Rails – assign an order number to each record - ruby-on-rails

So I am importing passages from a book into my application. I am giving all the passages in a given book the class Passage. i.e. Passage.all
I do have many books so I also have a class Book. Therefore, when I am finding all the passages from one book I call:
Passage.where(book_id: self.book_id)
When I use the where method, does it preserve the "natural order", which Passage.all would generally return. If not, I could change the code to:
Passage.where(book_id: self.book_id).order("created_at ASC")
Anyway, I then proceed to write this code:
a = Passage.where(book_id: self.book_id)
b = a.index(self)+1
self.passage_number = b
[first line: returns all the passages in the book]
[second line: returns their number in the array + 1 to account for the 0 starting value thing (pardon the colloquialism)]
[third line: assigns that index value to the passage number]
Ultimately, I am trying to compute passage numbers, without having to hard code them.
SO WHAT'S MY ISSUE? Right now I am getting three passage #3's, and two passage #4's. My last passage is this:
Passage.last.passage_number = 217
Passage.where(book_id: 5).count = 241
It is skipping numbers and incorrectly indexing, so I think I need to code a better method! What's a better way to index an array in this context?

There is no such thing as "natural order": without an order clause Passage.all may return things in any order the database wants (which could depend on things like location of items on disk, query plan etc).
The first and last methods are special in that they order by id if your relation does not already have an order applied to it.
If you need things in a specific order then add an order clause.

Related

We giving a task for Lua table but it is not working as expectable

Our task is create a table, and read values to the table using a loop. Print the values after the process is complete. - Create a table. - Read the number of values to be read to the table. - Read the values to the table using a loop. - Print the values in the table using another loop. for this we had written code as
local table = {}
for value in ipairs(table) do
io.read()
end
for value in ipairs(table) do
print(value)
end
not sure where we went wrong please help us. Our exception is
Input (stdin)
3
11
22
abc
Your Output (stdout)
~ no output ~
Expected Output
11
22
abc
Correct Code is
local table1 = {}
local x = io.read()
for line in io.lines() do
table.insert(table1, line)
end
for K, value in ipairs(table1) do
print(value)
end
Let's walk through this step-by-step.
Create a table.
Though the syntax is correct, table is a reserved pre-defined global name in Lua, and thus cannot should not be declared a variable name to avoid future issues. Instead, you'll need to want to use a different name. If you're insistent on using the word table, you'll have to distinguish it from the function global table. The easiest way to do this is change it to Table, as Lua is a case-sensitive language. Therefore, your table creation should look something like:
local Table = {}
Read values to the table using a loop.
Though Table is now established as a table, your for loop is only iterating through an empty table. It seems your goal is to iterate through the io.read() instead. But io.read() is probably not what you want here, though you can utilize a repeat loop if you wish to use io.read() via table.insert. However, repeat requires a condition that must be met for it to terminate, such as the length of the table reaching a certain amount (in your example, it would be until (#Table == 4)). Since this is a task you are given, I will not provide an example, but allow you to research this method and use it to your advantage.
Print the values after the process is complete.
You are on the right track with your printing loop. However, it must be noted that iterating through a table always returns two results, an index and a value. In your code, you would only return the index number, so your output would simply return:
1
2
3
4
If you are wanting the actual values, you'll need a placeholder for the index. Oftentimes, the placeholder for an unneeded variable in Lua is the underscore (_). Modify your for loop to account for the index, and you should be set.
Try modifying your code with the suggestions I've given and see if you can figure out how to achieve your end result.
Edited:
Thanks, Piglet, for corrections on the insight! I'd forgotten table itself wasn't a function, and wasn't reserved, but still bad form to use it as a variable name whether local or global. At least, it's how I was taught, but your comment is correct!

Custom order on string

I have a project model. Projects have a code attribute, which is in AAXXXX-YY format like "AA0001-18", "ZA0012-19", where AA is two characters, XXXX is a progressive number, and YY is the last two digits of the year of its creation.
I need to define a default scope that orders projects by code in a way that the year takes precedence over the other part. Supposing I have the codes "ZZ0001-17", "AA0001-18", and "ZZ002-17", "ZZ001-17" is first, "ZZ002-17" is second, and "AA001-18" is third.
I tried:
default_scope { order(:code) }
but I get "AA001-18" first.
Short answer
order("substring(code from '..$') ASC, code ASC")
Wait but why?
So as you said, you want to basically sort by 2 things:
the last 2 characters in the code string. YY
the rest of the code AAXXXX-
So first things first,
the order function as per Rails documentation will take the arguments you added and use them in the ORDER BY clause of the query.
Then, the substring function according to the documentation of PostgreSQL is:
substring(string from pattern)
If we want 2 characters .. from the end of the string $ we use ..$
Hence, substring(code from '..$')
For more information about pattern matching please refer to the documentation here.
Now finally, with the second part of our ordering the code which already will act as a sorter for all the preceding characters AAXXXX-.

