For example I could type an emoji character code such as:
NSString* str = #"π";
NSLog(#"%#", str);
The smile emoji would be seen in the console.
Maybe the code editor and the compiler would trade the literal in UTF-8.
And now I'm working in a full unicode, I mean 32bit per char, environment and I've got the unicode of the emoji, I want to convert the 32bit unicode into a NSString for example:
int charcode = 0x0001F60A;
NSLog(#"%??", charcode);
The question is what should I put at the "??" position and then I could format the charcode into a emoji string?
BTW the charcode was a variable which can not be determine at the compile time.
I don't want to compress the 32bit int into UTF-8 bytes unless that would be the only way.
If 0x0001F60A is a dynamic value determined at runtime then
you can use the NSString method
- (instancetype)initWithBytes:(const void *)bytes length:(NSUInteger)len encoding:(NSStringEncoding)encoding;
to create a string containing a character with the given Unicode value:
int charcode = 0x0001F60A;
uint32_t data = OSSwapHostToLittleInt32(charcode); // Convert to little-endian
NSString *str = [[NSString alloc] initWithBytes:&data length:4 encoding:NSUTF32LittleEndianStringEncoding];
NSLog(#"%#", str); // π
Use NSString initialization method
int charcode = 0x0001F60A;
NSLog(#"%#", [[NSString alloc] initWithBytes:&charcode length:4 encoding:NSUTF32LittleEndianStringEncoding]);
Related
I need to substring char* to some length and need to convert to NSString.
char *val substring Length
I tried
NSString *tempString = [NSString stringWithCString:val encoding:NSAsciiStringEncoding];
NSRange range = NSMakeRange (0, length);
NSString *finalValue = [tempString substringWithRange: range];
This works but not for other special character languages like chinese.
If i convert To UTF8Encoding then substring length will mismatch.
Is there any other way to substring the char* then convert to UTF8 encoding?
You have to use the encoding, the string is encoded in.
In your case, you say to interpret the string as ASCII string. ASCII does not have chinese characters. Therefore this cannot work with chinese characters: They are not there.
Likely you have an UTF8 encoded string. But simply switching to UTF8 does not help. Since NSString and OS X/iOS at all encodes 16-Bit Unicode, but extended Unicode has 20 bits, chinese characters needs multiple codes. This has some effects, for example -length returns the number of codes, not the number of chinese characters. However, with -rangeOfComposedCharacterSequencesForRange: you can adjust the range.
For example π (CJK unified ideograph-0x20016):
NSString *str = #"π "; // One chinese whatever
NSLog(#"%ld", [str length]); // This are "2" characters
NSRange range = {0, 1}; // Range for the "first" character
NSLog(#"%ld %ld", range.location, range.length); // 0 1
range = [str rangeOfComposedCharacterSequencesForRange:range];
NSLog(#"%ld %ld", range.location, range.length); // 0 2
You can get a better answer, if you add information about the encoding of the string coming in and the required encoding for putting out.
Strings are not UTF8 or whatever strings. Strings are strings. Their storage, their representation in computer memory has an encoding, but they don't have an encoding themselves.
I found the solution for my question
char subString[length+1];
strncpy(subString, val, length);
subString[length] = '\0'; // place the null terminator
NSString *finalString = [NSString stringWithCString: subString encoding:NSUTF8StringEncoding];
I did the char* sub string and UTF8 encoding both.
Now I have a range of unicode numbers, I want to show them in UILabel, I can show them if i hardcode them, but that's too slow, so I want to substitute them with a variable, and then change the variable and get the relevant character.
For example, now I know the unicode is U+095F, I want to show the range of U+095F to U+096f in UILabel, I can do that with hardcode like
NSString *str = [NSString stringWithFormat:#"\u095f"];
but I want to do that like
NSInteger hex = 0x095f;
[NSString stringWithFormat:#"\u%ld", (long)hex];
I can change the hex automatically,just like using #"%ld", (long)hex, so anybody know how to implement that?
