I just get started with WatchKit and I'm trying to do this (if I'm not wrong, it is possible to do): I'd like the WatchKit Extension to ask the containing app for requesting some data to a web service, and then return the service response to the Extension to update the WatchKit App interface accordingly.
As I read in Apple Watch Programming Guide, yo can call the openParentApplication:reply: method in the WatchKit Extension to request something to its containing app, and then the application:handleWatchKitExtensionRequest:reply: method in the AppDelegate of the containing app should be called. Once this method called, I need to perform the service request, wait for its response, and then send it back to the Extension.
However, when I run the WatchKit App scheme in the simulator, the openParentApplication:reply: method is called, but a breakpoint within the application:handleWatchKitExtensionRequest:reply: is not reached. So I'm not even able to test if I can correctly perform the web service request and get its response back.
What could I be missing? Should I configure somehow the schema to reach breakpoints in the containing app as well? Is it needed to declare some kind of background feature for this?
Thanks in advance
I just answered a very similar question here which will allow you to open the iOS app from the Watch Extension and getting a reply back.
In order to debug the iOS app while running the Watch Extension, you should follow the steps explained here.
Related
I tested:
UIControl().sendAction(#selector(URLSessionTask.suspend), to: UIApplication.shared, for: nil)
which is for putting app on background and it works.
How do I put app back on foreground?
I tried:
UIControl().sendAction(#selector(URLSessionTask.resume), to: UIApplication.shared, for: nil)
But eventually it crashes...
Thank you
Update:
Since you've indicated that you're looking for any technical solution, even those not compatible with the App Store or Apple's terms, this should be possible using the Private API LSApplicationWorkspace: openApplicationWithBundleID. Try something like this:
Create a .h file and set up an interface to the LSApplicationWorkspace class and list the required method. You will need to #import "PrivateHeaders.h" in your bridging header.
//
// PrivateHeaders.h
//
#ifndef PrivateHeaders_h
#define PrivateHeaders_h
#interface LSApplicationWorkspace : NSObject
- (bool)openApplicationWithBundleID:(id)arg1;
#end
#endif /* PrivateHeaders_h */
You should then be able to call this function and pass in the Bundle Identifier of your app as an string.
//
// SomeClass.swift
//
import MobileCoreServices
let workspace = LSApplicationWorkspace()
/**
Launch an App given its bundle identifier
- parameter bundleIdentifier: The bundle identifier of the app to launch
- returns: True if app is launched, otherwise false
*/
func openApp(withBundleIdentifier bundleIdentifier: String) -> Bool {
// Call the Private API LSApplicationWorkspace method
return workspace.openApplication(withBundleID: bundleIdentifier)
}
Original:
What you are doing is likely a violation of the iOS Human Interface Guidelines (although the "Don’t Quit Programmatically" is no longer specifically defined), so as the comments have said, it is not suited to the App Store. Regardless, once your app is suspended in this way, I don't expect that there is a way to resume it programmatically, unless you can hook into a Background Operation to run URLSessionTask.resume, but I have not tested it and am unsure whether it can work.
Apps can be launched (and hence brought into the foreground) programmatically from another app or today extension by using a Custom URL Scheme, or via a Push Notification. It isn't possible to launch the app from the Background Operation via a URL Scheme, since it is part of the UIKit framework, which must be run in the main thread.
In summary, I think your best option is to try to use a Notification. This just means that the user will need to click on the notification to bring your app back into the foreground.
Closing/opening the app should be done explicitly by the user. Any other way of closing or opening the app is not supported by Apple and will be rejected when uploaded to app store. iOS Human Interface Guideline states:
Don’t Quit Programmatically
Never quit an iOS application
programmatically because people tend to interpret this as a crash.
However, if external circumstances prevent your application from
functioning as intended, you need to tell your users about the
situation and explain what they can do about it. Depending on how
severe the application malfunction is, you have two choices.
*Display
an attractive screen that describes the problem and suggests a
correction. A screen provides feedback that reassures usersthat
there’s nothing wrong with your application. It puts usersin control,
letting them decide whether they want to take corrective action and
continue using your application or press the Home button and open a
different application
*If only some of your application's features are
not working, display either a screen or an alert when people activate
the feature. Display the alert only when people try to accessthe
feature that isn’t functioning
Just as a follow up to Jordan's excellent answer I want to give an explanation for why your code works in the first place and why that alone will get your app rejected, even without any functionality to make it active again and bring it to the foreground.
As maddy pointed out in a comment, you're basically calling a method from UIApplication's private API. This works due to the Objective-C runtime's dynamic linking. You might wonder "But I am using Swift, what does that have to do with Objective-C?" The answer lies in #selector mechanism. A Selector is basically just a symbol that the Objective-C runtime looks up in a table to get a method it invokes (for you). This is why it's technically not correct to say you "call a method" when you do something like myObjectInstance.someMethod(). The correct way to phrase that would be to "send a message" to the object, because that's what is happening in the runtime. The target-action mechanism is build around that. The sendAction(_: Selector?, to: Any?) method does the same thing. So in effect your code does the following:
Get the symbol that corresponds to URLSessionTask's suspend() method.
