Switching on class type in Dart - dart

I'm looking to write a function in a Dart superclass that takes different actions depending on which subclass is actually using it. Something like this:
class Foo {
Foo getAnother(Foo foo) {
var fooType = //some code here to extract fooType from foo;
switch (fooType) {
case //something about bar here:
return new Bar();
case //something about baz here:
return new Baz();
}
}
}
class Bar extends Foo {}
class Baz extends Foo {}
where the idea is that I have some object and want to get a new object of the same (sub)class.
The main question is what type should fooType be? My first thought was Symbol, which leads to easy case statements like case #Bar:, but I don't know how I would populate fooType with a Symbol. The only options I can think of are to do something like Symbol fooType = new Symbol(foo.runtimeType.toString()); but my understanding is that runtimeType.toString() won't work when converted to javascript. You could get around that by using Mirrors, but this is meant to be a lightweight library, so those aren't on the table. Object.runtimeType returns something of the Type class, but I have no idea how to create instances of Type I could use for the case statements. Maybe I'm missing some other piece of the Dart library that is better suited for this?

You can use the runtimeType in switch :
class Foo {
Foo getAnother(Foo foo) {
switch (foo.runtimeType) {
case Bar:
return new Bar();
case Baz:
return new Baz();
}
return null;
}
}
In the case statements the class name is used directly (AKA class literal). This gives a Type object corresponding to the class mentioned. Thus foo.runtimeType can be compared with the specified type.
Note that you can not use generics for now in class literals. Thus, case List<int>: is not allowed.

Related

How to override enum's "name" property?

Minimal reproducible code:
enum Foo {
a,
b;
String get name {
switch (this) {
case Foo.a: return 'A';
case Foo.b: return 'B';
}
}
}
void main() {
printEnum<Foo>(Foo.values);
}
void printEnum<T extends Enum>(List<T> list) {
for (var e in list) {
print(e.name);
}
}
The for loop prints
a
b
But I wanted it to print
A
B
So, how do I override the name property in the enum?
Note:
Using (e as Foo).name will solve the issue, but I have many enums in my project, so I can't cast them like this.
Also, please don't post answers like, use toUpperCase(), etc, because I just provided a simple example, but in real world, things are quite different.
You cannot override the name getter "on Enum" because it's an extension getter, not an instance getter.
Overriding, aka. late binding, of instance members only apply to actual (virtual) instance members.
Extension members are statically resolved, so a call of .name either hits the extension member, or it doesn't, and it depends entirely on the static type of the receiver. If you have an Enum e; ... e.name ... then it will call the extension member, and there is absolutely no way to change that, or change what it does.
If you want to have a custom and overridable name getter, I'd introduce an interface like
abstract class NamedEnum extends Enum {
String get name;
}
and then let all your enums implement NamedEnum.
Then you can do (enumValue as NamedEnum).name for any of your enums.
It won't interact with other enum types' extension name getter.
Casting e as dynamic works, as long as you ensure that the name property exists on the enum you are printing. Ex:
void printEnum<T extends Enum>(List<T> list) {
for (var e in list) {
print((e as dynamic).name);
}
}

