I need to open in the LinkedIn app a company url from my iOS app in Swift. I have tried to do that with URL Scheme, but I haven't achieved it.
This code open the LinkedIn app, but not in the url I need:
UIApplication.sharedApplication().openURL(NSURL(string: "linkedin://profile/xxx_id_company_xxx")!)
Can anyone help me?
Swift 4
In your info.plist under LSApplicationQueriesSchemes add
<string>linkedin</string>, then in your code just add
let webURL = URL(string: "https://www.linkedin.com/in/yourName-yourLastName-yourID/")!
let appURL = URL(string: "linkedin://profile/yourName-yourLastName-yourID")!
if UIApplication.shared.canOpenURL(appURL) {
UIApplication.shared.open(appURL, options: [:], completionHandler: nil)
} else {
UIApplication.shared.open(webURL, options: [:], completionHandler: nil)
}
It seems the correct format is "linkedin://companyName/companyId"
See this SO question: How can open LinkedIn Comapny Url in iPhone app programmatically?
This linkedin company url scheme is working for me
linkedin://company?id={company-id}
This objective c code trys to open linkedin company page in linkedin app and fall backs to a modal webview presenting company web page.
/* try to open linkedin app with company url */
if (![[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"linkedin://company?id=2589010"]]) {
/* Unable to open linked app, present web page with url #"https://www.linkedin.com/company/sesli-sozluk" */
...
}
You can find your "company id" in the source code of your company page on linkedin. Search for "company-id" or "companyId", it is in a hidden input field.
Related
I'm beginning iOS developer. I create an application that uses GitHub authorization. When I register a new OAuth application in GitHub developer program I must enter Authorization callback URL. But I do not have any site for my app. What do I need to specify in this field?
You can use deep linking.
you can read more about it here
The deeplink will try to open the app or redirect to it. The web browser or SFAuthenticationSession will close the browser and call the completion hander where you can check for the response code without any implementation for the deeplink.
To add the deep link in the app you can this below:
Select the project in Xcode navigator.
then select your target that you want to add the deep link to it.
select info from the top bar
at the bottom open the URL Types
add a name for the scheme
when you generate the URL for the oauth you can pass anything you want I just pass login in this example:
func getAuthenticateURL() -> URL {
var urlComponent = URLComponents(string: "https://github.com/login/oauth/authorize")!
var queryItems = urlComponent.queryItems ?? []
queryItems.append(URLQueryItem(name: "client_id", value: "YOUR_CLIENT_ID_HERE"))
queryItems.append(URLQueryItem(name: "redirect_uri", value: "APP_SCHEME_GOES_HERE://login"))
urlComponent.queryItems = queryItems
return urlComponent.url!
}
Then when you need to login do this:
import SafariServices
var authSession: SFAuthenticationSession?
func authenticate(with url: URL, completion: #escaping ((_ token: String?, _ error: Error?) -> Void)) {
authSession?.cancel()
authSession = SFAuthenticationSession(url: url, callbackURLScheme: nil, completionHandler: { url, error in
//get the token and call the completion handler
})
authSession?.start()
}
or use ASWebAuthenticationSession the same way if you're on iOS 12
Using SFAuthenticationSession you can do something like this. On your App add URLType:
Then on GitHub 'Developer Settings' for your app, add Authorization callback URL like this:
This way, after you login and authorize, Git Hub will call back //yourappname and Safari will redirect it back to your app completing the flow.
I'm developing an iOS app
i have a payment page designed by angular
user click on a payment button in ios app and i run a url page with few paramaters :
UIApplication.sharedApplication().openURL(NSURL(string:"http://www.testt.com/price/personId/packageName")!)
price is money user has entered in textfield and package-name id the schema name i should send it to web page that runs my app (return to app with running that string) i have declared in info.plist
then after been successful or unsuccessful payment. it should return to app by clicking on “return to app” button on web site.
actually angular runs the packageName i have sent with url like this way : http://packageName://
i tried to implement this by universal link like this way : packageName:// but wont open this link because of special chars in url.i used encoding method to encode chars but not successful because url removes the chars :// then i tried app site association method which i faced cannot parse app site association file
so i have few question for you :
1_is there any trick to run url with special chars ??
2_what would you do if you were me ??
3_i tried apple-app-site-association too but can not parse error which i have a question about this method how could this file opens my app? this way : applink:http://msite.com ?? because it contains spacial chars in it again
excuse my awful English at the end
talk to me before voting down
update :
var encodedChars="openMyApp" //schema name
encodedChars=encodedChars.addingPercentEncoding(withAllowedCharacters:CharacterSet.alphanumerics)!
let url="http://test.com/#/payment/\(id)/\(price!)/\(encodedChars)"
UIApplication.shared.openURL(NSURL(string: url)! as URL)
angular code :
if (this.accounting.packageName === 'openMyApp') {
this.url = this.accounting.packageName + '://';
} else {
this.url = 'http://' + this.accounting.packageName;
}
<a class="btn btn-default" title="" href="{{url}}"></a>
I have implemented custom url scheme for my app. If i write some thing like this
myappName://
in safari and press enter, my app is opened.
My angular + backend developer is using this line of code to open my app using custom url scheme. he is sending parameters along the scheme which i can read
this.document.location.href = 'myappname://appname.com/login?name='+id+'&id='+token;
Follow these 2 simple steps, i hope this will help you.
