I want to make button which save data and unwind to another controller (UITableViewController). My button is succeeded save data, but I don't make to unwind to another controller.
My button
#IBAction func buttonDone(sender: UIBarButtonItem) {
saveText() // it is a function of save data
[back]
}
A function
override func prepareForSegue(segue: (UIStoryboardSegue!), sender: AnyObject!) {
if (segue.identifier == "first") {
// pass data to next view
var backToFirst = segue.destinationViewController as FirstTableViewController
}
}
I make next
let back = prepareForSegue
To perform the unwind segue to have to call performSegueWithIdentifier("myUnwindSegueID") from the view controller that you're unwinding from.
You also need to make sure you've set up the unwind segue in IB. Have a look at this in case you haven't: http://spin.atomicobject.com/2014/10/25/ios-unwind-segues/
Assuming it's within a navigationcontroller simply call
self.navigationController!.popViewControllerAnimated(true)
Related
I have setting like this:
First controller reads data and sets in Second Controller.
Second Controller has a button that executes push segue to Third Controller with a countdown.
After countdown I want to go back from third controller to second that should still have data. Is there any way to achieve this?
Also I am using Storyboards.
I send data to Second Controller in prepare func. Second to Third controller change is connected directly to button in Storyboards.
override func prepare(for segue: UIStoryboardSegue, sender: AnyObject?) {
let controller = segue.destination as! QuestionViewController
controller.questionIDs = sender as! [Int]
}
To come back from Third to Second controller I use this code from Third controller:
self.performSegue(withIdentifier: "nobodyAnsweredSegue", sender: self)
Change this:
self.performSegue(withIdentifier: "nobodyAnsweredSegue", sender: self)
To this:
self.navigationController?.popViewControllerAnimated(true)
I want to create a segue to pass data to another view controller but there are certain criteria that must happen for the segue to happen. If possible i would prefer to use the segue Id instead of the dragging method.
this is an example Im trying to accomplish
#IBAction func SubmitButtonPressed(sender: AnyObject) {
if 1<0 {
// dont perform segue
}else{
//Perform segue
// i want to pass this data in the next VC
var data = "foo"
//this is my segue id i want o use to go to the Second VC
var segueId = "segueForgotPasswordTwo"
// second VC
var secondVc = "viewController2"
// Iwant to to use prepare for segue but im getting errors in the parameters
prepareForSegue(UIStoryboardSegue, sender: AnyObject?){
}
}
}
Your question is a bit unclear but I believe this is what you are looking for...
func someFunction(){
if //some condition {
//code
}else if //some condition {
//code
} else {
//perform segue by using the folowing line. Assign the identifier to the segue in the storyboard.
//Do this by first creating a segue by dragging from a view controller to the destination view controller. Be sure to drag from the VIEWCONTROLLER, to the destination VIEWCONTROLLER. DO NOT just drag from the button. Next, choose the type of segue (eg. show or present modally), and then type in an indentifier for this segue.
performSegueWithIdentifier("SegueIdentifier", sender: nil)
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "SegueIdentifier" {
//now find your view controller that you are seguing to.
let controller = segue.destinationViewController as! SomeViewController
//access the properties of your viewController and set them as desired. this is how you will pass data along
controller.property = someValue
}
}
Overview:
Hook the segue from the source view controller to the destination view controller (see left side red arrows)
Don’t hook it from the button to the destination view controller
Create an action for the button to do your custom condition check then perform segue
Screenshot:
Code:
var data = "foo"
#IBAction func buttonPressed(sender: UIButton) {
let someCondition = true
if someCondition {
performSegueWithIdentifier("showGreen", sender: self)
}
else {
performSegueWithIdentifier("showPink", sender: self)
}
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "showGreen" {
let greenVC = segue.destinationViewController as! GreenViewController
// Make sure the data variable exists in GreenViewController
greenVC.data = data
}
}
You can implement the shouldPerformSegueWithIdentifier function in your ViewController. When the segue is triggered, this function can cancel the segue if it returns false, so you can simply include whatever logic is required in this function and return true/false as appropriate.
I am using for the first time the Unwind Segue approach. I have multiple view controllers as can be seen in the picture below (a few of them shown of course). In the Edit Profile I have a Done button. Once clicked I trigger an IBAction that triggers an unwind segue.
Here is the code for the Done button in the nav bar:
#IBAction func unwindToMainViews(sender: UIStoryboardSegue) {
//let sourceViewController = sender.sourceViewController
self.performSegueWithIdentifier("unwindToMainSegue", sender: self)
}
and in the
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!)
