No visible #interface for method declares the selector - ios

Question

I'm trying to write an app that takes photo from contact named Jan Kowalski and shows on screen.
I'm pretty new to iOS and xCode and so I got errors in my code.
Here's my .m file
#import "ViewController.h"
#interface ViewController ()
#end
#implementation ViewController
//#synthesize labelNewImage;
#synthesize labelOldImage;
//#synthesize imageViewNew;
#synthesize imageViewOld;
- (void) changePositionOfView:(UIView *)paramView to:(CGFloat)paramY
{
CGRect viewFrame = paramView.frame;
viewFrame.origin.y = paramY;
paramView.frame = viewFrame;
}
- (void) createLabelAndImageViewForOldImage
{
self.labelOldImage = [[UILabel alloc] initWithFrame:CGRectZero];
self.labelOldImage.text = #"Obraz";
self.labelOldImage.font = [UIFont systemFontOfSize:16.0f];
[self.labelOldImage sizeToFit];
self.labelOldImage.center = self.view.center;
[self.view addSubview:self.labelOldImage];
[self changeYPositionOfView:[self.labelOldImage
to:80.0f]];// error - no visible #interface for 'UILabel' that declares the selector to
self.imageViewOld = [[UIImageView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, 100.0f, 100.0f)];
self.imageViewOld.center = self.view.center;
self.imageViewOld.contentMode = UIViewContentModeScaleAspectFit;
[self.view addSubview:self.imageViewOld];
[self changeYPositionOfView:[self.imageViewOld to:105.0f]];
}
- (ABRecordRef)getPersonWithFirstName:(NSString *)paramFirstName
lastName:(NSString *)paramLastName
inAddressBook:(ABRecordRef)paramAddressBook
{
ABRecordRef result = NULL;
if (paramAddressBook == NULL) {
NSLog(#"Ksiazka ma wartosc NULL");
return NULL;
}
NSArray *allPeople = (__bridge_transfer NSArray *)
ABAddressBookCopyArrayOfAllPeople(paramAddressBook);
NSUInteger peopleCounter = 0;
for (peopleCounter=0; peopleCounter < [allPeople count]; peopleCounter++) {
ABRecordRef person = (__bridge ABRecordRef)
[allPeople objectAtIndex:peopleCounter];
NSString *firstName = (__bridge_transfer NSString *)
ABRecordCopyValue(person, kABPersonFirstNameProperty);
NSString *lastName = (__bridge_transfer NSString *)
ABRecordCopyValue(person, kABPersonLastNameProperty);
BOOL firstNameIsEqual = NO;
BOOL lastNameIsEqual = NO;
if ([firstName length] == 0 && [paramFirstName length] == 0)
{
firstNameIsEqual = YES;
}
else if ([firstName isEqualToString:paramFirstName])
{
firstNameIsEqual = YES;
}
if ([lastName length] == 0 && [paramLastName length] == 0)
{
lastNameIsEqual = YES;
}
else if ([lastName isEqualToString:paramLastName])
{
lastNameIsEqual = YES;
}
if (firstNameIsEqual && lastNameIsEqual) {
return person;
}
}
return result;
}
- (void)viewDidLoad {
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
self.view.backgroundColor = [UIColor blackColor];
[self createLabelAndImageViewForOldImage];
ABAddressBookRef addressBook = ABAddressBookCreate();
if (addressBook !=NULL) {
ABRecordRef janKowalski = [self getPersonWithFirstName:#"Jan" lastName:#"Kowalski" inAddressBook:addressBook];
if (janKowalski == NULL) {
NSLog(#"Nie znaleziono kontaktu tworzenie nowego.");
janKowalski = [self newPersonWithFirstName:#"Jan" // error - no visible #interface for 'ViewController' that declares the selector 'newPersonWithFirstName
lastName:#"Kowalski"
inAddressBook:addressBook];
}
if (janKowalski == NULL) {
NSLog(#"Nie udało się utworzyć nowego rekordu dla tego kontaktu.");
CFRelease(addressBook);
return;
}
self.imageViewOld.image = [[self getPersonImage]:janKowalski]; // error - no visible #interface for 'ViewController' delcares the selector 'getPersonImage'
}
}
and my .h file:
#import <UIKit/UIKit.h>
#import <AddressBook/AddressBook.h>
#interface ViewController : UIViewController
#property (strong, nonatomic) UILabel *labelOldImage;
#property (strong, nonatomic) UIImageView *imageViewOld;
#end
I'm getting these "no visible #interface for 'UILabel' that declares the selector to" errors.
Could you guys get me on the right way how to solve this problem?
Thank you so much!

Answer 1

It's really just an error in placing square brackets. You've defined a method with two parameters...
changePositionOfView:(UIView *)paramView to:(CGFloat)paramY
...but you're calling it with only one...
[self changeYPositionOfView:[self.labelOldImage to:80.0f]];
Check the matching of the brackets.
The compiler thinks you want to call [self.labelOldImage to:80.0f] and pass the result to a single-parameter method called justchangeYPositionOfView:.
Pass values to both parameters by fixing the nesting:
[self changeYPositionOfView:self.labelOldImage to:80.0f];

Answer 2

The problem:
- changePositionOfView:(UIView *)paramView to:(CGFloat)paramY
But you send this:
[self changeYPositionOfView:[self.labelOldImage
to:80.0f]];// error - no visible #interface for 'UILabel' that declares the selector to
Make it with 2 params.
And yeah, when you use #synthesize, after that call label/image with labelOldImager, not self.labelOldImage.