How to use regular expression match "in iOS - ios

For example , the following is the source I want match:
<div class="cont">
I use
<div\s+class\=\"cont\">
But it doesn't work , if I modify the expression like
<div\s+class\=.*?cont.*?>
Now , it can give me the result I want .
So I think , the problem should be in " this character.
Following is the code I use in iOS , it can works for some other regular expression:
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:reg options:NSRegularExpressionCaseInsensitive error:nil];
NSArray *matches = [regex matchesInString:resultStr options:0 range:NSMakeRange(0, [resultStr length])];
for (NSTextCheckingResult *match in matches) {
NSRange matchRange = [match range];
NSString *tagString = [resultStr substringWithRange:matchRange];
[resultArr addObject:tagString];
}

You are trying to match HTML with regular expressions. It is definitely very troublesome, since HTML you receive can be all uppercase, single quotes may be used instead of double or be missing, etc.
That said, if you really need a regex solution, I'd recommend to account for any number of attributes before class=cont and allow any attribute value delimiters:
NSString *pattern = #"<div\\b[^<]*class=[\"']?cont\\b[^<]*>";
Here, I am using \b to match a word boundary, [^<]* checks for any other attributes before class, ["']? allows either a single or double quotation mark or nothing, then \b makes sure cont is followed by a non-word character, and [^<]* checks for any other attributes before final >.
Also, \" is escaped once as it is a C string delimiter and \\b is escaped twice to make sure we pass \b to the regex engine.
Sample code at CodingGround:
#import <Foundation/Foundation.h>
#import <Foundation/NSTextCheckingResult.h>
int main (int argc, const char * argv[])
{
NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
NSError *error = nil;
NSString *pattern = #"<div\\b[^<]*class=[\"']?cont\\b[^<]*>";
NSString *string = #"<div class=\"cont\">";
NSRange range = NSMakeRange(0, string.length);
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:&error];
NSArray *matches = [regex matchesInString:string options:0 range:range];
for (NSTextCheckingResult *match in matches) {
NSRange matchRange = [match range];
NSString *m = [string substringWithRange:matchRange];
NSLog(#"Matched string: %#", m);
}
[pool drain];
return 0;
}

Here goes the code:
NSString *stricterFilterString = #"[A-Z0-9a-z\\._%+-]+#([A-Za-z0-9-]+\\.)+[A-Za-z]{2,4}";
NSString *laxString = #".+#([A-Za-z0-9]+\\.)+[A-Za-z]{2}[A-Za-z]*";
NSString *emailRegex = stricterFilter ? stricterFilterString : laxString;
NSPredicate *emailTest = [NSPredicate predicateWithFormat:#"SELF MATCHES %#", emailRegex];

Related

Objective C - NSRegularExpression with specific substring

I have an NSString which I am checking if there is an NSLog and then I comment it out.
I am using NSRegularExpression and then looping through result.
The code:
-(NSString*)commentNSLogFromLine:(NSString*)lineStr {
NSString *regexStr =#"NSLog\\(.*\\)[\\s]*\\;";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:regexStr options:NSRegularExpressionCaseInsensitive error:nil];
NSArray *arrayOfAllMatches = [regex matchesInString:lineStr options:0 range:NSMakeRange(0, [lineStr length])];
NSMutableString *mutStr = [[NSMutableString alloc]initWithString:lineStr];
for (NSTextCheckingResult *textCheck in arrayOfAllMatches) {
if (textCheck) {
NSRange matchRange = [textCheck range];
NSString *strToReplace = [lineStr substringWithRange:matchRange];
NSString *commentedStr = [NSString stringWithFormat:#"/*%#*/",[lineStr substringWithRange:matchRange]];
[mutStr replaceOccurrencesOfString:strToReplace withString:commentedStr options:NSCaseInsensitiveSearch range:matchRange];
NSRange rOriginal = [mutStr rangeOfString:#"NSLog("];
if (NSNotFound != rOriginal.location) {
[mutStr replaceOccurrencesOfString:#"NSLog(" withString:#"DSLog(" options:NSCaseInsensitiveSearch range:rOriginal];
}
}
}
return [NSString stringWithString:mutStr];
}
The problem is with the test case:
NSString *str = #"NSLog(#"A string"); NSLog(#"A string2")"
Instead of returning "/*DSLog(#"A string");*/ /*DSLog(#"A string2")*/" it returns: "/*DSLog(#"A string"); NSLog(#"A string2")*/".
The issue is how the Objective-C handles the regular expression. I would expected 2 results in arrayOfAllMatches but instead that I am getting only one. Is there any way to ask Objective-C to stop on the first occurrence of ); ?
The problem is with the regular expression. You are searching for .* inside the parentheses, which causes it to include the first close parenthesis, continue through the second NSLog statement, and go all the way to the final close parentheses.
So what you want to do is something like this:
NSString *regexStr =#"NSLog\\([^\\)]*\\)[\\s]*\\;";
That tells it to include everything inside the parenthesis except for the ) character. Using that regex, I get two matches. (note that you omitted the final ; in your string sample).