Creating an interface for construction

A few times now I've run into a use case where I need to define an interface for how classes construct themselves. One such example could be if I want to make an Interface Class that defines the interface by which objects can serialize and unserialize themselves (for input into a database, to be sent as JSON, etc). You might write something like this:
abstract class Serializable {
String serialize();
Serializable unserialize(String serializedString);
}
But now you have a problem, as serialize() is properly an instance method, and unserialize() should instead be a static method (which isn't inheritable or enforced by the Interface) or a constructor (which also isn't inheritable).
This leaves a state where classes that impliment the Serializable interface are required to define a serialize() method, but there is no way to require those classes to define a static unserialize() method or Foo.fromSerializedString() constructor.
If you make unserialize() an instance method, then unserializing an implementing class Foo would look like:
Foo foo = new Foo();
foo = foo.unserialize(serializedString);
which is rather cumbersome and ugly.
The only other option I can think of is to add a comment in the Serializable interface asking nicely that implementing classes define the appropriate static method or constructor, but this is obviously prone to error if a developer misses it and also hurts code completion.
So, is there a better way to do this? Is there some pattern by which you can have an interface which forces implementing classes to define a way to construct themselves, or something that gives that general effect?
You will have to use instance methods if you want the inheritance guarantees. You can do a bit nicer than manual instantiation though, by using reflection.
abstract class Serializable {
static Serializable fromSerializedString(Type type, String serializedString) {
ClassMirror cm = reflectClass(type);
InstanceMirror im = cm.newInstance(const Symbol(''), []);
var obj = im.reflectee;
obj.unserialize(serializedString);
return obj;
}
String serialize();
void unserialize(String serializedString);
}
Now if someone implements Serializable they will be forced to provide an unserialize method:
class Foo implements Serializable {
#override
String serialize() {
// TODO: implement serialize
}
#override
void unserialize(String string) {
// TODO: implement unserialize
}
}
You can get an instance like so:
var foo = Serializable.fromSerializedString(Foo, 'someSerializedString');
This might be a bit prettier and natural than the manual method, but keep in mind that it uses reflection with all the problems that can entail.
If you decide to go with a static method and a warning comment instead, it might be helpful to also provide a custom Transformer that scans through all classes implementing Serializable and warn the user or stops the build if any don't have a corresponding static unserialize method or constructor (similar to how Polymer does things). This obviously wouldn't provide the instant feedback the an editor could with instance methods, but would be more visible than a simple comment in the docs.
I think this example is a more Dart-like way to implement the encoding and decoding. In practice I don't think "enforcing" the decode signature will actually help catch bugs, or improve code quality. If you need to make the decoder types pluggable then you can make the decoders map configurable.
const Map<String,Function> _decoders = const {
'foo': Foo.decode,
'bar': Bar.decode
};
Object decode(String s) {
var obj = JSON.decode(s);
var decoder = _decoders[obj['type']];
return decoder(s);
}
abstract class Encodable {
abstract String encode();
}
class Foo implements Encodable {
encode() { .. }
static Foo decode(String s) { .. }
}
class Bar implements Encodable {
encode() { .. }
static Foo decode(String s) { .. }
}
main() {
var foo = decode('{"type": "foo", "i": 42}');
var bar = decode('{"type": "bar", "k": 43}');
}
A possible pattern I've come up with is to create a Factory class that utilize instance methods in a slightly less awkward way. Something like follows:
typedef Constructable ConstructorFunction();
abstract class Constructable {
ConstructorFunction constructor;
}
abstract class Serializable {
String serialize();
Serializable unserialize(String serializedString);
}
abstract class SerializableModel implements Serializable, Constructable {
}
abstract class ModelFactory extends Model {
factory ModelFactory(ConstructorFunction constructor) {
return constructor();
}
factory ModelFactory.fromSerializedString(ConstructorFunction constructor, String serializedString) {
Serializable object = constructor();
return object.unserialize(serializedString);
}
}
and finally a concrete implementation:
class Foo extends SerializableModel {
//required by Constructable interface
ConstructorFunction constructor = () => new Foo();
//required by Serializable interface
String serialize() => "I'm a serialized string!";
Foo unserialize(String serializedString) {
Foo foo = new Foo();
//do unserialization work here to populate foo
return foo;
};
}
and now Foo (or anything that extends SerializableModel can be constructed with
Foo foo = new ModelFactory.fromSerializedString(Foo.constructor, serializedString);
The result of all this is that it enforces that every concrete class has a method which can create a new instance of itself from a serialized string, and there is also a common interface which allows that method to be called from a static context. It's still creating an extra object whose whole purpose is to switch from static to instance context, and then is thrown away, and there is a lot of other overhead as well, but at least all that ugliness is hidden from the user. Still, I'm not yet convinced that this is at all the best way to achieve this.
I suggest you define the unserialize function as named constructor like so:
abstract class Serializable<T> {
String serialize();
Serializable.unserialize(String serializedString);
}
This eliminates the need of static methods.
A possible implementation could look like this:
import 'dart:convert';
class JsonMap implements Serializable<JsonMap> {
Map map = {};
JsonMap() {
}
String serialize() {
return JSON.encode(map);
}
JsonMap.unserialize(String serializedString) {
this.map = JSON.decode(serializedString);
}
}
You can (de)serialize like so:
JsonMap m = new JsonMap();
m.map = { 'test': 1 };
print(m.serialize());
JsonMap n = new JsonMap.unserialize('{"hello": 1}');
print(n.map);
While testing this, I noticed that Dart will not throw any errors at you if you dont actually implement the methods that your class promises to implement with implements. This might just be a hicc-up with my local Dart, though.

