How to correctly use Resque workers? - ruby-on-rails

I have the following tasks to do in a rails application:
Download a video
Trim the video with FFMPEG between a given duration (Eg.: 00:02 - 00:09)
Convert the video to a given format
Move the converted video to a folder
Since I wanted to make this happen in background jobs, I used 1 resque worker that processes a queue.
For the first job, I have created a queue like this
#queue = :download_video that does it's task, and at the end of the task I am going forward to the next task by calling Resque.enqueue(ConvertVideo, name, itemId). In this way, I have created a chain of queues that are enqueued when one task is finished.
This is very wrong, since if the first job starts to enqueue the other jobs (one from another), then everything get's blocked with 1 worker until the first list of queued jobs is finished.
How should this be optimised? I tried adding more workers to this way of enqueueing jobs, but the results are wrong and unpredictable.
Another aspect is that each job is saving a status in the database and I need the jobs to be processed in the right order.
Should each worker do a single job from above and have at least 4 workers? If I double the amount to 8 workers, would it be an improvement?

Have you considered using sidekiq ?
As said in Sidekiq documentation :
resque uses redis for storage and processes messages in a single-threaded process. The redis requirement makes it a little more difficult to set up, compared to delayed_job, but redis is far better as a queue than a SQL database. Being single-threaded means that processing 20 jobs in parallel requires 20 processes, which can take a lot of memory.
sidekiq uses redis for storage and processes jobs in a multi-threaded process. It's just as easy to set up as resque but more efficient in terms of raw processing speed. Your worker code does need to be thread-safe.
So you should have two kind of jobs : download videos and convert videos and any download video job should be done in parallel (you can limit that if you want) and then each stored in one queue (the "in-between queue") before being converted by multiple convert jobs in parallel.
I hope that helps, this link explains quite well the best practices in Sidekiq : https://github.com/mperham/sidekiq/wiki/Best-Practices

As #Ghislaindj noted Sidekiq might be an alternative - largely because it offers plugins that control execution ordering.
See this list:
https://github.com/mperham/sidekiq/wiki/Related-Projects#execution-ordering
Nonetheless, yes, you should be using different queues and more workers which are specific to the queue. So you have a set of workers all working on the :download_video queue and then you other workers attached to the :convert_video queue, etc.
If you want to continue using Resque another approach would be to use delayed execution, so when you enqueue your subsequent jobs you specify a delay parameter.
Resque.enqueue_in(10.seconds, ConvertVideo, name, itemId)
The down-side to using delayed execution in Resque is that it requires the resque-scheduler package, so you're introducing a new dependency:
https://github.com/resque/resque-scheduler
For comparison Sidekiq has delayed execution natively available.

Have you considered merging all four tasks into just one? In this case you can have any number of workers, one will do the job. It will work very predictable, you can even know how much time will take to finish the task. You also don't have problems when one of the subtasks takes longer than all others and it piles up in the queue.

Related

How to make multiple parallel concurrent requests with Rails and Heroku

I am currently developing a Rails application which takes a long list of links as input, scrapes them using a background worker (Resque), then serves the results to the user. However, in some cases, there are numerous URLs and I would like to be able to make multiple requests in parallel / concurrency such that it would take much less time, rather than waiting for one request to complete to a page, scraping it, and moving on to the next one.
Is there a way to do this in heroku/rails? Where might I find more information?
I've come across resque-pool but I'm not sure whether it would solve this issue and/or how to implement. I've also read about using different types of servers to run rails in order to make concurrency possible, but don't know how to modify my current situation to take advantage of this.
Any help would be greatly appreciated.
Don't use Resque. Use Sidekiq instead.
Resque runs in a single-threaded process, meaning the workers run synchronously, while Sidekiq runs in a multithreaded process, meaning the workers run asynchronously/simutaneously in different threads.
Make sure you assign a URL to scrape per worker. It's no use if one worker scrape multiple URLs.
With Sidekiq, you can pass the link to a worker, e.g.
LINKS = [...]
LINKS.each do |link|
ScrapeWoker.perform_async(link)
end
The perform_async doesn't actually execute the job right away. Instead, the link is just put in a queue in redis along with the worker class, and so on, and later (could be milliseconds later) workers are assigned to execute each job in queue in its own thread by running the perform instance method in ScrapeWorker. Sidekiq will make sure to retry again if exception occur during execution of a worker.
PS: You don't have pass a link to the worker. You can store the links to a table and then pass the ids of the records to workers.
More info about sidekiq
Adding these two lines to your code will also let you wait until the last job is complete before proceeding:
this line ensures that your program waits for at least one job is enqueued before checking that all jobs are completed as to avoid misinterpreting an unfilled queue as the completion of all jobs
sleep(0.2) until Sidekiq::Queue.new.size > 0 || Sidekiq::Workers.new.size > 0
this line ensures your program waits till all jobs are done
sleep(0.5) until Sidekiq::Workers.new.size == 0 && Sidekiq::Queue.new.size == 0

How can I configure Delayed jobs to not wait for a task before starting the others?