Tell the shared instance of UIApplication to invoke the method that it has for that symbol.
Now usually that would result in a crash with the typical "unknown selector sent to instance..." error message. But here, by sure coincidence UIApplication also has a method for that instance (or rather, the runtime also has one of its methods listed in its table for that symbol). You kind of "found" a method that is not declared in its public header. You successfully circumvented a compile-time check for this and invoke a method that is part of a private API. This is explicitly forbidden in the Apple Developer Program License Agreement
Besides all that, I would strongly advise against trying to design an app that way in the first place. As maddy pointed out it's also likely considered to violate the HIGs. Even if you're not trying to do anything malicious and properly explain the feature in your app's description, that won't make Apple let it slide (I assume). Personally, as a user, I'd also find it annoying if the app did something the system already has a specific mechanic for in a different manner, at least in terms of app's coming to background and foreground.
I don't think it can be done without user interaction
The option is you can generate a push notification to tell the user to bring the application to foreground
When the operating system delivers push notification and the target application is not running in the foreground, it presents the notification.
If there is a notification alert and the user taps or clicks the action button (or moves the action slider), the application launches and calls a method to pass in the local-notification object or remote-notification payload.
I tested:
UIControl().sendAction(#selector(URLSessionTask.suspend), to: UIApplication.shared, for: nil)
which is for putting app on background and it works.
How do I put app back on foreground?
I tried:
UIControl().sendAction(#selector(URLSessionTask.resume), to: UIApplication.shared, for: nil)
But eventually it crashes...
Thank you
Update:
Since you've indicated that you're looking for any technical solution, even those not compatible with the App Store or Apple's terms, this should be possible using the Private API LSApplicationWorkspace: openApplicationWithBundleID. Try something like this:
Create a .h file and set up an interface to the LSApplicationWorkspace class and list the required method. You will need to #import "PrivateHeaders.h" in your bridging header.
//
// PrivateHeaders.h
//
#ifndef PrivateHeaders_h
#define PrivateHeaders_h
#interface LSApplicationWorkspace : NSObject
- (bool)openApplicationWithBundleID:(id)arg1;
#end
#endif /* PrivateHeaders_h */
You should then be able to call this function and pass in the Bundle Identifier of your app as an string.
//
// SomeClass.swift
//
import MobileCoreServices
let workspace = LSApplicationWorkspace()
/**
Launch an App given its bundle identifier
- parameter bundleIdentifier: The bundle identifier of the app to launch
- returns: True if app is launched, otherwise false
*/
func openApp(withBundleIdentifier bundleIdentifier: String) -> Bool {
// Call the Private API LSApplicationWorkspace method
return workspace.openApplication(withBundleID: bundleIdentifier)
}
Original:
What you are doing is likely a violation of the iOS Human Interface Guidelines (although the "Don’t Quit Programmatically" is no longer specifically defined), so as the comments have said, it is not suited to the App Store. Regardless, once your app is suspended in this way, I don't expect that there is a way to resume it programmatically, unless you can hook into a Background Operation to run URLSessionTask.resume, but I have not tested it and am unsure whether it can work.
Apps can be launched (and hence brought into the foreground) programmatically from another app or today extension by using a Custom URL Scheme, or via a Push Notification. It isn't possible to launch the app from the Background Operation via a URL Scheme, since it is part of the UIKit framework, which must be run in the main thread.
In summary, I think your best option is to try to use a Notification. This just means that the user will need to click on the notification to bring your app back into the foreground.
Closing/opening the app should be done explicitly by the user. Any other way of closing or opening the app is not supported by Apple and will be rejected when uploaded to app store. iOS Human Interface Guideline states:
Don’t Quit Programmatically
Never quit an iOS application
programmatically because people tend to interpret this as a crash.
However, if external circumstances prevent your application from
functioning as intended, you need to tell your users about the
situation and explain what they can do about it. Depending on how
severe the application malfunction is, you have two choices.
*Display
an attractive screen that describes the problem and suggests a
correction. A screen provides feedback that reassures usersthat
there’s nothing wrong with your application. It puts usersin control,
letting them decide whether they want to take corrective action and
continue using your application or press the Home button and open a
different application
*If only some of your application's features are
not working, display either a screen or an alert when people activate
the feature. Display the alert only when people try to accessthe
feature that isn’t functioning
Just as a follow up to Jordan's excellent answer I want to give an explanation for why your code works in the first place and why that alone will get your app rejected, even without any functionality to make it active again and bring it to the foreground.
As maddy pointed out in a comment, you're basically calling a method from UIApplication's private API. This works due to the Objective-C runtime's dynamic linking. You might wonder "But I am using Swift, what does that have to do with Objective-C?" The answer lies in #selector mechanism. A Selector is basically just a symbol that the Objective-C runtime looks up in a table to get a method it invokes (for you). This is why it's technically not correct to say you "call a method" when you do something like myObjectInstance.someMethod(). The correct way to phrase that would be to "send a message" to the object, because that's what is happening in the runtime. The target-action mechanism is build around that. The sendAction(_: Selector?, to: Any?) method does the same thing. So in effect your code does the following:
Get the symbol that corresponds to URLSessionTask's suspend() method.
