How do I create and append to an associative array in Swift? I would think it should be something like the following (note that some values are strings and others are numbers):
var myArray = []
var make = "chevy"
var year = 2008
var color = "red"
myArray.append("trackMake":make,"trackYear":year,"trackColor":color)
The goal is to be able to have an array full of results where I can make a call such as:
println(myArray[0]["trackMake"]) //and get chevy
println(myArray[0]["trackColor"]) //and get red
Simply like this:
myArray.append(["trackMake":make,"trackYear":year,"trackColor":color])
Add the brackets. This will make it a hash and append that to the array.
In such cases make (extensive) use of let:
let dict = ["trackMake":make,"trackYear":year,"trackColor":color]
myArray.append(dict)
The above assumes that your myArray has been declared as
var myArray = [[String:AnyObject]]()
so the compiler knows that it will take dictionary elements.
I accept above answer.It is good.Even you have given correct answer,I like to give simplest way.The following steps are useful,if you guys follow that.Also if someone new in swift and if they go through this,they can easily understand the steps.
STEP 1 : Declare and initialize the variables
var array = Array<AnyObject>()
var dict = Dictionary<String, AnyObject>()
var make = "chevy"
var year = 2008
var color = "red"
STEP 2 : Set the Dictionary(adding keys and Values)
dict["trackMake"] = make
dict["trackYear"] = year
dict["trackColor"] = color
println("the dict is-\(dict)")
STEP 3 : Append the Dictionary to Array
array.append(dict)
println("the array is-\(array)")
STEP 4 : Get Array values to variable(create the variable for getting value)
let getMakeValue = array[0]["trackMake"]
let getYearValue = array[0]["trackYear"]
let getColorValue = array[0]["trackColor"]
println("the getMakeValue is - \(getMakeValue)")
println("the getYearValue is - \(getYearValue)")
println("the getColorVlaue is - \(getColorValue)")
STEP 5: If you want to get values to string, do the following steps
var stringMakeValue:String = getMakeValue as String
var stringYearValue:String = ("\(getYearValue as Int)")
var stringColorValue:String = getColorValue as String
println("the stringMakeValue is - \(stringMakeValue)")
println("the stringYearValue is - \(stringYearValue)")
println("the stringColorValue is - \(stringColorValue)")
STEP 6 : Finally the total output values are
the dict is-[trackMake: chevy, trackColor: red, trackYear: 2008]
the array is-[{
trackColor = red;
trackMake = chevy;
trackYear = 2008;
}]
the getMakeValue is - Optional(chevy)
the getYearValue is - Optional(2008)
the getColorVlaue is - Optional(red)
the stringMakeValue is - chevy
the stringYearValue is - 2008
the stringColorValue is - red
Thank You
This sounds like you are wanting an array of objects that represent vehicles. You can either have an array of dictionaries or an array of vehicle objects.
Likely you will want to go with an object as Swift arrays and dictionaries must be typed. So your dictionary with string keys to values of differing types would end up having the type [String : Any] and you would be stuck casting back and forth. This would make your array of type [[String : Any ]].
Using an object you would just have an array of that type. Say your vehicle object's type is named Vehicle, that would make your array of type [Vehicle] and each array access would return an instance of that type.
If I want to try it with my own statement. Which also I want to extend my array with the data in my dictionary and print just the key from dictionary:
var myArray = ["Abdurrahman","Yomna"]
var myDic: [String: Any] = [
"ahmed": 23,
"amal": 33,
"fahdad": 88]
for index in 1...3 {
let dict: [String: Any] = [
"key": "new value"
]
// get existing items, or create new array if doesn't exist
var existingItems = myDic[myArray] as? [[String: Any]] ?? [[String: Any]]()
// append the item
existingItems.append(myArray)
// replace back into `data`
myDic[myArray] = existingItems
}
Related
this might be a common situation, but I was not able to figure out a way how to do it.
I have a dictionary with the stock amount for several items: dict = ["item1" : 2, "item2" : 5, "item3" : 10 ]
How can I now assign the keys and values to different labels in a tableView, using indexPath?