I am doing the following to pass data from Edit Profile back to Home View
if (segue.identifier == "unwindToMainSegue") {
// pass data to next view
let tabCtrl = segue.destinationViewController as! UITabBarController
let destinationVC = tabCtrl.viewControllers![0] as! HomeViewController
destinationVC.userObject = self.userObject;
}
When segue identifier is matched and code is executed (to transfer userObject from this controller to another), it triggers the error:
Could not cast value of type 'app.EditProfileViewController' (0x100b99d80) to 'UITabBarController' (0x104a1d030).
How can this error be fixed? I am surprised since i am casting to UITabBarController so thought it should work.
You don't return to the UITabBarController in an unwind segue. You return to the ViewController that triggered the original segue, or one if its ancestors.
As #jlehr stated in the comments:
Unwind segues don't return to anything; they dismiss any pushed and
presented view controllers between the source and destination view
controller. The destination is wherever the implementation of the
unwind method is found, regardless of how the source view controller
was presented.
To unwind to the viewController that triggered the original segue, you need to implement the #IBAction func returnToHere(segue: UIStoryboardSegue) function in the viewController you want to return to.
Then when you set up your Done button by dragging to the Exit icon, you select returnToHere from the pop-up.
To pass data back to the sourceViewController, give your unwind segue an identifier such as "unwindToSource", then override prepareForSegue in the viewController you are returning from:
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "unwindToSource" {
let dvc = segue.destinationViewController as! SourceViewController
dvc.userObject = self.userObject
}
}
I have a segue running form a Collection View (wrapped in a view controller) in to a another view controller, how ever the function never gets called:
func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
println(segue.identifier)
println(sender)
println("SEGUE SELECTED: \(segue.identifier)")
if(segue.identifier == "segueToDetailView") {
let cell = sender as CollectionViewCell;
}
}
Have placed a breakpoint at start of function but never reached.
Any input appreciated.
I will suggest not to create segue(s) from cell or any object(like button).
Create segue from one ViewController to OtherViewController with unique identifier.
And then call the performSegueWithIdentifier yourself using the identifier.
help me please. how to make a button to do some operation or change to another view? I want that by pressing on it, commands were complete then need that moved on another view. please tell me how else to do to another kind in which a transition is updated when you press the button, all the same. And there were set data from datamodel
#IBAction func addNew(sender: AnyObject) {
let entity = NSEntityDescription.entityForName("Items", inManagedObjectContext:managedObjectContext!)
var item = Items(entity: entity!, insertIntoManagedObjectContext:managedObjectContext)
// I make the init from row coredata
item.titleIt = titleItem.description
item.textIt = textViewItem.description
var error: NSError?
managedObjectContext?.save(&error)
// MasterViewController.setValue(Items(), fromKey: "titlIt")
}
Add this at the end of your method:
let viewControllerToGoTo = ClassNameOfViewController()
self.presentViewController(viewController, animated: true, completion: nil)
Note: You may need to instantiate the view controller you want to present in a different way than just (). For example, you may want to load a view controller defined in a nib or storyboard.
To move to another view controller, you write these lines:
var viewController = ViewControllerNew()
self.presentViewController(viewController, animated: true, completion: nil)
But if you want to pass data to another view, I'd recommend using this method instead:
In your storyboard, select the view controller and drag from the blue-outlined yellow square at the top of the view controller to another view controller. A popup will appear, showing a list of segues. Select the item named 'Show'. Segues are placeholders for presenting view controllers -- you can call them at any time in your program. Select the segue, and under the menu on the right hand side type a name, for example 'toOtherScreen' into the text field labeled 'Identifier'. This will let you call the segue from a specific name.
Now go back to your IBAction for the button, and type this:
self.performSegueWithIdentifier("toOtherScreen", sender: self)
This will transition to the other screen. But what if you want to pass data to a screen, or do something when a segue is about to happen? Luckily for you, UIViewController class has a method named 'prepareForSegue', as shown below:
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "toOtherScreen" {
println("yes")
}
}
In this, we check if the segue has an identifier of "toOtherScreen", and if so, print "yes" to the logs. Now, to pass data to another view controller, it is a little more tricky. In the other view controller file, add a variable at the start of the class:
class OtherViewController: UIViewController {
var dataPassed: String = ""
override func viewDidLoad() {
super.viewDidLoad()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
}
And in your prepareForSegue method in the main view controller, type this:
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "toOtherScreen" {
let newViewController = segue.destinationViewController as OtherViewController()
newViewController.dataPassed = "NEW DATA"
}
}
Now it will change the variable named dataPassed in OtherViewController to 'NEW DATA'. You can see how you can achieve a lot through this simple way of passing data to other view controllers.
Hope I helped.