So here I have my routes
concern :search do
scope '/search' do
get '/', to: 'users#search'
get '/schedule/:id', to: 'schedules#user'
end
end
concerns :search
scope '/dashboard' do
concerns :search
end
The problem is rails didn't give me path helpers. How can I have different path for my concerns based on where I call it. I'd like to have something like this
search_path
search_schedule_path
dashboard_search_path
dashboard_search_schedule_path
Finally I've figured it
concern :search do
scope '/search', as: :search do
get '/', to: 'users#search'
get '/schedule/:id', to: 'schedules#user', as: :schedule
end
end
concerns :search
scope '/dashboard', as: :dashboard do
concerns :search
end
and here is my path helper
search_path
search_schedule_path
dashboard_search_path
dashboard_search_schedule_path
Related
I have written freindly URLs for the show action of the School Resource but now have
before i had ;
http://webaddress/schools/2
and now i have;
http://webaddress/schools/school_name
However, i want
http://webaddress/school_name
My config routes look like this for the resource;
resources :schools do
collection do
match 'search' => 'schools#search', via: [:get, :post], as: :search
end
end
How can i achieve that? thank you
Add this at the last your routes file:
match ':id' => 'schools#show', via: [:get]
A more conventional way would be to use the path: option in your route resources, like this:
#config/routes.rb
...
resources :schools, path: "", only: :show #-> has to go at end of file!
This will give you the ability to add different methods to this, as well as keeping with Rails conventions :)
I have a search scope for my users with the following route:
resources :users do
collection do
get :search
end
end
This however generates /users/search as url. I would like to have /search as url. I tried the following:
get '/search', as: :search
get '/search' => 'users#search', as: :search
get :search, to: 'users#search', as: :search
They don't seem to work since I keep getting routing errors. What would be the correct way to write it?
This one should work (without the leading '/') :
resources :users
get 'search' => 'users#search', as: :search
The named helpers for this route will be search_path and search_url
you can also use match:
match "/search", to: "users#search", via: "get"
I'm trying to setup a route that looks like this: acme.com/posts/:category/:status. Both :category and :status are optional. I wrote many variations, but none worked:
resources :posts do
match '(/:category)(/:status)', to: 'posts#index', as: 'filter', on: :collection
end
# Category Links
link_to "Questions", filter_posts_path(:questions)
link_to "Suggestions", filter_posts_path(:suggestions)
# Status Links
link_to "Published", filter_posts_path(params[:category], :published)
link_to "Draft", filter_posts_path(params[:category], :draft)
The idea is to be able to 1) filter by category, 2) filter by status, and 3) filter by both category and status if both are available. The current setup has also broken my /posts/new path, always redirecting to posts#index.
I had this variation and it seems working fine:
namespace :admin do
resources :posts, :except => [:show] do
collection do
get "/(:category(/:status))", to: "posts#index", as: "list", :constraints => lambda{|req|
req.env["PATH_INFO"].to_s !~ /new|\d/i
}
end
end
end
= CONTROLLER=admin/posts rake route
list_admin_posts GET /admin/posts(/:category(/:status))(.:format) admin/posts#index
You can use the more RESTful resources :posts (in config/routes.rb) and send the params in the query string.
With that approach, all parameters are optional and you're not limited to using predefined parameters.
Do this works for you?
resources :posts do
collection do
match '/:category(/:status)', to: 'posts#index', as: 'filter'
match '/:status', to: 'posts#index', as: 'filter'
end
end
Hope at least it helps!
You could try something like this:
match '/filter/*category_or_status' => 'posts#index', as: 'filter'
With this you can build your own filter path. Then you could parse params[:category_or_status] in your controller and get the category or status if they are given.
I want to get link to user like: /chicago/123-olegpasko .
In my helper:
def users_path(user)
"/#{if user.city; user.city.name; else; "city";end}/#{user.to_param}"
end
How can I create a right routes?
Now I have something like:
match 'dontknow/:id' => 'users#show', :as => :users
Check out the Railcasts about friendly_url
Also take a look at the routes casts
Simple add this lines in you model:
def to_param
"#{id}-#{name.parameterize}"
end
The solution was simple:
match ':name/:id' => 'users#show', :as => :users
I have a few reoccurring patterns in my routes.rb and I would like to make it DRY by creating a method that creates those routes for me.
An example of what I want to accomplish can be seen in the Devise gem where you can use the following syntax:
#routes.rb
devise_for :users
Which will generate all the routes necessary for Devise. I would like to create something similar. Say for example that I have the following routes:
resources :posts do
member do
get 'new_file'
post 'add_file'
end
match 'files/:id' => 'posts#destroy_file', :via => :delete, :as => :destroy_file
end
resources :articles do
member do
get 'new_file'
post 'add_file'
end
match 'files/:id' => 'articles#destroy_file', :via => :delete, :as => :destroy_file
end
This starts getting messy quite quickly so I would like to find a way to do it like this instead:
resources_with_files :posts
resources_with_files :articles
So my question is, how can I create the resources_with_files method?
Put this in something like lib/routes_helper.rb:
class ActionDispatch::Routing::Mapper
def resources_with_files(*resources)
resources.each do |r|
Rails.application.routes.draw do
resources r do
member do
get 'new_file'
post 'add_file'
delete 'files' => :destroy_file
end
end
end
end
end
end
and require it in config/routes.rb