rails combine parameters in controller

Hopefully this is a little clearer. I'm sorry but I'm very new to coding in general. I have multiple tables that I have to query in succession in order to get to the correct array that I need. The following logic for the query is as follows:
this gives me an array based upon the store :id
store = Stores.find(params[:id])
this gives me another array based upon the param .location found in the table store where that value equals the row ID in the table Departments
department = Departments.find(store.location)
I need to preform one last query but in order to do so I need to figure out which day of the meeting is needed. In order to do this I have to create the parameter day_of_meeting found in the table Stores. I try to call it from the array above and create a new variable. In the Table Departments, I there are params such as day_1, day_2 and so on. I need to be able to call something like department.day_1 or department.day_2. Thus, I'm trying to actually create the variable by join the words "department.day_" to the variable store.day_of_meeting which would equal some integer, creating department.day_1...
which_day = ["department.day_", store.day_of_meeting].join("")
This query finds uses the value found from the variable department.day_1 to query table Meeting to find the values in the corresponding row.
meeting = Meeting.find(which_day)
Does this make my problem any clearer to understand?
findmethod can only accept parameters like Meeting.find(1) or Meeting.find("1-xx").
so, what you need is Meeting.find(department.send("day_" + store.day_of_meeting.to_s))
Hope to help!

detect if a combination of string objects from an array matches against any commands

Please be patient and read my current scenario. My question is below.
My application takes in speech input and is successfully able to group words that match together to form either one word or a group of words - called phrases; be it a name, an action, a pet, or a time frame.
I have a master list of the phrases that are allowed and are stored in their respective arrays. So I have the following arrays validNamesArray, validActionsArray, validPetsArray, and a validTimeFramesArray.
A new array of phrases is returned each and every time the user stops speaking.
NSArray *phrasesBeingFedIn = #[#"CHARLIE", #"EAT", #"AT TEN O CLOCK",
#"CAT",
#"DOG", "URINATE",
#"CHILDREN", #"ITS TIME TO", #"PLAY"];
Knowing that its ok to have the following combination to create a command:
COMMAND 1: NAME + ACTION + TIME FRAME
COMMAND 2: PET + ACTION
COMMAND n: n + n, .. + n
//In the example above, only the groups of phrases 'Charlie eat at ten o clock' and 'dog urinate'
//would be valid commands, the phrase 'cat' would not qualify any of the commands
//and will therefor be ignored
Question
What is the best way for me to parse through the phrases being fed in and determine which combination phrases will satisfy my list of commands?
POSSIBLE solution I've come up with
One way is to step through the array and have if and else statements that check the phrases ahead and see if they satisfy any valid command patterns from the list, however my solution is not dynamic, I would have to add a new set of if and else statements for every single new command permutation I create.
My solution is not efficient. Any ideas on how I could go about creating something like this that will work and is dynamic no matter if I add a new command sequence of phrase combination?
I think what I would do is make an array for each category of speech (pet, command, etc). Those arrays would obviously have strings as elements. You could then test each word against each simple array using
[simpleWordListOfPets containsObject:word]
Which would return a BOOL result. You could do that in a case statement. The logic after that is up to you, but I would keep scanning the sentence using NSScanner until you have finished evaluating each section.
I've used some similar concepts to analyze a paragraph... it starts off like this:
while ([scanner scanUpToString:#"," intoString:&word]) {
processedWordCount++;
NSLog(#"%i total words processed", processedWordCount);
// Does word exist in the simple list?
if ([simpleWordList containsObject:word]) {
//NSLog(#"Word already exists: %#", word);
You would continue it with whatever logic you wanted (and you would search for a space rather than a ",".

How to sort a list of 1million records by the first letter of the title

I have a table with 1 million+ records that contain names. I would like to be able to sort the list by the first letter in the name.
.. ABCDEFGHIJKLMNOPQRSTUVWXYZ
What is the most efficient way to setup the db table to allow for searching by the first character in the table.name field?
The best idea right now is to add an extra field which stores the first character of the name as an observer, index that field and then sort by that field. Problem is it's no longer necessarily alphabetical.
Any suggestions?
You said in a comment:
so lets ignore the first letter part. How can I all records that start with A? All A's no B...z ? Thanks – AnApprentice Feb 21 at 15:30
I issume you meant How can I RETURN all records...
This is the answer:
select * from t
where substr(name, 1, 1) = 'A'
I agree with the questions above as to why you would want to do this -- a regular index on the whole field is functionally equivalent. PostgreSQL (with some new ones in v. 9) has some rather powerful indexing capabilities for special cases which you might want to read about here http://www.postgresql.org/docs/9.1/interactive/sql-createindex.html

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