Generics type parameter wildcard

I would like to create an abstract class which takes a type parameter and the constructor of that class should be passed another Action eg.
abstract class Action<Tc> {
public function __construct(private ?Action<*> $onSuccess = null) {}
}
How can I express a type parameter wildcard ie. "?" (Java) or "_" (Scala) in Hack?
Hack doesn't have wildcard type parameters right now, so the closest you can get is actually specifying a dummy type parameter that you don't actually need, e.g.,
abstract class Action<Tc, Ta> {
public function __construct(private ?Action<Ta> $onSuccess = null) {}
// ...
}
Depending on how exactly you use the $onSuccess member variable, you may want it to be some specific subclass of Action<T> to be determined later, and so you may want something like this:
abstract class Action<Tc, Ta, To as Action<Ta>> {
public function __construct(private ?To $onSuccess = null) {}
// ...
}
However, I question whether the "dummy" types above above are really a dummy -- the vast, vast majority of use cases of Action<T> are going to care what exactly the T is, otherwise how exactly would you use the Action<T>? (There are certainly rare cases where you don't care about the T at a callsite, but they are, well, rare and so I encourage you to consider whether that is actually your case as you build out this functionality.)
Not sure about a wildcard, but could this achieve what you want?
<?hh
abstract class Action<T1 as Action, T2> {
public function __construct(private ?T1 $onSuccess = null, private ?T2 $bla = null) {}
}
class ActionA<T1 as Action, T2> extends Action<T1, T2> {}
class ActionB<T1 as Action, T2> extends Action<T1, T2> {}
class ActionC<T1 as Action, T2> extends Action<T1, T2> {}
$action = new ActionA(new ActionB(new ActionC(null)));
var_dump($action);
When I run this against HHVM 3.1.0, I get:
object(ActionA)#1 (2) {
["onSuccess":"Action":private]=>
object(ActionB)#2 (2) {
["onSuccess":"Action":private]=>
object(ActionC)#3 (2) {
["onSuccess":"Action":private]=>
NULL
["bla":"Action":private]=>
NULL
}
["bla":"Action":private]=>
NULL
}
["bla":"Action":private]=>
NULL
}
And the 3.1.0 type checker also returns "No errors!".
However, the T1 as Action statement on the abstract class doesn't appear to be enforcing. For instance, I can change the instantiation line to:
$action = new ActionA(new ActionB(new ActionC(new DateTime())));
And it hums along fine, with the typechecker returning no errors still. And this is after taking the class definitions out into their own file with <?hh // strict.
So not really your answer, but perhaps close? The behavior above might suggest Hack has some issues with this sort of pattern?

