Create Regular Expression for specified string in objective c - ios

Question

My NSString like below
#"[o=uid=35=] hghk\u00c2\u00a0 [o=uid=30=] [o=uid=35=] cong."
I need to create regular expression which search numeric values (e.g in first square brackets there is 35 in second there is 30 like this) in between square parenthesis. How could i achieve this task. Is there any alternate way to search numeric values in between square parenthesis? Please help me to short resolve from this. your help would be appreciable.

Answer 1

Using NSRegularExpression,
NSString* strSource = #"[o=uid=35=] hghk\u00c2\u00a0 [o=uid=30=] [o=uid=35=] cong.";
NSError* errRegex = NULL;
NSRegularExpression* regex = [NSRegularExpression
regularExpressionWithPattern:#"uid=([0-9]+)"
options:NSRegularExpressionCaseInsensitive
error:&errRegex];
NSUInteger countMatches = [regex numberOfMatchesInString:strSource
options:0
range:NSMakeRange(0, [strSource length])];
NSLog(#"Number of Matches: %ld", (unsigned long)countMatches);
[regex enumerateMatchesInString:strSource options:0
range:NSMakeRange(0, [strSource length])
usingBlock:^(NSTextCheckingResult* match,
NSMatchingFlags flags, BOOL* stop) {
NSLog(#"Ranges: %ld", (unsigned long)[match numberOfRanges]);
NSString *matchFull = [strSource substringWithRange:[match range]];
NSLog(#"Match: %#", matchFull);
for (int i = 0; i < [match numberOfRanges]; i++) {
NSLog(#"\tRange %i: %#", i,
[strSource substringWithRange:[match rangeAtIndex:i]]);
}
}];
if (errRegex) {
NSLog(#"%#", errRegex);
}

Answer 2

http://regexpal.com/
use above link to check the expression
\b[0-9]+
to find all the integer values
([0-9])+
it works.

Answer 3

You can build a regular expression like this:
uid=([0-9]+)
This will find any numbers after "uid=" sequence in a string. The value of the number will be available in "match 1", since it is put in parentheses. You can try out this Regex interactively with http://rubular.com/.

Answer 4

if you just want numeric value then you can try this
NSString *mainString = #"[o=uid=35=] hghk\u00c2\u00a0 [o=uid=30=] [o=uid=35=] cong.";
NSArray *arr = [mainString componentsSeparatedByString:#"="];
for(int i=0;i<arr.count;i++)
{
NSString *newString = arr[i];
NSCharacterSet* notDigits = [[NSCharacterSet decimalDigitCharacterSet] invertedSet];
if ([newString rangeOfCharacterFromSet:notDigits].location == NSNotFound)
{
NSLog(#"%#",newString);
// newString consists only of the digits 0 through 9
}
}

Answer 5

Here is my code,it works perfectly..we can check easily below array contains object(numbers between '[' and ']') or not without using any regex.
NSString *tmpTxt = #"[o=uid=35=] hghk\u00c2\u00a0 [o=uid=30=] [o=uid=35=] cong.";
NSString*splittxt=tmpTxt;
NSMutableArray*array=[[NSMutableArray alloc]init];
for (int i=0; i<i+1; i++) {
NSRange r1 = [splittxt rangeOfString:#"["];
NSRange r2 = [splittxt rangeOfString:#"]"];
NSRange rsub=NSMakeRange(r1.location + r1.length-1, r2.location - r1.location - r1.length+2);
if (rsub.length >2 ){
NSCharacterSet *AllowedChars = [[NSCharacterSet characterSetWithCharactersInString:#"1234567890"] invertedSet];
NSString*stringg=[splittxt substringWithRange:rsub];
stringg = [[stringg componentsSeparatedByCharactersInSet:AllowedChars] componentsJoinedByString:#""];
[array addObject:stringg];
}
else
{
break;
}
splittxt=[splittxt stringByReplacingCharactersInRange:rsub withString:#""];
}
NSLog(#"%#",array);
}
the array value is
(
35,
30,
35
)