1.How to implement custom url schemes
Official docs
Helpful link
2.How to handle custom URL scheme with params in app delegate
handle the custom url and read params in appDelegate in this function
func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
if let query = url.query {
//that's my logic. yours url may be different
let components = query.components(separatedBy: "=")
print(components)
}
}
let me know if you need any help
What are the openURL parameters for Yahoo Mail?
"ymail:" appears to work, but it just simply opens up the application. I can't seem to figure out how to pre-fill the recipient address.
Got it
"ymail://mail/compose?subject=Subject&to=email#gmail.com&body=message_content"
SWIFT 3.0
if let appSettings = URL(string:"ymail://mail/compose?subject=Subject&to=email#gmail.com&body=message_content") {
UIApplication.shared.open(appSettings, completionHandler: { (success) in})
}
Don't forget to add "ymail" into LSApplicationQueriesSchemes in your Info.plist
I like to forward app to iTunes or Apple Music (like done for Instagram or FV) when user clicks a button, below code gives found nil error. Is there a way to do that? Or even better play previews in my app.
var url = NSURL(string: "itms://itunes.apple.com/us/album/ne-olacak-dj-funky-c-vs-ogün-dalka-single/id1202943921")
if UIApplication.shared.canOpenURL(url! as URL) {
UIApplication.shared.openURL(url! as URL)
}
This method expects URLString to contain only characters that are allowed in a properly formed URL. All other characters must be properly percent escaped. Any percent-escaped characters are interpreted using UTF-8 encoding.
and you need to encode it before passing it to NSURL, you can do this via stringByAddingPercentEncodingWithAllowedCharacters
let url = URL(string: "itms://itunes.apple.com/us/album/ne-olacak-dj-funky-c-vs-ogün-dalka-single/id1202943921".addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)!)
if UIApplication.shared.canOpenURL(url! as URL) {
UIApplication.shared.open(url!, options: [:], completionHandler: nil)
}
for that error you need to follow this
This is a new enforced security measure that apple has implemented on any app that is build in iOS 9.
The only solution so far is to add an entry in the info.plist file with the Key LSApplicationQueriesSchemes and add "itms" and any other url scheme that your app will be linking to in this array.
I'm trying to update my app to work correctly with the new features of GameCenter in iOS10.
I create a new GKGameSession on device1, get a share URL, and all that works fine. I send the share URL out via a share sheet to device 2.
Device2 clicks the link, the device briefly displays 'Retrieving...' and then launches my app. Great! But, now what? Is there context information available for this URL that I can somehow access? Otherwise I have no way how to respond when the app is launched.
Previously you'd get a callback to something adhering to the GKLocalPlayerListener protocol, to the method player:didAcceptInvite:, and you could join the match that way. But with these iCloud-based messages, the player might not be even logged into GameCenter, right? This part seems to have been glossed over in the WWDC presentation.
Also, as of today (12/28/2016) there is no Apple documentation on these new methods.
Since the GKGameSessionEventListener callback session:didAddPlayer: only fires if the game is already running, to be sure you can process this callback every time requires a work around. I've tested this and it works.
When you send out an iMessage or email invite to the game, don't include the Game Session Invite URL directly in the message. Instead use a registered URL that will open your app when opened on a device on which your app is installed. Check here to see how:
Complete Tutorial on iOS Custom URL Schemes
But add a percent escaped encoding of the game invite URL as a parameter to this URL thusly (I'm assuming the registration of a url e.g. newGameRequest but it will be best to make this quite unique, or even better - though it requires more setup, try Universal Link Support as this will allow you to direct users who don't have your app installed to a webpage with a download link)
let openOverWordForPlayerChallenge = "newGameRequest://?token="
gameState.gameSession?.getShareURL { (url, error) in
guard error == nil else { return }
// No opponent so we need to issue an invite
let encodedChallengeURL = url!.absoluteString.addingPercentEncoding(withAllowedCharacters:.urlHostAllowed)
let nestedURLString = openOverWordForPlayerChallenge + encodedChallengeURL!
let nestedURL = URL(string: nestedURLString)!
}
send the URL in a message or email or WhatsApp or whatever. Then in your app delegate, add the following:
func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
var success = false
if let queryString = url.query {
if let urlStringToken = queryString.removingPercentEncoding {
let token = "token="
let startIndex = urlStringToken.startIndex
let stringRange = startIndex..<urlStringToken.index(startIndex, offsetBy: token.characters.count)
let urlString = urlStringToken.replacingOccurrences(of: token, with: "", options: .literal, range: stringRange)
if let url = URL(string: urlString) {
if UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(url, options: [:], completionHandler: nil)
success = true
}
}
}
}
return success
}
Now you can be sure the session:didAddPlayer: will be called. What's the betting this workarround is good for about 2 weeks, and they fix this in the next release of iOS showcased at WWDC 2017 ! Update: this problem hasn't been fixed - so the workaround above remains good!
I agree, the lack of documentation is frustrating. From what I can see, we have to:
add <GKGameSessionEventListener> protocol in the class' header
Then session:didAddPlayer: fires on the joining player's device after accepting an invite link.
update:
Unfortunately, I'm not surprised to hear your results. I hadn't tried all of those scenarios, but GKTurnBasedMatch had similar shortcomings. The way I got around it there was: I added a list of player statuses to match data (invited, active, quit, etc). I gave the player a view of "pending invitations." When they opened that view, I would load all of their matches and display the entries where the player was in invited state. With GKGameSession, that should work too.
Or, it might be easier if you could maintain a local list of sessions that you are aware of. Whenever the game becomes active, pull the entire list of sessions from the server and look for a new entry. The new entry would have to be the match the player just accepted by clicking the share URL.