You can initialize the string with the a buffer of bytes of the hex (you simply provide its pointer). The point is, and the important thing to notice is that you provide the character encoding to be applied. Specifically you should notice the byte order.
Here's an example:
UInt32 hex = 0x095f;
NSString *unicodeString = [[NSString alloc] initWithBytes:&hex length:sizeof(hex) encoding:NSUTF32LittleEndianStringEncoding];
Note that solutions like using the %C format are fine as long as you use them for 16-bit unicode characters; 32-bit unicode characters like emojis (for example: 0x1f601, 0x1f41a) will not work using simple formatting.
You would have to use
[NSString stringWithFormat:#"%C", (unichar)hex];
or directly declare the unichar (unsigned short) as
unichar uni = 0x095f;
[NSString stringWithFormat:#"%C", uni];
A useful resource might be the String Format Specifiers, which lists %C as
16-bit Unicode character (unichar), printed by NSLog() as an ASCII character, or, if not an ASCII character, in the octal format \ddd or the Unicode hexadecimal format \udddd, where d is a digit.
Like this:
unichar charCode = 0x095f;
NSString *s = [NSString stringWithFormat:#"%C",charCode];
NSLog(#"String = %#",s); //Output:String = ΰ₯
I have a unicode string as
{\rtf1\ansi\ansicpg1252\cocoartf1265
{\fonttbl\f0\fswiss\fcharset0 Helvetica;\f1\fnil\fcharset0 LucidaGrande;}
{\colortbl;\red255\green255\blue255;}
{\*\listtable{\list\listtemplateid1\listhybrid{\listlevel\levelnfc23\levelnfcn23\leveljc0\leveljcn0\levelfollow0\levelstartat1\levelspace360\levelindent0{\*\levelmarker \{check\}}{\leveltext\leveltemplateid1\'01\uc0\u10003 ;}{\levelnumbers;}\fi-360\li720\lin720 }{\listname ;}\listid1}}
{\*\listoverridetable{\listoverride\listid1\listoverridecount0\ls1}}
\paperw11900\paperh16840\margl1440\margr1440\vieww22880\viewh16200\viewkind0
\pard\li720\fi-720\pardirnatural
\ls1\ilvl0
\f0\fs24 \cf0 {\listtext
\f1 \uc0\u10003
\f0 }One\
{\listtext
\f1 \uc0\u10003
\f0 }Two\
}
Here i have unicode data \u10003 which is equivalent to "β" characters. I have used
[NSString stringWithCharacters:"\u10003" length:NSUTF16StringEncoding] which is throwing compilation error. Please let me know how to convert these unicode characters to "β".
Regards,
Boom
I have same for problem and the following code solve my issue
For Encode
NSData *dataenc = [yourtext dataUsingEncoding:NSNonLossyASCIIStringEncoding];
NSString *encodevalue = [[NSString alloc]initWithData:dataenc encoding:NSUTF8StringEncoding];
For decode
NSData *data = [yourtext dataUsingEncoding:NSUTF8StringEncoding];
NSString *decodevalue = [[NSString alloc] initWithData:data encoding:NSNonLossyASCIIStringEncoding];
Thanks
I have used below code to convert a Uniode string to NSString. This should work fine.
NSData *unicodedStringData =
[unicodedString dataUsingEncoding:NSUTF8StringEncoding];
NSString *emojiStringValue =
[[NSString alloc] initWithData:unicodedStringData encoding:NSNonLossyASCIIStringEncoding];
In Swift 4
let emoji = "π"
let unicodedData = emoji.data(using: String.Encoding.utf8, allowLossyConversion: true)
let emojiString = String(data: unicodedData!, encoding: String.Encoding.utf8)
I assume that:
You are reading this RTF data from a file or other external source.
You are parsing it yourself (not using, say, AppKit's built-in RTF parser).