How to work with the results from NSRegularExpression when using the regex pattern as a string delimiter

I'm using a simple pattern with NSRegularExpression to delimit content within a string:
(\s)+(and|or)(\s)+
So, when I use matchesInString it's not the matches that I'm interested in, but the other stuff.
Below is the code that I'm using. Iterating over the matches and then using indexes and lengths to pull out the content.
Question: I'm just wondering if I'm missing something in the api to get the other bits? Or, is the approach below generally ok?
- (NSArray*)separateText:(NSString*)text
{
NSString* regExPattern = #"(\\s)+(and|or)(\\s)+";
NSError* error = NULL;
NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:regExPattern
options:NSRegularExpressionCaseInsensitive
error:&error];
NSArray* matches = [regex matchesInString:text options:0 range:NSMakeRange(0, text.length)];
if (matches.count == 0) {
return #[text];
}
NSInteger itemStartIndex = 0;
NSMutableArray* result = [NSMutableArray new];
for (NSTextCheckingResult* match in matches) {
NSRange matchRange = [match range];
if (!matchRange.location == 0) {
NSInteger matchStartIndex = matchRange.location;
NSInteger length = matchStartIndex - itemStartIndex;
NSString* item = [text substringWithRange:NSMakeRange(itemStartIndex, length)];
if (item.length != 0) {
[result addObject:item];
}
}
itemStartIndex = NSMaxRange(matchRange);
}
if (itemStartIndex != text.length) {
NSInteger length = text.length - itemStartIndex;
NSString* item = [text substringWithRange:NSMakeRange(itemStartIndex, length)];
[result addObject:item];
}
return result;
}
You can capture the string before the and|or with parentheses, and add it to your array with rangeAtIndex.
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"(.+?)(\\s+(and|or)\\W+|\\s*$)" options:NSRegularExpressionCaseInsensitive error:&error];
NSMutableArray *phrases = [NSMutableArray array];
[regex enumerateMatchesInString:string options:0 range:NSMakeRange(0, [string length]) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
NSRange range = [result rangeAtIndex:1];
[phrases addObject:[string substringWithRange:range]];
}];
A couple of minor points about my regex:
I added the |\\s*$ construct to capture the last string after the final and|or. If you don't want that, you can eliminate that.
I replaced the second \\s+ (whitespace) with a \\W+ (non-word characters), in case you encountered something like and|or followed by a comma or something else. You could alternatively look explicitly for ,?\\s+ if the comma was the only non-word character you cared about. It just depends upon the specific business problem you're solving.
You might want to replace the first \\s+ with \\W+, too.
If your string contains newline characters, you might want to use the NSRegularExpressionDotMatchesLineSeparators option when you instantiate the NSRegularExpression.
You could replace all matches of the regex with a template string (e.g. ", " or "," etc) and then separate the string components based on that new delimiter.
NSString *stringToBeMatched = #"Your string to be matched";
NSString *regExPattern = #"(\\s)+(and|or)(\\s)+";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:regExPattern
options:NSRegularExpressionCaseInsensitive
error:&error];
if (error) {
// handle error
}
NSString *replacementString = [regex stringByReplacingMatchesInString:stringToBeMatched
options:0
range:NSMakeRange(0, stringToBeMatched.length)
withTemplate:#","];
NSArray *otherItemsInString = [replacementString componentsSeparatedByString:#","];

iOS: extract substring of NSString in objective C

I have an NSString as:
"<a href='javascript:void(null)' onclick='handleCommandForAnchor(this, 10);return false;'>12321<\/a>"
I need to extract the 12321 near the end of the NSString from it and store.
First I tried
NSString *shipNumHtml=[mValues objectAtIndex:1];
NSInteger htmlLen=[shipNumHtml length];
NSString *shipNum=[[shipNumHtml substringFromIndex:htmlLen-12]substringToIndex:8];
But then I found out that number 12321 can be of variable length.
I can't find a method like java's indexOf() to find the '>' and '<' and then find substring with those indices. All the answers I've found on SO either know what substring to search for or know the location if the substring. Any help?
I don't usually advocate using Regular expressions for parsing HTML contents but it seems a regex matching >(\d+)< would to the job in this simple string.
Here is a simple example:
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#">(\\d+)<"
options:0
error:&error];
// Handle error != nil
NSTextCheckingResult *match = [regex firstMatchInString:string
options:0
range:NSMakeRange(0, [string length])];
if (match) {
NSRange matchRange = [match rangeAtIndex:1];
NSString *number = [string substringWithRange:matchRange]
NSLog(#"Number: %#", number);
}
As #HaneTV says, you can use the NSString method rangeOfString to search for substrings. Given that the characters ">" and "<" appear in multiple places in your string, so you might want to take a look at NSRegularExpression and/or NSScanner.
that may help on you a bit, I've just tested:
NSString *_string = #"<a href='javascript:void(null)' onclick='handleCommandForAnchor(this, 10);return false;'>12321</a>";
NSError *_error;
NSRegularExpression *_regExp = [NSRegularExpression regularExpressionWithPattern:#">(.*)<" options:NSRegularExpressionCaseInsensitive error:&_error];
NSArray *_matchesInString = [_regExp matchesInString:_string options:NSMatchingReportCompletion range:NSMakeRange(0, _string.length)];
[_matchesInString enumerateObjectsUsingBlock:^(NSTextCheckingResult * result, NSUInteger idx, BOOL *stop) {
for (int i = 0; i < result.numberOfRanges; i++) {
NSString *_match = [_string substringWithRange:[result rangeAtIndex:i]];
NSLog(#"%#", _match);
}
}];

