How to send Json as parameter in url using swift - ios

Question

I am new in swift language. I looked at some questions for parsing Json in swift in here but my issue is alittle different from others.
when i write /cmd=login&params{'user':'username','password':'pass'} it returns correct data. how to resolve this in swift
I send username and password to url as json but
it retrieve error which means "invalid format "
Please help me.
Here is what i have tried:
var url:NSURL = NSURL(string: "http://<host>?cmd=login")!
//var session = NSURLSession.sharedSession()
var responseError: NSError?
var request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData, timeoutInterval: 5)
// var request:NSMutableURLRequest = NSMutableURLRequest(URL: url)
var response: NSURLResponse?
request.HTTPMethod = "POST"
let jsonString = "params={\"user\":\"username\",\"password\":\"pass\"}"
request.HTTPBody = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion:true)
request.setValue("application/json; charset=UTF-8", forHTTPHeaderField: "Content-Type")
// send the request
NSURLConnection.sendSynchronousRequest(request, returningResponse: &response, error: &responseError)
// look at the response
if let httpResponse = response as? NSHTTPURLResponse {
println("HTTP response: \(httpResponse.statusCode)")
} else {
println("No HTTP response")
}
let task = NSURLSession.sharedSession().dataTaskWithRequest(request){
data, response, error in
if error != nil {
println("error=\(error)")
return
}
println("****response= \(response)")
let responseString = NSString(data: data, encoding: NSUTF8StringEncoding)
println("**** response =\(responseString)")
var err: NSError?
var json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers , error: &err) as? NSDictionary
}
task.resume()

Answer 1

Assuming based on your question that the format the server is expecting is something like this:
http://<host>?cmd=login&params=<JSON object>
You would need to first URL-encode the JSON object before appending it to the query string to eliminate any illegal characters.
You can do something like this:
let jsonString = "{\"user\":\"username\",\"password\":\"pass\"}"
let urlEncoadedJson = jsonString.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())
let url = NSURL(string:"http://<host>?cmd=login&params=\(urlEncoadedJson)")

Answer 2

Let's say url is
https://example.com/example.php?Name=abc&data={"class":"625","subject":"english"}
in Swift 4
let abc = "abc"
let class = "625"
let subject = "english"
let baseurl = "https://example.com/example.php?"
let myurlwithparams = "Name=\(abc)" + "&data=" +
"{\"class\":\"\(class)\",\"subject\":\"\(subject)\"}"
let encoded =
myurlwithparams.addingPercentEncoding(withAllowedCharacters:
.urlFragmentAllowed)
let encodedurl = URL(string: encoded!)
var request = URLRequest(url: encodedurl!)
request.httpMethod = "GET"

Answer 3

I don't think you need to encode your JSON the way you're doing it. Below should work.
let jsonString = "params={\"user\":\"username\",\"password\":\"pass\"}"
var url:NSURL = NSURL(string: "http://<host>?cmd=login&?\(jsonString)")!
//var session = NSURLSession.sharedSession()
var responseError: NSError?
var request = NSMutableURLRequest(URL: url!, cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalCacheData, timeoutInterval: 5)
// var request:NSMutableURLRequest = NSMutableURLRequest(URL: url)
var response: NSURLResponse?
request.HTTPMethod = "POST"

Answer 4

You json string is not valid, it should be like:
let jsonString = "{\"user\":\"username\",\"password\":\"pass\"}"
As for the request, I think GET it what you really need:
var urlString = "http://<host>" // Only the host
let payload = "?cmd=login&params=" + jsonString // params goes here
urlString += payload
var url:NSURL = NSURL(string: urlString)!
// ...
request.HTTPMethod = "GET"