encoding url using swift code - ios

Question

I need to send an URL in Arabic language, so I need to encode it before I put it in URL. I am using Swift code.
Below is an example what i really need
var s = "www.example.com/السلام عليكم"
let url = NSURL(string : s)
So the word (السلام عليكم) is in Arabic characters that what I want to send.

Answer 1

Swift 2.0
let urlwithPercentEscapes = myurlstring.stringByAddingPercentEncodingWithAllowedCharacters( NSCharacterSet.URLQueryAllowedCharacterSet())
Swift 3
let urlwithPercentEscapes = myurlstring.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed)

Answer 2

To improve #Druva's answer
create an extention somewhere in the project
Swift 2.0
extension String
{
func encodeUrl() -> String
{
return self.stringByAddingPercentEncodingWithAllowedCharacters( NSCharacterSet.URLQueryAllowedCharacterSet())
}
func decodeUrl() -> String
{
return self.stringByRemovingPercentEncoding
}
}
Swift 3.0
extension String
{
func encodeUrl() -> String
{
return self.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed)
}
func decodeUrl() -> String
{
return self.stringByRemovingPercentEncoding
}
}

Answer 3

You need to encode url as you have written. You can do so with that string method:
stringByAddingPercentEscapesUsingEncoding(NSStringEncoding)
So your code will be:
var s = "www.example.com/السلام عليكم"
// you may add check before force unwrapping
let url = NSURL(string : s.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!)

Answer 4

You need to encode this string as it contains special characters.
var s = "www.example.com/السلام عليكم"
let encodedLink = s.addingPercentEncoding(withAllowedCharacters: .urlFragmentAllowed)
let encodedURL = NSURL(string: encodedLink!)! as URL
where encodedURL is your final URL

Answer 5

swift 4
we face the same problem it solved by this way
extension String {
var fixedArabicURL: String? {
return self.addingPercentEncoding(withAllowedCharacters: CharacterSet.alphanumerics
.union(CharacterSet.urlPathAllowed)
.union(CharacterSet.urlHostAllowed))
} }

Answer 6

you have to Encode this URL before sending this URL