How can I pop specific View Controller in Swift - ios

Question

I used the Objective-C code below to pop a specific ViewController.
for (UIViewController *controller in self.navigationController.viewControllers) {
if ([controller isKindOfClass:[AnOldViewController class]]) {
//Do not forget to import AnOldViewController.h
[self.navigationController popToViewController:controller
animated:YES];
break;
}
}
How can I do that in Swift?

Answer 1

Try following code:
for controller in self.navigationController!.viewControllers as Array {
if controller.isKind(of: ViewController.self) {
self.navigationController!.popToViewController(controller, animated: true)
break
}
}

Answer 2

Swift 5
To pop to the latest instance of a specific class, for example SomeViewController:
navigationController?.popToViewController(ofClass: SomeViewController.self)
But you need to add ths UINavigationController extension:
extension UINavigationController {
func popToViewController(ofClass: AnyClass, animated: Bool = true) {
if let vc = viewControllers.last(where: { $0.isKind(of: ofClass) }) {
popToViewController(vc, animated: animated)
}
}
}

Answer 3

For Swift 3+
let viewControllers: [UIViewController] = self.navigationController!.viewControllers
for aViewController in viewControllers {
if aViewController is YourViewController {
self.navigationController!.popToViewController(aViewController, animated: true)
}
}

Answer 4

From Swift 4.0 and Above
for controller in self.navigationController!.viewControllers as Array {
if controller.isKind(of: DashboardVC.self) {
_ = self.navigationController!.popToViewController(controller, animated: true)
break
}
}
This is working Perfect.

Answer 5

I prefer a generic way to do it.
I have this extension for the UINavigationController :
extension UINavigationController {
func backToViewController(vc: Any) {
// iterate to find the type of vc
for element in viewControllers as Array {
if "\(element.dynamicType).Type" == "\(vc.dynamicType)" {
self.popToViewController(element, animated: true)
break
}
}
}
}
Let's say I have a FOHomeVC class (who is a UIViewController) instantiated in the navigation stack.
So I would do this in my code:
self.navigationController?.backToViewController(FOHomeVC.self)

Answer 6

I have added an extension to UINavigationController which helps you to find if that controller exist in navigation stack. If yes then it will be popped to that controller or else you pass new controller to push with pushController param.
extension UINavigationController {
func containsViewController(ofKind kind: AnyClass) -> Bool {
return self.viewControllers.contains(where: { $0.isKind(of: kind) })
}
func popPushToVC(ofKind kind: AnyClass, pushController: UIViewController) {
if containsViewController(ofKind: kind) {
for controller in self.viewControllers {
if controller.isKind(of: kind) {
popToViewController(controller, animated: true)
break
}
}
} else {
pushViewController(pushController, animated: true)
}
}
}

Answer 7

Swift 4 / Swift 5
for controller in self.navigationController!.viewControllers as Array {
if controller.isKind(of: HomeViewController.self) {
self.navigationController!.popToViewController(controller, animated: true)
break
}
}

Answer 8

I prefer a "real generic" and more functional approach.
So I came up with following UINavigationController extension functions. You can also use the first function, for anything else, where you just need to access a specific VC in the navigation stack.
Extensions
extension UINavigationController {
func getViewController<T: UIViewController>(of type: T.Type) -> UIViewController? {
return self.viewControllers.first(where: { $0 is T })
}
func popToViewController<T: UIViewController>(of type: T.Type, animated: Bool) {
guard let viewController = self.getViewController(of: type) else { return }
self.popToViewController(viewController, animated: animated)
}
}
Usage
self.navigationController?.popToViewController(of: YourViewController.self, animated: true)
This should work at least in Swift 4 and 5.

Answer 9

Find your view controller from navigation stack and pop to that view controller if it exists
for vc in self.navigationController!.viewControllers {
if let myViewCont = vc as? VCName
{
self.navigationController?.popToViewController(myViewCont, animated: true)
}
}

Answer 10

swift5
let controllers : Array = self.navigationController!.viewControllers
self.navigationController!.popToViewController(controllers[1], animated: true)

Answer 11

Swift 5 Answer of #PabloR is Here :
extension UINavigationController {
func backToViewController(vc: Any) {
// iterate to find the type of vc
for element in viewControllers as Array {
if "\(type(of: element)).Type" == "\(type(of: vc))" {
self.popToViewController(element, animated: true)
break
}
}
}
}
Usage :
self.navigationController?.backToViewController(vc: TaskListViewController.self)

Answer 12

In latest swift
#IBAction func popToConversationsVC(_ sender: UIButton) {
if (self.navigationController != nil) {
for vc in self.navigationController!.viewControllers {
if vc is ConversationsVC {
self.navigationController?.popToViewController(vc, animated: false)
}
}
}
}

Answer 13

For Swift 4.0 and above Using Filter
guard let VC = self.navigationController?.viewControllers.filter({$0.isKind(of: YourViewController.self)}).first else {return}
self.navigationController?.popToViewController(VC, animated: true)

Answer 14

Please use this below code for Swift 3.0:
let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];
for aViewController:UIViewController in viewControllers {
if aViewController.isKind(of: YourViewController.self) {
_ = self.navigationController?.popToViewController(aViewController, animated: true)
}
}

Answer 15

I needed to use this, because in some cases app crashes:
if let navVC = self.navigationController {
let views = navVC.viewControllers as Array
for controller in views {
if controller.isKind(of: YourVC.self) {
navVC.popToViewController(controller, animated: true)
return
}
}
}

Answer 16

This solution worked for me :)
extension UINavigationController {
func backToViewController(_ viewController: AnyClass, animated: Bool) {
guard let viewController = self.viewControllers.first(where: {$0.isKind(of: viewController)}) else { return }
self.popToViewController(viewController, animated: animated)
}
}

Answer 17

I adapt from all answer above. It look like Yakup Ad answer, because it's very short way.
I force type by using generic for argument, that make sure you must pass only UIViewController to this func.
I search viewController that already in stack by using .first this make me got only one VC then stop the loop.
I also return passing VC back if you need to customize somethings.
Let's enjoy.
extension UINavigationController {
func popToViewController<T: UIViewController>(_ viewController: T.Type, animated: Bool) -> T? {
guard let viewController = self.viewControllers.first(where: {$0 is T}) else { return nil }
self.popToViewController(viewController, animated: animated)
return viewController as? T
}
}
Usage
let poppedVC = self.navigationController?.popToViewController(HomeViewController.self, animated: true)

Answer 18

extension UINavigationController {
func popBack(to vc: AnyClass, animated: Bool = true) {
guard let elementFound = (viewControllers.filter { $0.isKind(of: vc) }).first else {
fatalError("cannot pop back to \(vc) as it is not in the view hierarchy")
}
self.popToViewController(elementFound, animated: animated)
}
}

Answer 19

simple and best solution without force unwrapped is
if let vc = navigationController.viewControllers.filter({$0 is YourViewController}).first as? YourViewController {
self.navigationController.popToViewController(vc, animated: true)
}