Share files between host system and docker container using specific UID - docker

Question

I'm trying to share files within a Docker guest using the volume sharing. In order to get the same UID, and therefore interoperability with those files, I would like to create a user in the Docker guest with the same UID as my own user.
In order to test out the idea, I wrote the following simplistic Dockerfile:
FROM phusion/baseimage
RUN touch /root/uid-$UID
Testing it with docker build -t=docktest . and then docker run docktest ls -al /root reveals that the file is simply named uid-.
Is there a means to share host environment variables with Docker during the guest build process?

Answer 1

While researching a solution to this problem, I have found the following article to be a great resource: https://medium.com/#mccode/understanding-how-uid-and-gid-work-in-docker-containers-c37a01d01cf
In my scripts, the solution boiled down to the following :
docker run --user $(id -u):$(id -g) -v /hostdirectory:/containerdirectory -v /etc/passwd:/etc/passwd myimage
Of course, id -u can be replaced by other means of retrieving a user's gid, such as stat -c "%u" /somepath

Answer 2

The environment is not shared, you could use -e, --env options to set env variables in container.
I usually use this approach when I want to have the same owner of the mapped volume: I check uid & gid of directory in container and then create a corresponding user. Here my script (setuser.sh) which creates a user for a directory:
#!/bin/bash
setuser() {
if [ -z "$1" ]; then
echo "Usage: $0 <path>"
return
fi
CURRENT_UID=`id -u`
DEST_UID=`stat -c "%u" $1`
if [ $CURRENT_UID = $DEST_UID ]; then
return
fi
DEST_GID=`stat -c "%g" $1`
if [ -e /home/$DEST_UID ]; then
return
fi
groupadd -g $DEST_GID $DEST_GID
useradd -u $DEST_UID -g $DEST_GID $DEST_UID
mkdir -p /home/$DEST_UID
chown $DEST_UID:$DEST_GID /home/$DEST_UID
}
setuser $1
And this is the wrapper script which runs commands as the user, where the directory with permissions is specified either as $USER_DIR or in /etc/user_dir
#!/bin/bash
if [ -z "$USER_DIR" ]; then
if [ -e /etc/user_dir ]; then
export USER_DIR=`head -n 1 /etc/user_dir`
fi
fi
if [ -n "$USER_DIR" ]; then
if [ ! -d "$USER_DIR" ]; then
echo "Please mount $USER_DIR before running this script"
exit 1
fi
. `dirname $BASH_SOURCE`/setuser.sh $USER_DIR
fi
if [ -n "$USER_DIR" ]; then
cd $USER_DIR
fi
if [ -e /etc/user_script ]; then
. /etc/user_script
fi
if [ $CURRENT_UID = $DEST_UID ]; then
"$#"
else
su $DEST_UID -p -c "$#"
fi
P.S. Alleo suggested different approach: to map users and groups files into container and to specify uid and gid. So your container does not depend on built-in users/groups you could use it without additional scripts.

Answer 3

This is not possible and will probably never be possible because of the design philosophy of keeping builds independent of machines. Issue 6822.

Answer 4

I slightly modified #ISanych answer:
#!/usr/bin/env bash
user_exists() {
id -u $1 > /dev/null 2>&1
}
group_exists() {
id -g $1 > /dev/null 2>&1
}
setuser() {
if [[ "$#" != 3 ]]; then
echo "Usage: $0 <path> <user> <group>"
return
fi
local dest_uid=$(stat -c "%u" $1)
local dest_gid=$(stat -c "%g" $1)
if user_exists $dest_uid; then
id -nu $dest_uid
return
fi
local dest_user=$2
local dest_group=$3
if user_exists $dest_user; then
userdel $dest_user
fi
if group_exists $dest_group; then
groupdel $dest_user
fi
groupadd -g $dest_gid $dest_group
useradd -u $dest_uid -g $dest_gid -s $DEFAULT_SHELL -d $DEFAULT_HOME -G root $dest_user
chown -R $dest_uid:$dest_gid $DEFAULT_HOME
id -nu $dest_user
}
REAL_USER=$(setuser $SRC_DIR $DEFAULT_USER $DEFAULT_GROUP)
setuser function accepts user and group names that you want to assign to uid and gid of provided directory. Then if user with such uid exists then it simply returns login corresponding to this uid, otherwise it creates user and group and returns login originally passed to function.
So you get the login of user that owns destination directory.