I have a UITableViewController that I would like people to access as the main page. I do have a login view controller but I do not want this to be my initial view controller. I have an if statement checking if the user has logged in previously. If not, I would like to perform a segue to the login view controller. When I run the app however, it goes through the if statement, recognizes that the user is == nil, and then goes right over the performSegueWithIdentifier operation.
override func viewDidLoad() {
super.viewDidLoad()
if user == nil {
self.performSegueWithIdentifier("LoginSegue", sender: self)
}
}
Any idea why?
You should move your code into the viewWillAppear or viewDidAppear method.
Then it should use properly.
But now the view flickers a short time. To remove that flickering, just hide the view in your viewWillApear method:
self.view.hidden = true
Also the viewDidLoad method doesn't get called everytime the view appears but only the first time it loads. If you for example perform a segue and return back to the view, it doesn't load again but only calls viewWillAppear and viewDidAppear again.
For Swift 3.0, try to run on the main thread like this.
DispatchQueue.main.async {
self.performSegue(withIdentifier: "LoginSegue", sender: self)
}
Without more information it is hard to say.
Do you have a button or something with an already established segue, and have you provided the identifier for the segue? I made a similar call in viewDidLoad and it worked.
Have you embedded the view controller in a UINavigationController? If not, performing the segue is not possible. It sounds like you're using a UITableViewController, which inherits from UIViewController. So this may be the issue.
dispatch_async(dispatch_get_main_queue(), { () -> Void in
let viewController:UIViewController = self.storyboard?.instantiateViewControllerWithIdentifier("ViewControllerClassId") as! ViewControllerClassName
self.presentViewController(viewController, animated: true, completion: nil)
})
this code solved my problem.
use my code instead of
self.performSegueWithIdentifier("LoginSegue", sender: self)
and give your destination ViewController an ID like ViewControllerClassId
Related
I start of with a tableViewController that has a list of names. When the user taps on a name, they are segued to a view controller.
While in that viewController the user may press a button that will take them to another table view Controller.
The layout is like this:
TableViewController(1) -> ViewController -> TableViewController(2)
My question is, how can I pop back to the first TableViewController from the Second TableViewController.
My rootViewController is my signIn View controller so I cannot pop back to root.
You can run this to pop to your rootViewController:
self.navigationController?.popToRootViewController(animated: true)
Update:
Since your rootViewController is not where you want to end up then you can iterate through your controllers and pop to a specific one:
for controller in self.navigationController!.viewControllers {
if controller.isKind(of: TableViewControllerOne.self) {
self.navigationController!.popToViewController(controller, animated: true)
break
}
}
Instead of TableViewControllerOne.self update to your desired controller.
If you're familiar with segues, you can implement an unwind segue. That would give you the added benefit of passing information back to TableViewController(1) if you needed to. To make that work in TableViewController1 you would add some code that looked like:
#IBAction func unwind(fromTableVC2 segue: UIStoryboardSegue) {
if (segue.source is TableVC2) {
if let svc = segue.source as? TableVC2 {
// pass information back
}
}
}
Then in your storyboard you would go to where you have your TableVC2 and drag the yellow VC circle to the exit and choose the function we created above. Name the segue (for this example we'll call it "UnwindToTableVC1"), and then somewhere in TableVC2 add the code:
func setVariableToPassBack () {
// Set up variables you want to pass back
performSegue(withIdentifier: "UnwindToTableVC1", sender: self) }
And that will take you back to your chosen destination with any information you wanted to pass back.
If you don't want to pass anything back, you really just need call the below line in your TableVC2:
performSegue(withIdentifier: "UnwindToTableVC1", sender: self)
In my App, I've created a new storyboard that serves as a very basic tutorial for how to use certain features. (Instructions.storyboard). This storyboard has it's own class - InstructionsVC.swift
I want to present InstructionsVC when MainVC loads within viewDidAppear.
It works great. Fires up on App load just like it's supposed to. The problem occurs when I press the [Close] button on the Instructions interface. It closes the VC, fades to the main screen, and then immediately fires the Instructions VC back up.
How can I prevent the Instructions VC from loading back up once it's closed?
func openInstructions() {
let storyboard = UIStoryboard(name: "Instructions", bundle: nil)
let instructionsView = storyboard.instantiateViewController(withIdentifier: "instructionsStoryboardID")
instructionsView.modalPresentationStyle = .fullScreen
instructionsView.modalTransitionStyle = .crossDissolve
self.present(instructionsView, animated: true, completion:nil)
}
override func viewDidAppear(_ animated: Bool) {
openInstructions()
}
And within my instructions class, I have the following action on the close button:
#IBAction func closeButtonPressed(_ sender: UIButton) {
let presentingViewController: UIViewController! = self.presentingViewController
presentingViewController.dismiss(animated: true, completion: nil)
}
Note - I'd rather not use UserDefaults to resolve this, because I'm going to be incorporating something similar in other parts of the App and don't want to resort to UserDefaults to achieve the desirable behavior.
