I'm facing a problem when I try to remove a character in a 'NSString'. The character is a backend (\n).
My 'NSString' is for example like this :
My text is
also in a second line
And I want to get all in one line like this :
My text is also in a second line
The problem is I don't know how to change this...
I tried to locate the '\n' characters with a loop :
for (int delete = 0; delete < myString.length; delete++)
{
if ([myString characterAtIndex:delete] == 10)
{
[myString stringByReplacingCharactersInRange:NSMakeRange(delete,0) withString:#" "];
}
}
Or things like :
myString = [myString stringByReplacingOccurrencesOfString:#"\r" withString:#" "];
(I see that \r could be the backend in a nslog...)
Nothings work..
Thank you for your help in advance !
myString = [myString stringByReplacingOccurrencesOfString:#"\n" withString:#""];
is correct.
If it doesn't work, then the assumption that there is a combination of "\" and "n" characters is wrong.
Do not use NSLog. NSLog already applies carriage returns to the string. Instead put a breakpoint on the line where we call stringByReplacing... and then hover over the myString. Wait a second or two and you will see the "original unformatted content"...this way you can check what you are really trying to replace..
Related
i have a NSString with parentheses in it.
I would like to remove the Text inside of the parentheses.
How to do that? ( In Objective-C )
Example String:
Tach auch. (lockeres Ruhrdeutsch) Und Hallo!
I would like to Remove "(lockeres Ruhrdeutsch)" from the String,
but the Strings i have to edit are always different.
How can i remove the String betweeen "(" and ")"?
Best Regards
Use regular expression:
NSString *string = #"Tach auch. (lockeres Ruhrdeutsch) Und Hallo!";
NSString *filteredString = [string stringByReplacingOccurrencesOfString:#"\\(.*\\)"
withString:#""
options:NSRegularExpressionSearch range:NSMakeRange(0, string.length)];
NSLog(#"%#", filteredString);
If you want to consider also a whitespace character after the closing parenthesis, add \\s? to the end of the regex pattern.
Here is the function you can call to get your required string:
-(NSString*)getStringWithBlankParaFrom:(NSString*)oldStr{
NSArray*strArray1=[oldStr componentsSeparatedByString:#"("];
NSString*str2=[strArray1 objectAtIndex:1];
NSArray*strArray2 =[str2 componentsSeparatedByString:#")"];
NSString*strToReplace=[strArray2 objectAtIndex:0];
return [oldStr stringByReplacingOccurrencesOfString:strToReplace withString:#""];
}
This function is valid for the string which contains one pair of parentheses**()**
You can change it as per your requirement.
Hope this helps!
Inside of a for loop, I have an if statement that looks like this:
if([numberValues rangeOfString:#"+"].location == NSNotFound) {
NSLog(#"Phone Number does not contain a plus sign.");
} else {
NSLog(#"Phone number does contain a +");
[numberValues stringByReplacingOccurrencesOfString:#"+" withString:#""];
NSLog(#"This new numberValues object should not have a + anymore: %#", numberValues);
}
I can confirm that the rangeOfString: method call works perfectly because there are phone numbers in my address book that do not start with a "+" and it will print "Phone Number does not contain a plus sign." to the log.
My problem is that the stringByReplacingOccurrencesOfString: call does not work. Right after the call, when I print the numberValues object data to the log, the phone number still looks like this "+13997573173" instead of being printed without the plus sign like "13997573173".
I have even tried changing the "+" in the method call to something like the first 4 digits of the phone number and it still will not replace the target string with the new string.
It just prints the same value every time. Any ideas why stringByReplacingOccurrencesOfString: is not working for me?
The method stringByReplacingOccurrencesOfString:withString: actually returns a string, and does not mutate the string you've passed in.
So you likely want to do something like this instead:
numberValues = [numberValues stringByReplacingOccurrencesOfString:#"+"
withString:#""];
numberValues = [numberValues stringByReplacingOccurrencesOfString:#"+"
withString:#""];
stringByReplacingOccurrencesOfString return a new string.assign it to origin string.
I am reading a line of code in from a source file on disk and the line is a string, and it is of a string that contains HTML code in it:
line = #"format = #"<td width=\"%#\">";"
I need to remove the escaped characters from the html string. So any place that there is a '\"', I need to replace it with ''. I tried this:
[line stringByReplacingOccurrencesOfString:#"\\""" withString:#""];
But it only removed the '\' character, not the accompanying '"'. How can I remove the escaped '"' from this string?
EDIT: The key part of this problem is that I need to figure out a way to identify the location of the first #", and the closing " of the string declaration, and ignore/remove everything else. If there is a better way to accomplish this I am all ears.
[s stringByReplacingOccurrencesOfString:#"\\\"" withString:#""]
The replacement string there is a slash, which has to be escaped in the literal replacement string using another slash, followed by a quote, which also has to be escaped in the literal by a slash.
Try use this:
NSString *unfilteredString = #"!##$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:#"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"] invertedSet];
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:#""];
NSLog (#"Result: %#", resultString);
I'm trying to check the suffix of a string against a character set but I'm getting errors:
if ([string hasSuffix:[NSCharacterSet characterSetWithCharactersInString:#"(+-*/"])
What am I doing wrong, is there a correct alternative?
-[NSString hasSuffix:] takes an NSString as its argument, not an NSCharacterSet. Your best bet is probably to call -[NSString rangeOfCharacterFromSet:options:] with NSBackwardsSearch as an option and check that the location is at the end of the string.
What are you trying to do?
I think that you are trying to see if the first letter of your string is one of the characters from the set. If so, then use this:
NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:#"(+-*/"];
if ([[string substringToIndex:1] rangeOfCharacterFromSet:set].location != NSNotFound)
// String starts with one of the characters from the character set
In Objective-C for iOS, how would I remove the last character of a string using a button action?
In your controller class, create an action method you will hook the button up to in Interface Builder. Inside that method you can trim your string like this:
if ([string length] > 0) {
string = [string substringToIndex:[string length] - 1];
} else {
//no characters to delete... attempting to do so will result in a crash
}
If you want a fancy way of doing this in just one line of code you could write it as:
string = [string substringToIndex:string.length-(string.length>0)];
*Explanation of fancy one-line code snippet:
If there is a character to delete (i.e. the length of the string is greater than 0)
(string.length>0) returns 1 thus making the code return:
string = [string substringToIndex:string.length-1];
If there is NOT a character to delete (i.e. the length of the string is NOT greater than 0)
(string.length>0) returns 0 thus making the code return:
string = [string substringToIndex:string.length-0];
Which prevents crashes.
If it's an NSMutableString (which I would recommend since you're changing it dynamically), you can use:
[myString deleteCharactersInRange:NSMakeRange([myRequestString length]-1, 1)];
The solutions given here actually do not take into account multi-byte Unicode characters ("composed characters"), and could result in invalid Unicode strings.
In fact, the iOS header file which contains the declaration of substringToIndex contains the following comment:
Hint: Use with rangeOfComposedCharacterSequencesForRange: to avoid breaking up composed characters
See how to use rangeOfComposedCharacterSequenceAtIndex: to delete the last character correctly.
The documentation is your friend, NSString supports a call substringWithRange that can shorten the string that you have an return the shortened String. You cannot modify an instance of NSString it is immutable. If you have an NSMutableString is has a method called deleteCharactersInRange that can modify the string in place
...
NSRange r;
r.location = 0;
r.size = [mutable length]-1;
NSString* shorted = [stringValue substringWithRange:r];
...