Tell the shared instance of UIApplication to invoke the method that it has for that symbol.
Now usually that would result in a crash with the typical "unknown selector sent to instance..." error message. But here, by sure coincidence UIApplication also has a method for that instance (or rather, the runtime also has one of its methods listed in its table for that symbol). You kind of "found" a method that is not declared in its public header. You successfully circumvented a compile-time check for this and invoke a method that is part of a private API. This is explicitly forbidden in the Apple Developer Program License Agreement
Besides all that, I would strongly advise against trying to design an app that way in the first place. As maddy pointed out it's also likely considered to violate the HIGs. Even if you're not trying to do anything malicious and properly explain the feature in your app's description, that won't make Apple let it slide (I assume). Personally, as a user, I'd also find it annoying if the app did something the system already has a specific mechanic for in a different manner, at least in terms of app's coming to background and foreground.
I don't think it can be done without user interaction
The option is you can generate a push notification to tell the user to bring the application to foreground
When the operating system delivers push notification and the target application is not running in the foreground, it presents the notification.
If there is a notification alert and the user taps or clicks the action button (or moves the action slider), the application launches and calls a method to pass in the local-notification object or remote-notification payload.
I have an iPhone app and added a WatchExtension. Now I managed to send a string to the Watch using the MMWormhole. In order to use the string I must call update() inside the WKInterfaceController from a method inside my UIViewController, so the iPhone application.
Is that possible?
I tried to do something like InterfaceController.update() but Xcode complained that it does not know the variable InterfaceController.
Thanks in advance :)
The iPhone App and Watch Extension are TWO seperate process, although they are stored in ONE bundle, so you can not call the method of other process in runtime.
In WatchKit:
If you want to share code, use Framework.
If you want to share data, use App Group.
If you want to use notification, use Inter-Process Communication(In iOS, It's Darwin Notification, and MMWormhole use this feature).
I think you want to let the Watch update its interface when iPhone app do something, you can do like this:
send a message to Watch Extension.
Watch Extension receive that message.
In the message handler, update interface.
In my option, the iPhone App and Watch Extension can be seen as a kind of C/S architecture, iPhone App is Server and Watch Extension is Client, maybe this metaphor is easier to understand.
I have a share extension implemented for iOS8. The service uses OAuth to authenticate. The login info I use for the extension is shared with the container app.
The problem is:
When I am in the extension, then app switch to the container app and logout, and then app switch back to the host app containing the extension - How do I detect that the extension has just re-appeared? The extension is relying on certain information to be present in the shared DB between the container app and the extension, however, that data is removed when the app logs out.
I have tried registering for various "app notifications" such as UIApplicationDidBecomeActiveNotification. However, as expected, these aren't called for extensions.
How can I detect when the state of the extension changes such that I can make my extension more robust when it reappears?
The viewDidAppear:animated: method of your main view controller class should be called every time you reenter your extension. When you are about to leave, viewWillDisappear:animated: should be called.
See
NSExtensionContext.h
iOS 8.2 added a number of notifications to use for extensions:
NSExtensionHostDidBecomeActiveNotification
NSExtensionHostDidEnterBackgroundNotification
NSExtensionHostWillEnterForegroundNotification
NSExtensionHostWillResignActiveNotification
How programmatically restart an iPhone app in iOS?
I find this way http://writeitstudios.com/david/?p=54
But may be something simple.
The only way I know to do this is not ideal, but it works.
First, your app has to opt out of background execution (multitasking) The app has to quit when exited, not run as a background task. This is done with the plist key UIApplicationExitsOnSuspend.
Second, your app needs to register a custom URL scheme that can be used to launch the app.
Third, you need a web page hosted somewhere that when loaded will redirect to your app's custom URL scheme.
Forth, the user needs an active Internet connection.
To exit and restart, call UIApplication openURL on your hosted redirecting web page. Your app will exit and safari will launch and load your page. The page will redirect Safari to your custom URL scheme, prompting Safari to internally call openURL, causing iOS to launch your app.
my post that you linked to is referring to a Cocoa Application, not the iOS. On the iOS, you can quit an application (but Apple doesn't like this) by using exit(0); but I don't recommend that. You cannot restart iPhone apps though.
Unless you're developing for jailbroken devices, Apple won't even allow you to programatically terminate your app. So restarting the device is out of the question.
Your AppDelegate instance has a method
(void)applicationDidBecomeActive:(UIApplication *)application
{
}
In here, you can put logic to figure out if the app should restart, or continue doing whatever it was doing. For example you can have a BOOL variable appMustRestart that is false at first but gets triggered as true whenever something happens in your app that you'd like the next time to be a fresh relaunch.
if (appMustRestart)
{
[self resetVars]; // call a method that resets all your vars to initial settings
// INSERT CODE HERE TO TRANSFER FOCUS TO INITIAL VIEWCONTROLLER
}