The logic I want to achieve:
cell.itemLabel.text = dict.[firstItemName]
cell.amountLabel.text = dict.[firstItemAmount]
A dictionary as data source can be annoying because a dictionary is unordered.
My suggestion is to map the dictionary to an array of a custom struct and sort the array by the keys
struct Model {
let name : String
let value: Int
}
let dict = ["item1" : 2, "item2" : 5, "item3" : 10 ]
let array = dict.map(Model.init).sorted{$0.name < $1.name}
Then in the table view you can write
cell.itemLabel.text = array[indexPath.row].name
You can use map function to get separate array of key and values
print(dict.map({$0.key}))
print(dict.map({$0. value}))
Try this:
cell.itemLabel.text = dict.map({$0.key})[indexPath.row]
cell.amountLabel.text = dict.map({$0.value})[indexPath.row]
I just want to create a dictionary with the help of for loop
sample code :
var counter: Int = 1;
var pageCountDict = [String:Any]();
for filterCount in counter..<6
{
if let count = "page_\(filterCount)_vtime" as? String
{
pageCountDict = [count: timeInterval_Int];
}
}
print(pageCountDict);
This print command give me only last value of forloop
I just want all the value of this variable pageCountDict in a dictonary
The way to assign to a dictionary is first use the subscript and assign the value to it:
pageCountDict[YourKey] = YourValue
Also, you can see many examples and explanations in Apple documentation regarding dictionaries.
With each loop, you are replacing the dictionary with one that contains only one element. What you want to do is this :
pageCountDict[count] = timeInterval_Int
Also, you shouldn't need the as? String part. This should be sufficient :
for filterCount in counter..<6
{
pageCountDict[count] = "page_\(filterCount)_vtime"
}
var pageCountDict = [String:Any]()
You can add values to this dictionary by merging previous contents and new data as follows...
let counter: Int = 1
var pageCountDict = [String:Any]()
for filterCount in counter..<6
{
let value = 9
let count = "page_\(filterCount)_vtime" //'if' is not needed as it is always true
pageCountDict.merge([count: timeInterval_Int], uniquingKeysWith:{ (key, value) -> Any in
//assign value for similar key
timeInterval_Int
})
}
print(pageCountDict)`
I've seen a lot of answers to similar questions but none of the methods have worked so far.
if let users = snapshot.value!["users"] as? Dictionary<String,AnyObject> {
each.users = Int(users.count)
var pointsArray = [Dictionary<String,Int>]()
for (key, value) in users {
let uid = key
let points = value["points"] as! Int
pointsArray.append([uid : points])
}
I'm then needing to sort pointsArray by the "points", sort it from high to low, grab the 0th (highest) element, then grab the uid to use.
I've tried:
var myArr = Array(pointsArray.keys)
var sortedKeys = sort(myArr) {
var obj1 = dict[$0] // get ob associated w/ key 1
var obj2 = dict[$1] // get ob associated w/ key 2
return obj1 > obj2
}
This gives me
Value of type [ Dictionary <String,Int>] has no member keys.
I guess that's cause I'm trying to run the sort on my array of dicts vs the dicts themselves? How do I switch this up to get into the actual dictionaries vs. running the sort on the array?
Right - you're not properly accessing the keys of the dictionaries.
Here's a working code:
var pointsArray = [Dictionary<String, Int>]()
pointsArray.append(["1" : 10])
pointsArray.append(["2" : 45])
pointsArray.append(["3" : 30])
// sort by points
let sorted = pointsArray.sort({ $0.first!.1 > $1.first!.1 })
print(sorted) // [["2": 45], ["3": 30], ["1": 10]]
Array(pointsArray.keys) - this doesn't work, because pointsArray is an array, therefore it doesn't have keys property. The contents of pointsArray are dictionaries and they have keys. So you can access the keys of the first dictionary like this: pointsArray[0].keys
I am trying to get all the key values of NSMutableDictionary as String Array. I am using this myNSMutableDictionary.allkeys to get the values as an Array but I cannot find a way to unwrap the key values.
This is what I have tried so far:
for (key, _) in NSMutableDictionary {
println("THIS IS MY NEW KEY\(key)")
}
And I tried this
var myArray:NSArray = myNSMutableDictionary.allKeys
var string:NSString? = uniqueIDArray[0] as? NSString
println("This is unwraped value\(string!)")