Thanks in advance buddies!
viewWillAppear and viewDidAppear are called every time a view controller's content view becomes visible. That includes the first time it's rendered and when it's shown again after being covered by a modal or by another view controller being pushed on top of it in a navigation stack.
viewDidLoad is only called once when a view controller's content view has been loaded, but before it is displayed. Thus when viewDidLoad is called it may be too soon to invoke your second view controller.
You might want to add an instance variable hasBeenDisplayed to your view controller. In viewDidAppear, check hasBeenDisplayed. If it's false, display your second view controller and set hasBeenDisplayed to true.
Here's what I'm trying to do:
I have 2 views, Settings and Main Screen.
I've coded a segue to occur when a button in Settings is pressed, taking the view to the Main Screen. The identifier is "reset".
I'm trying to have the Main Screen perform a series of actions if this segue is triggered, but I can't find the function or way to do this.
Any help on how to implement this? I'd like it to trigger when the segue occurs.
You can pass arguments to the main screen in the prepareForSegue function in the settings page. Then in your main screen you can put in checks in your viewWillAppear function to handle them as you see fit.
Example:
In Settings:
override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!) {
if (segue.identifier == "reset") {
// pass data to next view
let viewController:ViewController = segue!.destinationViewController as MainViewController
viewController.settings = settings // where settings is what you want to pass
}
}
In Main Screen:
override func viewWillAppear(animated: Bool) {
super.viewWillAppear(animated)
if self.settings { // Do something }
}
If you're wanting something to happen when the segued view controller is triggered you can do it in a couple of places.
If you want the event to happen at the time the segue is fired, perform your code inside of prepareForSegue. There you can check the UIStoryboardSegue object's identifier field for "reset" and if true, call your logic.
If you want it to happen when the destination view controller loads or appears, do it inside of its viewDidLoad or viewDidAppear methods. In your case those methods would exist on the "Main Screen" view controller class.
I created a file called "Util.swift" and it has a class "class VC: UIViewController" and has a 2 functions:
Next(segue: String) {
performSegueWithIdentifier(segue, completion: nil)
}
Back() {
dismissViewControllerAnimated(true, completion: nil)
}
So basically, the functions just tell the current viewController to go to the next View or go back to the previous view.
However, in another file, I have an IBAction which is attached to a button and in that action I call the function "Back" in the Util file by doing this:
#IBACTION func ~~~ {
nextVC = Util()
nextVC.back()
}
However, when I click the button, it doesn't do anything.
When I try to connect another button to an action that calls the "next" function in the Util file by doing the same thing and putting in the segue indetifier parameter, it says SIGABRT error: no segue identifier called "xxx".
Can anyone help me? Should I simply use XIB and not use segues?
You have to initialize the UIViewController either with storyBoard or with XIB. If you are doing with factory init() method then it doesn't do anything for you; that means, that is not a viewController which is associated either with storyBoard or XIB. So all you need to do is instantiate the viewController with either options. Before that you need to set an identifier for the viewController to instantiate it.
let storyBoard = UIStoryBoard(name: "MainStoryBoard", bundle: nil)
let vc = storyBoard.instanstiateViewControllerWithIdentifier("YOUR_IDENTIFIER") as! Util
//call your Next method like this
vc.Next(segue:"identifier")
Please refer the document
Apple Doc
In order to use segues, the view controller instance needs to be associated with a Storyboard. In order to be associated with a storyboard, a view controller instance either needs to be the result of a segue or instantiated from a storyboard via instantiateViewControllerWithIdentifier.
When you create an instance of Util via Util() you have a view controller instance that isn't associated with a storyboard and isn't actually presented on screen.
As a result, when you try and perform a segue, you get an error since the segue can't be found.
Also, when you try and dismiss the view controller in back() you are trying to dismiss a view controller that isn't presented.
I am not sure why you want to wrap two fairly simple functions inside next and back, but you can do this using a superclass for all of your view controllers and have this superclass implement your next and back functions:
class MyViewContollerSuperclass: UIViewController {
func next(segue: String) {
self.performSegueWithIdentifier(segue, sender: self)
}
func back() {
self.dismissViewControllerAnimated(true, completion: nil)
}
}
Then you actual view controller would be declared as:
class MyActualViewController: MyViewContollerSuperclass {
#IBACTION func ~~~ {
self.back()
}
}
I am trying to make a splash screen. I have a view that has a background image being drawn onto it and then another view I want to transition to after a few seconds. I am trying to use the following code:
self.performSegueWithIdentifier("showApp", sender: self)
I created a segue between the two views by ctrl+dragging a line from one to the other. I set the segue's identifier to "showApp".
When I run the code nothing happens and there are no errors. Any ideas?
Here is the controller for the splash screen:
class SplashViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
sleep(2)
// THIS DOES NOTHING:
self.performSegueWithIdentifier("showApp", sender: self)
// THIS AS SUGGESTED ALSO DOES NOTHING:
var otherViewController:UIViewController = self.storyboard.instantiateViewControllerWithIdentifier("test") as UIViewController
self.presentViewController(otherViewController, animated: true, completion: nil)
}
}
Normally, you need a navigation controller in order to use segue.
Highlight your SplashViewController object inside the Storyboard and go to
Editor -> Embeded In -> Navigation Controller
After that, remove the code suggested by Clement and try running the project again, you should get the result that you expected.