I am using Delayed jobs for my Ruby app hosted in Heroku to perform a very long task that can take up to 5 minutes.
I've noticed that, in development mode at least, when this task is running the ones that come afterwards are not started until that one finishes. I would like other tasks to be able to start running without having to wait for the other to finish (to have at least 3 concurrent tasks, for example).
I don't wish to increase the number of workers in Heroku ($$$).
I noticed the 'pool' param in delayed jobs but I don't fully understand if this is what I need or how to use it.
https://github.com/collectiveidea/delayed_job/blob/master/README.md
I achieved it using threads in the task code, but maybe this is not the best way to do it.
If you could tell me exactly how I could achieve concurrency in delayed jobs I would really appreciate it.
A DJ worker only runs a single job at a time. If you want concurrent processing of your background jobs, you'll need multiple background workers.
You are way better off implementing sidekiq.

Does Sidekiq execute jobs in the order they are sent to a worker?

I have a rake task which is going to call 4 more rake tasks, in order:
rake:one
rake:two
rake:three
rake:four
Rake tasks one, two, and three are getting data and adding it to my database. Then rake:four is going to do something with that data. But I need to make sure that one, two, and three are complete first. Each rake task is actually spinning up Sidekiq workers to run in the background. In this scenario, would all of the workers created by rake:one finish first, then rake:two, etc?
If not, how can I ensure that the workers are executed in order?
Sidekiq processes jobs in the order which they are created, but by default it processes multiple jobs simultaneously, and there is no guarantee that a given job will finish before another job is started.
Quoting from https://github.com/mperham/sidekiq/wiki/FAQ:
How can I process a certain queue in serial?
You can't, by design. Sidekiq is designed for asynchronous processing
of jobs that can be completed in isolation and independent of each
other. Jobs will be popped off of Redis in the order in which they
were pushed but there's no guarantee that Job #1 will execute fully
before Job #2 is started.
If you need serial execution, you should look into other systems which
give those types of guarantees.
Note you can create a Sidekiq process dedicated to processing a queue
with a single worker. This will give you serial execution but it's a
hack.
Also note you can use third-party extensions for sidekiq to achieve
that goal.
You can simply create one meta rake task, which will include all those tasks in right order.
Or as a less hacky solution: reduce number of workers per queue to 1:
https://github.com/brainopia/sidekiq-limit_fetch#limits
And add all your jobs to this queue

Resque and resque-scheduler works in parallel

I have resque and resque-scheduler workers with 2 different queues,
they do the same task, fetch links for a certain website and save that links.
What will happen if resque-scheduler and resque workers work in parallel and do the same task (fetching links for the same website)? How can i handle such situations?
Either you have not clarified your setup or there are some big issues there. Resque and Resque-scheduler were meant to be run together. Resue-scheduler is only supposed to schedule tasks in the future. Such tasks are still executed by Resque workers. Please read this section on their homepage on github: https://github.com/resque/resque-scheduler#delayed-jobs. To quote them,
This will store the job ... in the resque delayed queue at
which time the scheduler process will pull it from the delayed queue
and put it in the appropriate work queue for the given job and it will
be processed as soon as a worker is available (just like any other
resque job).
So, there you go. Keep running your resque workers and schedulers together forever. To answer the other part of your question, if you schedule some task through scheduler and the same task is also queued for resque to pick up directly, the net outcome depends on the task execution logic. "Fetching something from a website" sounds a harmless thing to do twice. But if you update some transaction table to make payments to your vendors based on the result of the fetch, you are in deep trouble.

Improve Controller Performance Ruby on Rails

I have the following code in a controller
user = RegUser.create_reg_user(:some_parameters)
UserStuff.pass_user(some_parameters)
#hex = user.hex
The #hex is passed to the view and returned. The UserStuff call is taking a decent amount of time and is not actually important to the #hex which is needed for the view. Is there a way to go ahead and return the #hex and load the view and let the UserStuff process afterwards?
Offload these kinds of long running "jobs" to a background queue. Probably the easiest for you to get setup and running is Delayed Job.
We use Beanstalkd (a queue) and many worker processes to handle all long-running tasks (or any tasks that takes longer than 1-2 seconds).
The beauty of having a background system to process these kinds of jobs is that you can scale quickly, you can spin-up any number of worker processes which all pull jobs from a master queue (or DB in the case of Delayed Job).
Delayed Job is good, and easy to use. I recommend it.

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