherString = otherString else {
return false
}
return self.caseInsensitiveCompare(otherString) == ComparisonResult.orderedSame
}
}
"string 1".caseInsensitiveEquals("string 2") // false
"thingy".caseInsensitiveEquals("thingy") // true
let nilString1: String? = nil
"woohoo".caseInsensitiveEquals(nilString1) // false

Answer 12

Swift 3: You can define your own operator, e.g. ~=.
infix operator ~=
func ~=(lhs: String, rhs: String) -> Bool {
return lhs.caseInsensitiveCompare(rhs) == .orderedSame
}
Which you then can try in a playground
let low = "hej"
let up = "Hej"
func test() {
if low ~= up {
print("same")
} else {
print("not same")
}
}
test() // prints 'same'

Answer 13

You could also make all the letters uppercase (or lowercase) and see if they are the same.
var a = “Cash”
var b = “CASh”
if a.uppercaseString == b.uppercaseString{
//DO SOMETHING
}
This will make both variables as ”CASH” and thus they are equal.
You could also make a String extension
extension String{
func equalsIgnoreCase(string:String) -> Bool{
return self.uppercaseString == string.uppercaseString
}
}
if "Something ELSE".equalsIgnoreCase("something Else"){
print("TRUE")
}

Answer 14

Swift 3
if a.lowercased() == b.lowercased() {
}

Answer 15

Swift 3:
You can also use the localized case insensitive comparison between two strings function and it returns Bool
var a = "cash"
var b = "Cash"
if a.localizedCaseInsensitiveContains(b) {
print("Identical")
} else {
print("Non Identical")
}

Answer 16

extension String
{
func equalIgnoreCase(_ compare:String) -> Bool
{
return self.uppercased() == compare.uppercased()
}
}
sample of use
print("lala".equalIgnoreCase("LALA"))
print("l4la".equalIgnoreCase("LALA"))
print("laLa".equalIgnoreCase("LALA"))
print("LALa".equalIgnoreCase("LALA"))