And this
var myArray:Array = myNSMutableDictionary.allKeys
println("This is unwraped value\(myArray[0])")
I keep getting the value as Optional("kMSZgoTmiX") instead of kMSZgoTmiX which is the key value I need
Thank you for all your help!
So you've got a dictionary with values that are strings (and keys that are something, assume String):
var dictionaryOfStringValues : [String:String] = /* your dictionary */
And you want to iterate over the contents:
for (key, val) in dictionaryOfStringValues {
// use key and val
}
If you just want the values in a way you can easily iterate over:
var theValues = dictionaryOfStringValues.values
If you insist that theValues be an Array:
var theValuesAsAnArray = Array(dictionaryOfStringValues.values)
If you are starting with an NSMutableDictionary, then convert it at the point where it FIRST ENTERS your Swift code into a Swift Dictionary. Use an as variant to do that. After that, pure Swift.
Like this:
7> for (key, value) in ["a":1, "b":2] {
8. println (key)
9. println (value)
10. }
b
2
a
1
let myNSMutableDictionary = NSMutableDictionary()
myNSMutableDictionary["myKey1"] = 5
myNSMutableDictionary["myKey2"] = 10
myNSMutableDictionary["myKey3"] = 15
let myKeysArrayUnsorted = myNSMutableDictionary.allKeys as [String]
let myValuesArrayUnsorted = myNSMutableDictionary.allValues as [Int]
let keyString = myKeysArrayUnsorted[0] // "myKey2"
let keyValue = myNSMutableDictionary[keyString] as Int // 10
println("This is my first unsorted key \(keyString) = \(keyValue)")
let myKeysArraySorted = (myNSMutableDictionary.allKeys as [String]).sorted(<)
for key in myKeysArraySorted {
println(myNSMutableDictionary[key]!) // 5 10 15
}
var sourceEntries: [Entry] = [entry1, ..., entry14]
var myDict: Dictionary<String, [Entry]> = [:]
for entry in sourceEntries {
if var array = myDict[entry.attribute1] { theArray.append(entry) }
else { myDict[entry.attribute1] = [entry] }
}
I am intending to create a Dictionary, which matches all the objects of the struct "Eintrag" with the same attribute from the source-Array "alleEinträge" to a String containing the value of the shared attribute. For some reason my final Dictionary just matches Arrays of one element to the Strings, although some Arrays ought to contain up to four elements.
The problem is that the array is passed by value (i.e. "copied"), so the array you are writing to when you say array.append is not the array that is "inside" the dictionary. You have to write back into the dictionary explicitly if you want to change what's in it.
Try it in a simple situation:
var dict = ["entry":[0,1,2]]
// your code
if var array = dict["entry"] { array.append(4) }
// so what happened?
println(dict) // [entry: [0, 1, 2]]
As you can see, the "4" never got into the dictionary.
You have to write back into the dictionary explicitly:
if var array = dict["entry"] { array.append(4); dict["entry"] = array }
FURTHER THOUGHTS: You got me thinking about whether there might be a more elegant way to do what you're trying to do. I'm not sure whether you will think this is "more elegant", but perhaps it has some appeal.
I will start by setting up a struct (like your Entry) with a name attribute:
struct Thing : Printable {
var name : String
var age : Int
var description : String {
return "{\(self.name), \(self.age)}"
}
}
Now I will create an array like your sourceEntries array, where some of the structs share the same name (like your shared attribute attribute1):
let t1 = Thing(name: "Jack", age: 40)
let t2 = Thing(name: "Jill", age: 38)
let t3 = Thing(name: "Jill", age: 37)
let arr = [t1,t2,t3]
And of course I will prepare the empty dictionary, like your myDict, which I call d:
var d = [String : [Thing]]()
Now I will create the dictionary! The idea is to use map and filter together to do all the work of creating key-value pairs, and then we just build the dictionary from those pairs:
let pairs : [(String, [Thing])] = arr.map {
t in (t.name, arr.filter{$0.name == t.name})
}
for pair in pairs { d[pair.0] = pair.1 }