How to get all strings inside [...] in one NSString?

Say given an NSString:
#"[myLabel]-10-[youImageView]"
I need an array of:
#[#"myLabel", #"yourImageView"]
How do I do it?
I thought about going through the string and check each '[' and ']', get string inside them, but is there any other better way?
Thanks
You can use regular expressions:
NSString *string = #"[myLabel]-10-[youImageView]";
// Regular expression to find "word characters" enclosed by [...]:
NSString *pattern = #"\\[(\\w+)\\]";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern
options:0
error:NULL];
NSMutableArray *list = [NSMutableArray array];
[regex enumerateMatchesInString:string
options:0
range:NSMakeRange(0, [string length])
usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
// range = location of the regex capture group "(\\w+)" in the string:
NSRange range = [result rangeAtIndex:1];
[list addObject:[string substringWithRange:range]];
}
];
NSLog(#"%#", list);
Output:
(
myLabel,
youImageView
)
Would this work for you?
NSCharacterSet *aSet = [NSCharacterSet characterSetWithCharactersInString:#"]-10["];
NSArray *anArray = [aString componentsSeparatedByCharactersInSet:aSet];

How to use regular expressions to find words that begin with a three character prefix

My goal is to count the number of words (in a string) that begin with a specified prefix of more than one letter. A case is words that begin with "non". So in this example...
NSString * theFullTestString = #"nonsense non-issue anonymous controlWord";
...I want to get hits on "nonsense" and "non-issue", but not on "anonymous" or "controlWord". The total count of my hits should be 2.
So here's my test code which seems close, but none of the regular expression forms I've tried works correctly. This code catches "nonsense" (correct) and "anonymous" (wrong) but not "non-issue" (wrong). Its count is 2, but for the wrong reason.
NSUInteger countOfNons = 0;
NSString * theFullTestString = #"nonsense non-issue anonymous controlWord";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"non(\\w+)" options:0 error:&error];
NSArray *matches = [regex matchesInString:theFullTestString options:0 range:NSMakeRange(0, theFullTestString.length)];
for (NSTextCheckingResult *match in matches) {
NSRange wordRange = [match rangeAtIndex:1];
NSString* word = [theFullTestString substringWithRange:wordRange];
++countOfNons;
NSLog(#"Found word:%# countOfNons:%d", word, countOfNons);
}
I'm stumped.
The regex \bnon[\w-]* should do the trick
\bnon[\w-]*
^ (\b) Start of word
^ (non) Begins with non
^ ([\w-]) A alphanumeric char, or hyphen
^ (*) The character after 'non' zero or more times
So, in your case:
NSUInteger countOfNons = 0;
NSString * theFullTestString = #"nonsense non-issue anonymous controlWord";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"(\\bnon[\\w-]*)" options:0 error:&error];
NSArray *matches = [regex matchesInString:theFullTestString options:0 range:NSMakeRange(0, theFullTestString.length)];
for (NSTextCheckingResult *match in matches) {
NSRange wordRange = [match rangeAtIndex:1];
NSString* word = [theFullTestString substringWithRange:wordRange];
++countOfNons;
NSLog(#"Found word:%# countOfNons:%d", word, countOfNons);
}
I think regular expressions are a bit of an overkill here.
NSString *words = #"nonsense non-issue anonymous controlWord";
NSArray *wordsArr = [words componentsSeparatedByString:#" "];
int count = 0;
for (NSString *word in wordsArr) {
if ([word hasPrefix:#"non"]) {
count++;
NSLog(#"%dth match: %#", count, word);
}
}
NSLog(#"Count: %d", count);
There is more easier way to do this. You can use NSPredicate and use this format BEGINSWITH[c] %#.
Sample code
NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:#"Firstname BEGINSWITH[c] %#", text];
NSArray *results = [People filteredArrayUsingPredicate:resultPredicate];

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