Effective implementation of generic matching Tokens

This is a base trait that I use in my tiny parser app:
trait Token[ValueType] {
def value: ValueType
}
This is what I require. I'd also like to combine a good feature of Java with a good feature of Scala i.e.:
Java approach to enums (they're normal objects with methods, can ihnerit etc.)
Scala suport for matching (readable code)
so an example of classes extending Token are:
// this to emulate Java enums; ProperEnumeration just adds some simple methods like fromChars etc.
object Keywords extends ProperEnumeration {
val AND, ARRAY, BEGIN, CASE, CONST, ... = Value
}
// this to enable matching
final case class Keyword(keyword: Keywords.Value) extends Token[Keywords.Value] {
def this(string: String) = this(Keywords.fromString(string))
def value = keyword
}
object SpecialSymbols extends ProperEnumeration {
val LEFT_BRACE = Value("{")
val RIGHT_BRACE = Value("}")
...
}
final case class SpecialSymbol(symbol: SpecialSymbols.Value) extends Token[SpecialSymbols.Value] {
def this(symbol: String) = this(SpecialSymbols.fromString(symbol))
def value = symbol
}
// there are also non-enum subclasses of Token
case class Identifier(identifier: String) extends Token[String] {
override def value: String = identifier
}
This is the best I came up with. I can use it like this:
token match {
case Keyword(Keywords.BEGIN) => ...
case SpecialSymbol(SpecialSymbols.LEFT_BRACE) => ...
case Identifier(name) => ...
}
I'd like to modify it to allow me to be more concise, I'd like something like this:
token match {
case Keyword.BEGIN => ... // or Keyword(BEGIN)
case SpecialSymbol.LEFT_BRACE => ...
case Identifier(name) => ...
}
to also suport a method called consume that would work with any kind of Token subclass (consume should throw an exception if the next token from source is NOT the argument supplied).
consume(Keyword.BEGIN);
consume(SpecialSymbol.LEFT_BRACE);
consume(Identifier(name));
I want the code to be clean, that's why I use Scala in the first place. So I hope for no function overloads to allow easy addition of Trait subclasses.
So, dear Scalists, what to do?
The simplest way to have
case Keyword(BEGIN) => ...
is to simply import the keywords:
import Keywords._
It won't require any other changes to your code.
However, I personally would prefer to avoid ProperEnumerarion and have a simple hierarchy of traits and case objects:
trait Keyword
case object BEGIN extends Keyword
case object CASE extends Keyword
This will automatically give pattern matching:
token match {
case BEGIN => ...
}
If you need some methods in objects you may have them declared in the trait of have some abstract class (with a constructor):
abstract class Keyword(val name:String) {
def myMethod = "Keyword."+name
}
case object BEGIN extends Keyword("BEGIN")
case object CASE extends Keyword("CASE")
UPD: You may use an object that instantiates "enum" instances the same way as Enumeration:
object AllMyKeywords {
val BEGIN = Keyword("BEGIN")
val CASE = Keyword("CASE")
// etc.
val values = List(BEGIN, CASE, ...).map(k => (k.name, k)).toMap
}
UPD2: There is also a way to make pattern matching with strings:
abstract class Keyword(val name:String) {
def unapply(str:String):Option[Keyword] = {
if(AllMyKeywords.values.contains(str))
Some(AllMyKeywords.values(str)
else
None
}
}
In this case the unapply method is implemented by every BEGIN, CASE keywords and thus it is directly called (at least I think so).
"BEGIN" match { case BEGIN => ??? }

Does the Dart programming language have an equivalent to Javascript's "prototype"?

In Dart, is it possible for a function to have a prototype associated with it?
Example Javascript code:
doStuff.prototype.isDefined = true; //is there anything like Javascript's function prototypes in Dart?
function doStuff(){
console.log("The function doStuff was called!");
}
Is it possible to do the equivalent of this in Dart (i.e., create a list of properties for each function?)
Two things to address here:
First, Dart doesn't have prototypes or prototypal inheritance, and instead uses classical inheritance. Rather than a prototype, objects have a class, and instead of a prototype chain, objects have superclasses.
Second, for your specific case, I think we'd have to see more of what you need to do to figure out the idiomatic way to do it in Dart. It should soon be possible to emulate functions with objects so that you can invoke an object and still have state and other methods associated with it.
See this article for more: http://www.dartlang.org/articles/emulating-functions/
When that capability lands you'll be able to do this:
class DoStuff {
bool isDefined = true;
call() => print("The function doStuff was called!");
}
var doStuff = new DoStuff();
main() => doStuff();
Which works if you have a fixed set of metadata about your function that you need to keep track of. It's slightly different from JavaScript because each instance of the function in Dart will have its own state for isDefined. I'm not sure if it's possible or easy to get multiple instances of the function in JavasScript, but you might need to make isDefined static so that the value is shared across all instances.
Dart does not allow you to add or remove member variables from an instance of a class at runtime. Rewriting your example in Dart it might look something like this:
class doStuff {
bool isDefined;
doStuff() {
isDefined = true;
}
void stuff() {
print('The function stuff was called!');
}
}
main() {
new doStuff().stuff();
}
If you wanted to add a property bag to a class in Dart you would write:
class PropertyObject {
Map<String, Dynamic> properties;
PropertyObject() {
properties = new Map<String, Dynamic>();
}
Dynamic operator[](String K) => properties[K];
void operator[]=(String K, Dynamic V) => properties[K] = V;
}
main() {
PropertyObject bag = new PropertyObject();
bag['foo'] = 'world';
print('Hello ${bag['foo']}');
}
Note that you can't access map properties using the '.' operator.

Resources