You have a reason why you're parsing it yourself, and that reason isn't βwait, AppKit has this built in?β.
You have come upon \u⦠in the input you're parsing and need to convert that to a character for further handling and/or inclusion in the output text.
You have ruled out \uc, which is a different thing (it specifies the number of non-Unicode bytes that follow the \u⦠sequence, if I understood the RTF spec correctly).
\u is followed by hexadecimal digits. You need to parse those to a number; that number is the Unicode code point number for the character the sequence represents. You then need to create an NSString containing that character.
If you're using NSScanner to parse the input, then (assuming you have already scanned past the \u itself) you can simply ask the scanner to scanHexInt:. Pass a pointer to an unsigned int variable.
If you're not using NSScanner, do whatever makes sense for however you're parsing it. For example, if you've converted the RTF data to a C string and are reading through it yourself, you'll want to use strtoul to parse the hex number. It'll interpret the number in whatever base you specify (in this case, 16) and then put the pointer to the next character wherever you want it.
Your unsigned int or unsigned long variable will then contain the Unicode code point value for the specified character. In the example from your question, that will be 0x10003, or U+10003.
Now, for most characters, you could simply assign that over to a unichar variable and create an NSString from that. That won't work here: unichars only go up to 0xFFFF, and this code point is higher than that (in technical terms, it's outside the Basic Multilingual Plane).
Fortunately, *CF*String has a function to help you:
unsigned int codePoint = /*β¦*/;
unichar characters[2];
NSUInteger numCharacters = 0;
if (CFStringGetSurrogatePairForLongCharacter(codePoint, characters)) {
numCharacters = 2;
} else {
characters[0] = codePoint;
numCharacters = 1;
}
You can then use stringWithCharacters:length: to create an NSString from this array of 16-bit characters.
Use this:
NSString *myUnicodeString = #"\u10003";
Thanks to modern Objective C.
Let me know if its not what you want.
NSString *strUnicodeString = "\u2714";
NSData *unicodedStringData = [strUnicodeString dataUsingEncoding:NSUTF8StringEncoding];
NSString *emojiStringValue = [[NSString alloc] initWithData:unicodedStringData encoding:NSUTF8StringEncoding];
I have seen questions in stackoverflow that convert unichar to NSString but now I would like to do the reverse.
How do i do it?
Need some guidance.. Thanks
For example, I have an array of strings:[#"o",#"p",#"q"];
These are strings inside. How do i convert it back to unichar?
The following will work as long as the first character isn't actually two composed characters (in other words as long as the character doesn't have a Unicode value greater than \UFFFF):
unichar ch = [someString characterAtIndex:0];
You could convert it to a buffer in NSData:
if ([string canBeConvertedToEncoding:NSUnicodeStringEncoding]) {
NSData * data = [string dataUsingEncoding:NSUnicodeStringEncoding];
const unichar* const ptr = (const unichar*)data.bytes;
...
}
I have the following char[] str = "\xe7a";
This is the result of having converted "Γ§a" into unicode escaped with python .encode('unicode-escape')
When it gets to iOS I'm trying to convert it to "Γ§a" again... but I can't find the right method to do it.
How can I convert \x escaped characters into their proper characters using iOS functions?
str = [[NSString alloc] initWithBytes:m.param5 length:STRING_PARAM_LENGTH encoding:NSASCIIStringEncoding] UTF8String];
doesn't work
str = [[NSString alloc] initWithBytes:m.param5 length:STRING_PARAM_LENGTH NSUTF8StringEncoding];
doesn't work
str = [NSString stringWithUTF8String:m.param5];
doesn't work as well
Any ideas?
Assuming \xe7 means the byte 0xe7, the char array is encoded as Windows-1252/ISO-8859-1... so:
NSString *string = [NSString stringWithCString:str encoding:NSISOLatin1StringEncoding];
If the contents are literally a backslash, x, e, and 7, you need to turn that into the real implied byte value
before running the above code